Edexcel GCSE Maths coverage

Number

Section N
16 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

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N1

Order positive and negative integers, decimals and fractions; use the symbols =, ≠, <, >, ≤, ≥

  • Numbers can be compared reliably after converting them to a common form, such as decimals or fractions with a common denominator.
  • On a number line, values increase from left to right; among negative numbers, the value farther from zero is the smaller one.
  • For example, 1.7<32-1.7<-\dfrac{3}{2} because 1.7<1.5-1.7<-1.5, while 0.4=250.4=\dfrac{2}{5}.
  • A common error is to compare only the digits and claim that 8>3-8>-3; the inequality is reversed because 8-8 lies farther left.

Tier 1 · Easy

1 mark
ORIGINAL

Insert either <<, >> or == between 0.62-0.62 and 35-\dfrac{3}{5}.

Tier 2 · Standard

2 marks
ORIGINAL

Write 74-\dfrac{7}{4}, 1.68-1.68, 53\dfrac{5}{3} and 1.71.7 in ascending order.

Tier 3 · Hard

3 marks
ORIGINAL

An integer kk satisfies 2.4<k31.7-2.4<\dfrac{k}{3}\leq1.7. Write down every possible value of kk.

N2

Apply the four operations, including formal written methods, to integers, decimals and simple fractions (proper and improper), and mixed numbers, positive and negative; understand and use place value

  • The four operations apply to integers, decimals, fractions and mixed numbers; convert mixed numbers to improper fractions before multiplying or dividing.
  • For addition or subtraction of fractions, use a common denominator; for division by a fraction, multiply by its reciprocal.
  • For example, 214÷35=94×53=154-2\dfrac{1}{4}\div\dfrac{3}{5}=-\dfrac{9}{4}\times\dfrac{5}{3}=-\dfrac{15}{4}.
  • A common error is to ignore place value in decimal work, so align decimal points in written addition and subtraction rather than aligning final digits.

Tier 1 · Easy

1 mark
ORIGINAL

Work out 17+29-17+29.

Tier 2 · Standard

2 marks
ORIGINAL

Work out 214÷35-2\dfrac{1}{4}\div\dfrac{3}{5}.

Tier 3 · Hard

3 marks
ORIGINAL

Work out 3.6(1.75)+56÷(59)3.6-(-1.75)+\dfrac{5}{6}\div\left(-\dfrac{5}{9}\right). Give your answer as a decimal.

N3

Recognise and use relationships between operations, including inverse operations; use conventional notation for priority of operations, including brackets, powers, roots and reciprocals

  • Inverse operations undo each other: addition and subtraction, multiplication and division, squaring and taking a square root are inverse pairs in suitable domains.
  • Use brackets first, then powers and roots, then multiplication and division, then addition and subtraction; work left to right within the same level.
  • For example, 1832×2=189×2=018-3^2\times2=18-9\times2=0, not 162162 or 1818.
  • A common error is to treat a reciprocal as a negative: the reciprocal of ab\dfrac{a}{b} is ba\dfrac{b}{a}, whereas its additive inverse is ab-\dfrac{a}{b}.

Tier 1 · Easy

1 mark
ORIGINAL

Work out 1832×218-3^2\times2.

Tier 2 · Standard

2 marks
ORIGINAL

Work out (815)2÷2\left(\sqrt{81}-5\right)^2\div2.

Tier 3 · Hard

3 marks
ORIGINAL

A positive number is squared, 1111 is subtracted, and the reciprocal of the result is 114\dfrac{1}{14}. Find the original number.

N4

Prime numbers, factors (divisors), multiples, common factors and multiples, highest common factor, lowest common multiple, prime factorisation with product notation and unique factorisation theorem

  • A prime number has exactly two positive factors, while every integer greater than 11 has a unique prime factorisation apart from the order of its factors.
  • Write each number as a product of prime powers; the HCF uses the smaller shared powers and the LCM uses the largest powers present.
  • For example, 84=22×3×784=2^2\times3\times7 and 126=2×32×7126=2\times3^2\times7, so their HCF is 2×3×7=422\times3\times7=42.
  • A common error is to count 11 as prime or to find the LCM by multiplying the numbers without removing repeated prime factors.

Tier 1 · Easy

2 marks
ORIGINAL

Write 756756 as a product of its prime factors.

