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G14

Use standard units of measure and related concepts (length, area, volume/capacity, mass, time, money, etc.)

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Units of measure

Worked answers and methods for G14 on Edexcel GCSE Maths 1MA1.

Explanation

  • Choose standard units that match the quantity: length uses mm, cm, m or km; area uses square units; volume uses cubic units; capacity uses ml or litres; mass uses g or kg; and time uses seconds, minutes or hours.
  • Convert all measurements to compatible units before calculating.
  • A linear conversion factor must be squared for area and cubed for volume: because 1 m=100 cm1\text{ m}=100\text{ cm}, 1 m2=10000 cm21\text{ m}^2=10\,000\text{ cm}^2 and 1 m3=1000000 cm31\text{ m}^3=1\,000\,000\text{ cm}^3.
  • Examiners expect a numerical value with the correct unit and sensible rounding for the context, especially money and time.
Linear conversion factors are squared for area and cubed for volume.

Worked example

Convert 2.4 m22.4\text{ m}^2 to cm2\text{cm}^2.

  1. 1.1 m=100 cm1\text{ m}=100\text{ cm}, so the area factor is 1002=10000100^2=10\,000.
  2. 2.Multiply the area: 2.4×10000=240002.4\times10\,000=24\,000.
  3. 3.Attach square centimetres because an area was converted.

Answer: 24000 cm224\,000\text{ cm}^2.

Common mistakes

  • Don't multiply a square-metre value by 100100 instead of 1002100^2.
  • Don't carry a length unit such as cm into a final answer that is an area or volume.

Exam tip

Write the unit conversion before the arithmetic; this makes the required power and final unit visible for method marks.

Worked practice

Q1
Tier 1 · Easy

1

Convert 3.75 kg3.75\text{ kg} to grams.

(1)

(Total for Question 1 is 1 mark)

Mark scheme

Mark scheme for question 1
QuestionAnswerMarkMark scheme
1
  • 3750 g3750\text{ g}
1There are 1000 g1000\text{ g} in 1 kg1\text{ kg}, so 3.75×1000=37503.75\times1000=3750. Therefore the mass is 3750 g3750\text{ g}.
Q2
Tier 2 · Standard

2

A rectangular water tank is 0.8 m0.8\text{ m} long, 0.5 m0.5\text{ m} wide and 0.6 m0.6\text{ m} high. It is 65%65\% full. Work out the volume of water in litres.

(3)

(Total for Question 2 is 3 marks)

Mark scheme

Mark scheme for question 2
QuestionAnswerMarkMark scheme
2
  • 156156 litres
3The full volume is 0.8×0.5×0.6=0.24 m30.8\times0.5\times0.6=0.24\text{ m}^3. The water occupies 0.65×0.24=0.156 m30.65\times0.24=0.156\text{ m}^3. Since 1 m3=10001\text{ m}^3=1000 litres, the volume is 0.156×1000=1560.156\times1000=156 litres.
Q3
Tier 3 · Hard

3

A floor measures 4.8 m4.8\text{ m} by 3.6 m3.6\text{ m}. Square tiles have side length 30 cm30\text{ cm} and are sold in boxes of 1212. A decorator buys at least 8%8\% more tiles than the exact number needed. Each box costs £14.7514.75. Work out the total cost.

(5)

(Total for Question 3 is 5 marks)

Mark scheme

Mark scheme for question 3
QuestionAnswerMarkMark scheme
3
  • £265.50265.50
5Each tile has side 0.30 m0.30\text{ m}, so its area is 0.302=0.09 m20.30^2=0.09\text{ m}^2. The floor area is 4.8×3.6=17.28 m24.8\times3.6=17.28\text{ m}^2, requiring exactly 17.28/0.09=19217.28/0.09=192 tiles. Including 8%8\% gives 192×1.08=207.36192\times1.08=207.36, so at least 208208 tiles are needed. Since 208/12=17.3208/12=17.\overline{3}, the decorator must buy 1818 boxes. The cost is 18×14.75=265.5018\times14.75=265.50, so the total is £265.50265.50.
Q4
Tier 1 · Easy

4

Change 33 hours 1818 minutes into minutes.

