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AQA GCSE Chemistry revision notes

Atomic structure and the periodic table

Section 4.1
15 specification points

Notes and three levels of exam-style practice for each registered specification point in this section.

Checked against AQA 8462 section 4.1

Checked against AQA 8462 section 4.1. Review basis: the qualification registry sourced from the AQA GCSE Chemistry (8462) specification; registry verification recorded 17 July 2026.

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4.1.1.1

Atoms, elements and compounds

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • All substances are made of atoms, and an atom is the smallest part of an element that can exist. Required chemical symbols include the first 20 elements, Groups 1 and 7, and other elements named in the specification.
  • Compounds form when elements react and become chemically combined in fixed proportions, so a formula records the elements and their ratio.
  • A compound has different properties from its constituent elements and can be separated into elements only by chemical reactions.
  • Exam questions require names, symbols and formulae to be distinguished, then specified reactions to be represented using word equations or balanced symbol equations.
  • Higher tier: write balanced half equations and ionic equations where appropriate.
Worked example

Classify oxygen, sodium chloride and air as an element, compound or mixture, giving one reason for each.

  1. 1.Oxygen contains only oxygen atoms, so it is an element.
  2. 2.Sodium chloride contains sodium and chlorine chemically combined in a fixed ratio, so it is a compound.
  3. 3.Air contains several gases not chemically combined, so it is a mixture.

Answer: Oxygen is an element, sodium chloride is a compound and air is a mixture.

Common mistakes

  • Don't call a compound a mixture because it contains more than one element, ignoring that its elements are chemically combined in fixed proportions.
  • Don't change a formula when balancing an equation, which changes the substance instead of changing the number of particles.

Exam tip

For a ‘state the difference’ question, contrast both chemical combination and the method of separation.

Tier 1 · Easy

ORIGINAL

A sealed jar contains only argon atoms. State whether its contents are an element, a compound or a mixture, and give one reason.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Magnesium burns in oxygen to form magnesium oxide. Write the word equation, then complete and balance the symbol equation Mg + O2 → MgO.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Molecule E has formula C2H6O\mathrm{C}_2\mathrm{H}_6\mathrm{O}. It reacts fully with oxygen to produce carbon dioxide and water. Balance C2H6O+O2CO2+H2O\mathrm{C}_2\mathrm{H}_6\mathrm{O}+\mathrm{O}_2\rightarrow\mathrm{CO}_2+\mathrm{H}_2\mathrm{O}, then explain why chemical products are not merely the starting materials mixed together.

[5 marks]

Total for this question: 5

Your progress and exam materials
4.1.1.2

Mixtures

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A mixture contains two or more elements or compounds that are not chemically combined, so each substance keeps its chemical properties and no new substance is formed.
  • Separation therefore uses physical properties.
  • Filter an insoluble solid from a liquid; crystallise a dissolved solid from solution; use simple distillation to recover a solvent; use fractional distillation for miscible liquids with different boiling points; and use chromatography when substances move differently because of their solubilities and attractions.
  • When asked to suggest a method, identify the relevant property and describe what is collected.
  • Examiners reward a linked explanation, not just the name of a technique.
Worked example

A mixture contains sand, salt and water. Describe how to obtain dry salt crystals.

  1. 1.Filter the mixture: insoluble sand remains as the residue and salt solution passes through.
  2. 2.Heat the filtrate to evaporate some water until the solution is concentrated.
  3. 3.Cool the solution so crystals form, then filter and dry the crystals.

Answer: Filter off the sand, crystallise the salt from the filtrate, then filter and dry the salt crystals.

Common mistakes

  • Don't use filtration to separate a dissolved solid, although dissolved particles pass through the filter paper.
  • Don't say fractional distillation separates liquids by density instead of by their different boiling points.
  • Don't evaporate a solution to complete dryness when the question asks for crystals.

Exam tip

In a method question, name the physical property that makes the chosen separation work.

Tier 1 · Easy

ORIGINAL

A beaker contains chalk powder suspended in water. Name the physical process that collects the chalk and identify what passes through the paper.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A student needs dry copper sulfate crystals from a copper sulfate solution. Describe a suitable sequence after the solution has been placed in an evaporating basin.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A liquid mixture contains propanone, which boils at 56 °C, water, which boils at 100 °C, and a dissolved non-volatile blue solid. Design a separation that obtains all three components.

