4.1 Atomic structure and the periodic table — notes on one page
Every AQA GCSE Chemistry 8462 specification point in 4.1, read straight through: 15 points with definitions, explanations, mark-scheme wording and worked examples. Practice questions are in the printable question pack.
Checked against AQA 8462 section 4.1. Review basis: the qualification registry sourced from the AQA GCSE Chemistry (8462) specification; registry verification recorded 17 July 2026.
4.1.1.1 · Atoms, elements and compounds
Definition. An element is a substance made of only one type of atom, and an atom is the smallest part of an element that can exist. A compound contains two or more elements chemically combined in fixed proportions, and can be separated into those elements only by chemical reactions.
- About 100 elements are shown in the periodic table; every atom of an element shares one chemical symbol — O for oxygen, Na for sodium. You must know the symbols of the first 20 elements, Groups 1 and 7, and others named in the specification.
- Compounds form from elements by chemical reactions, which make new substances, often with a detectable energy change. The elements in a compound are chemically combined in a fixed ratio, so a formula records which elements are present and how many atoms of each.
- That fixed ratio separates a compound from a mixture, whose substances keep their own properties.
- Reactions are shown by word equations, or by balanced symbol equations with equal atoms of each element on both sides; only coefficients may change, never the subscripts in a formula.
- Higher tier: AQA restricts "write balanced half equations and ionic equations where appropriate" to Higher tier; Foundation answers use word or balanced symbol equations.
Worked example
Classify oxygen, sodium chloride and air as an element, compound or mixture, giving one reason for each.
- 1.Oxygen contains only oxygen atoms, so it is an element.
- 2.Sodium chloride contains sodium and chlorine chemically combined in a fixed ratio, so it is a compound.
- 3.Air contains several gases not chemically combined, so it is a mixture.
Answer: Oxygen is an element, sodium chloride is a compound and air is a mixture.
Mark-scheme wording to use
- “(atoms of) argon have a stable arrangement of electrons — allow (atoms of) argon have a full outer shell (of electrons)”
- “bauxite contains a variable percentage of aluminium … bauxite does not have a fixed proportion / percentage of aluminium”
- “Ba + 2 HCl → BaCl2 + H2 — allow multiples; ignore state symbols”
What the examiner wants. A classification answer that names the deciding feature, not the appearance: chemically combined or not, and fixed proportions or not. In equation questions the examiner accepts multiples and ignores state symbols, but never a changed formula.
Common mistakes
- Don't call a compound a mixture because it contains more than one element, ignoring that its elements are chemically combined in fixed proportions.
- Don't change a formula when balancing an equation, which changes the substance instead of changing the number of particles.
Exam tip. For a ‘state the difference’ question, contrast both chemical combination and the method of separation.
4.1.1.2 · Mixtures
Definition. A mixture consists of two or more elements or compounds that are not chemically combined together. The chemical properties of each substance in a mixture are unchanged, so a mixture can be separated by physical processes alone.
- The specification names five physical separation processes: filtration, crystallisation, simple distillation, fractional distillation and chromatography. None involves a chemical reaction or makes a new substance, which is why they work on mixtures and not on compounds.
- Filtration separates an insoluble solid from a liquid, because the solid particles are too large to pass through the filter paper. Crystallisation separates a soluble solid from its solution by evaporating the solvent until crystals form; heat gently near the end to avoid decomposing the solid.
- Simple distillation separates a solvent from a solution by boiling it off and condensing the vapour. Fractional distillation separates miscible liquids using the difference in their boiling points, the column giving repeated evaporation and condensation so the lowest-boiling liquid reaches the top first.
- Chromatography separates substances by how they distribute between a stationary phase and a mobile phase.
- You must describe and explain each named process and choose a suitable technique for an unfamiliar mixture.
Worked example
A mixture contains sand, salt and water. Describe how to obtain dry salt crystals.
- 1.Filter the mixture: insoluble sand remains as the residue and salt solution passes through.
- 2.Heat the filtrate to evaporate some water until the solution is concentrated.
- 3.Cool the solution so crystals form, then filter and dry the crystals.
Answer: Filter off the sand, crystallise the salt from the filtrate, then filter and dry the salt crystals.
