1
(1)
(Total for Question 1 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 1 |
| 1 | Use the long-run tendency: for unbiased coin tosses the empirical proportion tends towards the theoretical probability as the sample becomes large. |
Sampling and probability
Worked answers, methods and verified real exam appearances for P5 on Edexcel GCSE Maths 1MA1.
Explanation
Worked example
A fair coin gives heads in tosses and heads in tosses. Compare the two relative frequencies with .
Answer: The larger sample gives the closer relative frequency in this experiment.
Common mistakes
Exam tip
When comparing experiments, calculate relative frequencies rather than comparing raw counts.
1
(1)
(Total for Question 1 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 1 |
| 1 | Use the long-run tendency: for unbiased coin tosses the empirical proportion tends towards the theoretical probability as the sample becomes large. |
2
(3)
(Total for Question 2 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 2 |
| 3 | Calculate and . Their distances from are and , so the empirical result from spins is closer to the theoretical probability. |
3
(4)
(Total for Question 3 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 3 |
| 4 | Compare each empirical probability with . The differences are about for the first rolls and after rolls. Random variation explains a non-zero difference, and the movement towards as the sample grows is consistent with a fair die. |
4
(1)
(Total for Question 4 is 1 mark)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 4 |
| 1 | For a small total, one extra head changes the fraction by a relatively large amount. As the denominator grows, one result changes the fraction less, so random variation has less effect. |
5
(4)
(Total for Question 5 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 5 |
| 4 | Divide each frequency by its experiment total. For spins this gives , and . For spins it gives , and . Every value in the larger sample is closer to its theoretical probability. |
6
(4)
(Total for Question 6 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 6 |
| 4 | The first empirical probability is and the second is . The larger result has less random variation for the sampled group, but every person sampled is a chess-club member, so increasing the sample size does not remove this selection bias. |
7
(3)
(Total for Question 7 is 3 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 7 |
| 3 | Calculate and . The first value matches the theoretical probability, whereas the later value differs by . Long-run convergence is a tendency rather than a guarantee for every growing sample. |
8
(5)
(Total for Question 8 is 5 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 8 |
| 5 | Divide the first four frequencies by and the second four by . For spins the absolute differences are , so red differs most. For spins the differences are , all smaller, and the larger number of trials is expected to lie closer to the theoretical distribution. |
9
(4)
(Total for Question 9 is 4 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 9 |
| 4 | A relative frequency of after spins means there are red results altogether. Therefore of the further spins land on red. Since , the maintenance warning should be issued. |
10
(5)
(Total for Question 10 is 5 marks)
Mark scheme
| Question | Answer | Mark | Mark scheme |
|---|---|---|---|
| 10 |
| 5 | Divide each red frequency by its number of spins. The early results are both fairly close to , but the -spin results are more stable evidence. Wheel A moves closer to , while wheel B moves much farther away and remains there over the larger sample. |
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