Edexcel A-level Maths coverage

Trigonometry

Section 5
9 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

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5.1

Understand and use the definitions of sine, cosine and tangent for all arguments; the sine and cosine rules; the area of a triangle in the form ½ab sin C; work with radian measure, including use for arc length and area of sector.

  • For a unit-circle angle θ\theta, cosθ\cos\theta and sinθ\sin\theta are the point's horizontal and vertical coordinates, while tanθ=sinθ/cosθ\tan\theta=\sin\theta/\cos\theta where cosθ0\cos\theta\neq0; this extends the ratios beyond acute angles.
  • For a triangle, use a/sinA=b/sinB=c/sinCa/\sin A=b/\sin B=c/\sin C when an opposite side-angle pair is known, a2=b2+c22bccosAa^2=b^2+c^2-2bc\cos A for three sides or an included angle, and 12absinC\tfrac12ab\sin C for area.
  • Radian measure makes arc and sector formulae direct: an angle θ\theta radians in a circle of radius rr gives arc length s=rθs=r\theta and sector area A=12r2θA=\tfrac12r^2\theta.
  • Keep the calculator in the required angle mode and label sides opposite their matching angles; using degrees in s=rθs=r\theta or pairing the wrong side and angle is a common error.

Tier 1 · Easy

2 marks
ORIGINAL

A circular arc has radius 7.5cm7.5\,\text{cm} and subtends 1.21.2 radians at the centre. Find its length.

Tier 2 · Standard

4 marks
ORIGINAL

Two sides of a triangular sail are 8m8\,\text{m} and 11m11\,\text{m}, with included angle 0.90.9 radians. Calculate the third side and the area of the sail, giving each answer to 33 significant figures.

Tier 3 · Hard

5 marks
ORIGINAL

A minor segment is cut from a circle of radius 6cm6\,\text{cm} by a chord whose endpoints subtend 1.41.4 radians at the centre. Determine the perimeter and area of the segment, giving both to 33 significant figures.

5.2

Understand and use the standard small angle approximations of sine, cosine and tangent: sin θ ≈ θ, cos θ ≈ 1 − θ²/2, tan θ ≈ θ.

  • For θ|\theta| close to zero and measured in radians, sinθθ\sin\theta\approx\theta, tanθθ\tan\theta\approx\theta and cosθ1θ2/2\cos\theta\approx1-\theta^2/2.
  • Replace each trigonometric function by its stated approximation, simplify algebraically, and retain only a solution whose magnitude is small enough for the approximation to be credible.
  • For example, 1cosθθ2/21-\cos\theta\approx\theta^2/2, so (1cosθ)/θ21/2(1-\cos\theta)/\theta^2\approx1/2 for a small non-zero θ\theta.
  • The approximations are radian results, not degree results; another common error is to accept a large root created by the approximate polynomial.

Tier 1 · Easy

1 mark
ORIGINAL

Use a standard small-angle approximation to estimate sin(0.064)\sin(0.064).

Tier 2 · Standard

2 marks
ORIGINAL

Without using a calculator's trigonometric keys, estimate 1cos(0.08)(0.08)2\dfrac{1-\cos(0.08)}{(0.08)^2} by a small-angle approximation.

Tier 3 · Hard

4 marks
ORIGINAL

A small positive angle xx satisfies sinx+cosx=1.08\sin x+\cos x=1.08. Use the standard small-angle approximations to estimate xx, giving 44 decimal places, and explain which algebraic root is admissible.

5.3

Understand and use the sine, cosine and tangent functions; their graphs, symmetries and periodicity; know and use exact values of sin, cos and tan for standard angles and their multiples.

  • sinx\sin x and cosx\cos x have range [1,1][-1,1] and period 2π2\pi, while tanx\tan x has range R\mathbb{R}, period π\pi and vertical asymptotes at x=π/2+kπx=\pi/2+k\pi.
  • Use sin(x)=sinx\sin(-x)=-\sin x, cos(x)=cosx\cos(-x)=\cos x and tan(x)=tanx\tan(-x)=-\tan x, then reduce an angle by a whole period before using its reference angle and quadrant.
  • The exact first-quadrant values come from the 4545^\circ and 3030^\circ-6060^\circ triangles; quadrant signs then determine standard-angle values around the unit circle.
  • Do not read the period from the amplitude: in acos(bx)+ca\cos(bx)+c, the amplitude is a|a|, the period is 2π/b2\pi/|b|, and cc moves the midline.

Tier 1 · Easy

2 marks
ORIGINAL

Find the exact value of tan(5π/6)\tan(5\pi/6).

Tier 2 · Standard

4 marks
ORIGINAL

For y=3cos(2x)1y=3\cos(2x)-1, state the amplitude, period, maximum value and minimum value.

Tier 3 · Hard

4 marks
ORIGINAL

Evaluate exactly sin(11π/6)\sin(-11\pi/6), cos(13π/3)\cos(13\pi/3) and tan(7π/4)\tan(7\pi/4).

5.4

Understand and use the definitions of secant, cosecant and cotangent and of arcsin, arccos and arctan; their relationships to sine, cosine and tangent; understanding of their graphs; their ranges and domains.