Mark-scheme wording to use
- “Mobile phase – Solvent … Stationary phase – Paper”
- “a mixture of metals … a mixture of a metal with other elements”
- “start line does not dissolve/run/smudge or pencil is insoluble”
What the examiner wants. The property the separation exploits, named explicitly — particle size, solubility, or a difference in boiling point — and then the technique. A technique named with no property attached is usually worth nothing.
Common mistakes
- Don't use filtration to separate a dissolved solid, although dissolved particles pass through the filter paper.
- Don't say fractional distillation separates liquids by density instead of by their different boiling points.
- Don't evaporate a solution to complete dryness when the question asks for crystals.
Exam tip. In a method question, name the physical property that makes the chosen separation work.
4.1.1.3 · The development of the model of the atom (common content with physics)
- Atomic models changed when new experimental evidence could not be explained by the existing model. Atoms were first pictured as indivisible spheres.
- Discovering the electron produced the plum pudding model: negative electrons embedded in a ball of positive charge. In alpha-particle scattering, most particles passed straight through, a few were deflected and very few rebounded.
- This showed that the atom is mostly empty space and that nearly all its mass and positive charge are concentrated in a tiny nucleus, so the nuclear model replaced plum pudding.
- Bohr then proposed electrons at specific distances; later work identified protons and Chadwick supplied evidence for neutrons.
- Examiners expect evidence linked explicitly to each conclusion.
Worked example
Most alpha particles passed through gold foil, but a very small number rebounded. Explain what each observation showed.
- 1.Most particles passing through showed that most of an atom is empty space.
- 2.Rare large deflections showed that positive charge is concentrated in a very small region.
- 3.Particles rebounding showed that this small nucleus is dense and contains most of the atom’s mass.
Answer: The observations support a mostly empty atom with a tiny, dense, positively charged nucleus.
Common mistakes
- Don't claim that every alpha particle was deflected, instead of recognising that most passed through the mostly empty atom.
- Don't say Rutherford’s scattering experiment discovered electrons, although it provided evidence for a small, charged nucleus.
Exam tip. For ‘explain why the model changed’, pair each observation with the conclusion it supports.
4.1.1.4 · Relative electrical charges of subatomic particles
- Protons have relative charge , neutrons have charge and electrons have charge .
- Protons and neutrons are in the nucleus; electrons occupy energy levels around it.
- An atom has no overall electrical charge because it has equal numbers of protons and electrons, so the positive and negative charges cancel.
- The atomic number is the number of protons, and it identifies the element: every atom of one element has the same proton number, while atoms of different elements have different proton numbers.
- In questions, use the atomic number to find protons and, for a neutral atom, electrons; do not infer neutron number unless a mass number is also supplied.
Worked example
A neutral atom has atomic number . State its numbers of protons and electrons and explain its overall charge.
- 1.Atomic number , so the nucleus contains protons.
- 2.A neutral atom has equal numbers of protons and electrons, so it has electrons.
- 3.The charges sum to .
Answer: It has protons and electrons, giving no overall charge.
Common mistakes
- Don't use the atomic number as the number of neutrons rather than the number of protons.
- Don't give a neutral atom one more electron than proton, which would describe a negative ion.
Exam tip. When the particle is an atom, explicitly use ‘protons = electrons’ before concluding that its charge is zero.
4.1.1.5 · Size and mass of atoms
Definition. The mass number of an atom is the sum of its protons and neutrons. Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons, so they have the same atomic number and different mass numbers.
- Atoms have a radius of about 0.1 nm, which is 1 x 10−10 m, and the nucleus has a radius less than one ten-thousandth of that, about 1 x 10−14 m. Almost all the mass is in the nucleus, because protons and neutrons each have a relative mass of 1 while an electron's is very small (about 1/1836).
- The atomic number is the number of protons and fixes which element the atom is; the mass number is the total of protons and neutrons, written at the top left of the symbol.
- Subtracting the atomic number from the mass number gives the neutrons, and a neutral atom has as many electrons as protons.
- For an ion, add one electron for each unit of negative charge and remove one for each unit of positive charge, but never change the protons — that would change the element.
- Isotopes differ only in neutrons, so they have identical electronic structures and identical chemical properties.
Worked example
An isotope is written as . Determine its numbers of protons, neutrons and electrons.
- 1.The lower number is the atomic number, so there are protons.
- 2.Neutrons .
- 3.The symbol represents a neutral atom, so there are electrons.
