AQA GCSE Chemistry coverage

Atomic structure and the periodic table

Section 4.1
15 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

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4.1.1.1

Atoms, elements and compounds

  • All substances are made from atoms. An atom is the smallest part of an element that can exist, and each element has its own chemical symbol.
  • A compound contains atoms of two or more elements chemically combined in fixed proportions; its formula shows which atoms are present and their ratio.
  • Represent reactions with word equations or balanced symbol equations, checking that each element has the same number of atoms on both sides.
  • A common error is to call a mixture a compound: substances in a mixture are not chemically combined, keep their chemical properties and can be separated physically.

Tier 1 · Easy

2 marks
ORIGINAL

A sealed jar contains only argon atoms. State whether its contents are an element, a compound or a mixture, and give one reason.

Tier 2 · Standard

3 marks
ORIGINAL

Magnesium burns in oxygen to form magnesium oxide. Write the word equation, then complete and balance the symbol equation Mg + O<sub>2</sub> → MgO.

Tier 3 · Hard

5 marks
ORIGINAL

Molecule E has formula C2H6O\mathrm{C}_2\mathrm{H}_6\mathrm{O}. It reacts fully with oxygen to produce carbon dioxide and water. Balance C2H6O+O2CO2+H2O\mathrm{C}_2\mathrm{H}_6\mathrm{O}+\mathrm{O}_2\rightarrow\mathrm{CO}_2+\mathrm{H}_2\mathrm{O}, then explain why chemical products are not merely the starting materials mixed together.

4.1.1.2

Mixtures

  • A mixture contains two or more elements or compounds that are not chemically combined, so each substance keeps its chemical properties.
  • Choose a physical separation method from the property that differs: particle size for filtration, solubility for crystallisation, boiling point for distillation, or attraction to phases for chromatography.
  • For example, filter sand from salt solution, then evaporate some water and cool the concentrated solution so salt crystals form.
  • A common error is to evaporate a solution to complete dryness when crystallisation is required; strong heating can spoil crystals or decompose the solute.

Tier 1 · Easy

2 marks
ORIGINAL

A beaker contains chalk powder suspended in water. Name the physical process that collects the chalk and identify what passes through the paper.

Tier 2 · Standard

4 marks
ORIGINAL

A student needs dry copper sulfate crystals from a copper sulfate solution. Describe a suitable sequence after the solution has been placed in an evaporating basin.

Tier 3 · Hard

6 marks
ORIGINAL

A liquid mixture contains propanone, which boils at 56 °C, water, which boils at 100 °C, and a dissolved non-volatile blue solid. Design a separation that obtains all three components.

4.1.1.3

The development of the model of the atom (common content with physics)

  • Scientific models change when new observations cannot be explained by the current model: indivisible spheres were replaced after the electron was discovered.
  • The plum pudding model placed negative electrons within a diffuse ball of positive charge; alpha scattering instead supported a tiny charged nucleus containing most of the mass.
  • Bohr proposed electrons at specific distances from the nucleus, later work identified protons, and Chadwick's evidence established neutrons in the nucleus.
  • A common error is to claim that most alpha particles bounced back; most passed straight through, while only a very small fraction were deflected through large angles.

Tier 1 · Easy

2 marks
ORIGINAL

Place these developments in chronological order: Chadwick's neutron evidence, the plum pudding model, Bohr's shells, the nuclear model.

Tier 2 · Standard

4 marks
ORIGINAL

In an alpha-scattering trial, nearly every alpha particle crossed a thin metal sheet without changing direction, but a tiny proportion returned towards the source. Explain the conclusions about atomic structure.

Tier 3 · Hard

6 marks
ORIGINAL

Compare the plum pudding and nuclear models, then explain how scattering evidence and later discoveries produced the modern GCSE model of the atom.

4.1.1.4

Relative electrical charges of subatomic particles

  • The relative charges are proton +1, neutron 0 and electron −1.
  • For a neutral atom, proton number equals electron number; an ion's overall charge is the total positive charge plus the total negative charge.
  • For example, a particle with 12 protons and 10 electrons has charge +2.
  • A common error is to change the proton number when an ion forms; ordinary ions form by gaining or losing electrons, while the nucleus remains unchanged.

Tier 1 · Easy

3 marks
ORIGINAL

State the relative charge of a proton, a neutron and an electron.

Tier 2 · Standard

3 marks
ORIGINAL

A particle contains 13 protons, 14 neutrons and 10 electrons. Determine its overall charge and explain whether it is an atom or an ion.

