Maths

Forces & Newton's laws

Edexcel Mech 8

A-level Maths (9MA0) · exam-style practice, examiner-report intelligence and the tools that drill it.

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The topic on one screen

  • A force diagram is the start of the solution. Draw only forces acting on the chosen body: weight mgmg, normal reactions, tensions, friction and any applied forces. Motion arrows are not forces.
  • Newton's first law gives equilibrium when the resultant force is zero. Newton's second law is the vector equation F=ma\mathbf{F}=m\mathbf{a}, so resolve it separately in two perpendicular directions.
  • Weight is mgmg and acts vertically downwards. A normal reaction is perpendicular to the contact surface; it is not automatically equal to mgmg on an inclined plane or when another force has a perpendicular component.
  • Newton's third-law forces act on different bodies. For connected particles, draw a separate diagram and F=maF=ma equation for each particle, while a light inextensible string over a smooth pulley gives common tension and common acceleration magnitude.
  • On an incline at angle α\alpha, the weight components are mgsinαmg\sin\alpha down the plane and mgcosαmg\cos\alpha perpendicular to it. Resolve relative to the plane unless another choice is clearly simpler.
  • Friction opposes actual or impending relative motion and satisfies FμRF\leq\mu R. Use F=μRF=\mu R only when the body is moving or is stated to be in limiting equilibrium.
  • Mechanics models need interrogation: particles have no size, strings are light and inextensible, pulleys are smooth, and constant friction coefficients simplify real contact forces.

Where students actually lose marks

Writing F=μRF=\mu R immediately is not a harmless shortcut. In static equilibrium the friction may be any value up to μR\mu R unless limiting equilibrium is stated or proved.

Edexcel 9MA0 friction convention

For connected particles, tension is an internal force only if the whole system is treated as one body. If you isolate one particle, tension must appear on its diagram and in its equation.

Edexcel 9MA0 connected-particle convention

A resolved equation should include every force component in that direction. Missing a weight component or resolving the normal reaction along the surface is the usual source of a plausible but wrong answer.

Edexcel 9MA0 force-resolution convention

Try it — exam-style

Medium
6 marks
ORIGINAL

A particle of mass 66 kg is pulled up a rough plane inclined at 3030^\circ to the horizontal by a force of 5050 N parallel to the plane. The coefficient of friction is 0.200.20 and the particle is moving up the plane. Find its acceleration. Use g=9.8 m s2g=9.8\text{ m s}^{-2}.

Hard
6 marks
ORIGINAL

Particle A of mass 44 kg lies on a rough horizontal table and is connected by a light inextensible string over a smooth pulley to a hanging particle B of mass 33 kg. The coefficient of friction between A and the table is 0.250.25. The system is released from rest with B moving down. Find the acceleration and the tension in the string. Use g=9.8 m s2g=9.8\text{ m s}^{-2}.

Medium
5 marks
ORIGINAL

A particle of mass 1010 kg is held in equilibrium by two strings. The left string has tension T1T_1 and is at 3030^\circ above the horizontal; the right string has tension T2T_2 and is at 6060^\circ above the horizontal. Find T1T_1 and T2T_2. Use g=9.8 m s2g=9.8\text{ m s}^{-2}.

Medium
5 marks
ORIGINAL

A particle of mass 22 kg is acted on by forces (6i2j)(6\mathbf{i}-2\mathbf{j}) N and (i+8j)(-\mathbf{i}+8\mathbf{j}) N. Find its acceleration vector, the magnitude and direction of the acceleration, and its velocity after 4 s if its initial velocity is (i2j) m s1(\mathbf{i}-2\mathbf{j})\text{ m s}^{-1}.

Questions are written in the style of past Edexcel papers (source shown on each) — never copied from them.

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