Tier 2 · Standard

3 marks
ORIGINAL

Find both the HCF and the LCM of 8484 and 126126.

Tier 3 · Hard

4 marks
ORIGINAL

180n180n is a cube number, where nn is a positive integer. Find the smallest possible value of nn.

N5

Apply systematic listing strategies, including use of the product rule for counting (m ways of doing one task and n ways of doing another gives m × n ways in total)

  • A systematic list uses a fixed order so that every possible outcome appears once and no outcome is repeated.
  • Fix one choice while cycling through every permitted value of the next choice, then move to the next case.
  • For example, pairing A and B with 11, 22 and 33 gives A1, A2, A3, B1, B2, B3.
  • A common error is to change two choices at once, which can omit an outcome or list the same outcome twice.

Tier 1 · Easy

2 marks
ORIGINAL

A badge uses one of the letters A, B or C and one of the numbers 11, 22 or 33. List every possible badge code in a systematic order.

Tier 2 · Standard

3 marks
ORIGINAL

A three-digit number is made using three different digits from 22, 44, 55 and 77. List all the possible even numbers.

Tier 3 · Hard

3 marks
ORIGINAL

Two different numbers are selected from 11, 22, 33, 44 and 55. The order of selection does not matter. List every pair whose product is even and whose sum is greater than 55.

N6

Use positive integer powers and associated real roots (square, cube and higher), recognise powers of 2, 3, 4, 5; estimate powers and roots of any given positive number

  • A positive integer power is repeated multiplication, and an associated root reverses that power, such as 1253=5\sqrt[3]{125}=5 because 53=1255^3=125.
  • Learn common powers of 22, 33, 44 and 55; match a root to the power that it reverses.
  • For example, 53=1255^3=125, so 1253=5\sqrt[3]{125}=5.
  • A common error is to multiply the base by the exponent, so remember that 34=3×3×3×33^4=3\times3\times3\times3, not 3×43\times4.

Tier 1 · Easy

1 mark
ORIGINAL

Work out 252^5.

Tier 2 · Standard

1 mark
ORIGINAL

Work out 3433\sqrt[3]{343}.

Tier 3 · Hard

3 marks
ORIGINAL

Work out 12964+5123\sqrt[4]{1296}+\sqrt[3]{512}.

N7

Calculate with roots, and with integer and fractional indices

  • Integer indices include positive, zero and negative values: a0=1a^0=1 and an=1/ana^{-n}=1/a^n for non-zero aa.
  • Evaluate a root by identifying the number whose corresponding power gives the radicand.
  • For example, 2163=6\sqrt[3]{-216}=-6 because (6)3=216(-6)^3=-216.
  • A common error is to make a negative index produce a negative value; it produces a reciprocal, so 42=1/164^{-2}=1/16, not 16-16.

Tier 1 · Easy

1 mark
ORIGINAL

Work out 424^{-2}.

Tier 2 · Standard

1 mark
ORIGINAL

Work out 2163\sqrt[3]{-216}.

Tier 3 · Hard

3 marks
ORIGINAL

Work out 144+52\sqrt{144}+5^{-2}. Give an exact answer.

N8

Calculate exactly with fractions, surds and multiples of π; simplify surd expressions involving squares (e.g. √12 = √(4 × 3) = √4 × √3 = 2√3) and rationalise denominators

  • An exact answer keeps fractions and multiples of π\pi rather than replacing them with rounded decimals.
  • Use a common denominator for exact fraction calculations and leave a circle result as a coefficient multiplied by π\pi.
  • For example, a circle of radius 77 has exact area π×72=49π\pi\times7^2=49\pi.
  • A common error is to replace π\pi with 3.143.14 when an exact answer is requested.

Tier 1 · Easy

2 marks
ORIGINAL

Work out 34+56\dfrac{3}{4}+\dfrac{5}{6}. Give an exact answer.

Tier 2 · Standard

2 marks
ORIGINAL

A circle has radius 77 cm. Work out its exact area.

Tier 3 · Hard

3 marks
ORIGINAL

Work out 3π5+7π8π4\dfrac{3\pi}{5}+\dfrac{7\pi}{8}-\dfrac{\pi}{4}. Give an exact answer.