Tier 3 · Hard

5 marks
ORIGINAL

Species X has 26 protons, 30 neutrons and 23 electrons. Give its atomic number, mass number and ionic charge, then identify X using a periodic table.

4.1.1.5

Size and mass of atoms

  • An atom has a radius of about 0.1nm=1×1010m0.1\,\text{nm}=1\times10^{-10}\,\text{m}; a nucleus is about 1×1014m1\times10^{-14}\,\text{m} in radius and less than one ten-thousandth of the atom's radius.
  • Almost all atomic mass lies in the nucleus: protons and neutrons each have relative mass 1, while an electron's relative mass is very small.
  • Mass number is protons plus neutrons, so neutron number is mass number minus atomic number; adjust only electrons when working with ions.
  • A common error is to confuse mass number with relative atomic mass: mass number belongs to one isotope and is always a whole number.

Tier 1 · Easy

2 marks
ORIGINAL

Convert an atomic radius of 0.12nm0.12\,\text{nm} into metres and write the result in standard form.

Tier 2 · Standard

4 marks
ORIGINAL

An oxygen-18 atom has atomic number 8. Calculate its numbers of protons, neutrons and electrons, and state where almost all its mass is located.

Tier 3 · Hard

6 marks
ORIGINAL

An atom has radius 9.0×1011m9.0\times10^{-11}\,\text{m} and its nucleus has radius 7.5×1015m7.5\times10^{-15}\,\text{m}. Calculate how many times larger the atomic radius is. A related ion has 26 protons, 30 neutrons and 24 electrons; write its nuclide symbol and charge.

4.1.1.6

Relative atomic mass

  • Relative atomic mass, A<sub>r</sub>, is the weighted mean mass of an element's atoms, accounting for the abundance of each isotope.
  • Calculate A<sub>r</sub> using (isotope mass×percentage abundance)100\dfrac{\sum(\text{isotope mass}\times\text{percentage abundance})}{100} when abundances are percentages.
  • For isotopes of mass 24, 25 and 26 with abundances 80%, 10% and 10%, the weighted mean is (24×80+25×10+26×10)/100=24.3(24\times80+25\times10+26\times10)/100=24.3.
  • A common error is to take an unweighted mean of isotope masses; a more abundant isotope must contribute more strongly to A<sub>r</sub>.

Tier 1 · Easy

2 marks
ORIGINAL

A sample of copper contains 69% copper-63 and 31% copper-65. Calculate its relative atomic mass.

Tier 2 · Standard

3 marks
ORIGINAL

Element Z has isotopes Z-24, Z-25 and Z-26. Their abundances are 79%, 10% and 11% respectively. Determine the relative atomic mass of Z.

Tier 3 · Hard

4 marks
ORIGINAL

An element has only isotopes of mass 79 and 81. Its relative atomic mass is 79.90. Calculate the percentage abundance of the mass-79 isotope.

4.1.1.7

Electronic structure

  • Electrons occupy the lowest available energy levels or shells first; for the first 20 elements the shells fill in the pattern 2, then 8, then 8 before the fourth shell begins.
  • Use the atomic number to find the electron total for a neutral atom, then distribute those electrons from the innermost shell outwards.
  • For example, atomic number 13 gives 13 electrons and electronic structure 2,8,3; a shell diagram must show the same arrangement.
  • A common error is to put eight electrons in the first shell; the first shell holds only two.

Tier 1 · Easy

2 marks
ORIGINAL

Give the electronic structure of an aluminium atom, which has atomic number 13.

Tier 2 · Standard

3 marks
ORIGINAL

Calcium has atomic number 20. State the electronic structure of a calcium atom and of a Ca<sup>2+</sup> ion.

Tier 3 · Hard

5 marks
ORIGINAL

Neutral atom X is one of the first 20 elements. It has three occupied shells and seven electrons in its outer shell. Identify X, give its atomic number and electronic structure, and state the structure after it gains one electron.

4.1.2.1

The periodic table

  • The modern periodic table is ordered by increasing atomic number, and elements with similar properties occur at regular intervals.
  • A group is a column; for Groups 1 to 7, atoms in the same group have the same number of outer-shell electrons and therefore similar reactions.
  • Use electronic structure to connect atomic number and position: 2,8,2 contains 12 electrons, lies in period 3 and belongs to Group 2.
  • A common error is to use the total number of shells as the group number; occupied shells indicate the period, while outer electrons indicate the group for the main groups.