[6 marks]

Total for this question: 6

4.1.1.3

The development of the model of the atom (common content with physics)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Atomic models changed when new experimental evidence could not be explained by the existing model. Atoms were first pictured as indivisible spheres.
  • Discovering the electron produced the plum pudding model: negative electrons embedded in a ball of positive charge. In alpha-particle scattering, most particles passed straight through, a few were deflected and very few rebounded.
  • This showed that the atom is mostly empty space and that nearly all its mass and positive charge are concentrated in a tiny nucleus, so the nuclear model replaced plum pudding.
  • Bohr then proposed electrons at specific distances; later work identified protons and Chadwick supplied evidence for neutrons.
  • Examiners expect evidence linked explicitly to each conclusion.
The sequence of atomic models from the solid sphere to electrons in shells around a nucleus.
Worked example

Most alpha particles passed through gold foil, but a very small number rebounded. Explain what each observation showed.

  1. 1.Most particles passing through showed that most of an atom is empty space.
  2. 2.Rare large deflections showed that positive charge is concentrated in a very small region.
  3. 3.Particles rebounding showed that this small nucleus is dense and contains most of the atom’s mass.

Answer: The observations support a mostly empty atom with a tiny, dense, positively charged nucleus.

Common mistakes

  • Don't claim that every alpha particle was deflected, instead of recognising that most passed through the mostly empty atom.
  • Don't say Rutherford’s scattering experiment discovered electrons, although it provided evidence for a small, charged nucleus.

Exam tip

For ‘explain why the model changed’, pair each observation with the conclusion it supports.

Tier 1 · Easy

ORIGINAL

Place these developments in chronological order: Chadwick's neutron evidence, the plum pudding model, Bohr's shells, the nuclear model.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

In an alpha-scattering trial, nearly every alpha particle crossed a thin metal sheet without changing direction, but a tiny proportion returned towards the source. Explain the conclusions about atomic structure.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Compare the plum pudding and nuclear models, then explain how scattering evidence and later discoveries produced the modern GCSE model of the atom.

[6 marks]

Total for this question: 6

4.1.1.4

Relative electrical charges of subatomic particles

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Protons have relative charge +1+1, neutrons have charge 00 and electrons have charge 1-1.
  • Protons and neutrons are in the nucleus; electrons occupy energy levels around it.
  • An atom has no overall electrical charge because it has equal numbers of protons and electrons, so the positive and negative charges cancel.
  • The atomic number is the number of protons, and it identifies the element: every atom of one element has the same proton number, while atoms of different elements have different proton numbers.
  • In questions, use the atomic number to find protons and, for a neutral atom, electrons; do not infer neutron number unless a mass number is also supplied.
Worked example

A neutral atom has atomic number 1313. State its numbers of protons and electrons and explain its overall charge.

  1. 1.Atomic number =13=13, so the nucleus contains 1313 protons.
  2. 2.A neutral atom has equal numbers of protons and electrons, so it has 1313 electrons.
  3. 3.The charges sum to 13(+1)+13(1)=013(+1)+13(-1)=0.

Answer: It has 1313 protons and 1313 electrons, giving no overall charge.

Common mistakes

  • Don't use the atomic number as the number of neutrons rather than the number of protons.
  • Don't give a neutral atom one more electron than proton, which would describe a negative ion.

Exam tip

When the particle is an atom, explicitly use ‘protons = electrons’ before concluding that its charge is zero.

Tier 1 · Easy

ORIGINAL

State the relative charge of a proton, a neutron and an electron.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

A particle contains 13 protons, 14 neutrons and 10 electrons. Determine its overall charge and explain whether it is an atom or an ion.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Species X has 26 protons, 30 neutrons and 23 electrons. Give its atomic number, mass number and ionic charge, then identify X using a periodic table.

