AQA A-level Physics coverage

Astrophysics (A-level only)

Section 3.9
14 spec leafs
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Notes and three levels of exam-style practice for each registered specification leaf in this section.

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3.9.1.1

Astronomical telescope consisting of two converging lenses

  • In normal adjustment the objective forms a real intermediate image at the eyepiece focal plane, so the final image is virtual and at infinity; the lens separation is fo+fef_o+f_e.
  • The magnitude of the angular magnification is M=angle at the eye through the telescopeangle at the unaided eye=fofeM=\dfrac{\text{angle at the eye through the telescope}}{\text{angle at the unaided eye}}=\dfrac{f_o}{f_e}.
  • A ray diagram should show parallel incident rays, an inverted intermediate image, and parallel emergent rays; mark both principal foci and use ruled rays.
  • Keep fof_o and fef_e in the same units. A common error is to use image-height magnification or to subtract the focal lengths in normal adjustment.

Tier 1 · Easy

1 mark
ORIGINAL

An astronomical telescope in normal adjustment has objective focal length 1.20m1.20\,\text{m} and eyepiece focal length 30.0mm30.0\,\text{mm}. Calculate the magnitude of its angular magnification.

Tier 2 · Standard

3 marks
ORIGINAL

A distant crater subtends 2.0×104rad2.0\times10^{-4}\,\text{rad} at the unaided eye. It is viewed through a normal-adjustment telescope with fo=1.500mf_o=1.500\,\text{m} and fe=25.0mmf_e=25.0\,\text{mm}. Determine the angle subtended at the eye and the lens separation.

Tier 3 · Hard

5 marks
ORIGINAL

A telescope is to make an object that subtends 1.50×104rad1.50\times10^{-4}\,\text{rad} appear to subtend at least 4.80×103rad4.80\times10^{-3}\,\text{rad}. The objective focal length is 0.960m0.960\,\text{m}. Determine the greatest acceptable eyepiece focal length and the corresponding maximum telescope length in normal adjustment.

3.9.1.2

Reflecting telescopes

  • A Cassegrain telescope uses a parabolic concave primary mirror and a convex secondary mirror; the secondary returns converging rays through a central hole in the primary to the eyepiece.
  • Reflection is independent of wavelength, so mirrors do not produce chromatic aberration. A spherical mirror can produce spherical aberration, whereas an on-axis parabolic primary brings parallel rays to one focus.
  • A large mirror can be supported from behind and can be made thinner than a comparable objective lens, so large-aperture reflectors are more practical than refractors.
  • In a ray diagram, show the primary and secondary reflections before the eyepiece. Do not draw rays passing through the secondary as if it were a lens.

Tier 1 · Easy

1 mark
ORIGINAL

State one aberration that a reflecting telescope avoids because its primary element is a mirror rather than a lens.

Tier 2 · Standard

3 marks
ORIGINAL

Describe the path of initially parallel rays through a Cassegrain reflecting telescope up to the eyepiece.

Tier 3 · Hard

5 marks
ORIGINAL

A research group must choose between a large refracting telescope and a Cassegrain reflector of the same aperture. Discuss why the reflector is usually preferred, including aberrations and construction.

3.9.1.3

Single dish radio telescopes, I-R, U-V and X-ray telescopes

  • A single-dish radio telescope uses a concave reflecting surface to direct radio waves to a receiver near the focus; as with an optical telescope, collecting power grows as D2D^2, so a large dish gathers more of a weak signal.
  • Because radio wavelengths are much longer than visible wavelengths, a radio dish needs a much larger diameter for comparable angular resolution through θλ/D\theta\approx\lambda/D.
  • Infrared observatories favour high, dry sites and cooled detectors; most ultraviolet and X-ray astronomy must be carried out above the atmosphere because those bands are strongly absorbed.
  • Radio observations can be made from the ground and through cloud, but human-made radio interference matters. Do not claim that every non-visible telescope can operate at sea level or uses a glass lens.

Tier 1 · Easy

1 mark
ORIGINAL

State why most X-ray telescopes used for astronomy are placed on satellites.

Tier 2 · Standard

3 marks
ORIGINAL

An optical telescope of diameter 0.200m0.200\,\text{m} observes at 550nm550\,\text{nm}. Estimate the diameter of a radio dish observing at 0.210m0.210\,\text{m} that would have the same Rayleigh angular resolution.

Tier 3 · Hard

6 marks
ORIGINAL

Discuss suitable observing locations for radio, infrared, ultraviolet and X-ray astronomy, and explain why a radio dish generally has a much larger diameter than an optical telescope.

