A charity walk is long. Change this distance to metres.
Ratio, proportion and rates of change
Notes and three levels of exam-style practice for each registered specification leaf in this section.
Open the printable packChange freely between related standard units (time, length, area, volume/capacity, mass) and compound units (speed, rates of pay, prices, density, pressure) in numerical and algebraic contexts
- Standard-unit conversions multiply or divide by a fixed factor, such as and .
- Convert every measurement to compatible units before using a formula; for a rate, convert the numerator and denominator separately.
- Area and volume factors are powered: since , and .
- A common error is to use a length conversion unchanged for an area or volume conversion.
Tier 1 · Easy
Tier 2 · Standard
A pump moves water at litres per minute. Change this rate to cubic metres per second.
Tier 3 · Hard
A solid block measures by by and has mass . Work out its density in .
Use scale factors, scale diagrams and maps
- A scale means one unit on the diagram represents of the same units in reality.
- Measure or calculate the diagram length, apply the scale factor, and then convert to the unit requested.
- For example, at , represents .
- A common error is to mix centimetres and metres before applying the scale factor.
Tier 1 · Easy
A ranger's sketch uses scale . A footpath trace measures . Find the real distance in kilometres.
Tier 2 · Standard
A model theatre uses scale . A real doorway is high. Work out the model doorway height in centimetres.
Tier 3 · Hard
A site plan has scale . A garden occupies on the plan. Calculate its real area in hectares. Use hectare .
Express one quantity as a fraction of another, where the fraction is less than 1 or greater than 1
- To express quantity as a fraction of quantity , write and simplify.
- First convert the quantities to the same units; the units then cancel in the fraction.
- The fraction is greater than when the first quantity is larger than the quantity it is compared with.
- A common error is to reverse the numerator and denominator because the phrase 'of another' is misread.
Tier 1 · Easy
Express as a fraction of . Give the fraction in its simplest form.
Tier 2 · Standard
Express minutes as a fraction of minutes. Simplify your answer.
Tier 3 · Hard
Express as a fraction of . Give the fraction in its simplest form.
Use ratio notation, including reduction to simplest form
- A ratio compares quantities in a stated order, using notation such as .
- Convert all quantities to the same units, then divide every part by their highest common factor.
- Equivalent ratios are made by multiplying or dividing every part by the same non-zero number.
- A common error is to simplify only one part or to change the order of the quantities.
Tier 1 · Easy
Write the ratio in its simplest form.
Tier 2 · Standard
Write as a ratio in its simplest form.
Tier 3 · Hard
Given and , find in its simplest integer form.
Divide a quantity in a given part:part or part:whole ratio; express division into two parts as a ratio; apply ratio to real problems (conversion, comparison, scaling, mixing, concentrations)
- For a part:part ratio , the whole contains equal shares.
- Find one share by dividing the total by the sum of the parts, then multiply by each stated part.
- A part:whole fraction such as gives the complementary part , so the two parts are in ratio .
- A common error is to divide a total by one ratio number instead of by the sum of all parts.
Tier 1 · Easy
Divide £84 in the ratio .
Tier 2 · Standard
A box holds counters. Red counters make up of the whole. Find the number of red and non-red counters, and state their ratio.
Tier 3 · Hard
A technician mixes a solution with a solution to make litres of a solution. Find the volume of each starting solution.
Express a multiplicative relationship between two quantities as a ratio or a fraction
- A multiplicative comparison states how many times one quantity is another, not their additive difference.
- If , then and is the fraction of .
- For integer ratio notation, rewrite a fractional multiplier such as as the ratio .
- A common error is to subtract the quantities and report the difference as though it were a ratio.
Tier 1 · Easy
Quantity is and quantity is . Express as a fraction of and write in simplest form.
Tier 2 · Standard
The mass of parcel is times the mass of parcel . Express as an integer ratio and express as a fraction of .
Tier 3 · Hard
Quantities , and satisfy and . Express in simplest form and write as a fraction of .
Understand and use proportion as equality of ratios
- Two quantities are in proportion when corresponding ratios are equal.
- Write an equation between matching ratios, then use scaling or cross-multiplication to find an unknown.
- For example, implies when and are non-zero.
- A common error is to compare quantities in different orders on the two sides of the equation.
Tier 1 · Easy
Solve the proportion .
Tier 2 · Standard
Eight identical notebooks cost £11.20. Use proportion to find the cost of notebooks.
Tier 3 · Hard
Solve and verify that the two ratios are equal.
Relate ratios to fractions and to linear functions
- If two parts are in ratio , their fractions of the whole are and .
- A constant ratio gives the linear relationship .
- The graph of a constant ratio is a straight line through the origin, with gradient equal to the multiplier.
- A common error is to use for the fraction of the whole instead of .
Tier 1 · Easy
The ratio of cats to dogs at a shelter is . What fraction of the animals are cats?
Tier 2 · Standard
Quantities and are always in the ratio . Write as a linear function of , then find when .
Tier 3 · Hard
A mixture contains concentrate and water in the ratio . Let litres be the concentrate and litres be the total mixture. Express as a linear function of , then find both component volumes when .
Define percentage as 'number of parts per hundred'; interpret percentages and percentage changes as fractions/decimals, multiplicatively; percentages > 100%; percentage change and simple interest
- A percentage is a number of parts per hundred, so .
- Use a multiplier: an increase of multiplies by , while a decrease multiplies by .
- Percentages above have multipliers above ; simple interest is calculated repeatedly from the original principal only.
- A common error in reverse percentage problems is to undo a decrease by adding the same percentage to the reduced value.