Tier 1 · Easy

3 marks
ORIGINAL

An atom has electronic structure 2,8,2. Give its atomic number, period and group.

Tier 2 · Standard

4 marks
ORIGINAL

Elements P and Q have electronic structures 2,1 and 2,8,1. Explain why they have similar chemical properties and identify which one has the larger atomic number.

Tier 3 · Hard

6 marks
ORIGINAL

Element R has atomic number 16 and element S has atomic number 19. Write both electronic structures, locate each by period and group, and predict which is more likely to form a positive ion.

4.1.2.2

Development of the periodic table

  • Early tables arranged elements mainly by atomic weight, but they were incomplete and strict weight order sometimes placed elements with unlike properties together.
  • Mendeleev left gaps for undiscovered elements and sometimes changed the weight order so elements with similar properties stayed in the same group.
  • When newly discovered elements matched his predicted properties and filled the gaps, the agreement provided evidence supporting his table.
  • A common error is to say Mendeleev knew atomic numbers; protons had not yet been discovered, and knowledge of isotopes later explained weight-order anomalies.

Tier 1 · Easy

2 marks
ORIGINAL

Give two decisions Mendeleev made that improved the arrangement of the elements known in his time.

Tier 2 · Standard

3 marks
ORIGINAL

Mendeleev predicted that an empty position would be filled by an element forming an oxide X<sub>2</sub>O<sub>3</sub>. Years later, a new element was found and its oxide had that formula. Explain why this strengthened his periodic table.

Tier 3 · Hard

5 marks
ORIGINAL

Two elements have relative atomic masses 39.1 and 40.0. Their chemical properties place the 40.0 element before the 39.1 element in the modern table. Explain why this ordering troubled early tables, how Mendeleev could respond, and how later atomic theory resolved the issue.

4.1.2.3

Metals and non-metals

  • Metals form positive ions in reactions and are found mainly on the left and towards the bottom of the periodic table; non-metals occupy the upper-right region.
  • Typical metals conduct heat and electricity, are strong, malleable and often have high melting points; non-metals generally lack this combination of properties.
  • Atomic structure explains the broad division: metal atoms tend to lose outer electrons, whereas non-metal atoms do not form positive ions and may gain or share electrons.
  • A common error is to classify an element from one physical property alone; use its position, ion formation and a pattern of characteristic properties.

Tier 1 · Easy

2 marks
ORIGINAL

Element T reacts by losing two electrons from each atom. Classify T as a metal or non-metal and state the charge on the ion formed.

Tier 2 · Standard

4 marks
ORIGINAL

Magnesium has electronic structure 2,8,2, while sulfur has 2,8,6. Use these structures and periodic-table positions to explain why magnesium is a metal but sulfur is a non-metal.

Tier 3 · Hard

6 marks
ORIGINAL

Unknown A is shiny, bends without snapping, conducts electricity and forms A<sup>3+</sup>. Unknown B is dull, breaks when hammered and does not conduct as a solid. Compare the evidence and predict where each lies in the periodic table.

4.1.2.4

Group 0

  • Group 0 elements are the noble gases. Their stable outer electron arrangements make them very unreactive, so they do not easily form molecules.
  • Helium has two outer electrons; the other noble gases have eight. In each case the occupied outer shell is full.
  • Boiling points increase down Group 0 as relative atomic mass increases, so a value for a lower noble gas should continue the trend.
  • A common error is to say noble gases have no electrons available for bonding; their lack of reactivity is explained by a stable full outer shell.

Tier 1 · Easy

2 marks
ORIGINAL

Explain why neon is unreactive using its electronic structure 2,8.

Tier 2 · Standard

3 marks
ORIGINAL

The boiling points of neon, argon and krypton are −246 °C, −186 °C and −153 °C. Choose the most plausible boiling point for xenon from −260 °C, −170 °C and −108 °C, and justify your choice.

Tier 3 · Hard

5 marks
ORIGINAL

An unknown gas is monatomic, has electronic structure 2,8,8 and boils at a higher temperature than neon. Identify the gas and explain all three observations.

4.1.2.5

Group 1

  • Group 1 elements are alkali metals with one outer electron; they form 1+ ions by losing that electron and therefore have similar reactions.
  • Lithium, sodium and potassium react with oxygen to form oxides, with chlorine to form chlorides, and with water to form a metal hydroxide and hydrogen.
  • Reactivity increases down the group because the outer electron is farther from the nucleus and more shielded, so the attraction to the nucleus is weaker and the electron is lost more easily.
  • A common error is to reverse the trend or attribute it to having more outer electrons; every Group 1 atom has exactly one outer electron.