[5 marks]

Total for this question: 5

4.1.1.5

Size and mass of atoms

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • An atom has a radius of about 0.1 nm0.1\ \mathrm{nm}, or 1×1010 m1\times10^{-10}\ \mathrm{m}. Its nucleus has a radius below one ten-thousandth of the atom’s radius, about 1×1014 m1\times10^{-14}\ \mathrm{m}, yet contains almost all the mass.
  • Protons and neutrons each have relative mass 11; an electron’s relative mass is very small.
  • The mass number is the total number of protons and neutrons, so neutron number equals mass number minus atomic number.
  • Isotopes are atoms of the same element with the same proton number but different neutron numbers.
  • Exam questions may require scale comparisons, particle-count calculations or an explanation of why isotopes remain the same element.
Worked example

An isotope is written as 1737Cl^{37}_{17}\mathrm{Cl}. Determine its numbers of protons, neutrons and electrons.

  1. 1.The lower number is the atomic number, so there are 1717 protons.
  2. 2.Neutrons =3717=20=37-17=20.
  3. 3.The symbol represents a neutral atom, so there are 1717 electrons.

Answer: 1717 protons, 2020 neutrons and 1717 electrons.

Common mistakes

  • Don't subtract the mass number from the atomic number and obtain a negative neutron count.
  • Don't define isotopes as having different proton numbers, which would make them different elements.

Exam tip

Write ‘neutrons = mass number − atomic number’ before substituting values.

Tier 1 · Easy

ORIGINAL

Convert an atomic radius of 0.12nm0.12\,\text{nm} into metres and write the result in standard form.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

An oxygen-18 atom has atomic number 8. Calculate its numbers of protons, neutrons and electrons, and state where almost all its mass is located.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

An atom has radius 9.0×1011m9.0\times10^{-11}\,\text{m} and its nucleus has radius 7.5×1015m7.5\times10^{-15}\,\text{m}. Calculate how many times larger the atomic radius is. A related ion has 26 protons, 30 neutrons and 24 electrons; write its nuclide symbol and charge.

[6 marks]

Total for this question: 6

4.1.1.6

Relative atomic mass

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Relative atomic mass, ArA_r, is the weighted mean mass of an atom of an element compared with one-twelfth of the mass of a carbon-12 atom.
  • It accounts for both the masses of the isotopes and their relative abundances, so the periodic-table value is often not a whole number.
  • Multiply each isotope mass by its abundance, add the products, then divide by the total abundance: Ar=(isotope mass×abundance)abundancesA_r=\dfrac{\sum(\text{isotope mass}\times\text{abundance})}{\sum\text{abundances}}.
  • Percentages total 100100, but ratios may have another total.
  • In an exam, show the complete weighted calculation because an unsupported rounded answer can lose method marks.
Worked example

A sample contains 72%72\% of isotope 63Cu^{63}\mathrm{Cu} and 28%28\% of isotope 65Cu^{65}\mathrm{Cu}. Calculate ArA_r.

  1. 1.Multiply each isotope mass by its percentage abundance: 63×7263\times72 and 65×2865\times28.
  2. 2.Add the weighted masses: 4536+1820=63564536+1820=6356.
  3. 3.Divide by the total percentage: Ar=6356÷100=63.56A_r=6356\div100=63.56.

Answer: Ar=63.56A_r=63.56.

Common mistakes

  • Don't take the simple mean of the isotope masses even though their abundances are unequal.
  • Don't divide by the number of isotopes instead of the total abundance.
  • Don't round the relative atomic mass to a whole number without being asked.

Exam tip

Keep the abundance products visible so the examiner can award the weighted-mean method mark.

Tier 1 · Easy

ORIGINAL

A sample of copper contains 69% copper-63 and 31% copper-65. Calculate its relative atomic mass.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Element Z has isotopes Z-24, Z-25 and Z-26. Their abundances are 79%, 10% and 11% respectively. Determine the relative atomic mass of Z.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

An element has only isotopes of mass 79 and 81. Its relative atomic mass is 79.90. Calculate the percentage abundance of the mass-79 isotope.

[4 marks]

Total for this question: 4

4.1.1.7

Electronic structure

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Electrons occupy the lowest available energy levels, also called shells. For the first 20 elements, use the simple filling pattern 2,8,8,22,8,8,2: fill an inner shell before starting the next.
  • Electronic structure may be written as numbers separated by commas or drawn as electrons on concentric shells.
  • For example, sodium has atomic number 1111, so a neutral atom has 1111 electrons and structure 2,8,12,8,1.
  • The number of occupied shells gives the period, while the outer-shell electron count explains the group and similar chemical properties of main-group elements.
  • Examiners expect the correct total and distribution, not merely the right number of shells.
A sodium atom with two electrons in the first shell, eight in the second and one in the third.
Worked example

Give the electronic structure and period of a neutral calcium atom, atomic number 2020.