Tier 1 · Easy
Work out of .
Tier 2 · Standard
After a decrease, a machine is valued at £704. Work out its value before the decrease.
Tier 3 · Hard
A saver deposits £2500 in an account paying simple interest each year. After years, a fee equal to of the final balance is charged. Calculate the amount left after the fee.
Solve problems involving direct and inverse proportion, including graphical and algebraic representations
- In direct proportion, both quantities change by the same factor and the graph is a straight line through the origin.
- In inverse proportion, multiplying one quantity by a factor divides the other by that factor, so their product is constant.
- Find the constant from a known pair, write the relationship, and then substitute the required value.
- A common error is to treat an inverse relationship as linear and add or subtract the same amount.
Tier 1 · Easy
A direct variation links and . The pair , is known. Determine at .
Tier 2 · Standard
Variables and vary inversely. One recorded pair is , . Determine at .
Tier 3 · Hard
and are inversely proportional. Initially and . The value of is increased by . Find the new value of and the percentage decrease in .
Use compound units such as speed, rates of pay, unit pricing, density and pressure
- A compound unit combines two or more units, such as , £ per hour, or .
- Use , and with compatible units.
- Unit pricing and rates of pay are found by dividing the total cost or pay by the relevant number of units or hours.
- A common error is to substitute minutes into a calculation whose required rate is per hour.
Tier 1 · Easy
A shift lasting hours pays £52.50. Work out the hourly rate of pay.
Tier 2 · Standard
A coach travels in hours minutes. Calculate its average speed in .
Tier 3 · Hard
A force of acts uniformly on a rectangular pad measuring by . Calculate the pressure in pascals, where .
Compare lengths, areas and volumes using ratio notation; make links to similarity (including trigonometric ratios) and scale factors
- For similar shapes with length scale factor , corresponding lengths are in ratio , areas in ratio and volumes in ratio .
- Find the linear scale factor first, then square or cube it to compare areas or volumes.
- Corresponding angles and trigonometric ratios are unchanged in similar right-angled triangles, while all corresponding lengths share one scale factor.
- A common error is to apply the linear scale factor directly to an area or a volume.
Tier 1 · Easy
Two similar shapes have corresponding sides of and . Write the smaller-to-larger length ratio in simplest form.
Tier 2 · Standard
The corresponding length ratio of two similar tiles is . The smaller tile has area . Find the area of the larger tile.
Tier 3 · Hard
Two similar solids have smaller-to-larger volume ratio . The smaller solid has surface area . Work out the larger surface area.
Understand that X is inversely proportional to Y is equivalent to X is proportional to 1/Y; construct and interpret equations that describe direct and inverse proportion
- If is inversely proportional to , then and for a constant .
- Use one known pair to calculate , then write the complete equation before finding another value.
- Direct proportion may involve powers, such as , while inverse proportion may be written .
- A common error is to write for inverse proportion or to invert the wrong variable.
Tier 1 · Easy
Variables and vary inversely, with recorded values and . Write their connecting equation.
Tier 2 · Standard
The relationship between and is direct proportion. Given when , form the equation and evaluate at .
Tier 3 · Hard
For positive , the variable varies inversely with . Given at , determine when .
Interpret the gradient of a straight line graph as a rate of change; recognise and interpret graphs that illustrate direct and inverse proportion
- The gradient is a rate of change, with units formed from the vertical and horizontal axes.
- Choose two well-separated points on a straight line, calculate the changes, and interpret the result in context.
- A direct-proportion graph is a straight line through the origin; an inverse-proportion graph has constant product and approaches the axes.
- A common error is to calculate run over rise or to omit the rate's units and meaning.
Tier 1 · Easy
A straight distance-time graph passes through and , where time is in seconds and distance in metres. Find and interpret its gradient.
Tier 2 · Standard
A phone-call cost graph is modelled by , where is cost in pounds and is time in minutes. Interpret the gradient and calculate the cost of a -minute call.
Tier 3 · Hard
An inverse-proportion model contains the points , and . Check that all three coordinates are consistent with the model, write its equation, and find when .
Interpret the gradient at a point on a curve as the instantaneous rate of change; apply average and instantaneous rates of change (gradients of chords and tangents) (not calculus) [Higher only]
- The gradient of a chord between two points on a curve gives the average rate of change over that interval.
- The gradient of the tangent at one point estimates the instantaneous rate of change there.
- Use two clear points on the chord or tangent and calculate , including the compound units.
- A common error is to use two points on the curve when the question requires two points on the drawn tangent.
Tier 1 · Easy
A curve passes through and . Calculate the average rate of change of with respect to between these points.
Tier 2 · Standard
A tangent to a curve at passes through the grid points and . Estimate the instantaneous rate of change at .
Tier 3 · Hard
A curve shows water volume litres after minutes and passes through and . The tangent at passes through and . Find the average rate from to , estimate the instantaneous rate at , and compare them.
Set up, solve and interpret the answers in growth and decay problems, including compound interest and work with general iterative processes
- Repeated growth by uses multiplier each period; repeated decay uses .
- For equal periods, use and keep full calculator precision until the end.
- An iterative process defines each new value from the previous one, so substitute successively and interpret the first term meeting the stated condition.
- A common error is to calculate compound change as simple change or to round every intermediate iteration.
Tier 1 · Easy
£600 is invested at compound interest per year. Work out the value after years.
Tier 2 · Standard
A culture initially contains cells and decreases by each hour. Calculate the expected number after hours.
Tier 3 · Hard
A cooling model uses with . Find the first value of for which , and give that temperature to one decimal place.