Show that is equivalent to .
Algebra · equations and reasoning
Notes and three levels of exam-style practice for each registered specification point in this section.
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Know the difference between an equation and an identity; argue mathematically to show algebraic expressions are equivalent, and use algebra to support and construct arguments and proofs
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- An equation is satisfied by particular values, whereas an identity states that two expressions are equivalent for every permitted value.
- To show expressions are equivalent, expand or factorise one side until it matches the other.
- Foundation tier: use algebra to support and construct an argument by defining quantities with variables, translating the claim and linking the resulting algebra back to it.
- Higher tier: extend this to a proof by using a general form, such as for an even integer or for an odd integer, and reasoning that covers every permitted case.
- Checking examples alone is not a proof.
Worked example
Higher tier: prove algebraically that the sum of two consecutive integers is odd.
- 1.Let the first integer be , so the next is .
- 2.Their sum is .
- 3. is even for every integer , so is odd.
Answer: The sum has form , so it is odd.
Common mistakes
- Don't treat expressions that agree for one value as equivalent without simplifying them generally.
- Don't make this mistake: Higher tier: checks several numerical cases and calls the pattern a proof.
- Don't make this mistake: Higher tier: finishes with algebra but does not state why its form proves the claim.
Exam tip
Foundation tier: show each algebraic step and link the result to the argument. Higher tier: a “prove” question needs a general variable-based argument, not examples.
Tier 1 · Easy
Tier 2 · Standard
Prove algebraically that the sum of two consecutive integers is odd.
Tier 3 · Hard
An odd number is written as . Demonstrate algebraically that squaring it leaves remainder after division by .
Interpret simple expressions as functions with inputs and outputs; interpret the reverse as the 'inverse function' and two successive functions as a 'composite function' (formal notation expected)
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- A function maps each allowed input to one output. To evaluate , substitute the complete input into every occurrence of the variable and then simplify.
- A function can be represented by a rule, mapping diagram or input-output table.
- Higher tier: an inverse function reverses a one-to-one function, while a composite applies two functions successively; in , acts first.
- Formal function notation is expected for those extensions.
- Examiners require careful brackets when the input is an expression, because the whole input replaces .
Worked example
Given , work out and .
- 1.Substitute : .
- 2.Substitute the complete input : .
- 3.Simplify to .
Answer: and .
Common mistakes
- Don't treat as instead of function notation.
- Don't substitute only part of an expression supplied as the input.
- Don't make this mistake: Higher tier: reads as .
Exam tip
Put the complete input in brackets everywhere appears before simplifying.
Tier 1 · Easy
Given , work out .
Tier 2 · Standard
Given , find and work out .
Tier 3 · Hard
Let and . Solve , where .
Work with coordinates in all four quadrants
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- A coordinate gives horizontal position first and vertical position second. Positive is right, negative is left, positive is up and negative is down.
- The signs identify the quadrant, numbered anticlockwise from the top right.
- Find a displacement by subtracting starting coordinates from ending coordinates.
- Find a midpoint by averaging the two -coordinates and separately averaging the two -coordinates.
- Examiners expect coordinate order and negative signs to be preserved, with the two component calculations shown clearly.
Worked example
Find the midpoint of the segment joining and .
- 1.Average the -coordinates: .
- 2.Average the -coordinates: .
- 3.Write the coordinates in order.
Answer: .
Common mistakes
- Don't write the vertical coordinate first and swaps .
- Don't lose a negative sign when averaging coordinates.
- Don't find half the coordinate differences but forgets to add them to an endpoint.
Exam tip
Write the midpoint as two separate averages before combining them into one ordered pair.
Tier 1 · Easy
State the quadrant containing the point .
Tier 2 · Standard
Find the midpoint of the line segment joining and .
Tier 3 · Hard
The point divides the line segment from to in the ratio . Find the coordinates of .
Plot graphs of straight-line equations; use y = mx + c to identify parallel and perpendicular lines; find the equation of a line through two given points, or one point with a given gradient
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- A non-vertical straight line has equation , where is the gradient and is the -intercept. Plot a line by calculating at least two accurate coordinate pairs and joining them carefully with a ruler.
- From two points, find , then substitute either point to find .
- Parallel lines have equal gradients.
- Higher tier: perpendicular non-vertical lines have gradients whose product is .
- Examiners expect the gradient calculation, substitution for the intercept and a final equation in a requested form.
Worked example
Find the equation of the line through and .
- 1..
- 2.Use and substitute : .
- 3., so the equation is .
Answer: .
Common mistakes
- Don't subtract coordinates in different orders in the gradient numerator and denominator.
- Don't use the -intercept as in .
- Don't make this mistake: Higher tier: changes only the sign of a gradient to make a perpendicular line.
Exam tip
For a line through two points, show the gradient first and then substitute one point to find .
Tier 1 · Easy
Write the equation of the line with gradient and -intercept .
Tier 2 · Standard
Line has equation . Line passes through the points and . Show that the two lines are parallel.
Tier 3 · Hard
Find the equation of the line through that is perpendicular to . Give your answer in the form .
Identify and interpret gradients and intercepts of linear functions graphically and algebraically
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- The gradient of a linear function is the change in the vertical quantity per unit change in the horizontal quantity. Its sign shows whether the line rises or falls.
- The -intercept is the output when ; the -intercept is where the output is zero.
