1
(1)
(Total for Question 1 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 1 | 1 | The highest common factor of and is . Dividing both parts by gives . |
Ratio notation
Worked answers, methods and verified real exam appearances for R4 on Edexcel GCSE Maths 1MA1.
Explanation
Worked example
Given and , find in its simplest integer form.
Answer: .
Common mistakes
Exam tip
For linked ratios, show the common value of the repeated quantity to secure the method mark.
1
(1)
(Total for Question 1 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 1 | 1 | The highest common factor of and is . Dividing both parts by gives . |
2
(2)
(Total for Question 2 is 2 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 2 | 2 | Convert to . Then after dividing both parts by . |
3
(3)
(Total for Question 3 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 3 | 3 | Write . Multiplying every part by clears all the denominators: . |
4
(1)
(Total for Question 4 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 4 | 1 | Multiply both parts by to get , then divide both parts by to get . |
5
(2)
(Total for Question 5 is 2 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 5 | 2 | Convert to . Then after dividing every part by . |
6
(3)
(Total for Question 6 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 6 | 3 | Write , and . Then and . The ratio simplifies to . |
7
(3)
(Total for Question 7 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 7 | 3 | boys and girls are present. The ratio simplifies to . |
8
(4)
(Total for Question 8 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 8 | 4 | In metres per minute, the rates are , and . The ratio simplifies to . |
9
(3)
(Total for Question 9 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 9 | 3 | and . Multiplying all three parts by gives , which has no common factor. |
10
(4)
(Total for Question 10 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 10 | 4 | Match the shared quantity : and , so take , and . Then and , giving . |
| Series | Paper | Question | Marks | Calculator | Tier | Links |
|---|---|---|---|---|---|---|
| 2024-06 | 1F | Q10 | 2 | Non-calculator | Foundation | QPMS |
| 2024-06 | 3F | Q20 | 5 | Allowed | Foundation | QPMS |
| 2024-11 | 1F | Q9 | 7 | Non-calculator | Foundation | QPMS |
| 2019-11 | 3F | Q6 | 1 | Allowed | Foundation | QPMS |
| 2022-11 | 1F | Q13 | 4 | Non-calculator | Foundation | QPMS |
| 2023-06 | 3F | Q28 | 4 | Allowed | Foundation | QPMS |
| 2023-11 | 2F | Q10 | 2 | Allowed | Foundation | QPMS |
| 2023-06 | 2F | Q9 | 3 | Allowed | Foundation | QPMS |
| 2022-06 | 3H | Q3 | 5 | Allowed | Higher | QPMS |
| 2021-11 | 3H | Q14 | 4 | Allowed | Higher | QPMS |
| 2022-11 | 3F | Q12 | 2 | Allowed | Foundation | QPMS |
| 2022-06 | 1F | Q29 | 3 | Non-calculator | Foundation | QPMS |
| 2022-11 | 1F | Q24 | 6 | Non-calculator | Foundation | QPMS |
| 2022-06 | 2F | Q9 | 3 | Allowed | Foundation | QPMS |
| 2019-11 | 1H | Q2 | 4 | Non-calculator | Higher | QPMS |
| 2024-11 | 2F | Q9 | 2 | Allowed | Foundation | QPMS |
| 2021-11 | 1F | Q12 | 3 | Non-calculator | Foundation | QPMS |
| 2019-11 | 1F | Q21 | 4 | Non-calculator | Foundation | QPMS |
| 2019-06 | 2F | Q14 | 1 | Allowed | Foundation | QPMS |
| 2022-11 | 1H | Q6 | 6 | Non-calculator | Higher | QPMS |
| 2022-06 | 3F | Q24 | 5 | Allowed | Foundation | QPMS |
Bring R4 or any tricky specification point, and we can work through the method and exam wording together.