  • The reciprocal functions are secx=1/cosx\sec x=1/\cos x, cosecx=1/sinx\cosec x=1/\sin x and cotx=cosx/sinx\cot x=\cos x/\sin x; secant and cosecant have range (,1][1,)(-\infty,-1]\cup[1,\infty) and period 2π2\pi, while cotangent has range R\mathbb{R} and period π\pi.
  • The principal ranges are π/2arcsinxπ/2-\pi/2\leq\arcsin x\leq\pi/2, 0arccosxπ0\leq\arccos x\leq\pi and π/2<arctanx<π/2-\pi/2<\arctan x<\pi/2; arcsinx\arcsin x and arccosx\arccos x require 1x1-1\leq x\leq1.
  • To determine a composite inverse-trigonometric domain, first restrict its input to the inverse function's domain; for example, arccos(2x1)\arccos(2x-1) requires 12x11-1\leq2x-1\leq1.
  • The notation sin1x\sin^{-1}x means the inverse function arcsinx\arcsin x, not the reciprocal 1/sinx1/\sin x; the reciprocal is cosecx\cosec x.

Tier 1 · Easy

1 mark
ORIGINAL

Given cosθ=4/5\cos\theta=-4/5, write down secθ\sec\theta.

Tier 2 · Standard

2 marks
ORIGINAL

Give the principal values, in radians, of arcsin(1/2)\arcsin(-1/2) and arctan(1)\arctan(-1).

Tier 3 · Hard

5 marks
ORIGINAL

For y=2secx1y=2\sec x-1, state the period and range, then give all vertical asymptotes in πxπ-\pi\leq x\leq\pi.

5.5

Understand and use tan θ = sin θ / cos θ; understand and use sin²θ + cos²θ = 1, sec²θ = 1 + tan²θ and cosec²θ = 1 + cot²θ.

  • The quotient identity is tanθ=sinθ/cosθ\tan\theta=\sin\theta/\cos\theta, and the three Pythagorean identities are sin2θ+cos2θ=1\sin^2\theta+\cos^2\theta=1, sec2θ=1+tan2θ\sec^2\theta=1+\tan^2\theta and cosec2θ=1+cot2θ\cosec^2\theta=1+\cot^2\theta.
  • Choose an identity containing the known and required functions, rearrange it, and use the stated quadrant to select the correct sign after taking a square root.
  • If tanθ=7/24\tan\theta=-7/24 in quadrant II, a reference triangle has side magnitudes 77, 2424 and 2525, so sinθ=7/25\sin\theta=7/25 and cosθ=24/25\cos\theta=-24/25.
  • From sin2θ+cos2θ=1\sin^2\theta+\cos^2\theta=1 one obtains two possible signs; ignoring the quadrant or silently choosing the positive root can change every reciprocal ratio that follows.

Tier 1 · Easy

3 marks
ORIGINAL

An acute angle θ\theta satisfies sinθ=5/13\sin\theta=5/13. Find tanθ\tan\theta and secθ\sec\theta exactly.

Tier 2 · Standard

4 marks
ORIGINAL

Given that tanθ=7/24\tan\theta=-7/24 and π/2<θ<π\pi/2<\theta<\pi, determine sinθ\sin\theta, cosθ\cos\theta and cosecθ\cosec\theta.

Tier 3 · Hard

5 marks
ORIGINAL

An angle θ\theta lies in the first quadrant and satisfies secθ+tanθ=5\sec\theta+\tan\theta=5. Find sinθ\sin\theta exactly.

5.6

Understand and use double angle formulae; formulae for sin(A ± B), cos(A ± B), tan(A ± B) with geometrical proofs; express a cos θ + b sin θ in the form r cos(θ ± α) or r sin(θ ± α).

  • The compound-angle formulae are sin(A±B)=sinAcosB±cosAsinB\sin(A\pm B)=\sin A\cos B\pm\cos A\sin B, cos(A±B)=cosAcosBsinAsinB\cos(A\pm B)=\cos A\cos B\mp\sin A\sin B and tan(A±B)=(tanA±tanB)/(1tanAtanB)\tan(A\pm B)=(\tan A\pm\tan B)/(1\mp\tan A\tan B); a geometrical proof can calculate the same unit-circle chord by coordinates and by the cosine rule.
  • Setting A=B=θA=B=\theta gives sin2θ=2sinθcosθ\sin2\theta=2\sin\theta\cos\theta, cos2θ=cos2θsin2θ=12sin2θ=2cos2θ1\cos2\theta=\cos^2\theta-\sin^2\theta=1-2\sin^2\theta=2\cos^2\theta-1 and tan2θ=2tanθ/(1tan2θ)\tan2\theta=2\tan\theta/(1-\tan^2\theta).
  • To write acosθ+bsinθ=Rcos(θα)a\cos\theta+b\sin\theta=R\cos(\theta-\alpha), compare coefficients to obtain Rcosα=aR\cos\alpha=a, Rsinα=bR\sin\alpha=b, hence R=a2+b2R=\sqrt{a^2+b^2} with the quadrant of α\alpha set by the signs.
  • For a compound-angle expression, the sign in the cosine formula reverses; for an RR-form, expanding the proposed form before choosing α\alpha prevents a wrong sign.

