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Physics

Worked examples

AQA · GCSE Physics (8463)

Reading a worked solution isn't revising it. Each example fades in three stages: see it fully worked, then fill in the blanked middle steps, then do the whole thing with just the question. Every one ends with the error that most often costs the marks.

Energy

Kinetic energy

4.1.1.2

A cyclist and her bicycle have a combined mass of 80 kg80\,\text{kg}. She speeds up from 4.0 m/s4.0\,\text{m/s} to 9.0 m/s9.0\,\text{m/s}. Calculate the increase in the energy in the kinetic energy store of the cyclist and bicycle.

Find the kinetic store at each speed, then subtract — never square the change in speed.

Gravitational potential energy

4.1.1.2

A drone of mass 1200 g1200\,\text{g} rises vertically and gains 330 J330\,\text{J} of energy in its gravitational potential energy store. Gravitational field strength =9.8 N/kg= 9.8\,\text{N/kg}. Calculate the height the drone rises. Give your answer to 2 significant figures.

Convert grams to kilograms, rearrange Ep = mgh for the height, and round once at the end.

Specific heat capacity (required practical)

4.1.1.3

In the specific heat capacity required practical, a student heats a 1.0 kg1.0\,\text{kg} aluminium block with a 50 W50\,\text{W} heater for 6.06.0 minutes. The temperature of the block rises from 21.0 ∘C21.0\,{}^\circ\text{C} to 40.5 ∘C40.5\,{}^\circ\text{C}. (a) Calculate the specific heat capacity of aluminium given by these results. (b) The accepted value is about 900 J/kg ∘C900\,\text{J/kg}\,{}^\circ\text{C}. Explain why the student's value is higher.

Energy from E = Pt, the temperature change, then c = ΔE ÷ (mΔθ) — and why the result comes out too high.

Power and efficiency

4.1.1.4, 4.1.2.2

An electric motor has an input power of 400 W400\,\text{W}. In 6.0 s6.0\,\text{s} it transfers 1800 J1800\,\text{J} of energy usefully to lift a load. Calculate (a) the total energy supplied to the motor, (b) the efficiency of the motor, (c) the useful power output of the motor.

Input energy from power × time, efficiency as useful ÷ total, and the useful power output — with a check that efficiency is below 1.

From energy to power (two steps)

4.1.1.2, 4.1.1.4

A lift motor raises a lift of mass 540 kg540\,\text{kg} at a steady speed through a vertical height of 24 m24\,\text{m} in 18 s18\,\text{s}. Gravitational field strength =9.8 N/kg= 9.8\,\text{N/kg}. Calculate the useful power output of the motor. Give your answer in kilowatts to 2 significant figures.

Step 1 finds the energy transferred, step 2 divides by the time — carrying the unrounded energy through.

Electricity

Particle model of matter

Forces

Moments: balancing a seesaw

4.5.4

A uniform seesaw is pivoted at its centre. Child A, weight 320 N320\,\text{N}, sits 1.5 m1.5\,\text{m} to the left of the pivot, and a bag of weight 80 N80\,\text{N} rests 0.50 m0.50\,\text{m} to the left of the pivot. Child B, weight 400 N400\,\text{N}, sits on the right. How far from the pivot must Child B sit for the seesaw to balance?

Total anticlockwise moment = total clockwise moment, with every force paired with its own distance.

Pressure in a fluid

4.5.5.1.1, 4.5.5.1.2

A diver is 12 m12\,\text{m} below the surface of the sea. The density of sea water is 1030 kg/m31030\,\text{kg/m}^3 and gravitational field strength is 9.8 N/kg9.8\,\text{N/kg}. (a) Calculate the pressure due to the water at this depth. (b) The glass window of the diver's mask has an area of 0.015 m20.015\,\text{m}^2. Calculate the force on the window due to the water.

Pressure from a liquid column with p = hρg, then the force on a surface with F = pA.

Momentum in a collision and the force it needs

4.5.7.2, 4.5.7.3

A trolley of mass 0.80 kg0.80\,\text{kg} moving at 2.5 m/s2.5\,\text{m/s} collides with a stationary trolley of mass 1.2 kg1.2\,\text{kg}. The trolleys stick together. (a) Calculate their velocity just after the collision. (b) The collision lasts 0.040 s0.040\,\text{s}. Calculate the average force on the 1.2 kg1.2\,\text{kg} trolley.

Conservation of momentum for the velocity after, then force as the rate of change of momentum.

Waves

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