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Points , , and lie on a circle. is a diameter, and and lie in the same segment cut off by chord . Angle and angle . Find and angle .
Link same-segment angles, a diameter, and a triangle angle sum in one algebraic chain.
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Every step worked, with the reasoning.
Angles and subtend the same chord in the same segment, so they are equal.
Rearrange and solve the linear equation.
Substitute into either given angle.
The angle subtended by diameter at the circumference is a right angle.
Angles in triangle sum to .
Answer: and .
Everything here stays free. If circle theorems with algebra is where the marks keep going, I teach it one to one from the mark schemes. Free intro call, then a free first lesson.