Answer: protons, neutrons and electrons.
Mark-scheme wording to use
- “same number of protons / same element / same atomic number … different numbers of neutrons”
- “approximately 115”
- “(atoms of) argon have a full outer shell (of electrons)”
What the examiner wants. Both halves of the isotope definition in one answer — the same protons and the different neutrons. Answers that give only the difference in mass number, without naming the particle responsible, do not score the second mark.
Common mistakes
- Don't subtract the mass number from the atomic number and obtain a negative neutron count.
- Don't define isotopes as having different proton numbers, which would make them different elements.
Exam tip. Write ‘neutrons = mass number − atomic number’ before substituting values.
4.1.1.6 · Relative atomic mass
- Relative atomic mass, , is the weighted mean mass of an atom of an element compared with one-twelfth of the mass of a carbon-12 atom.
- It accounts for both the masses of the isotopes and their relative abundances, so the periodic-table value is often not a whole number.
- Multiply each isotope mass by its abundance, add the products, then divide by the total abundance: .
- Percentages total , but ratios may have another total.
- In an exam, show the complete weighted calculation because an unsupported rounded answer can lose method marks.
Worked example
A sample contains of isotope and of isotope . Calculate .
- 1.Multiply each isotope mass by its percentage abundance: and .
- 2.Add the weighted masses: .
- 3.Divide by the total percentage: .
Answer: .
Common mistakes
- Don't take the simple mean of the isotope masses even though their abundances are unequal.
- Don't divide by the number of isotopes instead of the total abundance.
- Don't round the relative atomic mass to a whole number without being asked.
Exam tip. Keep the abundance products visible so the examiner can award the weighted-mean method mark.
4.1.1.7 · Electronic structure
- Electrons occupy the lowest available energy levels, also called shells. For the first 20 elements, use the simple filling pattern : fill an inner shell before starting the next.
- Electronic structure may be written as numbers separated by commas or drawn as electrons on concentric shells.
- For example, sodium has atomic number , so a neutral atom has electrons and structure .
- The number of occupied shells gives the period, while the outer-shell electron count explains the group and similar chemical properties of main-group elements.
- Examiners expect the correct total and distribution, not merely the right number of shells.
Worked example
Give the electronic structure and period of a neutral calcium atom, atomic number .
- 1.A neutral calcium atom has electrons.
- 2.Fill the shells from the inside: .
- 3.Four shells are occupied, so calcium is in period .
Answer: Electronic structure ; period .
Common mistakes
- Don't place more than two electrons in the first shell.
- Don't use the mass number rather than the atomic number to choose the total electrons in a neutral atom.
Exam tip. After drawing shells, add the electrons and check that the total equals the atomic number.
4.1.2.1 · The periodic table
- The modern periodic table arranges elements in increasing atomic, or proton, number. Similar properties recur at regular intervals, so elements with related chemical behaviour are placed in vertical columns called groups.
- Main-group elements in the same group have the same number of outer-shell electrons, which explains their similar reactions.
- The period indicates the number of occupied electron shells.
- Use an electronic structure to locate an element, then use its position to predict likely reactions and reactivity.
- The modern ordering is not by relative atomic mass: atomic number gives each element one unambiguous position and explains apparent mass-order anomalies caused by isotopes.
Worked example
An element has electronic structure . State its period and group and predict whether it has properties similar to fluorine.
- 1.Three occupied shells place the element in period .
- 2.Seven outer-shell electrons place it in Group .
- 3.Fluorine is also in Group , so the elements have similar chemical properties.
Answer: Period , Group ; yes, it should have properties similar to fluorine.
Common mistakes
- Don't state that the modern table is ordered by relative atomic mass rather than atomic number.
- Don't use the total number of electrons as the group number instead of the outer-shell count.
Exam tip. For a prediction, cite the shared group or outer-electron arrangement before stating the similar property.
4.1.2.2 · Development of the periodic table
- Before subatomic particles were known, scientists tried to classify elements mainly in order of atomic weight. Early tables were incomplete, and keeping a strict weight order sometimes placed elements with different properties together.
- Mendeleev prioritised repeating chemical properties: he left gaps for elements not yet discovered and changed the order in a few places.
- Newly discovered elements filled those gaps and had properties close to his predictions, providing strong evidence for his arrangement.