  1. 1.A neutral calcium atom has 2020 electrons.
  2. 2.Fill the shells from the inside: 2,8,8,22,8,8,2.
  3. 3.Four shells are occupied, so calcium is in period 44.

Answer: Electronic structure 2,8,8,22,8,8,2; period 44.

Common mistakes

  • Don't place more than two electrons in the first shell.
  • Don't use the mass number rather than the atomic number to choose the total electrons in a neutral atom.

Exam tip

After drawing shells, add the electrons and check that the total equals the atomic number.

Tier 1 · Easy

ORIGINAL

Give the electronic structure of an aluminium atom, which has atomic number 13.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Calcium has atomic number 20. State the electronic structure of a calcium atom and of a Ca2+ ion.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Neutral atom X is one of the first 20 elements. It has three occupied shells and seven electrons in its outer shell. Identify X, give its atomic number and electronic structure, and state the structure after it gains one electron.

[5 marks]

Total for this question: 5

4.1.2.1

The periodic table

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • The modern periodic table arranges elements in increasing atomic, or proton, number. Similar properties recur at regular intervals, so elements with related chemical behaviour are placed in vertical columns called groups.
  • Main-group elements in the same group have the same number of outer-shell electrons, which explains their similar reactions.
  • The period indicates the number of occupied electron shells.
  • Use an electronic structure to locate an element, then use its position to predict likely reactions and reactivity.
  • The modern ordering is not by relative atomic mass: atomic number gives each element one unambiguous position and explains apparent mass-order anomalies caused by isotopes.
Worked example

An element has electronic structure 2,8,72,8,7. State its period and group and predict whether it has properties similar to fluorine.

  1. 1.Three occupied shells place the element in period 33.
  2. 2.Seven outer-shell electrons place it in Group 77.
  3. 3.Fluorine is also in Group 77, so the elements have similar chemical properties.

Answer: Period 33, Group 77; yes, it should have properties similar to fluorine.

Common mistakes

  • Don't state that the modern table is ordered by relative atomic mass rather than atomic number.
  • Don't use the total number of electrons as the group number instead of the outer-shell count.

Exam tip

For a prediction, cite the shared group or outer-electron arrangement before stating the similar property.

Tier 1 · Easy

ORIGINAL

An atom has electronic structure 2,8,2. Give its atomic number, period and group.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

Elements P and Q have electronic structures 2,1 and 2,8,1. Explain why they have similar chemical properties and identify which one has the larger atomic number.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Element R has atomic number 16 and element S has atomic number 19. Write both electronic structures, locate each by period and group, and predict which is more likely to form a positive ion.

[6 marks]

Total for this question: 6

4.1.2.2

Development of the periodic table

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Before subatomic particles were known, scientists tried to classify elements mainly in order of atomic weight. Early tables were incomplete, and keeping a strict weight order sometimes placed elements with different properties together.
  • Mendeleev prioritised repeating chemical properties: he left gaps for elements not yet discovered and changed the order in a few places.
  • Newly discovered elements filled those gaps and had properties close to his predictions, providing strong evidence for his arrangement.
  • Later knowledge of isotopes explained why atomic-weight order can appear inconsistent, while atomic number gives the correct modern sequence.
  • Examiners want a chronological account showing how predictions were tested by later evidence.
Worked example

Explain why the later discovery of an element with Mendeleev’s predicted properties supported his periodic table.

  1. 1.Mendeleev had left a gap because the repeating pattern suggested an undiscovered element.
  2. 2.He predicted properties for the element from neighbouring elements.
  3. 3.The discovered element fitted the gap and matched those predictions, so the table made a successful testable prediction.

Answer: The close match between prediction and later evidence supported Mendeleev’s arrangement.

Common mistakes

  • Don't say Mendeleev simply arranged every element in strict atomic-weight order, ignoring his deliberate gaps and reversals.
  • Don't claim Mendeleev used proton number, although protons had not yet been discovered.
  • Don't state that gaps weakened the table without explaining that accurate predictions later supported it.

