Maths

Moments

Edexcel Mech 9

A-level Maths (9MA0) · exam-style practice, examiner-report intelligence and the tools that drill it.

Verified against Edexcel 9MA0 (2026 spec)

The topic on one screen

  • The moment of a force about a point is F×dF\times d, where dd is the perpendicular distance from the point to the force's line of action. Its unit is N m\text{N m}.
  • For a rigid body in equilibrium, the resultant force is zero and the resultant moment about any point is zero. Force equilibrium alone does not prevent rotation.
  • Choose the moment centre to eliminate the most unknown forces. Reactions whose lines of action pass through that point contribute zero moment.
  • A uniform rod or lamina has its centre of mass at its geometric centre. For a non-uniform body, use the stated or deduced centre of mass rather than the midpoint.
  • For a rod at angle θ\theta to the horizontal, a vertical force has horizontal lever arm such as xcosθx\cos\theta, while a horizontal force has vertical lever arm such as xsinθx\sin\theta.
  • At the point of tipping, the reaction at the support that is losing contact is zero and the body is about to rotate around the remaining contact point.
  • After taking moments, still resolve horizontally and vertically to find remaining reactions or friction. Keep force units and distance units consistent throughout.

Where students actually lose marks

Using the length along a sloping rod instead of the perpendicular distance gives a dimensionally tidy but physically wrong equation. State the lever arm explicitly before multiplying.

Edexcel 9MA0 moments convention

Taking moments about a support should remove its reaction completely. If that reaction still appears, the chosen distance or force diagram is wrong.

Edexcel 9MA0 equilibrium convention

In a limiting-equilibrium rod problem, the moment equation, two force-resolution equations and F=μRF=\mu R have different jobs. Do not try to infer every unknown from moments alone.

Edexcel 9MA0 rod-and-friction convention

Try it — exam-style

Medium
5 marks
ORIGINAL

A uniform beam AB has length 66 m and mass 3030 kg. It is supported at A and at C, where AC=4AC=4 m. A particle of mass 1010 kg is attached at B. Find the vertical reactions at A and C. Use g=9.8 m s2g=9.8\text{ m s}^{-2}.

Hard
7 marks
ORIGINAL

A uniform rod of length 55 m and mass 2020 kg rests with its lower end A on rough horizontal ground and its upper end B against a smooth vertical wall. The rod is in limiting equilibrium and sinθ=3/5\sin\theta=3/5, where θ\theta is its angle to the ground. Find the wall reaction and the coefficient of friction at A. Use g=9.8 m s2g=9.8\text{ m s}^{-2}.

Hard
5 marks
ORIGINAL

A uniform horizontal board is 44 m long and weighs 240240 N. It rests on supports 0.50.5 m and 3.23.2 m from its left end. A person of weight 720720 N walks from left to right. Find how far from the left end the person is when the board is on the point of tipping, and find the reaction at the right support then.

Medium
6 marks
ORIGINAL

A non-uniform rod AB has length 44 m and weight 120120 N. It is supported horizontally at A and B. A load of 8080 N is placed 33 m from A, and the reactions at A and B are 5050 N and 150150 N respectively. Find the distance of the rod's centre of mass from A. The load is then moved to A; find the new reactions.

Questions are written in the style of past Edexcel papers (source shown on each) — never copied from them.

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