- Later knowledge of isotopes explained why atomic-weight order can appear inconsistent, while atomic number gives the correct modern sequence.
- Examiners want a chronological account showing how predictions were tested by later evidence.
Worked example
Explain why the later discovery of an element with Mendeleev’s predicted properties supported his periodic table.
- 1.Mendeleev had left a gap because the repeating pattern suggested an undiscovered element.
- 2.He predicted properties for the element from neighbouring elements.
- 3.The discovered element fitted the gap and matched those predictions, so the table made a successful testable prediction.
Answer: The close match between prediction and later evidence supported Mendeleev’s arrangement.
Common mistakes
- Don't say Mendeleev simply arranged every element in strict atomic-weight order, ignoring his deliberate gaps and reversals.
- Don't claim Mendeleev used proton number, although protons had not yet been discovered.
- Don't state that gaps weakened the table without explaining that accurate predictions later supported it.
Exam tip. In a history question, use the chain ‘prediction → discovery → matching properties → support’.
4.1.2.3 · Metals and non-metals
- Metals are elements that react to form positive ions; non-metals do not form positive ions. Most elements are metals, found mainly on the left and towards the bottom of the periodic table, while non-metals lie towards the right and top.
- Typical metals conduct heat and electricity, are strong and malleable, and often have high melting points.
- Solid non-metals are generally brittle and poor conductors, although the specification includes important structure-based exceptions such as graphite.
- Link chemical behaviour to electron arrangement: metal atoms tend to lose outer electrons, while non-metal atoms tend to gain or share electrons.
- In comparisons, state a property and then explain it using particles or electrons where requested.
Worked example
An element conducts electricity, is malleable and forms a ion. Decide whether it is a metal or non-metal.
- 1.Electrical conduction and malleability are characteristic metallic properties.
- 2.Forming a positive ion means the atom loses electrons, which is characteristic of a metal.
- 3.Both the physical and chemical evidence therefore support the same classification.
Answer: The element is a metal.
Common mistakes
- Don't define a metal only as shiny, instead of using its formation of positive ions as the chemical distinction.
- Don't claim every non-metal is a gas or every metal is magnetic.
- Don't say metals gain electrons when explaining the formation of positive ions.
Exam tip. For ‘explain the difference’, pair a characteristic property with the relevant electron behaviour.
4.1.2.4 · Group 0
- Group 0 elements are the noble gases. Their atoms have stable outer-electron arrangements: eight outer electrons, except helium, whose only shell is complete with two.
- This stability makes them very unreactive, so they do not easily form molecules and exist as single atoms.
- Down the group, relative atomic mass increases and boiling point increases.
- A data trend can be used to predict the boiling point or physical state of another noble gas, while recognising that a prediction is an estimate.
- For explanation marks, low reactivity must be connected directly to the complete outer shell rather than merely describing noble gases as ‘stable’.
Worked example
Neon boils at and argon at . Predict whether krypton’s boiling point is above or below .
- 1.Krypton is below argon in Group .
- 2.Boiling point increases down Group as relative atomic mass increases.
- 3.Krypton should therefore boil at a temperature above .
Answer: Krypton’s boiling point should be above .
Common mistakes
- Don't say helium needs eight outer electrons, although its first shell is complete with two.
- Don't describe noble gases as diatomic molecules rather than single atoms.
- Don't predict that boiling point decreases down Group 0, reversing the specified trend.
Exam tip. When explaining unreactivity, write ‘complete outer shell’ before stating that atoms do not readily react.
4.1.2.5 · Group 1
- Group 1 elements are alkali metals with one electron in their outer shell. They react by losing this electron to form ions, so their reactions are similar.
- Lithium, sodium and potassium react with oxygen to form oxides, with chlorine to form chlorides, and with water to form a metal hydroxide plus hydrogen.
- The water reactions become more vigorous down the group.
- Reactivity increases because the outer electron is farther from the nucleus and experiences more shielding, so the attraction to the nucleus is weaker and the electron is lost more easily.
- Examiners may ask for observations, products, balanced equations or a prediction for a lower element.
Worked example
Predict the products when potassium reacts with water and explain why potassium reacts more vigorously than lithium.
- 1.A Group 1 metal reacting with water forms the metal hydroxide and hydrogen.
- 2.The products are potassium hydroxide and hydrogen.
- 3.Potassium’s outer electron is farther from the nucleus and more shielded, so it is less strongly attracted and lost more easily.