Exam tip

In a history question, use the chain ‘prediction → discovery → matching properties → support’.

Tier 1 · Easy

ORIGINAL

Give two decisions Mendeleev made that improved the arrangement of the elements known in his time.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Mendeleev predicted that an empty position would be filled by an element forming an oxide X2O3. Years later, a new element was found and its oxide had that formula. Explain why this strengthened his periodic table.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Two elements have relative atomic masses 39.1 and 40.0. Their chemical properties place the 40.0 element before the 39.1 element in the modern table. Explain why this ordering troubled early tables, how Mendeleev could respond, and how later atomic theory resolved the issue.

[5 marks]

Total for this question: 5

4.1.2.3

Metals and non-metals

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Metals are elements that react to form positive ions; non-metals do not form positive ions. Most elements are metals, found mainly on the left and towards the bottom of the periodic table, while non-metals lie towards the right and top.
  • Typical metals conduct heat and electricity, are strong and malleable, and often have high melting points.
  • Solid non-metals are generally brittle and poor conductors, although the specification includes important structure-based exceptions such as graphite.
  • Link chemical behaviour to electron arrangement: metal atoms tend to lose outer electrons, while non-metal atoms tend to gain or share electrons.
  • In comparisons, state a property and then explain it using particles or electrons where requested.
Worked example

An element conducts electricity, is malleable and forms a 2+2+ ion. Decide whether it is a metal or non-metal.

  1. 1.Electrical conduction and malleability are characteristic metallic properties.
  2. 2.Forming a positive ion means the atom loses electrons, which is characteristic of a metal.
  3. 3.Both the physical and chemical evidence therefore support the same classification.

Answer: The element is a metal.

Common mistakes

  • Don't define a metal only as shiny, instead of using its formation of positive ions as the chemical distinction.
  • Don't claim every non-metal is a gas or every metal is magnetic.
  • Don't say metals gain electrons when explaining the formation of positive ions.

Exam tip

For ‘explain the difference’, pair a characteristic property with the relevant electron behaviour.

Tier 1 · Easy

ORIGINAL

Element T reacts by losing two electrons from each atom. Classify T as a metal or non-metal and state the charge on the ion formed.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Magnesium has electronic structure 2,8,2, while sulfur has 2,8,6. Use these structures and periodic-table positions to explain why magnesium is a metal but sulfur is a non-metal.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Unknown A is shiny, bends without snapping, conducts electricity and forms A3+. Unknown B is dull, breaks when hammered and does not conduct as a solid. Compare the evidence and predict where each lies in the periodic table.

[6 marks]

Total for this question: 6

4.1.2.4

Group 0

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Group 0 elements are the noble gases. Their atoms have stable outer-electron arrangements: eight outer electrons, except helium, whose only shell is complete with two.
  • This stability makes them very unreactive, so they do not easily form molecules and exist as single atoms.
  • Down the group, relative atomic mass increases and boiling point increases.
  • A data trend can be used to predict the boiling point or physical state of another noble gas, while recognising that a prediction is an estimate.
  • For explanation marks, low reactivity must be connected directly to the complete outer shell rather than merely describing noble gases as ‘stable’.
Worked example

Neon boils at 246C-246\,^{\circ}\mathrm{C} and argon at 186C-186\,^{\circ}\mathrm{C}. Predict whether krypton’s boiling point is above or below 186C-186\,^{\circ}\mathrm{C}.

  1. 1.Krypton is below argon in Group 00.
  2. 2.Boiling point increases down Group 00 as relative atomic mass increases.
  3. 3.Krypton should therefore boil at a temperature above 186C-186\,^{\circ}\mathrm{C}.

Answer: Krypton’s boiling point should be above 186C-186\,^{\circ}\mathrm{C}.

Common mistakes

  • Don't say helium needs eight outer electrons, although its first shell is complete with two.
  • Don't describe noble gases as diatomic molecules rather than single atoms.
  • Don't predict that boiling point decreases down Group 0, reversing the specified trend.

Exam tip

When explaining unreactivity, write ‘complete outer shell’ before stating that atoms do not readily react.