3.9.1.4

Advantages of large diameter telescopes

  • The Rayleigh criterion gives the minimum resolvable angle θλ/D\theta\approx\lambda/D in radians, so increasing diameter improves angular resolution at fixed wavelength.
  • Collecting power is proportional to D2D^2; a larger aperture gathers more energy per unit time and makes faint sources easier to detect.
  • A CCD generally has higher quantum efficiency than the eye, can integrate and store an exposure, and gives a permanent electronic record; small CCD pixels can improve detector resolution, although the aperture still sets the diffraction limit.
  • State ratios carefully: doubling DD halves the diffraction-limited angle but multiplies collecting power by four. Do not claim that collecting power is proportional to DD.

Tier 1 · Easy

1 mark
ORIGINAL

A telescope aperture is increased from 0.30m0.30\,\text{m} to 0.60m0.60\,\text{m}. Determine the factor by which its collecting power increases.

Tier 2 · Standard

3 marks
ORIGINAL

Calculate the Rayleigh minimum angular resolution of a 2.50m2.50\,\text{m} telescope at wavelength 500nm500\,\text{nm}. State the effect of increasing the diameter.

Tier 3 · Hard

6 marks
ORIGINAL

Two telescopes have diameters 4.00m4.00\,\text{m} and 10.0m10.0\,\text{m} and observe at 600nm600\,\text{nm}. A pair of faint stars is separated by 8.0×108rad8.0\times10^{-8}\,\text{rad}. Determine which telescope can resolve the pair, compare their collecting powers, and explain one advantage of recording with a CCD rather than the eye.

3.9.2.1

Classification by luminosity

  • Apparent magnitude mm is the brightness scale of Hipparchus as seen from Earth; smaller and more negative magnitudes mean brighter objects.
  • A difference of one magnitude corresponds to an intensity ratio of 2.512.51, so a difference Δm\Delta m corresponds to 2.51Δm2.51^{\Delta m} in the opposite brightness direction.
  • Under dark conditions the dimmest stars visible to the unaided eye have apparent magnitude about +6+6.
  • Brightness on this scale is subjective and logarithmic. A common error is to say that a magnitude-55 star is brighter than a magnitude-22 star because 5>25>2.

Tier 1 · Easy

1 mark
ORIGINAL

Two stars have apparent magnitudes +1.0+1.0 and +4.0+4.0. State which appears brighter.

Tier 2 · Standard

3 marks
ORIGINAL

Star P has apparent magnitude 2.002.00 and star Q has apparent magnitude 5.005.00. Calculate the ratio IP/IQI_P/I_Q.

Tier 3 · Hard

5 marks
ORIGINAL

Interstellar dust reduces the received intensity from a star by a factor of 20.020.0. Before the dimming, its apparent magnitude was 2.002.00. Determine its new apparent magnitude and whether it should remain visible to the unaided eye under dark conditions.

3.9.2.2

Absolute magnitude, M

  • Absolute magnitude MM is the apparent magnitude a star would have at a distance of 10pc10\,\text{pc}, so it compares intrinsic luminosities on the magnitude scale.
  • For distance dd in parsecs, mM=5log(d/10)m-M=5\log\left(d/10\right). Rearrange before substituting and use base-10 logarithms.
  • One parsec is about 3.263.26 light years. A parsec is a distance, not a time, and the distance-modulus equation does not take dd in metres.
  • A more negative MM means a greater intrinsic luminosity. Do not infer intrinsic power from mm alone because distance also affects apparent brightness.

Tier 1 · Easy

1 mark
ORIGINAL

A star is exactly 10pc10\,\text{pc} from Earth and has apparent magnitude 4.34.3. State its absolute magnitude.

Tier 2 · Standard

3 marks
ORIGINAL

A star has apparent magnitude 8.48.4 and absolute magnitude 3.43.4. Calculate its distance from Earth in parsecs.

Tier 3 · Hard

5 marks
ORIGINAL

A supergiant has apparent magnitude 12.012.0 and absolute magnitude 1.0-1.0. Determine its distance in parsecs and in light years. Use 1pc=3.26ly1\,\text{pc}=3.26\,\text{ly}.

3.9.2.3

Classification by temperature, black-body radiation

  • Treating a star as a black body, Wien's law λmaxT=2.9×103m K\lambda_{\max}T=2.9\times10^{-3}\,\text{m K} estimates its surface temperature from the peak wavelength.
  • Stefan's law is P=σAT4P=\sigma AT^4; for a spherical star A=4πR2A=4\pi R^2, so comparisons use PR2T4P\propto R^2T^4.
  • For isotropic radiation with negligible absorption, the received intensity follows I=P/(4πd2)I=P/(4\pi d^2). State these assumptions when applying the inverse-square law.
  • A hotter black-body curve peaks at a shorter wavelength and has greater area. Convert nanometres to metres and use kelvin, not degrees Celsius.

