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Solving a quadratic inequality

Algebra
(1MA1) · Higher
ORIGINAL

Solve the equation, sketch the parabola, then read the region — the sketch is what stops sign errors.

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Question

1

Solve x2−x−6>0x^2 - x - 6 > 0.

Every step worked, with the reasoning.

  1. 1
    x2−x−6=0x^2 - x - 6 = 0

    Solve the equation first to find the critical values.

  2. 2
    (x−3)(x+2)=0(x - 3)(x + 2) = 0

    Factorise.

  3. 3
    x=3x = 3 or x=−2x = -2

    The critical values — where the curve crosses the xx-axis.

  4. 4
    Sketch: a ∪\cup-shaped parabola with roots at −2-2 and 33; we want where it is >0> 0 (above the axis).

    A positive x2x^2 coefficient means the curve is above the axis OUTSIDE the roots.

  5. 5
    x<−2x < -2 or x>3x > 3

    Read off the two regions where the curve is above the xx-axis.

Answer: x<−2x < -2 or x>3x > 3

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