Skip to content
N11

Identify and work with fractions in ratio problems

Fractions in ratio problems

Worked answers, methods and verified real exam appearances for N11 on Edexcel GCSE Maths 1MA1.

Explanation

  • Fractions and ratios describe the same partition in different forms. If a group is 35\dfrac35 of the whole, the remainder is 25\dfrac25, so the part-to-part ratio is 3:23:2.
  • Conversely, in a ratio a:ba:b, the first share is aa+b\dfrac{a}{a+b} of the whole and the second is ba+b\dfrac{b}{a+b}.
  • In multi-step problems, first use the ratio to find each share, then apply any fraction operator to the relevant share.
  • Keep the named order of the groups throughout.
  • Examiners commonly award one mark for finding one ratio part and a later accuracy mark for the required fractional amount.

Worked example

£330\pounds330 is shared between Imran and Jo in the ratio 4:74:7. Imran spends 38\dfrac38 of his share and Jo spends 27\dfrac27 of hers. Find the total left.

  1. 1.There are 1111 parts, so one part is 330÷11=30330\div11=30.
  2. 2.Imran gets 120120 and keeps 58×120=75\dfrac58\times120=75; Jo gets 210210 and keeps 57×210=150\dfrac57\times210=150.
  3. 3.Add the amounts kept: 75+150=22575+150=225.

Answer: £225\pounds225.

Common mistakes

  • Don't say the remainder of 35\dfrac35 is 55\dfrac55 instead of 25\dfrac25.
  • Don't use one ratio part as the denominator of the fraction of the whole.
  • Don't apply a spending fraction as though it were the fraction left.

Exam tip

Label each share and write the total number of ratio parts before applying any later fraction.

Worked practice

Q1
Tier 1 · Easy

1

35\dfrac{3}{5} of the beads in a bag are red and the rest are blue. Write the ratio of red beads to blue beads.

(1)

(Total for Question 1 is 1 mark)

Mark scheme

Mark scheme for question 1
QuestionAnswerMarkMark scheme
1
  • 3:23:2
1The blue fraction is 135=251-\dfrac{3}{5}=\dfrac{2}{5}. Therefore red : blue is 35:25=3:2\dfrac{3}{5}:\dfrac{2}{5}=3:2.
Q2
Tier 2 · Standard

2

The ratio of Ava's tokens to Ben's tokens is 5:75:7. Ben has 8484 tokens. Work out 34\dfrac{3}{4} of Ava's number of tokens.

(3)

(Total for Question 2 is 3 marks)

Mark scheme

Mark scheme for question 2
QuestionAnswerMarkMark scheme
2
  • 4545 tokens
3Seven ratio parts represent 8484, so one part is 84÷7=1284\div7=12. Ava has 5×12=605\times12=60 tokens. Then 34×60=45\dfrac{3}{4}\times60=45.
Q3
Tier 1 · Easy

3

The ratio of silver counters to gold counters is 4:94:9. Write the fraction of the counters that are gold.

(1)

(Total for Question 3 is 1 mark)

Mark scheme

Mark scheme for question 3
QuestionAnswerMarkMark scheme
3
  • 913\dfrac{9}{13}
1There are 4+9=134+9=13 equal parts altogether and 99 are gold, so the required fraction is 913\dfrac9{13}.
Q4
Tier 2 · Standard

4

25\dfrac{2}{5} of some tiles are yellow. One quarter of the remaining tiles are green and the rest are blue. Write the ratio yellow : green : blue.

(3)

(Total for Question 4 is 3 marks)

Mark scheme

Mark scheme for question 4
QuestionAnswerMarkMark scheme
4
  • 8:3:98:3:9
3Use 2020 equal parts. Yellow tiles take 88 parts, leaving 1212. Green tiles take one quarter of the remainder, so take 33 parts, leaving 99 blue parts. The ratio is 8:3:98:3:9.
Q5
Tier 3 · Hard

5

Red, blue and green beads are in the ratio 2:5:32:5:3. Half of the red beads are removed. Work out the fraction of the remaining beads that are blue.

(3)

(Total for Question 5 is 3 marks)

Mark scheme

Mark scheme for question 5
QuestionAnswerMarkMark scheme
5
  • 59\dfrac{5}{9}
3Start with 2+5+3=102+5+3=10 equal parts. Removing half of the red beads removes 11 part, so 99 parts remain. The 55 blue parts are therefore 59\dfrac59 of the remaining beads.
Q6
Tier 2 · Standard

6

The ratio of adults to children at an event is 7:47 : 4. Three eighths of the children wear hats. Work out the fraction of all the people at the event who are children wearing hats.

(3)

(Total for Question 6 is 3 marks)

Mark scheme

Mark scheme for question 6
QuestionAnswerMarkMark scheme
6
  • 322\dfrac{3}{22}
3Children make up 411\dfrac4{11} of all the people. The required fraction is 38×411=1288=322\dfrac38\times\dfrac4{11}=\dfrac{12}{88}=\dfrac3{22}.
Q7
Tier 3 · Hard

7

The ratio A:BA : B is 4:94 : 9. The amount AA is 27\dfrac27 of the amount CC. Work out the fraction of the total amount A+B+CA+B+C that is BB.

(4)

(Total for Question 7 is 4 marks)

Mark scheme

Mark scheme for question 7
QuestionAnswerMarkMark scheme
7
  • 13\dfrac13
4Use A=8A=8 equal parts. Then A:B=4:9A : B=4 : 9 gives B=18B=18 parts. Since A=27CA=\dfrac27C, C=28C=28 parts. The total is 8+18+28=548+18+28=54 parts, so the fraction that is BB is 1854=13\dfrac{18}{54}=\dfrac13.
Q8
Tier 3 · Hard

8

The ratio of adults to children at a show is 7:57:5. One third of the adults and one fifth of the children leave. There are then 7878 people at the show. Work out the number of people who were at the show before anyone left.

(4)

(Total for Question 8 is 4 marks)

Mark scheme

Mark scheme for question 8
QuestionAnswerMarkMark scheme
8
  • 108108 people
4Let the original numbers be 7k7k and 5k5k. The numbers remaining are 23×7k=14k3\dfrac23\times7k=\dfrac{14k}{3} adults and 45×5k=4k\dfrac45\times5k=4k children. Thus 26k3=78\dfrac{26k}{3}=78, so k=9k=9. Originally there were 12k=10812k=108 people.
Q9
Tier 3 · Hard

9

Two positive amounts are AA and BB. Two fifths of AA is equal to three sevenths of BB. Work out the fraction of A+BA+B that is AA.

(3)

(Total for Question 9 is 3 marks)

Mark scheme

Mark scheme for question 9
QuestionAnswerMarkMark scheme
9
  • 1529\dfrac{15}{29}
325A=37B\dfrac25A=\dfrac37B. Multiplying by 3535 gives 14A=15B14A=15B, so A:B=15:14A:B=15:14. There are 2929 ratio parts altogether and 1515 belong to AA, so the required fraction is 1529\dfrac{15}{29}.

Verified exam appearances

SeriesPaperQuestionMarksCalculatorTierLinks
2022-113HQ174AllowedHigherQPMS
2022-111FQ246Non-calculatorFoundationQPMS
2023-113FQ112AllowedFoundationQPMS
2022-061HQ113Non-calculatorHigherQPMS
2022-111HQ66Non-calculatorHigherQPMS

Other points in N Number

Want help turning this into marks?

Bring N11 or any tricky specification point, and we can work through the method and exam wording together.