1
(1)
(Total for Question 1 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 1 | 1 | The blue fraction is . Therefore red : blue is . |
Fractions in ratio problems
Worked answers, methods and verified real exam appearances for N11 on Edexcel GCSE Maths 1MA1.
Explanation
Worked example
is shared between Imran and Jo in the ratio . Imran spends of his share and Jo spends of hers. Find the total left.
Answer: .
Common mistakes
Exam tip
Label each share and write the total number of ratio parts before applying any later fraction.
1
(1)
(Total for Question 1 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 1 | 1 | The blue fraction is . Therefore red : blue is . |
2
(3)
(Total for Question 2 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 2 |
| 3 | Seven ratio parts represent , so one part is . Ava has tokens. Then . |
3
(1)
(Total for Question 3 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 3 | 1 | There are equal parts altogether and are gold, so the required fraction is . |
4
(3)
(Total for Question 4 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 4 | 3 | Use equal parts. Yellow tiles take parts, leaving . Green tiles take one quarter of the remainder, so take parts, leaving blue parts. The ratio is . |
5
(3)
(Total for Question 5 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 5 | 3 | Start with equal parts. Removing half of the red beads removes part, so parts remain. The blue parts are therefore of the remaining beads. |
6
(3)
(Total for Question 6 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 6 | 3 | Children make up of all the people. The required fraction is . |
7
(4)
(Total for Question 7 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 7 | 4 | Use equal parts. Then gives parts. Since , parts. The total is parts, so the fraction that is is . |
8
(4)
(Total for Question 8 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 8 |
| 4 | Let the original numbers be and . The numbers remaining are adults and children. Thus , so . Originally there were people. |
9
(3)
(Total for Question 9 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 9 | 3 | . Multiplying by gives , so . There are ratio parts altogether and belong to , so the required fraction is . |
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