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Circle theorems with algebra

Circle theorems
(1MA1) · Higher
ORIGINAL

Link same-segment angles, a diameter, and a triangle angle sum in one algebraic chain.

Board and spec code confirmed against Edexcel 1MA1 · registry checked 2026-07-09How this checking works

Question

1

Points AA, BB, CC and DD lie on a circle. ABAB is a diameter, and AA and DD lie in the same segment cut off by chord BCBC. Angle BAC=(3x+4)∘BAC=(3x+4)^\circ and angle BDC=(5x−10)∘BDC=(5x-10)^\circ. Find xx and angle ABCABC.

Every step worked, with the reasoning.

  1. 1
    (3x+4)∘=(5x−10)∘(3x+4)^\circ=(5x-10)^\circ

    Angles BACBAC and BDCBDC subtend the same chord BCBC in the same segment, so they are equal.

  2. 2
    14=2x14=2x, so x=7x=7

    Rearrange and solve the linear equation.

  3. 3
    ∠BAC=3(7)+4=25∘\angle BAC=3(7)+4=25^\circ

    Substitute x=7x=7 into either given angle.

  4. 4
    ∠ACB=90∘\angle ACB=90^\circ

    The angle subtended by diameter ABAB at the circumference is a right angle.

  5. 5
    ∠ABC=180∘−90∘−25∘=65∘\angle ABC=180^\circ-90^\circ-25^\circ=65^\circ

    Angles in triangle ABCABC sum to 180∘180^\circ.

Answer: x=7x=7 and ∠ABC=65∘\angle ABC=65^\circ.

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