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N12

Interpret fractions and percentages as operators

Fractions and percentages as operators

Worked answers, methods and verified real exam appearances for N12 on Edexcel GCSE Maths 1MA1.

Definition

Specification N12: interpret fractions and percentages as operators. A fraction or percentage “of” a quantity means multiply by it, and a sequence of operators is applied in order, each to the current amount.

Explanation

  • To find ab\dfrac{a}{b} of an amount, divide by bb and multiply by aa, or multiply by the fraction directly: 27\dfrac{2}{7} of 420420 is 420×2÷7=120420\times2\div7=120. A percentage becomes a decimal or fraction operator, 35%35\% of 420420 being 420×0.35=147420\times0.35=147.
  • A percentage change is one multiplier: a 15%15\% decrease multiplies by 0.850.85, an increase of 15%15\% by 1.151.15.
  • When several operators apply, each acts on the amount that remains, not on the original: “38\dfrac{3}{8} of the reduced price” means multiply the reduced price by 38\dfrac{3}{8}.
  • Problems that mix a fraction, a percentage and a ratio are worked one step at a time, subtracting the shares already taken before splitting the remainder, and the scheme gives a process mark for each share.
  • A correct answer with no working scores nothing on these questions.

Worked example

1

A machine costs £640\pounds640. Its price is reduced by 15%15\%. A customer pays 38\dfrac{3}{8} of the reduced price as a deposit and the rest in one further payment. Work out the amount of the further payment.

(4)

(Total for Question 1 is 4 marks)

Working

  1. 1.Apply the reduction multiplier: 640×0.85=£544640\times0.85=\pounds544.
  2. 2.Find the deposit as a fraction of the reduced price: 544×38=£204544\times\dfrac{3}{8}=\pounds204.
  3. 3.Subtract to find the balance: 544−204=£340544-204=\pounds340, or directly 544×58544\times\dfrac{5}{8}.

Answer: £340\pounds340

Mark scheme

Mark scheme for question 1
QuestionAnswerMarkAdditional guidance
1for a process to find the reduced price, eg 640×0.85640\times0.85 or 640−640×15÷100640-640\times15\div100 (= 544)P1oe
for a process to find the deposit, eg “544” ×3÷8\times3\div8 (= 204)P1
(dep) for a complete process, eg “544” −- “204” or “544” ×5÷8\times5\div8P1
for 340340A1cao

Common mistakes

  • Don't divide by the numerator and multiply by the denominator for a fraction of an amount.
  • Don't use 0.150.15 as the multiplier for the price after a 15%15\% decrease.
  • Don't calculate the deposit from the original price instead of the reduced price.

Mark-scheme wording to use

  • “P1 for 160 ÷ (3+7) (= 16) or 3/(3 + 7) (= 3/10) P1 for “16” × 3 (= 48) or “3/10” × 160 (= 48) P1 for a correct step using 48 eg “48” ÷ 8 (= 6) or “48” × 25 ÷ 100 (= 12) … P1 for a complete process to find the number of petrol cars, eg “48” – “6” – “12” oe … A1 cao … Award no marks for a correct answer with no supportive working” — Pearson 1MA1, June 2022 Paper 1H, Q3
  • “for a process to find the number of banana cakes, eg 420 × 0.35 oe (= 147)” — Pearson 1MA1, June 2017 Paper 3H, Q4
  • “P1 Process to find number of boys walking and number of girls walking P1 Complete process to find probability A1 10/26 oe” — Pearson 1MA1, Sample Paper 3F, Q15

What the examiner wants

Each operator applied to the right amount, in order. The November 2024 Paper 3H report describes a ratio and percentage problem where students who found the quantities correctly then worked out a percentage profit for each item separately and added them, giving 88.8%88.8\%, and the Paper 3H report of the same series notes that increasing or decreasing £46.75\pounds46.75 by 15%15\% scored nothing when the operator had to be reversed.

Exam tip

Write each fraction or percentage as a multiplier beside the amount it operates on.

Worked practice

Q1
Tier 1 · Easy

1

Work out 35\dfrac{3}{5} of 7070.

(1)

(Total for Question 1 is 1 mark)

Mark scheme

Mark scheme for question 1
QuestionAnswerMarkMark scheme
1
  • 4242
1Divide by 55 and multiply by 33: 70÷5×3=14×3=4270\div5\times3=14\times3=42.
Q2
Tier 2 · Standard

2

Work out 17.5%17.5\% of 240240.

(2)

(Total for Question 2 is 2 marks)

Mark scheme

Mark scheme for question 2
QuestionAnswerMarkMark scheme
2
  • 4242
2Use the decimal operator 17.5%=0.17517.5\%=0.175. Then 0.175×240=420.175\times240=42.
Q3
Tier 3 · Hard

3

A machine costs £640\pounds640. Its price is reduced by 15%15\%, then a customer pays 38\dfrac{3}{8} of the reduced price as a deposit. Work out the balance still to pay.

(4)

(Total for Question 3 is 4 marks)

Mark scheme

Mark scheme for question 3
QuestionAnswerMarkMark scheme
3
  • £340\pounds340
4After the reduction, the price is 0.85×640=5440.85\times640=544. The deposit is 38×544=204\dfrac{3}{8}\times544=204. Therefore the remaining balance is 544−204=340544-204=340.
Q4
Tier 1 · Easy

4

Work out 30%30\% of 9090.

