AQA 8365 formula sheet & recall

June 2026

AQA

AQA provides the June 2026 8365 formula sheet with both papers; some additional mensuration formulae are printed in the relevant question. Paper 1 is non-calculator; a calculator is allowed for Paper 2.

AQA Level 2 Certificate in Further Mathematics (8365) · 2026. AQA provides the June 2026 8365 formula sheet with both papers; some additional mensuration formulae are printed in the relevant question. Paper 1 is non-calculator; a calculator is allowed for Paper 2.

Provided in the exam — do not spend revision time memorising these

On the June 2026 formulae sheet

Area of a trapezium Provided in the exam	$A=\dfrac{1}{2}(a+b)h$
Volume of a prism Provided in the exam	$V=\text{area of cross-section}\times\text{length}$
Circumference of a circle Provided in the exam	$C=\pi d=2\pi r$
Area of a circle Provided in the exam	$A=\pi r^2$
Quadratic formula Provided in the exam	$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$
Pythagoras' theorem Provided in the exam	$a^2+b^2=c^2$
Right-angled trigonometry Provided in the exam	$\sin\theta=\dfrac{O}{H},\quad \cos\theta=\dfrac{A}{H},\quad \tan\theta=\dfrac{O}{A}$
Sine rule Provided in the exam	$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$
Cosine rule Provided in the exam	$a^2=b^2+c^2-2bc\cos A$
Area of a triangle Provided in the exam	$A=\dfrac{1}{2}ab\sin C$
Tangent identity Provided in the exam	$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$
Pythagorean identity Provided in the exam	$\sin^2\theta+\cos^2\theta=1$
Equation of a straight line Provided in the exam	$y-y_1=m(x-x_1)$
Equation of a circle Provided in the exam	$(x-a)^2+(y-b)^2=r^2$

Provided in the relevant question when needed

These formulae are printed in the question that needs them; they are not on the formula sheet or in the booklet.

Supplied in the relevant question when needed

Curved surface area of a cone Provided in the relevant question	$A=\pi rl$
Surface area of a sphere Provided in the relevant question	$A=4\pi r^2$
Volume of a sphere Provided in the relevant question	$V=\dfrac{4}{3}\pi r^3$
Volume of a cone or pyramid Provided in the relevant question	$V=\dfrac{1}{3}\times\text{area of base}\times\text{perpendicular height}$

Not provided — know these

Expected knowledge not on the June 2026 sheet

Curved surface area of a cylinder Recall	$A=2\pi rh$
Volume of a cylinder Recall	$V=\pi r^2h$

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