Tier 1 · Easy

ORIGINAL

Explain why neon is unreactive using its electronic structure 2,8.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

The boiling points of neon, argon and krypton are −246 °C, −186 °C and −153 °C. Choose the most plausible boiling point for xenon from −260 °C, −170 °C and −108 °C, and justify your choice.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

An unknown gas is monatomic, has electronic structure 2,8,8 and boils at a higher temperature than neon. Identify the gas and explain all three observations.

[5 marks]

Total for this question: 5

4.1.2.5

Group 1

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Group 1 elements are alkali metals with one electron in their outer shell. They react by losing this electron to form +1+1 ions, so their reactions are similar.
  • Lithium, sodium and potassium react with oxygen to form oxides, with chlorine to form chlorides, and with water to form a metal hydroxide plus hydrogen.
  • The water reactions become more vigorous down the group.
  • Reactivity increases because the outer electron is farther from the nucleus and experiences more shielding, so the attraction to the nucleus is weaker and the electron is lost more easily.
  • Examiners may ask for observations, products, balanced equations or a prediction for a lower element.
Worked example

Predict the products when potassium reacts with water and explain why potassium reacts more vigorously than lithium.

  1. 1.A Group 1 metal reacting with water forms the metal hydroxide and hydrogen.
  2. 2.The products are potassium hydroxide and hydrogen.
  3. 3.Potassium’s outer electron is farther from the nucleus and more shielded, so it is less strongly attracted and lost more easily.

Answer: Potassium hydroxide and hydrogen form; potassium is more reactive because its outer electron is lost more easily.

Common mistakes

  • Don't write metal oxide as the product of a Group 1 metal reacting with water.
  • Don't reverse the trend and say lithium is the most reactive of the first three alkali metals.
  • Don't explain the trend only by saying atoms are larger, without linking distance and shielding to weaker attraction.

Exam tip

A reactivity-trend explanation needs distance, shielding, nuclear attraction and ease of electron loss.

Tier 1 · Easy

ORIGINAL

Name the two products when sodium reacts with water, and state one visible observation.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

Complete and balance the equation Na + Cl2 → NaCl. Explain why sodium and potassium both form compounds with one metal atom for each chlorine atom.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A teacher compares lithium, sodium and potassium in water using equal-sized pieces. Predict the order from least to most vigorous, explain the trend using atomic structure, and predict how rubidium would behave.

[6 marks]

Total for this question: 6

4.1.2.6

Group 7

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Group 7 elements are halogens: non-metals whose atoms have seven outer-shell electrons. They exist as diatomic molecules such as Cl2\mathrm{Cl}_2, and form ionic halides with metals or covalent compounds with non-metals.
  • Down the group, relative molecular mass, melting point and boiling point increase, but reactivity decreases.
  • A halogen reacts by gaining one electron; farther down the group, the outer shell is farther from the nucleus and more shielded, so attracting an incoming electron is harder.
  • A more reactive halogen displaces a less reactive halogen from an aqueous halide solution.
  • Examiners expect correct trends, observations or equations and an electron-based explanation.
Worked example

Chlorine water is added to potassium bromide solution. Predict the products and explain whether a reaction occurs.

  1. 1.Chlorine is above bromine in Group 77, so chlorine is more reactive.
  2. 2.The more reactive chlorine displaces bromine from bromide ions.
  3. 3.The equation is Cl2+2KBr2KCl+Br2\mathrm{Cl}_2+2\mathrm{KBr}\rightarrow2\mathrm{KCl}+\mathrm{Br}_2.

Answer: Potassium chloride and bromine form because chlorine is more reactive than bromine.

Common mistakes

  • Don't say Group 7 reactivity increases down the group, confusing the trend with Group 1.
  • Don't write a halogen atom as a 1-1 ion before it has gained an electron.
  • Don't predict that iodine displaces chlorine from chloride solution.

Exam tip

For displacement, compare the two halogens’ positions before writing the products.

Tier 1 · Easy

ORIGINAL

State two features shared by chlorine, bromine and iodine atoms or molecules that explain their placement in Group 7.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Chlorine water is added to aqueous potassium bromide. Predict the products, write a balanced equation and explain why the reaction occurs.

