AQA Level 2 Further Maths coverage

Calculus

Section C
9 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

Open the printable pack
C1

Know that the gradient function dy/dx gives the gradient of the curve and measures the rate of change of y with respect to x

  • The derivative dydx\frac{dy}{dx} is the gradient function of a curve y=f(x)y=f(x).
  • At a chosen value of xx, substitute into dydx\frac{dy}{dx} to find the instantaneous rate of change of yy with respect to xx.
  • A positive derivative means yy is increasing locally; a negative derivative means yy is decreasing locally.
  • Do not substitute into yy when the question asks for a rate of change; substitute into the derivative.

Tier 1 · Easy

1 mark
ORIGINAL

At x=2x=2, a curve has dydx=6\frac{dy}{dx}=6. State its instantaneous rate at this point.

Tier 2 · Standard

2 marks
ORIGINAL

For y=3x25xy=3x^2-5x, calculate dydx\frac{dy}{dx} when x=2x=2.

Tier 3 · Hard

3 marks
ORIGINAL

A curve has gradient function dydx=3x212x+5\frac{dy}{dx}=3x^2-12x+5. Find the value of xx at which the rate of change is 7-7.

C2

Know that the gradient of a function is the gradient of the tangent at that point

  • At a point on a curve, f(x)f'(x) is the gradient of the tangent at that point.
  • Differentiate first, then substitute the point's xx-coordinate into the derivative.
  • The tangent touches the curve locally and has the same instantaneous gradient there.
  • A common error is to substitute into the original function and report the yy-coordinate as the gradient.

Tier 1 · Easy

1 mark
ORIGINAL

For a function ff, f(3)=2f'(3)=-2. State the gradient of the tangent to y=f(x)y=f(x) where x=3x=3.

Tier 2 · Standard

2 marks
ORIGINAL

Work out the gradient of the tangent to y=x24x+1y=x^2-4x+1 at the point where x=1x=1.

Tier 3 · Hard

4 marks
ORIGINAL

Work out the coordinates of every point on y=x33x2+2y=x^3-3x^2+2 where the tangent has gradient 99.

C3

Differentiation of kx^n where n is an integer, and the sum of such functions

  • Use the power rule ddx(kxn)=knxn1\frac{d}{dx}(kx^n)=knx^{n-1} for integer nn.
  • Differentiate a sum term by term, keeping each sign and coefficient.
  • A constant differentiates to 00, and negative powers follow the same power rule.
  • A common error is to multiply by the power but forget to reduce the power by 11.

Tier 1 · Easy

1 mark
ORIGINAL

Differentiate 5x45x^4 with respect to xx.

Tier 2 · Standard

3 marks
ORIGINAL

Given y=4x33x2+7x9y=4x^3-3x^2+7x-9, find dydx\frac{dy}{dx}.

Tier 3 · Hard

4 marks
ORIGINAL

For y=2x53x2+4xy=2x^5-\frac{3}{x^2}+4x, find dydx\frac{dy}{dx} and hence find its value at x=1x=1.

C4

The equation of a tangent and normal at any point on a curve

  • Differentiate the curve and substitute the point's xx-coordinate to find the tangent gradient.
  • The normal is perpendicular to the tangent, so its gradient is the negative reciprocal when both gradients are defined.
  • Use the point on the curve in yy1=m(xx1)y-y_1=m(x-x_1) for either line.
  • If only an xx-coordinate is given, first substitute into the curve to find the corresponding yy-coordinate.

Tier 1 · Easy

2 marks
ORIGINAL

The curve y=x2y=x^2 passes through (2,4)(2,4). State the gradients of the tangent and the normal at this point.

Tier 2 · Standard

3 marks
ORIGINAL

Work out the equation of the tangent to y=x2+3x1y=x^2+3x-1 at the point where x=1x=1.

Tier 3 · Hard

4 marks
ORIGINAL

The normal to y=x3xy=x^3-x at the point where x=2x=2 meets the xx-axis at RR. Find the coordinates of RR.

C5

Increasing and decreasing functions

  • A differentiable function is increasing where dydx>0\frac{dy}{dx}>0 and decreasing where dydx<0\frac{dy}{dx}<0.
  • Find boundary values by solving dydx=0\frac{dy}{dx}=0, then test the sign of the derivative in each interval.
  • Values where the derivative is 00 are stationary candidates or interval boundaries; determine increasing and decreasing intervals from the derivative's sign on either side.
  • A common error is to inspect whether yy is positive or negative instead of checking the sign of the derivative.

Tier 1 · Easy

2 marks
ORIGINAL

A function has derivative f(x)=2x6f'(x)=2x-6. State the values of xx for which the function is increasing.

Tier 2 · Standard

3 marks
ORIGINAL

Work out where y=x28x+1y=x^2-8x+1 is decreasing and where it is increasing.

Tier 3 · Hard

4 marks
ORIGINAL

Work out the intervals on which f(x)=x33x29x+4f(x)=x^3-3x^2-9x+4 is increasing and the interval on which it is decreasing.

