Edexcel A-level Further Maths coverage

Hypothesis testing

Section FS1-4
2 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

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FS1-4.1

Extend ideas of hypothesis tests to test for the mean of a Poisson distribution.

  • For a Poisson-mean test, state H0H_0 and H1H_1 in terms of the population parameter λ\lambda or μ\mu, not the observed count.
  • Under H0H_0, combine independent observation periods into one Poisson total and use the direction of H1H_1 to choose the tail.
  • A critical region is the most extreme attainable tail whose probability under H0H_0 does not exceed the significance level; its probability is the actual size.
  • A common error is to say that H0H_0 is proved when it is not rejected; the conclusion should state that there is insufficient evidence for H1H_1.

Tier 1 · Easy

2 marks
ORIGINAL

A manager claims that the mean number of alerts per shift is 4.24.2. State hypotheses to test whether the mean has increased, defining your parameter.

Tier 2 · Standard

7 marks
ORIGINAL

Under H0H_0, defects occur at a mean rate of 2.52.5 per hour. Eight independent hours give a total of 2828 defects. Test at a 5%5\% significance level whether the mean rate has increased. State the critical region and its actual size.

Tier 3 · Hard

8 marks
ORIGINAL

A Poisson model has mean 1.81.8 events per batch. Twelve independent batches produce 1414 events in total. Test at a 5%5\% significance level whether the mean per batch has decreased. Give the critical region, its size and the pp-value.

FS1-4.2

Extend hypothesis testing to test for the parameter p of a geometric distribution.

  • For a geometric-parameter test, hypotheses are stated in terms of the success probability pp.
  • A larger pp tends to produce an earlier first success, so small trial numbers support H1:p>p0H_1:p>p_0 and large trial numbers support H1:p<p0H_1:p<p_0.
  • The sum of rr independent geometric variables with the same pp counts the trial of the rrth success and has a negative binomial distribution.
  • A common error is to reverse the tail: long waiting times are evidence for a smaller, not larger, success probability.

Tier 1 · Easy

3 marks
ORIGINAL

A geometric model uses p=0.35p=0.35. State hypotheses for testing whether the probability of success has fallen, and state which tail of the waiting time is critical.

Tier 2 · Standard

7 marks
ORIGINAL

Six independent geometric observations count trials to first success. Test H0:p=0.3H_0:p=0.3 against H1:p>0.3H_1:p>0.3 at the 5%5\% level of significance using their sum SS. Find the critical region and its size, then state the conclusion when S=9S=9.

Tier 3 · Hard

8 marks
ORIGINAL

Five independent geometric observations have common parameter pp. Use their sum SS to test H0:p=0.4H_0:p=0.4 against H1:p<0.4H_1:p<0.4 at the 5%5\% level. Determine the critical region and its size. Find the pp-value and conclusion when S=19S=19.