Answer: Potassium hydroxide and hydrogen form; potassium is more reactive because its outer electron is lost more easily.
Common mistakes
- Don't write metal oxide as the product of a Group 1 metal reacting with water.
- Don't reverse the trend and say lithium is the most reactive of the first three alkali metals.
- Don't explain the trend only by saying atoms are larger, without linking distance and shielding to weaker attraction.
Exam tip. A reactivity-trend explanation needs distance, shielding, nuclear attraction and ease of electron loss.
4.1.2.6 · Group 7
- Group 7 elements are halogens: non-metals whose atoms have seven outer-shell electrons. They exist as diatomic molecules such as , and form ionic halides with metals or covalent compounds with non-metals.
- Down the group, relative molecular mass, melting point and boiling point increase, but reactivity decreases.
- A halogen reacts by gaining one electron; farther down the group, the outer shell is farther from the nucleus and more shielded, so attracting an incoming electron is harder.
- A more reactive halogen displaces a less reactive halogen from an aqueous halide solution.
- Examiners expect correct trends, observations or equations and an electron-based explanation.
Worked example
Chlorine water is added to potassium bromide solution. Predict the products and explain whether a reaction occurs.
- 1.Chlorine is above bromine in Group , so chlorine is more reactive.
- 2.The more reactive chlorine displaces bromine from bromide ions.
- 3.The equation is .
Answer: Potassium chloride and bromine form because chlorine is more reactive than bromine.
Common mistakes
- Don't say Group 7 reactivity increases down the group, confusing the trend with Group 1.
- Don't write a halogen atom as a ion before it has gained an electron.
- Don't predict that iodine displaces chlorine from chloride solution.
Exam tip. For displacement, compare the two halogens’ positions before writing the products.
4.1.3.1 · Comparison with Group 1 elements (chemistry only)
- Transition elements are metals, including chromium, manganese, iron, cobalt, nickel and copper. Compared with Group 1 metals, they generally have higher melting points and densities and are stronger and harder.
- They are also much less reactive with water, oxygen and halogens.
- These differences make transition metals suitable where a material must keep its shape, withstand force or avoid rapid reaction, whereas Group 1 metals are soft and highly reactive.
- Questions often provide unfamiliar data and require an element to be classified or compared.
- Conclusions must use the data and stated general patterns, with a named transition element supporting broad statements when requested.
Worked example
Compare iron with sodium using density, hardness and reaction with water.
- 1.Iron, a transition metal, is generally denser than sodium, a Group metal.
- 2.Iron is harder and stronger, while sodium is soft.
- 3.Iron is much less reactive with water than sodium.
Answer: Iron is denser, harder and much less reactive with water than sodium.
Common mistakes
- Don't claim transition metals are more reactive than Group 1 metals because they are stronger.
- Don't use sodium or potassium as an example of a transition element.
- Don't treat every transition metal as having exactly the same melting point, density and reactivity.
Exam tip. In a comparison, use paired language such as ‘higher density but lower reactivity than Group 1’.
4.1.3.2 · Typical properties (chemistry only)
- Transition elements show characteristic chemical properties as well as typical metallic ones. Many form ions with different charges, form coloured compounds and are useful catalysts.
- For example, iron can form and ions, and iron is the catalyst in the Haber process.
- Compounds of chromium, manganese, iron, cobalt, nickel and copper provide examples of coloured transition-metal compounds.
- A catalyst increases reaction rate without being used up overall; being coloured does not itself make a compound a catalyst.
- In exams, identify the property shown by information in the question and give a named example rather than assuming every transition element shows every property in the same way.
Worked example
Iron forms and . State the transition-metal property shown and give one other typical property.
- 1.Chloride ions have charge , so the formulae contain iron ions with different charges.
- 2.The compounds therefore show that iron forms ions with different charges.
- 3.Another typical property is forming coloured compounds or acting as a catalyst.
Answer: Iron forms ions with different charges; transition elements also form coloured compounds or act as catalysts.
Common mistakes
- Don't say transition elements form only one ion charge, overlooking variable-charge ions such as and .
- Don't define a catalyst as a substance that is used up to provide energy.
- Don't assume any coloured compound must be acting as a catalyst.
Exam tip. When asked for a typical property, state it precisely and attach it to a named transition element or compound.