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Gravitational potential energy

Energy
GCSE Physics (8463)
ORIGINAL

Convert grams to kilograms, rearrange Ep = mgh for the height, and round once at the end.

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Question

A drone of mass 1200 g1200\,\text{g} rises vertically and gains 330 J330\,\text{J} of energy in its gravitational potential energy store. Gravitational field strength =9.8 N/kg= 9.8\,\text{N/kg}. Calculate the height the drone rises. Give your answer to 2 significant figures.

Every step worked, with the reasoning.

  1. 1
    m=1200 g=1.2 kgm = 1200\,\text{g} = 1.2\,\text{kg}

    Ep=mghE_p = mgh needs the mass in kilograms: divide grams by 1000.

  2. 2
    Ep=mgh⇒h=EpmgE_p = mgh \Rightarrow h = \dfrac{E_p}{mg}

    Rearrange before substituting: divide both sides by mgmg.

  3. 3
    h=3301.2×9.8=33011.76h = \dfrac{330}{1.2 \times 9.8} = \dfrac{330}{11.76}

    Work out the denominator first — mgmg is the drone's weight, 11.76 N11.76\,\text{N}.

  4. 4
    h=28.06… m=28 mh = 28.06\ldots\,\text{m} = 28\,\text{m} (2 s.f.)

    Keep the full value until the last line, then round to the 2 significant figures asked for.

Answer: 28 m28\,\text{m}

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