N9

Calculate with and interpret standard form A × 10^n, where 1 ≤ A < 10 and n is an integer

  • Standard form is A×10nA\times10^n with 1A<101\leq A<10 and integer nn; positive powers represent large values and negative powers represent small values.
  • When multiplying or dividing, operate on the decimal factors and the powers of 1010 separately, then adjust the result so its first factor is in the required range.
  • For example, (6×107)(4×103)=24×104=2.4×105(6\times10^7)(4\times10^{-3})=24\times10^4=2.4\times10^5.
  • A common error is to leave a result such as 24×10424\times10^4 uncorrected; it has the right value but is not in standard form because 241024\geq10.

Tier 1 · Easy

1 mark
ORIGINAL

Write 0.0000720.000072 in standard form.

Tier 2 · Standard

2 marks
ORIGINAL

Work out (6×107)(4×103)(6\times10^7)(4\times10^{-3}). Give your answer in standard form.

Tier 3 · Hard

4 marks
ORIGINAL

Work out 3.6×104+7.5×1051.5×103\dfrac{3.6\times10^{-4}+7.5\times10^{-5}}{1.5\times10^3}. Give your answer in standard form.

N10

Work interchangeably with terminating decimals and their corresponding fractions (such as 3.5 and 7/2 or 0.375 or 3/8); change recurring decimals into their corresponding fractions and vice versa

  • A terminating decimal has a finite number of decimal places and can be written as a fraction over a power of 1010.
  • To convert a fraction to a decimal, divide the numerator by the denominator; to convert back, use place value and simplify.
  • For example, 0.375=375/1000=3/80.375=375/1000=3/8, while 37/80=0.462537/80=0.4625.
  • A common error is to stop simplifying a fraction before the numerator and denominator have no common factor greater than 11.

Tier 1 · Easy

1 mark
ORIGINAL

Write 0.3750.375 as a fraction in its simplest form.

Tier 2 · Standard

1 mark
ORIGINAL

Write 3780\dfrac{37}{80} as a decimal.

Tier 3 · Hard

3 marks
ORIGINAL

Which is greater, 0.560.56 or 916\dfrac{9}{16}? Work out the difference as a fraction.

N11

Identify and work with fractions in ratio problems

  • A ratio describes relative parts, so a fraction of the whole can be converted into a part-to-part ratio by using the remaining fraction.
  • Find the total number of ratio parts, calculate one part, and then apply any stated fraction to the relevant share.
  • For example, if red counters are 3/53/5 of the total, blue counters are 2/52/5, so red : blue is 3:23:2.
  • A common error is to use the denominator as the other ratio part; if one group is 3/53/5, the remainder is 2/52/5, not 5/55/5.

Tier 1 · Easy

1 mark
ORIGINAL

35\dfrac{3}{5} of the beads in a bag are red and the rest are blue. Write the ratio of red beads to blue beads.

Tier 2 · Standard

3 marks
ORIGINAL

The ratio of Ava's tokens to Ben's tokens is 5:75:7. Ben has 8484 tokens. Work out 34\dfrac{3}{4} of Ava's number of tokens.

Tier 3 · Hard

4 marks
ORIGINAL

£330\pounds330 is shared between Imran and Jo in the ratio 4:74:7. Imran spends 38\dfrac{3}{8} of his share and Jo spends 27\dfrac{2}{7} of her share. Work out the total amount they have left.

N12

Interpret fractions and percentages as operators

  • A fraction or percentage acts as an operator meaning multiplication, so 3/53/5 of a quantity is found by multiplying it by 3/53/5.
  • Convert a percentage to a fraction over 100100 or a decimal multiplier; for repeated operations, apply the multipliers in the stated order.
  • For example, 17.5%17.5\% of 240240 is 0.175×240=420.175\times240=42.
  • A common error is to divide by the numerator and multiply by the denominator; for 3/53/5 of an amount, divide by 55 and then multiply by 33.

Tier 1 · Easy

1 mark
ORIGINAL

Work out 35\dfrac{3}{5} of 7070.

Tier 2 · Standard

2 marks
ORIGINAL

Work out 17.5%17.5\% of 240240.

Tier 3 · Hard

4 marks
ORIGINAL

A machine costs £640\pounds640. Its price is reduced by 15%15\%, then a customer pays 38\dfrac{3}{8} of the reduced price as a deposit. Work out the balance still to pay.