Tier 1 · Easy

3 marks
ORIGINAL

Use a compound-angle formula to find the exact value of sin(75)\sin(75^\circ).

Tier 2 · Standard

5 marks
ORIGINAL

Express 5cosθ12sinθ5\cos\theta-12\sin\theta as Rcos(θ+α)R\cos(\theta+\alpha), where R>0R>0 and 0<α<π/20<\alpha<\pi/2. Hence state its maximum and minimum values.

Tier 3 · Hard

5 marks
ORIGINAL

Use two points on the unit circle and the cosine rule to prove geometrically that cos(AB)=cosAcosB+sinAsinB\cos(A-B)=\cos A\cos B+\sin A\sin B.

5.7

Solve simple trigonometric equations in a given interval, including quadratic equations in sin, cos and tan and equations involving multiples of the unknown angle.

  • Solve first for the trigonometric ratio, use a reference angle and the signs in each quadrant, then list only solutions in the stated interval.
  • For a quadratic in one trigonometric function, substitute a temporary variable, factorise or use the quadratic formula, and reject any ratio outside its possible range before solving each remaining branch.
  • When the equation involves kxkx, transform the given interval for xx into the corresponding interval for kxkx, find every solution there, and divide only at the end.
  • Inverse-trigonometric buttons return a principal value rather than the full solution set; endpoints, excluded endpoints and degree-versus-radian mode must all be checked explicitly.

Tier 1 · Easy

3 marks
ORIGINAL

Solve sinθ=0.4\sin\theta=0.4 for 0θ2π0\leq\theta\leq2\pi, giving solutions to 33 decimal places.

Tier 2 · Standard

4 marks
ORIGINAL

Determine all xx satisfying 2cos2x3cosx+1=02\cos^2x-3\cos x+1=0 for 0x<2π0\leq x<2\pi.

Tier 3 · Hard

5 marks
ORIGINAL

Find every solution of tan(2x)=3\tan(2x)=-\sqrt3 in the interval π/2xπ-\pi/2\leq x\leq\pi.

5.8

Construct proofs involving trigonometric functions and identities.

  • A trigonometric identity is true for every value in its domain, so a proof transforms one side into the other using exact algebra and established identities rather than testing selected angles.
  • Usually begin with the more complicated side, replace secant, cosecant, cotangent or tangent by sine and cosine when helpful, and factor or take a common denominator before cancelling.
  • Multiplying numerator and denominator by a conjugate can expose 1sin2x=cos2x1-\sin^2x=\cos^2x or 1cos2x=sin2x1-\cos^2x=\sin^2x and complete the proof cleanly.
  • Never cancel terms across addition, and record domain restrictions: algebra such as division by sinx\sin x is valid only where that denominator is non-zero.

Tier 1 · Easy

2 marks
ORIGINAL

Prove that sinxcotx=cosx\sin x\cot x=\cos x wherever the left-hand side is defined.

Tier 2 · Standard

3 marks
ORIGINAL

Prove that 1cos(2x)sin(2x)=tanx\dfrac{1-\cos(2x)}{\sin(2x)}=\tan x for values at which both sides are defined.

Tier 3 · Hard

5 marks
ORIGINAL

Prove that 11sinx11+sinx=2tanxsecx\dfrac{1}{1-\sin x}-\dfrac{1}{1+\sin x}=2\tan x\sec x wherever the expressions exist.

5.9

Use trigonometric functions to solve problems in context, including problems involving vectors, kinematics and forces.

  • Resolve a vector of magnitude VV at angle θ\theta to the positive horizontal into components VcosθV\cos\theta and VsinθV\sin\theta, changing signs to match its actual direction.
  • For resultant or equilibrium problems, form separate equations in two perpendicular directions; a zero resultant requires both component sums to equal zero.
  • In a kinematics model, trigonometric functions can describe direction or periodic motion, and the mathematical solution must be interpreted using the stated time interval, units and physical constraints.
  • A calculator angle without a quadrant check can point in the opposite direction; draw and label a diagram, then state bearings or directions in the form the context requests.

Tier 1 · Easy

3 marks
ORIGINAL

A drone travels at 12m s112\,\text{m s}^{-1} on a path 3535^\circ above the horizontal. Calculate its horizontal and vertical velocity components to 33 significant figures.

Tier 2 · Standard

5 marks
ORIGINAL

Two horizontal forces act on a crate: 8N8\,\text{N} due east and 11N11\,\text{N} at 6060^\circ north of east. Find the magnitude and direction of their resultant, to 33 significant figures and the nearest degree respectively.

Tier 3 · Hard

5 marks
ORIGINAL

A ring is in equilibrium under its weight of 18N18\,\text{N}, a tension PP directed 2525^\circ above the horizontal, and a horizontal tension QQ acting oppositely. Calculate PP and QQ to 33 significant figures.