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All equation deep-dives

Specific heat capacity

Energy
AQA 8463
On the equation sheet
ORIGINAL

dE = m c d(theta)

The temperature CHANGE trips everyone — d(theta) is the difference, not the final temperature.

Current GCSE 8463 policy: The full AQA GCSE Physics 8463 equation sheet is provided with both papers in 2026; use fluency practice to learn selection and rearrangement, not to memorise the list.

Board and spec code confirmed against AQA 8463 · registry checked 2026-07-17How this checking works

Know the equation

SymbolQuantityUnit
dEchange in thermal energyJ
mmasskg
cspecific heat capacityJ/kg C
d(theta)temperature changeC

Rearrangements

  • c = dE / (m d(theta))
  • d(theta) = dE / (m c)
  • m = dE / (c d(theta))

Apply it — mark your own working

Work each one out on paper first, then reveal the mark scheme and tick the marks you actually earned. That is exactly how you should mark past papers.

Q1

0.50 kg of water is heated from 20 C to 80 C. The specific heat capacity of water is 4200 J/kg C. Calculate the energy transferred to the water.

[3 marks]

Total for this question: 3

Do the calculation on paper first — then mark it.

Q2

A 2.0 kg metal block is given 23 000 J of energy and its temperature rises by 25 C. Calculate the specific heat capacity of the metal.

[3 marks]

Total for this question: 3

Do the calculation on paper first — then mark it.

Where the marks get lost

  • Putting the final temperature into d(theta) instead of the temperature change (here 60, not 80).
  • Forgetting the mass must be in kg.
  • When rearranging for c, dividing by only m or only d(theta) instead of by both (m x d(theta)).

Exam tip: Work out d(theta) as a separate first line and label it. That single step earns a mark and stops the whole calculation going wrong.

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