Tier 1 · Easy

3 marks
ORIGINAL

Name the two products when sodium reacts with water, and state one visible observation.

Tier 2 · Standard

4 marks
ORIGINAL

Complete and balance the equation Na + Cl<sub>2</sub> → NaCl. Explain why sodium and potassium both form compounds with one metal atom for each chlorine atom.

Tier 3 · Hard

6 marks
ORIGINAL

A teacher compares lithium, sodium and potassium in water using equal-sized pieces. Predict the order from least to most vigorous, explain the trend using atomic structure, and predict how rubidium would behave.

4.1.2.6

Group 7

  • Group 7 elements are halogen non-metals with seven outer electrons and exist as diatomic molecules such as Cl<sub>2</sub>, Br<sub>2</sub> and I<sub>2</sub>.
  • Halogens form ionic halides with metals and covalent compounds with non-metals; each halogen atom needs one additional electron for a stable outer shell.
  • Down the group, relative molecular mass, melting point and boiling point increase, while reactivity decreases because gaining an electron becomes harder.
  • A common error is to reverse displacement: a more reactive halogen displaces a less reactive halogen from an aqueous halide salt, not the other way round.

Tier 1 · Easy

2 marks
ORIGINAL

State two features shared by chlorine, bromine and iodine atoms or molecules that explain their placement in Group 7.

Tier 2 · Standard

5 marks
ORIGINAL

Chlorine water is added to aqueous potassium bromide. Predict the products, write a balanced equation and explain why the reaction occurs.

Tier 3 · Hard

6 marks
ORIGINAL

Bromine water is tested separately with sodium chloride and sodium iodide solutions. Predict each result, write any equation that occurs, and explain the different outcomes using the Group 7 reactivity trend.

4.1.3.1

Comparison with Group 1 elements (chemistry only)

  • Transition elements are metals including chromium, manganese, iron, cobalt, nickel and copper, with general properties that differ from Group 1 metals.
  • Compared with Group 1 metals, transition metals usually have higher melting points and densities and are stronger and harder.
  • Transition metals are much less reactive with water, oxygen and halogens; for example, iron reacts far less vigorously with water than sodium.
  • A common error is to describe every transition metal as identical: these are general comparisons, illustrated using named examples rather than absolute rules for every element.

Tier 1 · Easy

3 marks
ORIGINAL

Give three ways in which iron typically differs from sodium in its physical or chemical properties.

Tier 2 · Standard

4 marks
ORIGINAL

A manufacturer needs a metal component that remains solid above 900 °C, resists deformation and does not react rapidly with water. Explain why nickel is a better choice than potassium.

Tier 3 · Hard

6 marks
ORIGINAL

Metal U melts at 98 °C, has low density, cuts easily and reacts violently with water. Metal V melts at 1495 °C, is dense and hard, and reacts slowly with oxygen when heated. Classify U and V, justify each classification, and name one specified transition element in V's class.

4.1.3.2

Typical properties (chemistry only)

  • Many transition elements form ions with different charges; iron, for example, forms Fe<sup>2+</sup> and Fe<sup>3+</sup> ions.
  • Many transition-metal compounds are coloured, so different ions or compounds can often be distinguished by their observed colours.
  • Transition elements and their compounds are often useful catalysts, increasing reaction rate without being used up overall.
  • A common error is to state that all transition-metal compounds have the same colour or that a catalyst supplies extra product; colours vary and a catalyst changes rate, not the final amount set by reactants.

Tier 1 · Easy

3 marks
ORIGINAL

State three typical chemical properties of transition elements or their compounds.

Tier 2 · Standard

4 marks
ORIGINAL

Iron forms pale-green FeCl<sub>2</sub> and yellow-brown FeCl<sub>3</sub>. Chloride ions have charge 1−. Determine the charge on iron in each compound and explain what the colours demonstrate.

Tier 3 · Hard

6 marks
ORIGINAL

Equal samples react under identical conditions. Without a catalyst the reaction takes 240 s; with an iron compound it takes 80 s; with a copper compound it takes 60 s. Select the more effective catalyst, calculate how many times faster its trial is than the uncatalysed trial using reciprocal time as rate, and explain two catalyst features.