Tier 1 · Easy

2 marks
ORIGINAL

The black-body spectrum of a star peaks at 580nm580\,\text{nm}. Estimate its surface temperature using Wien's law.

Tier 2 · Standard

3 marks
ORIGINAL

Star B has twice the radius of star A but 0.8000.800 times its surface temperature. Using Stefan's law, calculate PB/PAP_B/P_A.

Tier 3 · Hard

6 marks
ORIGINAL

A star 50.0pc50.0\,\text{pc} away produces an intensity of 3.20×1010W m23.20\times10^{-10}\,\text{W m}^{-2} at Earth and has peak wavelength 480nm480\,\text{nm}. Assuming isotropic emission and black-body behaviour, determine its surface temperature and radius. Use 1pc=3.086×1016m1\,\text{pc}=3.086\times10^{16}\,\text{m} and σ=5.67×108W m2K4\sigma=5.67\times10^{-8}\,\text{W m}^{-2}\text{K}^{-4}.

3.9.2.4

Principles of the use of stellar spectral classes

  • The sequence OBAFGKM runs from hottest to coolest; intrinsic colours are O/B blue, A blue-white, F white, G yellow-white, K orange and M red.
  • Temperature ranges are O 2500025000-50000K50000\,\text{K}, B 1100011000-25000K25000\,\text{K}, A 75007500-11000K11000\,\text{K}, F 60006000-7500K7500\,\text{K}, G 50005000-6000K6000\,\text{K}, K 35003500-5000K5000\,\text{K} and M below 3500K3500\,\text{K}.
  • Prominent absorption features progress from He+\text{He}^+, He and H in O stars; He and H in B; strongest H plus ionised metals in A; ionised metals in F; ionised and neutral metals in G; neutral metals in K; and neutral atoms plus TiO in M.
  • Hydrogen Balmer absorption requires hydrogen atoms in the n=2n=2 state and is strongest in class A: cooler stars have too few excited atoms, while hotter stars have much of their hydrogen ionised.
  • Line strength does not directly measure elemental abundance. Do not conclude that a weak Balmer line means that the star contains little hydrogen.

Tier 1 · Easy

1 mark
ORIGINAL

Three stars have spectral classes B, G and M. State which has the highest surface temperature.

Tier 2 · Standard

3 marks
ORIGINAL

A star's continuous spectrum peaks at 410nm410\,\text{nm}. Estimate its temperature and hence identify its most likely spectral class. Use Wien's constant 2.9×103m K2.9\times10^{-3}\,\text{m K}.

Tier 3 · Hard

5 marks
ORIGINAL

Explain why hydrogen Balmer absorption lines can be weak in both a very hot class O star and a cool class M star but strongest in a class A star.

3.9.2.5

The Hertzsprung-Russell (HR) diagram

  • An HR diagram plots absolute magnitude vertically, usually from about 10-10 at the top to +15+15 at the bottom, against temperature decreasing left to right from about 50000K50000\,\text{K} to 2500K2500\,\text{K} or classes OBAFGKM.
  • The main sequence runs from hot, luminous upper-left stars to cool, faint lower-right stars; giants lie mainly upper right and white dwarfs lower left.
  • The Sun is a class G main-sequence star with surface temperature about 5800K5800\,\text{K} and absolute magnitude about +5+5.
  • A Sun-like star moves from formation to the main sequence, then to the red-giant region and finally to the white-dwarf region. Do not reverse the temperature axis or put white dwarfs among cool faint stars.

Tier 1 · Easy

2 marks
ORIGINAL

State the region of an HR diagram occupied by the Sun and give its approximate spectral class.

Tier 2 · Standard

3 marks
ORIGINAL

A star has surface temperature 12000K12000\,\text{K} and absolute magnitude +12+12. Deduce its region on an HR diagram and justify your answer.

Tier 3 · Hard

5 marks
ORIGINAL

Describe the path of a star with a mass similar to the Sun on an HR diagram from formation until its white-dwarf stage. Refer to changes in temperature and absolute magnitude where appropriate.