(1)

(Total for Question 4 is 1 mark)

Mark scheme

Mark scheme for question 4
QuestionAnswerMarkMark scheme
4
  • 198198 minutes
133 hours is 3×60=1803\times60=180 minutes. Therefore the total time is 180+18=198180+18=198 minutes.
Q5
Tier 2 · Standard

5

A roll contains 7.5 m7.5\text{ m} of ribbon. Aisha cuts 1818 pieces, each 35 cm35\text{ cm} long. Work out the length of ribbon left. Give your answer in centimetres.

(2)

(Total for Question 5 is 2 marks)

Mark scheme

Mark scheme for question 5
QuestionAnswerMarkMark scheme
5
  • 120 cm120\text{ cm}
27.5 m=750 cm7.5\text{ m}=750\text{ cm}. The pieces use 18×35=630 cm18\times35=630\text{ cm}, so 750630=120 cm750-630=120\text{ cm} of ribbon is left.
Q6
Tier 3 · Hard

6

A bakery needs 2.6 kg2.6\text{ kg} of almonds. The almonds are sold in 375 g375\text{ g} bags costing £2.152.15 each. Work out the total cost of the bags needed.

(3)

(Total for Question 6 is 3 marks)

Mark scheme

Mark scheme for question 6
QuestionAnswerMarkMark scheme
6
  • £15.0515.05
32.6 kg=2600 g2.6\text{ kg}=2600\text{ g}. Since 2600÷375=6.932600\div375=6.93\ldots, the bakery must buy 77 whole bags. The total cost is 7×2.15=15.057\times2.15=15.05, so it costs £15.0515.05.
Q7
Tier 2 · Standard

7

A water butt contains 0.42 m30.42\text{ m}^3 of water. Then 135135 litres are used and 88 buckets, each containing 12.512.5 litres, are poured into the water butt. Work out the volume of water now in the water butt. Give your answer in litres.

(3)

(Total for Question 7 is 3 marks)

Mark scheme

Mark scheme for question 7
QuestionAnswerMarkMark scheme
7
  • 385385 litres
30.42 m3=4200.42\text{ m}^3=420 litres. The buckets add 8×12.5=1008\times12.5=100 litres. Therefore the volume is 420135+100=385420-135+100=385 litres.
Q8
Tier 3 · Hard

8

A square floor mat has area 0.81 m20.81\text{ m}^2. Work out the perimeter of the mat in millimetres.

(3)

(Total for Question 8 is 3 marks)

Mark scheme

Mark scheme for question 8
QuestionAnswerMarkMark scheme
8
  • 3600 mm3600\text{ mm}
3The side length is 0.81=0.9 m\sqrt{0.81}=0.9\text{ m}. The perimeter is 4×0.9=3.6 m4\times0.9=3.6\text{ m}. Since 1 m=1000 mm1\text{ m}=1000\text{ mm}, the perimeter is 3600 mm3600\text{ mm}.
Q9
Tier 3 · Hard

9

A rectangular metal sheet measures 1.8 m1.8\text{ m} by 75 cm75\text{ cm}. A rectangular opening measuring 320 mm320\text{ mm} by 450 mm450\text{ mm} is cut from the sheet. Work out the remaining area of the sheet in square centimetres.

(3)

(Total for Question 9 is 3 marks)

Mark scheme

Mark scheme for question 9
QuestionAnswerMarkMark scheme
9
  • 12060 cm212\,060\text{ cm}^2
31.8 m=180 cm1.8\text{ m}=180\text{ cm}, so the sheet has area 180×75=13500 cm2180\times75=13\,500\text{ cm}^2. The opening measures 32 cm32\text{ cm} by 45 cm45\text{ cm}, so its area is 32×45=1440 cm232\times45=1440\text{ cm}^2. The remaining area is 135001440=12060 cm213\,500-1440=12\,060\text{ cm}^2.
Q10
Tier 3 · Hard

10

A flight leaves at 22:4822{:}48. The flight lasts 77 hours 3535 minutes. At the destination, clocks are 22 hours ahead of the departure clocks. Work out the local arrival time. State whether the arrival is on the same day or the next day.

(3)

(Total for Question 10 is 3 marks)

Mark scheme

Mark scheme for question 10
QuestionAnswerMarkMark scheme
10
  • 08:2308{:}23 on the next day
3On the departure clock, 22:48+722{:}48+7 hours 3535 minutes is 06:2306{:}23 on the next day. The destination clock is 22 hours ahead, so the local arrival time is 08:2308{:}23 on the next day.

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