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S1

Infer properties of populations or distributions from a sample, while knowing the limitations of sampling

Sampling

Worked answers, methods and verified real exam appearances for S1 on Edexcel GCSE Maths 1MA1.

Explanation

  • A population is the whole group being studied; a sample is the smaller group from which data are collected.
  • If the sample is representative, its proportion or mean can be used to estimate a population value.
  • Scale a sample proportion by the population size when estimating a count.
  • The result is an estimate, not a certainty.
  • Small samples, convenience sampling, under-coverage and non-response can make the sample unrepresentative and the inference unreliable.

Worked example

In a random sample of 7575 residents, 2727 support a proposal. Estimate how many of the town's 12501250 residents support it and state the assumption needed.

  1. 1.Sample proportion =2775=0.36=\dfrac{27}{75}=0.36.
  2. 2.Estimated population count =0.36×1250=450=0.36\times1250=450.
  3. 3.The estimate assumes that the sample is representative of the town's residents.

Answer: About 450450 residents, provided the sample is representative.

Common mistakes

  • Don't fall into the trap of using the sample frequency as the population estimate without scaling.
  • Don't fall into the trap of assuming a large but biased sample must be representative.

Exam tip

State a limitation in context, explaining how it could make the sample unrepresentative.

Worked practice

Q1
Tier 1 · Easy

1

In a random sample of 5050 library users, 3030 prefer later opening. Estimate how many of the library's 10001000 users prefer later opening.

(2)

(Total for Question 1 is 2 marks)

Mark scheme

Mark scheme for question 1
QuestionAnswerMarkMark scheme
1
  • 600600 users
2The sample proportion is 30/50=0.630/50=0.6. Apply this to the population: 0.6×1000=6000.6\times1000=600.
Q2
Tier 2 · Standard

2

A random sample of 8080 items from a production run of 800800 contains 1818 items with a surface mark. Estimate the number in the whole run with a surface mark and state one limitation of the estimate.

(3)

(Total for Question 2 is 3 marks)

Mark scheme

Mark scheme for question 2
QuestionAnswerMarkMark scheme
2
  • 180180 items.
  • The sample may differ from the population by chance, so the estimate need not equal the true number.
3The sample is one tenth of the production run, so scale 1818 by 1010 to get 180180. Because only a sample was inspected, sampling variation remains even if the selection was random.
Q3
Tier 3 · Hard

3

A service invites a random sample of 450450 customers to answer a survey. Only 270270 reply, and 189189 of the replies support a change. Use the replies to estimate the number of supporters among all 1200012000 customers, then explain a serious limitation.

(4)

(Total for Question 3 is 4 marks)

Mark scheme

Mark scheme for question 3
QuestionAnswerMarkMark scheme
3
  • Estimated supporters =8400=8400.
  • Non-response bias may make the replies unrepresentative because the 180180 non-responders may have different views.
4Among replies, the support proportion is 189/270=0.7189/270=0.7, giving 0.7×12000=84000.7\times12000=8400. However, the estimate assumes responders and non-responders have similar opinions; the low response rate may break that assumption.
Q4
Tier 1 · Easy

4

A council wants the views of all 60006000 residents about a cycle lane and surveys 8080 visitors to a sports centre. Write down the population and give one reason why the sample may be unrepresentative.

(2)

(Total for Question 4 is 2 marks)

Mark scheme

Mark scheme for question 4
QuestionAnswerMarkMark scheme
4
  • The population is all 60006000 residents.
  • Visitors to the sports centre may have different views from residents who do not use it (accept any valid reason that the sports-centre sample may be biased).
2The group whose views the council wants is all 60006000 residents, so that is the population. The sample comes from only one location and may over-represent people who use the sports centre, so it may not represent all residents.
Q5
Tier 2 · Standard

5

Two random samples estimate support for a new crossing. In a sample of 2525, 1414 people support it. In a sample of 200200, 104104 people support it. Use the more reliable sample to estimate how many of 30003000 residents support the crossing. Give a reason for your choice of sample.

(3)

(Total for Question 5 is 3 marks)

Mark scheme

Mark scheme for question 5
QuestionAnswerMarkMark scheme
5
  • 15601560 residents.
  • The sample of 200200 is more reliable because a larger random sample is likely to have less sampling variation.
3Use the larger random sample. Its support proportion is 104200=0.52\dfrac{104}{200}=0.52, so the estimate is 0.52×3000=15600.52\times3000=1560. A larger random sample is generally less affected by chance variation than a sample of 2525.
Q6
Tier 3 · Hard

6

In a representative sample of 120120 households, 7878 own at least one pet. In a separate representative sample of 9090 pet-owning households, 5454 own a dog. Use both samples to estimate the percentage of all households that own a dog. Explain why using 54/9054/90 as the estimate would be wrong.