3.9.2.6

Supernovae, neutron stars and black holes

  • A typical type Ia supernova light curve rises steeply to about M=18M=-18 to 20-20 and then declines more slowly; this standardisable peak makes type Ia supernovae useful standard candles.
  • Neutron stars are extremely dense compact remnants composed mainly of neutrons. Collapse of a supergiant to a neutron star or black hole can produce a gamma-ray burst with enormous energy output.
  • For a black hole the escape velocity exceeds cc inside the event horizon; its Schwarzschild radius is Rs2GM/c2R_s\approx2GM/c^2. Supermassive black holes occur at galactic centres.
  • Type Ia distances helped reveal an accelerating Universe and motivate dark energy. Keep the observation separate from the interpretation, and do not describe absolute magnitude as a physical power unit.

Tier 1 · Easy

2 marks
ORIGINAL

A newly identified black hole has mass 5.20×1030kg5.20\times10^{30}\,\text{kg}. Determine its event-horizon radius using G=6.67×1011N m2kg2G=6.67\times10^{-11}\,\text{N m}^2\text{kg}^{-2} and c=3.00×108m s1c=3.00\times10^8\,\text{m s}^{-1}.

Tier 2 · Standard

4 marks
ORIGINAL

A type Ia supernova has absolute magnitude 19.5-19.5 and peak apparent magnitude 18.518.5. Use the distance modulus to estimate its distance in parsecs.

Tier 3 · Hard

6 marks
ORIGINAL

The collapse of a supergiant produces a gamma-ray burst of energy 4.0×1044J4.0\times10^{44}\,\text{J} and leaves a compact object of mass 6.0×1030kg6.0\times10^{30}\,\text{kg}. Calculate the object's Schwarzschild radius and the time for the Sun, at constant power 3.8×1026W3.8\times10^{26}\,\text{W}, to emit the burst energy. Give the time in years and use G=6.67×1011N m2kg2G=6.67\times10^{-11}\,\text{N m}^2\text{kg}^{-2}, c=3.00×108m s1c=3.00\times10^8\,\text{m s}^{-1} and 1year=3.156×107s1\,\text{year}=3.156\times10^7\,\text{s}.

3.9.3.1

Doppler effect

  • For speeds much smaller than cc, the fractional wavelength shift is z=Δλ/λv/cz=\Delta\lambda/\lambda\approx v/c in magnitude; a positive redshift means recession when vv is taken as the recession speed.
  • For frequency, Δf/f=v/c\Delta f/f=-v/c with the same recession-positive convention, so a receding source has a lower observed frequency.
  • In an edge-on binary system, each star's spectral lines shift periodically between red and blue as its radial velocity reverses; the shift is zero when its motion is transverse to the line of sight.
  • Use the unshifted laboratory wavelength or frequency in the denominator and check that vcv\ll c. Do not use the non-relativistic approximation for a large redshift without qualification.

Tier 1 · Easy

2 marks
ORIGINAL

A spectral line of laboratory wavelength 500.00nm500.00\,\text{nm} is observed at 500.40nm500.40\,\text{nm}. Calculate the redshift zz.

Tier 2 · Standard

3 marks
ORIGINAL

Radiation emitted at 1.42000GHz1.42000\,\text{GHz} is received from a gas cloud at 1.41900GHz1.41900\,\text{GHz}. Determine the cloud's radial speed and state whether it is approaching or receding. Use c=3.00×108m s1c=3.00\times10^8\,\text{m s}^{-1}.

Tier 3 · Hard

6 marks
ORIGINAL

In an equal-mass binary system viewed in the plane of its circular orbit, a line of rest wavelength 656.300nm656.300\,\text{nm} alternates between 656.000nm656.000\,\text{nm} and 656.600nm656.600\,\text{nm} for one star. The orbital period is 8.00days8.00\,\text{days}. Estimate the speed of that star, its orbital radius about the centre of mass, and the separation of the stars. Use c=3.00×108m s1c=3.00\times10^8\,\text{m s}^{-1}.

3.9.3.2

Hubble's law

  • Hubble's law is v=Hdv=Hd: on large scales, a galaxy's recession speed is proportional to its distance, which is interpreted as expansion of the Universe.
  • If HH has remained constant, the age estimate is t1/Ht\approx1/H. Convert km s1Mpc1\text{km s}^{-1}\text{Mpc}^{-1} into s1\text{s}^{-1} before taking the reciprocal.
  • The Big Bang model is supported by all-sky microwave background radiation, interpreted as relic radiation redshifted and cooled by expansion, and by the roughly 3:13:1 hydrogen-to-helium mass ratio produced by early fusion before the Universe cooled.
  • Nearby peculiar velocities can obscure the Hubble trend, and the constant-HH age is an estimate rather than an exact history. Keep distance units consistent with those used for HH.