(1)

(Total for Question 4 is 1 mark)

Mark scheme

Mark scheme for question 4
QuestionAnswerMarkMark scheme
4
  • 2727
110%10\% of 9090 is 99, so 30%30\% is 3×9=273\times9=27.
Q5
Tier 2 · Standard

5

A museum ticket costs £35\pounds35. Its price is increased by 18%18\%. Work out the new price.

(2)

(Total for Question 5 is 2 marks)

Mark scheme

Mark scheme for question 5
QuestionAnswerMarkMark scheme
5
  • £41.30\pounds41.30
218%18\% of £35\pounds35 is 0.18×35=£6.300.18\times35=\pounds6.30. Adding the increase gives £35+£6.30=£41.30\pounds35+\pounds6.30=\pounds41.30.
Q6
Tier 3 · Hard

6

35\dfrac{3}{5} of 250250 students travel by bus. Of these students, 40%40\% buy lunch at school. Work out how many bus students buy lunch at school.

(3)

(Total for Question 6 is 3 marks)

Mark scheme

Mark scheme for question 6
QuestionAnswerMarkMark scheme
6
  • 6060 students
3The number travelling by bus is 35×250=150\dfrac35\times250=150. Then 40%40\% of 150150 is 0.4×150=600.4\times150=60, so 6060 bus students buy lunch at school.
Q7
Tier 2 · Standard

7

35%35\% of a number is 8484. Work out the number.

(3)

(Total for Question 7 is 3 marks)

Mark scheme

Mark scheme for question 7
QuestionAnswerMarkMark scheme
7
  • 240240
335%=3510035\%=\dfrac{35}{100}. If 35%35\% is 8484, then 5%5\% is 84÷7=1284\div7=12, so 100%100\% is 12×20=24012\times20=240.
Q8
Tier 3 · Hard

8

A charity receives 480480 entries. Of these entries, 35%35\% are made online. Three eighths of the online entries are incomplete. Work out the number of complete online entries.

(4)

(Total for Question 8 is 4 marks)

Mark scheme

Mark scheme for question 8
QuestionAnswerMarkMark scheme
8
  • 105105 entries
4The number made online is 0.35×480=1680.35\times480=168. The complete fraction is 1−38=581-\dfrac38=\dfrac58. Therefore the number of complete online entries is 58×168=105\dfrac58\times168=105.
Q9
Tier 3 · Hard

9

Three fifths of a positive number is 4242 greater than 25%25\% of the number. Work out the number.

(4)

(Total for Question 9 is 4 marks)

Mark scheme

Mark scheme for question 9
QuestionAnswerMarkMark scheme
9
  • 120120
4The difference between 35=60%\dfrac35=60\% and 25%25\% is 35%35\%. Therefore 35%35\% of the number is 4242, so the number is 42÷0.35=12042\div0.35=120.
Q10
Tier 3 · Hard

10

A tank loses 15%15\% of its water. It then loses one quarter of the water that remains. Zoya says the tank has lost 40%40\% of its original amount. Is Zoya correct? Give a reason.

(4)

(Total for Question 10 is 4 marks)

Mark scheme

Mark scheme for question 10
QuestionAnswerMarkMark scheme
10
  • No; the tank has lost 36.25%36.25\% (or 2980\dfrac{29}{80}) of its original amount.
4After the first loss, 85%85\% remains. Three quarters of this then remains, so the final fraction is 0.85×34=0.63750.85\times\dfrac34=0.6375. The fraction lost is 1−0.6375=0.3625=36.25%=29801-0.6375=0.3625=36.25\%=\dfrac{29}{80}, not 40%40\%.

Verified exam appearances

SeriesPaperQuestionMarksCalculatorTierLinks
2022-113FQ73AllowedFoundationQPMS
2021-113FQ143AllowedFoundationQPMS
2024-062FQ254AllowedFoundationQPMS
2019-113FQ21AllowedFoundationQPMS
2023-112FQ153AllowedFoundationQPMS
2024-113FQ95AllowedFoundationQPMS
2023-112FQ51AllowedFoundationQPMS
2024-061FQ265Non-calculatorFoundationQPMS
2021-111FQ116Non-calculatorFoundationQPMS
2019-113FQ154AllowedFoundationQPMS
2023-061FQ145Non-calculatorFoundationQPMS
2022-061FQ255Non-calculatorFoundationQPMS
2019-113FQ115AllowedFoundationQPMS
2024-062HQ64AllowedHigherQPMS
2019-062FQ154AllowedFoundationQPMS
2022-112FQ124AllowedFoundationQPMS
2022-111FQ185Non-calculatorFoundationQPMS
2023-062FQ132AllowedFoundationQPMS
2019-063HQ103AllowedHigherQPMS
2021-113FQ41AllowedFoundationQPMS
2022-063FQ21AllowedFoundationQPMS
2024-061HQ75Non-calculatorHigherQPMS
2022-111FQ125Non-calculatorFoundationQPMS
2019-063FQ83AllowedFoundationQPMS
2023-111FQ51Non-calculatorFoundationQPMS
2023-063HQ25AllowedHigherQPMS
2019-063FQ235AllowedFoundationQPMS
2024-062FQ123AllowedFoundationQPMS
2019-061FQ142Non-calculatorFoundationQPMS
2022-111HQ52Non-calculatorHigherQPMS
2023-063HQ92AllowedHigherQPMS
2021-112FQ194AllowedFoundationQPMS
2022-063FQ194AllowedFoundationQPMS
2024-113FQ21AllowedFoundationQPMS
2019-063FQ62AllowedFoundationQPMS
2023-061FQ104Non-calculatorFoundationQPMS
2022-061HQ35Non-calculatorHigherQPMS

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