C6

Understand and use the notation d2y/dx2; know that it measures the rate of change of the gradient function

  • d2ydx2\frac{d^2y}{dx^2} is the derivative of dydx\frac{dy}{dx}, so it measures how the gradient changes as xx changes.
  • Differentiate the original function twice, simplifying negative or fractional powers before or after differentiating as convenient.
  • At a point, d2ydx2>0\frac{d^2y}{dx^2}>0 means the gradient is increasing and d2ydx2<0\frac{d^2y}{dx^2}<0 means the gradient is decreasing.
  • A common error is to square dydx\frac{dy}{dx}; the superscript 22 records a second differentiation, not a square.

Tier 1 · Easy

2 marks
ORIGINAL

For y=3x45x2+7y=3x^4-5x^2+7, work out d2ydx2\frac{d^2y}{dx^2}.

Tier 2 · Standard

3 marks
ORIGINAL

A curve has dydx=6x24x\frac{dy}{dx}=6x^2-4x. Work out the value of xx at which the gradient is changing at a rate of 2020, given x>0x>0.

Tier 3 · Hard

4 marks
ORIGINAL

For the curve y=x44x3+2x2y=x^4-4x^3+2x^2, work out the ranges of xx for which the gradient is increasing. Give exact values.

C7

Use of differentiation to find maxima and minima points on a curve

  • At a stationary point, dydx=0\frac{dy}{dx}=0; solve this equation and substitute each xx-value into the original curve to obtain coordinates.
  • If d2ydx2<0\frac{d^2y}{dx^2}<0 at a stationary point it is a local maximum; if d2ydx2>0\frac{d^2y}{dx^2}>0 it is a local minimum.
  • A change of gradient from positive to negative also proves a maximum, while negative to positive proves a minimum.
  • Always give the full coordinates when a question asks for points, and state their nature rather than stopping at the stationary xx-values.

Tier 1 · Easy

2 marks
ORIGINAL

The curve y=x33x2+2y=x^3-3x^2+2 has a stationary point where x=2x=2. Use d2ydx2\frac{d^2y}{dx^2} to determine its nature.

Tier 2 · Standard

3 marks
ORIGINAL

The curve y=x36x2+9x+1y=x^3-6x^2+9x+1 has stationary points where x=1x=1 and x=3x=3. Work out their coordinates and determine their nature.

Tier 3 · Hard

4 marks
ORIGINAL

Work out the coordinates and nature of every stationary point of y=2x416x2+3y=2x^4-16x^2+3.

C8

Using calculus to find maxima and minima in simple problems

  • Define the quantity to be optimised as a function of one variable, using any length, perimeter or other constraint to remove extra variables.
  • Differentiate the resulting function and solve dAdx=0\frac{dA}{dx}=0, or the corresponding derivative for the quantity in the question.
  • Check that the stationary value is the required maximum or minimum, using d2Adx2\frac{d^2A}{dx^2}, a sign change or the shape of a quadratic.
  • Return to the requested quantity: a stationary input value is not the final answer when the question asks for a maximum area or volume.
  • Reject values that are impossible in the context, such as negative lengths or values outside the stated domain.

Tier 1 · Easy

2 marks
ORIGINAL

A quantity is modelled by P=x(14x)P=x(14-x) for 0<x<140<x<14. Find the greatest possible value of PP by differentiating.

Tier 2 · Standard

3 marks
ORIGINAL

A rectangle has side lengths (x+2)(x+2) cm and (10x)(10-x) cm, where 0<x<100<x<10. Use calculus to work out its maximum area.

Tier 3 · Hard

4 marks
ORIGINAL

The upper corners of a rectangle lie on y=12x2y=12-x^2 at (x,y)(x,y) and (x,y)(-x,y), where x>0x>0. The lower corners lie on the xx-axis. Use calculus to work out the maximum area of the rectangle.

C9

Sketch/interpret a curve with known maximum and minimum points

  • A local maximum is a turning point where the curve changes from increasing to decreasing; a local minimum changes from decreasing to increasing.
  • On a sketch, plot and label the known turning points and intercepts before joining them with a smooth curve.
  • Use the sign of the gradient to decide which sections rise or fall as xx increases.
  • A sketch shows the required shape and key features; it does not need an exact scale, but it must not introduce extra turning points or intercepts.

Tier 1 · Easy

1 mark
ORIGINAL

A smooth curve has a local maximum at x=2x=-2 and a local minimum at x=1x=1, with no other stationary points. State where the curve is decreasing.

Tier 2 · Standard

3 marks
ORIGINAL

Sketch the cubic y=2x33x212x+2y=2x^3-3x^2-12x+2, which has local maximum L=(1,9)L=(-1,9) and local minimum M=(2,18)M=(2,-18). Label LL, MM and the yy-intercept NN.

Tier 3 · Hard

4 marks
ORIGINAL

A continuous smooth curve y=f(x)y=f(x) has roots x=4x=-4, x=1x=1 and x=5x=5. It has a local maximum at (2,5)(-2,5) and a local minimum at (3,4)(3,-4), with no other turning points. Sketch a possible curve, labelling all five given points.