[5 marks]

Total for this question: 5

Tier 3 · Hard

ORIGINAL

Bromine water is tested separately with sodium chloride and sodium iodide solutions. Predict each result, write any equation that occurs, and explain the different outcomes using the Group 7 reactivity trend.

[6 marks]

Total for this question: 6

4.1.3.1

Comparison with Group 1 elements (chemistry only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Transition elements are metals, including chromium, manganese, iron, cobalt, nickel and copper. Compared with Group 1 metals, they generally have higher melting points and densities and are stronger and harder.
  • They are also much less reactive with water, oxygen and halogens.
  • These differences make transition metals suitable where a material must keep its shape, withstand force or avoid rapid reaction, whereas Group 1 metals are soft and highly reactive.
  • Questions often provide unfamiliar data and require an element to be classified or compared.
  • Conclusions must use the data and stated general patterns, with a named transition element supporting broad statements when requested.
Worked example

Compare iron with sodium using density, hardness and reaction with water.

  1. 1.Iron, a transition metal, is generally denser than sodium, a Group 11 metal.
  2. 2.Iron is harder and stronger, while sodium is soft.
  3. 3.Iron is much less reactive with water than sodium.

Answer: Iron is denser, harder and much less reactive with water than sodium.

Common mistakes

  • Don't claim transition metals are more reactive than Group 1 metals because they are stronger.
  • Don't use sodium or potassium as an example of a transition element.
  • Don't treat every transition metal as having exactly the same melting point, density and reactivity.

Exam tip

In a comparison, use paired language such as ‘higher density but lower reactivity than Group 1’.

Tier 1 · Easy

ORIGINAL

Give three ways in which iron typically differs from sodium in its physical or chemical properties.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

A manufacturer needs a metal component that remains solid above 900 °C, resists deformation and does not react rapidly with water. Explain why nickel is a better choice than potassium.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Metal U melts at 98 °C, has low density, cuts easily and reacts violently with water. Metal V melts at 1495 °C, is dense and hard, and reacts slowly with oxygen when heated. Classify U and V, justify each classification, and name one specified transition element in V's class.

[6 marks]

Total for this question: 6

4.1.3.2

Typical properties (chemistry only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Transition elements show characteristic chemical properties as well as typical metallic ones. Many form ions with different charges, form coloured compounds and are useful catalysts.
  • For example, iron can form Fe2+\mathrm{Fe}^{2+} and Fe3+\mathrm{Fe}^{3+} ions, and iron is the catalyst in the Haber process.
  • Compounds of chromium, manganese, iron, cobalt, nickel and copper provide examples of coloured transition-metal compounds.
  • A catalyst increases reaction rate without being used up overall; being coloured does not itself make a compound a catalyst.
  • In exams, identify the property shown by information in the question and give a named example rather than assuming every transition element shows every property in the same way.
Worked example

Iron forms FeCl2\mathrm{FeCl}_2 and FeCl3\mathrm{FeCl}_3. State the transition-metal property shown and give one other typical property.

  1. 1.Chloride ions have charge 1-1, so the formulae contain iron ions with different charges.
  2. 2.The compounds therefore show that iron forms ions with different charges.
  3. 3.Another typical property is forming coloured compounds or acting as a catalyst.

Answer: Iron forms ions with different charges; transition elements also form coloured compounds or act as catalysts.

Common mistakes

  • Don't say transition elements form only one ion charge, overlooking variable-charge ions such as Fe2+\mathrm{Fe}^{2+} and Fe3+\mathrm{Fe}^{3+}.
  • Don't define a catalyst as a substance that is used up to provide energy.
  • Don't assume any coloured compound must be acting as a catalyst.

Exam tip

When asked for a typical property, state it precisely and attach it to a named transition element or compound.

Tier 1 · Easy

ORIGINAL

State three typical chemical properties of transition elements or their compounds.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

Iron forms pale-green FeCl2 and yellow-brown FeCl3. Chloride ions have charge 1−. Determine the charge on iron in each compound and explain what the colours demonstrate.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Equal samples react under identical conditions. Without a catalyst the reaction takes 240 s; with an iron compound it takes 80 s; with a copper compound it takes 60 s. Choose the more effective catalyst, calculate how many times faster its trial is than the uncatalysed trial using reciprocal time as rate, and explain two catalyst features.

[6 marks]

Total for this question: 6

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