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R1

Change freely between related standard units (time, length, area, volume/capacity, mass) and compound units (speed, rates of pay, prices, density, pressure) in numerical and algebraic contexts

Unit conversion and compound measures

Worked answers, methods and verified real exam appearances for R1 on Edexcel GCSE Maths 1MA1.

Explanation

  • Unit conversion means multiplying or dividing by a fixed conversion factor. Convert quantities to compatible units before substituting into a formula, and convert the numerator and denominator of a compound unit separately.
  • Length factors must be raised to the correct power: because 1m=100cm1\,\text{m}=100\,\text{cm}, then 1m2=1002cm21\,\text{m}^2=100^2\,\text{cm}^2 and 1m3=1003cm31\,\text{m}^3=100^3\,\text{cm}^3.
  • In algebraic contexts the same factor applies to the whole expression.
  • A sensible estimate can expose a conversion in the wrong direction.
  • Examiners expect the conversion step to be visible, especially when the final unit is compound.

Worked example

A block is 2.4m2.4\,\text{m} long, 35cm35\,\text{cm} wide and 80mm80\,\text{mm} high. Its mass is 26.88kg26.88\,\text{kg}. Find its density in kg/m3\text{kg}/\text{m}^3.

  1. 1.Convert to metres: 35cm=0.35m35\,\text{cm}=0.35\,\text{m} and 80mm=0.08m80\,\text{mm}=0.08\,\text{m}.
  2. 2.Volume =2.4×0.35×0.08=0.0672m3=2.4\times0.35\times0.08=0.0672\,\text{m}^3.
  3. 3.Density =26.880.0672=400kg/m3=\dfrac{26.88}{0.0672}=400\,\text{kg}/\text{m}^3.

Answer: 400kg/m3400\,\text{kg}/\text{m}^3.

Common mistakes

  • Don't use the length factor 100100 for an area or volume conversion instead of 1002100^2 or 1003100^3.
  • Don't substitute centimetres and metres into the same formula without converting first.
  • Don't convert only the numerator of a compound unit such as kilometres per hour.

Exam tip

For a multi-mark conversion, write the compatible units before the formula so the method mark is unambiguous.

Worked practice

Q1
Tier 1 · Easy

1

A charity walk is 3.6km3.6\,\text{km} long. Change this distance to metres.

(1)

(Total for Question 1 is 1 mark)

Mark scheme

Mark scheme for question 1
QuestionAnswerMarkMark scheme
1
  • 3600m3600\,\text{m}
13.6×1000=36003.6\times1000=3600, so the distance is 3600m3600\,\text{m}.
Q2
Tier 2 · Standard

2

A pump moves water at 540540 litres per minute. Change this rate to cubic metres per second.

(3)

(Total for Question 2 is 3 marks)

Mark scheme

Mark scheme for question 2
QuestionAnswerMarkMark scheme
2
  • 0.009m3/s0.009\,\text{m}^3/\text{s}
3540540 litres is 0.540m30.540\,\text{m}^3. Dividing by 6060 converts per minute to per second: 0.540/60=0.009m3/s0.540/60=0.009\,\text{m}^3/\text{s}.
Q3
Tier 3 · Hard

3

A solid block measures 2.4m2.4\,\text{m} by 35cm35\,\text{cm} by 80mm80\,\text{mm} and has mass 26.88kg26.88\,\text{kg}. Work out its density in kg/m3\text{kg}/\text{m}^3.

(4)

(Total for Question 3 is 4 marks)

Mark scheme

Mark scheme for question 3
QuestionAnswerMarkMark scheme
3
  • 400kg/m3400\,\text{kg}/\text{m}^3
4Convert the lengths to metres: 35cm=0.35m35\,\text{cm}=0.35\,\text{m} and 80mm=0.08m80\,\text{mm}=0.08\,\text{m}. The volume is 2.4×0.35×0.08=0.0672m32.4\times0.35\times0.08=0.0672\,\text{m}^3, so the density is 26.88/0.0672=400kg/m326.88/0.0672=400\,\text{kg}/\text{m}^3.
Q4
Tier 1 · Easy

4

Change 2.7m22.7\,\text{m}^2 to square centimetres.

(1)

(Total for Question 4 is 1 mark)

Mark scheme

Mark scheme for question 4
QuestionAnswerMarkMark scheme
4
  • 27000cm227\,000\,\text{cm}^2
11m2=10000cm21\,\text{m}^2=10\,000\,\text{cm}^2, so 2.7×10000=27000cm22.7\times10\,000=27\,000\,\text{cm}^2.
Q5
Tier 2 · Standard

5

A rectangle is 3x3x metres long and 40cm40\,\text{cm} wide. Express its area in square metres in terms of xx.

(2)

(Total for Question 5 is 2 marks)

Mark scheme

Mark scheme for question 5
QuestionAnswerMarkMark scheme
5
  • 1.2xm21.2x\,\text{m}^2
240cm=0.4m40\,\text{cm}=0.4\,\text{m}. The area is 3x×0.4=1.2xm23x\times0.4=1.2x\,\text{m}^2.
Q6
Tier 3 · Hard

6

A machine prints 480480 labels in 66 minutes, and each label has area 35cm235\,\text{cm}^2. Work out the area of labels printed in one hour, in square metres.