N13

Use standard units of mass, length, time, money and other measures (including standard compound measures) using decimal quantities where appropriate

  • Standard measures include length, area, volume, mass, time and money, while compound measures combine units, such as km/h, g/cm3^3 or litres per 100100 km.
  • Convert every quantity to compatible units before calculating, using place value carefully for squared or cubed conversion factors.
  • For example, 2.75 kg=2750 g2.75\text{ kg}=2750\text{ g} because 1 kg=1000 g1\text{ kg}=1000\text{ g}.
  • A common error is to treat decimal time as minutes: 1.51.5 hours is 11 hour 3030 minutes, not 11 hour 5050 minutes.

Tier 1 · Easy

1 mark
ORIGINAL

Change 2.752.75 kg to grams.

Tier 2 · Standard

2 marks
ORIGINAL

A workshop starts at 09:3809{:}38 and lasts for 11 hour 4747 minutes. Work out the finishing time.

Tier 3 · Hard

4 marks
ORIGINAL

A car travels 5454 km and uses fuel at a rate of 7.57.5 litres per 100100 km. Fuel costs £1.68\pounds1.68 per litre. Work out the fuel cost for the journey, giving your answer to the nearest penny.

N14

Estimate answers; check calculations using approximation and estimation, including answers obtained using technology

  • An estimate replaces awkward values with nearby numbers that are easy to calculate, often using one significant figure.
  • Round each input before calculating and use the estimate to check the order of magnitude and position of the decimal point in an exact or calculator answer.
  • For example, 19.8×0.4920×0.5=1019.8\times0.49\approx20\times0.5=10.
  • A common error is to round only the final calculator display; estimation must simplify the input values and provide an independent reasonableness check.

Tier 1 · Easy

1 mark
ORIGINAL

Estimate the value of 19.8×0.4919.8\times0.49.

Tier 2 · Standard

2 marks
ORIGINAL

Estimate 48.7×0.2030.098\dfrac{48.7\times0.203}{0.098}.

Tier 3 · Hard

3 marks
ORIGINAL

A calculator display gives 931.24931.24 for 598.4×0.03170.204\dfrac{598.4\times0.0317}{0.204}. Use an estimate to decide whether this display is reasonable. Give a reason.

N15

Round numbers and measures to an appropriate degree of accuracy (decimal places or significant figures); use inequality notation to specify simple error intervals due to truncation or rounding

  • Decimal places count digits after the decimal point, while significant figures begin at the first non-zero digit.
  • For rounding to a unit uu, the error interval extends half a unit below and above; include the lower bound but exclude the upper bound.
  • For example, 12.612.6 correct to 11 decimal place means 12.55x<12.6512.55\leq x<12.65.
  • A common error is to include the upper endpoint; that value would round to the next stated number, so the upper inequality is strict.

Tier 1 · Easy

1 mark
ORIGINAL

Write 0.0078460.007846 correct to 22 significant figures.

Tier 2 · Standard

2 marks
ORIGINAL

A number xx is 12.612.6 correct to 11 decimal place. Write the error interval for xx.

Tier 3 · Hard

3 marks
ORIGINAL

A positive number yy is truncated to 4.374.37 at 22 decimal places. Write its error interval and find the greatest possible integer value of 100y100y.

N16

Apply and interpret limits of accuracy, including upper and lower bounds

  • A rounded measurement represents a range of possible true values, determined by half of the rounding unit.
  • Use the smallest and largest possible input values to decide whether a claimed result is possible, without treating a rounded value as exact.
  • For example, a length shown as 1212 cm to the nearest centimetre can differ from 1212 cm by at most 0.50.5 cm.
  • A common error is to allow the top endpoint of a rounding interval even though it would round to the next displayed value.

Tier 1 · Easy

1 mark
ORIGINAL

A length is recorded as 1212 cm to the nearest centimetre. Write down the maximum possible rounding error.

Tier 2 · Standard

3 marks
ORIGINAL

Higher only: Two lengths are recorded as 4.24.2 cm and 3.73.7 cm, each to the nearest 0.10.1 cm. Could their exact total be less than 7.87.8 cm? Give a reason.

Tier 3 · Hard

3 marks
ORIGINAL

Higher only: A scale records the mass of each of 88 identical boxes as 2.42.4 kg to the nearest 0.10.1 kg. Could the exact total mass of the boxes be 2020 kg? Justify your answer.