Tier 1 · Easy

1 mark
ORIGINAL

Use H=70km s1Mpc1H=70\,\text{km s}^{-1}\text{Mpc}^{-1} to calculate the recession speed of a galaxy 120Mpc120\,\text{Mpc} away.

Tier 2 · Standard

4 marks
ORIGINAL

Estimate the age of the Universe for H=68.0km s1Mpc1H=68.0\,\text{km s}^{-1}\text{Mpc}^{-1}. Assume HH is constant and use 1Mpc=3.086×1022m1\,\text{Mpc}=3.086\times10^{22}\,\text{m} and 1year=3.156×107s1\,\text{year}=3.156\times10^7\,\text{s}.

Tier 3 · Hard

6 marks
ORIGINAL

A galaxy's hydrogen line has laboratory wavelength 486.10nm486.10\,\text{nm} and is observed at 493.40nm493.40\,\text{nm}. Use the non-relativistic Doppler approximation and H=70.0km s1Mpc1H=70.0\,\text{km s}^{-1}\text{Mpc}^{-1} to estimate the galaxy's distance. Check whether vcv\ll c, taking c=3.00×105km s1c=3.00\times10^5\,\text{km s}^{-1}.

3.9.3.3

Quasars

  • Quasars were discovered as bright radio sources and have very large optical redshifts, placing them among the most distant measurable objects.
  • Their enormous power output is produced by matter accreting onto an active supermassive black hole, not by an unusually luminous ordinary star.
  • For modest redshift, use vzcv\approx zc and d=v/Hd=v/H; if the received flux is FF and emission is isotropic, estimate power with P=4πd2FP=4\pi d^2F.
  • State the isotropic-emission and low-redshift assumptions. A common error is to compare flux at Earth directly with luminosity without allowing for inverse-square spreading.

Tier 1 · Easy

1 mark
ORIGINAL

State the central engine believed to power a quasar.

Tier 2 · Standard

3 marks
ORIGINAL

A quasar at distance 900Mpc900\,\text{Mpc} produces a flux of 2.5×1015W m22.5\times10^{-15}\,\text{W m}^{-2} at Earth. Estimate its power output assuming isotropic emission. Use 1Mpc=3.086×1022m1\,\text{Mpc}=3.086\times10^{22}\,\text{m}.

Tier 3 · Hard

6 marks
ORIGINAL

A low-redshift quasar has z=0.0200z=0.0200 and measured flux 1.60×1013W m21.60\times10^{-13}\,\text{W m}^{-2}. Estimate its distance, power output and power in units of the Sun's luminosity. Use c=3.00×105km s1c=3.00\times10^5\,\text{km s}^{-1}, H=70.0km s1Mpc1H=70.0\,\text{km s}^{-1}\text{Mpc}^{-1}, 1Mpc=3.086×1022m1\,\text{Mpc}=3.086\times10^{22}\,\text{m} and L=3.83×1026WL_{\odot}=3.83\times10^{26}\,\text{W}. Assume isotropic emission.

3.9.3.4

Detection of exoplanets

  • Direct detection is difficult because a planet is faint compared with its host star and has a very small angular separation from it.
  • The radial-velocity method detects periodic red and blue Doppler shifts in the star's spectral lines as the star orbits the system's centre of mass.
  • The transit method detects a repeated decrease in stellar brightness when an aligned planet crosses the stellar disc; approximately, transit depth ΔI/I=(Rp/R)2\Delta I/I=(R_p/R_*)^2.
  • A transit light curve has a steady baseline, a fall, a nearly flat or curved minimum, and a rise, repeated once per orbit. Transits require favourable alignment, while radial velocity measures only line-of-sight motion.

Tier 1 · Easy

1 mark
ORIGINAL

A star's brightness shows equal, regularly repeated dips. Name the exoplanet-detection method indicated by this observation.

Tier 2 · Standard

3 marks
ORIGINAL

During a transit, a star's detected intensity falls by 0.810%0.810\%. Estimate the radius of the planet if the star's radius is 6.90×108m6.90\times10^8\,\text{m}.

Tier 3 · Hard

6 marks
ORIGINAL

A star has radius 8.0×108m8.0\times10^8\,\text{m}. Every 5.2days5.2\,\text{days} its intensity falls by 0.160%0.160\%, while a 600.0nm600.0\,\text{nm} absorption line shifts with the same period by up to 0.014nm0.014\,\text{nm} to either side of its mean. Calculate the planet's radius and the star's maximum radial speed, then explain why the combined observations are stronger evidence for an exoplanet than either observation alone. Use c=3.00×108m s1c=3.00\times10^8\,\text{m s}^{-1}.