(4)

(Total for Question 6 is 4 marks)

Mark scheme

Mark scheme for question 6
QuestionAnswerMarkMark scheme
6
  • Estimated percentage =39%=39\%.
  • 54/9054/90 estimates the proportion of pet-owning households that own a dog, not the proportion of all households that own a dog.
4Estimate the proportion of households that own a pet as 78/120=0.6578/120=0.65. Estimate the proportion of pet-owning households that own a dog as 54/90=0.654/90=0.6. Therefore the estimated proportion of all households that own a dog is 0.65×0.6=0.390.65\times0.6=0.39, or 39%39\%. The second sample alone has pet-owning households as its population, so its 60%60\% cannot be applied to all households.
Q7
Tier 2 · Standard

7

A recycling team uses a sample of 160160 households to estimate that 10501050 of the district's 30003000 households use a food-waste collection. Work out how many households in the sample used the collection. Give one reason why the estimate of 10501050 may not equal the true district total.

(3)

(Total for Question 7 is 3 marks)

Mark scheme

Mark scheme for question 7
QuestionAnswerMarkMark scheme
7
  • 5656 households.
  • Households that use the food-waste collection may be more or less likely to appear in the sample — for example, uptake may vary between streets or seasons — so the sample proportion may differ from the district's (accept any valid sampling limitation).
3The estimated population proportion is 1050/3000=0.351050/3000=0.35. Apply this proportion to the sample: 0.35×160=560.35\times160=56. Even a representative sample gives an estimate, because another sample could contain a different proportion.
Q8
Tier 3 · Hard

8

A club emails 320320 randomly selected members. Of the 224224 who reply, 9898 intend to renew their membership. Without making an assumption about the members who did not reply, work out the least and greatest possible percentages of the 320320 sampled members who intend to renew. Explain why using 98/22498/224 to describe all club members may be unreliable.

(4)

(Total for Question 8 is 4 marks)

Mark scheme

Mark scheme for question 8
QuestionAnswerMarkMark scheme
8
  • Least possible percentage =30.625%=30.625\% (or 30.6%30.6\% to 1 d.p.); greatest possible percentage =60.625%=60.625\% (or 60.6%60.6\% to 1 d.p.).
  • The members who replied may have different intentions from those who did not reply, so the replies may be unrepresentative of all club members.
4There are 320224=96320-224=96 non-responders. The least possible number intending to renew is 9898, giving 98/320×100=30.625%98/320\times100=30.625\%. The greatest is 98+96=19498+96=194, giving 194/320×100=60.625%194/320\times100=60.625\%. This wide range shows the possible effect of non-response bias.
Q9
Tier 3 · Hard

9

A coach operator surveys 150150 passengers who booked their journeys using its app. Of these passengers, 9696 say the service was satisfactory. Use the sample to estimate how many of the operator's 32003200 weekly passengers are satisfied. Explain why this sampling method could make the estimate unreliable.

(4)

(Total for Question 9 is 4 marks)

Mark scheme

Mark scheme for question 9
QuestionAnswerMarkMark scheme
9
  • Estimated number satisfied =2048=2048.
  • Passengers who book at a ticket counter or by telephone are excluded, and their experience or opinion of the service may differ from that of app users.
4The sample proportion satisfied is 96/150=0.6496/150=0.64, so the estimate is 0.64×3200=20480.64\times3200=2048. The sampling frame contains only app users and excludes passengers using other booking methods, so it may not represent all weekly passengers.
Q10
Tier 3 · Hard

10

A leisure centre wants the views of all its adult members. Method A uses a random-number generator to select 120120 members from the complete membership list and arranges a time for each selected member to answer. Method B telephones members between 1010 am and 22 pm on a weekday until 120120 members have answered. State which method is more likely to give a representative sample. Explain why, referring to a group Method B is likely to exclude.

(3)

(Total for Question 10 is 3 marks)

Mark scheme

Mark scheme for question 10
QuestionAnswerMarkMark scheme
10
  • Method A is more likely to give a representative sample.
  • Method B is likely to exclude members who are at work, at college or otherwise unavailable during weekday daytime; their views may differ from those of members who are available then.
3Choose Method A first. Selecting at random from the complete membership list gives every adult member a chance of selection. Method B favours members who are available during weekday daytime and can omit working members, students and others who are away then, so it is more likely to be biased.

Verified exam appearances

SeriesPaperQuestionMarksCalculatorTierLinks
2019-112FQ243AllowedFoundationQPMS
2022-112HQ154AllowedHigherQPMS
2019-112HQ43AllowedHigherQPMS
2024-113HQ184AllowedHigherQPMS
2019-062HQ33AllowedHigherQPMS
2022-111HQ52Non-calculatorHigherQPMS
2022-062HQ143AllowedHigherQPMS
2019-062FQ223AllowedFoundationQPMS
2019-111HQ112Non-calculatorHigherQPMS

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