- Read axis scales and units before calculating or interpreting either feature.
- In a context, a gradient is a rate and an intercept is often an initial value or fixed charge.
- Examiners require a value, its unit and a sentence explaining what it represents.
Worked example
Water volume follows , where is litres and is minutes. Interpret the gradient and intercept.
- 1.The coefficient of is , so volume changes by litres per minute.
- 2.Therefore the volume decreases by litres each minute.
- 3.When , , so the intercept is the initial volume.
Answer: The tank starts with litres and loses litres per minute.
Common mistakes
- Don't calculate run divided by rise for the gradient.
- Don't read the wrong intercept because the axes have been confused.
- Don't give a contextual gradient as a bare number without units or meaning.
Exam tip
For “interpret”, state what happens per horizontal-axis unit and what the intercept means at zero.
Tier 1 · Easy
State the gradient and -intercept of .
Tier 2 · Standard
A straight line crosses the axes at and . Find its gradient and both intercepts.
Tier 3 · Hard
A straight-line graph of water volume litres against time minutes passes through and . Find and interpret its gradient and -intercept, then write in terms of .
Identify and interpret roots, intercepts, turning points of quadratic functions graphically; deduce roots algebraically and turning points by completing the square
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- A root of a quadratic is an -coordinate where its graph meets the -axis, so . The -intercept is found by setting .
- A turning point is the maximum or minimum point, and its vertical line is the axis of symmetry.
- Factorising can reveal roots algebraically and the graph confirms their positions.
- Higher tier: completing the square into reveals turning point .
- Examiners expect coordinates for points, equations for axes, and algebraic working when roots are to be deduced.
Worked example
Find the roots and -intercept of .
- 1.Factorise: .
- 2.Set : each factor can be zero, giving or .
- 3.Set : , so the -intercept is .
Answer: Roots and ; -intercept .
Common mistakes
- Don't report roots as -values instead of -coordinates.
- Don't find the -intercept by setting .
- Don't make this mistake: Higher tier: reads as having turning point .
Exam tip
State roots as -values, intercepts as coordinates, and the symmetry line as an equation.
Tier 1 · Easy
Find the roots and the -intercept of .
Tier 2 · Standard
For , state the turning point and axis of symmetry, and find the roots.
Tier 3 · Hard
Complete the square for . Hence state the turning point and find the roots.
Recognise, sketch and interpret graphs of linear, quadratic and simple cubic functions, the reciprocal y = 1/x (x ≠ 0), exponential y = k^x (k > 0), and y = sin x, cos x, tan x for angles of any size
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- Recognise graph families from their defining shapes and features: linear graphs have constant gradient, quadratics are symmetric parabolas, simple cubics have an S-shape, and has two reciprocal branches with asymptotes and .
- Sketch by marking intercepts, roots, turning points, asymptotes and representative values.
- Higher tier: also recognise exponentials and sine, cosine and tangent graphs for angles of any size, using their periods and standard values.
- Examiners expect a sketch to show correct shape and position, not merely a collection of plotted points.
Worked example
For , state both asymptotes and the quadrants containing its branches.
- 1. is excluded, so the vertical asymptote is .
- 2.As grows, approaches , so the horizontal asymptote is .
- 3. and have the same sign, so the branches lie in quadrants I and III.
Answer: Asymptotes and ; branches in quadrants I and III.
Common mistakes
- Don't draw a reciprocal branch touching or crossing an axis.
- Don't sketche a cubic as a parabola rather than an S-shaped curve.
- Don't make this mistake: Higher tier: treats exponential growth as a straight line.
Exam tip
Before sketching, list the intercepts, turning points and asymptotes that fix the graph's shape.
Tier 1 · Easy
A graph passes through and its -value doubles whenever increases by . Name the function as linear, quadratic, cubic, reciprocal or exponential.
Tier 2 · Standard
For the graph , state both asymptotes and the two quadrants containing its branches.
Tier 3 · Hard
For on , list the -intercepts and the coordinates of every maximum and minimum needed for an accurate sketch.
Sketch translations and reflections of a given function [Higher only]
The Secure button is a self-rating. Evidence-secure needs the latest Tier 2/3 attempt correct, plus three correct distinct drills across at least two dates and two practice sources.
Explanation
- For , translate the graph vertically by vector . For , translate it horizontally by ; the sign inside the function appears opposite to the movement.
- The graph is the reflection of in the -axis, while is its reflection in the -axis.
- Track distinctive points, including intercepts and turning points, and preserve the graph's exact shape and scale.
- A point provides a reliable coordinate check after transforming.
- Examiners expect a fully described transformation, including the correct axis or translation vector.
Worked example
The point lies on . Find its image on .
- 1. translates the graph units right.
- 2.Subtracting outside the function translates it units down.
- 3.Therefore maps to .
Answer: The image is , under translation by .
Common mistakes
- Don't move three units left instead of right.
- Don't reflect in the -axis rather than the -axis.
- Don't move only selected points and changes the graph's shape.
Exam tip
For a translation, state the vector; for a reflection, name the mirror axis.
Tier 1 · Easy
Describe fully the transformation from to .
Tier 2 · Standard
The point lies on . Find the corresponding point on and name the transformation.
Tier 3 · Hard
The point lies on . Find the corresponding point on , and describe the reflection and translations that produce the new graph.
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