(4)

(Total for Question 6 is 4 marks)

Mark scheme

Mark scheme for question 6
QuestionAnswerMarkMark scheme
6
  • 16.8m216.8\,\text{m}^2
4The machine prints 480÷6=80480\div6=80 labels per minute, so it prints 80×60=480080\times60=4800 labels per hour. Their area is 4800×35=168000cm2=16.8m24800\times35=168\,000\,\text{cm}^2=16.8\,\text{m}^2.
Q7
Tier 2 · Standard

7

A dairy uses 22.32m322.32\,\text{m}^3 of milk in 3131 days. Work out the average amount used in litres per hour.

(3)

(Total for Question 7 is 3 marks)

Mark scheme

Mark scheme for question 7
QuestionAnswerMarkMark scheme
7
  • 3030 litres per hour
322.32m3=2232022.32\,\text{m}^3=22\,320 litres and 3131 days is 31×24=74431\times24=744 hours. The average amount used is 22320÷744=3022\,320\div744=30 litres per hour.
Q8
Tier 3 · Hard

8

A uniform metal sheet has area 0.84m20.84\,\text{m}^2 and mass 6.72kg6.72\,\text{kg}. Work out the mass, in grams, of a piece with area 350cm2350\,\text{cm}^2.

(4)

(Total for Question 8 is 4 marks)

Mark scheme

Mark scheme for question 8
QuestionAnswerMarkMark scheme
8
  • 280g280\,\text{g}
40.84m2=8400cm20.84\,\text{m}^2=8400\,\text{cm}^2, so the piece is 350÷8400=124350\div8400=\dfrac{1}{24} of the sheet. Its mass is 6.72÷24=0.28kg=280g6.72\div24=0.28\,\text{kg}=280\,\text{g}.
Q9
Tier 3 · Hard

9

A roll of material has mass 9.6kg9.6\,\text{kg}. Its mass per unit area is 320g/m2320\,\text{g}/\text{m}^2 and its width is 75cm75\,\text{cm}. Work out the length of the roll in metres.

(4)

(Total for Question 9 is 4 marks)

Mark scheme

Mark scheme for question 9
QuestionAnswerMarkMark scheme
9
  • 40m40\,\text{m}
4320g/m2=0.32kg/m2320\,\text{g}/\text{m}^2=0.32\,\text{kg}/\text{m}^2, so the area is 9.6÷0.32=30m29.6\div0.32=30\,\text{m}^2. The width is 0.75m0.75\,\text{m}, giving length 30÷0.75=40m30\div0.75=40\,\text{m}.
Q10
Tier 3 · Hard

10

A pipe carries water at 420cm3420\,\text{cm}^3 per second from 08:35 until 10:20. Calculate the volume carried, in cubic metres.

(4)

(Total for Question 10 is 4 marks)

Mark scheme

Mark scheme for question 10
QuestionAnswerMarkMark scheme
10
  • 2.646m32.646\,\text{m}^3
4The time is 105×60=6300105\times60=6300 seconds. The volume is 420×6300=2646000cm3420\times6300=2\,646\,000\,\text{cm}^3. Since 1m3=1000000cm31\,\text{m}^3=1\,000\,000\,\text{cm}^3, the volume is 2.646m32.646\,\text{m}^3.

Verified exam appearances

SeriesPaperQuestionMarksCalculatorTierLinks
2023-063HQ63AllowedHigherQPMS
2024-112FQ223AllowedFoundationQPMS
2019-063FQ31AllowedFoundationQPMS
2019-111HQ94Non-calculatorHigherQPMS
2019-113FQ261AllowedFoundationQPMS
2021-113HQ44AllowedHigherQPMS
2022-062FQ274AllowedFoundationQPMS
2022-063HQ64AllowedHigherQPMS
2019-063FQ224AllowedFoundationQPMS
2024-062FQ163AllowedFoundationQPMS
2022-113FQ143AllowedFoundationQPMS
2023-112FQ31AllowedFoundationQPMS
2019-113HQ51AllowedHigherQPMS
2019-112FQ113AllowedFoundationQPMS
2021-113FQ124AllowedFoundationQPMS
2022-061FQ11Non-calculatorFoundationQPMS
2022-113FQ274AllowedFoundationQPMS
2022-111FQ145Non-calculatorFoundationQPMS
2022-063FQ274AllowedFoundationQPMS
2022-062FQ195AllowedFoundationQPMS
2024-113FQ134AllowedFoundationQPMS
2019-113FQ51AllowedFoundationQPMS
2019-113HQ64AllowedHigherQPMS
2022-062FQ245AllowedFoundationQPMS
2024-113FQ114AllowedFoundationQPMS
2021-112FQ21AllowedFoundationQPMS
2021-113FQ244AllowedFoundationQPMS
2022-062HQ45AllowedHigherQPMS
2024-062FQ21AllowedFoundationQPMS
2022-113HQ74AllowedHigherQPMS
2019-062HQ44AllowedHigherQPMS
2022-062FQ183AllowedFoundationQPMS
2024-111FQ31Non-calculatorFoundationQPMS
2019-062FQ41AllowedFoundationQPMS
2022-063FQ292AllowedFoundationQPMS
2023-112HQ74AllowedHigherQPMS
2022-062HQ74AllowedHigherQPMS
2022-112FQ41AllowedFoundationQPMS
2021-113FQ181AllowedFoundationQPMS
2023-111FQ63Non-calculatorFoundationQPMS

Other points in R Ratio, proportion and rates of change

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