At , a curve has . State its instantaneous rate at this point.
Calculus
Notes and three levels of exam-style practice for each registered specification leaf in this section.
Open the printable packKnow that the gradient function dy/dx gives the gradient of the curve and measures the rate of change of y with respect to x
- The derivative is the gradient function of a curve .
- At a chosen value of , substitute into to find the instantaneous rate of change of with respect to .
- A positive derivative means is increasing locally; a negative derivative means is decreasing locally.
- Do not substitute into when the question asks for a rate of change; substitute into the derivative.
Tier 1 · Easy
Tier 2 · Standard
For , calculate when .
Tier 3 · Hard
A curve has gradient function . Find the value of at which the rate of change is .
Know that the gradient of a function is the gradient of the tangent at that point
- At a point on a curve, is the gradient of the tangent at that point.
- Differentiate first, then substitute the point's -coordinate into the derivative.
- The tangent touches the curve locally and has the same instantaneous gradient there.
- A common error is to substitute into the original function and report the -coordinate as the gradient.
Tier 1 · Easy
For a function , . State the gradient of the tangent to where .
Tier 2 · Standard
Work out the gradient of the tangent to at the point where .
Tier 3 · Hard
Work out the coordinates of every point on where the tangent has gradient .
Differentiation of kx^n where n is an integer, and the sum of such functions
- Use the power rule for integer .
- Differentiate a sum term by term, keeping each sign and coefficient.
- A constant differentiates to , and negative powers follow the same power rule.
- A common error is to multiply by the power but forget to reduce the power by .
Tier 1 · Easy
Differentiate with respect to .
Tier 2 · Standard
Given , find .
Tier 3 · Hard
For , find and hence find its value at .
The equation of a tangent and normal at any point on a curve
- Differentiate the curve and substitute the point's -coordinate to find the tangent gradient.
- The normal is perpendicular to the tangent, so its gradient is the negative reciprocal when both gradients are defined.
- Use the point on the curve in for either line.
- If only an -coordinate is given, first substitute into the curve to find the corresponding -coordinate.
Tier 1 · Easy
The curve passes through . State the gradients of the tangent and the normal at this point.
Tier 2 · Standard
Work out the equation of the tangent to at the point where .
Tier 3 · Hard
The normal to at the point where meets the -axis at . Find the coordinates of .
Increasing and decreasing functions
- A differentiable function is increasing where and decreasing where .
- Find boundary values by solving , then test the sign of the derivative in each interval.
- Values where the derivative is are stationary candidates or interval boundaries; determine increasing and decreasing intervals from the derivative's sign on either side.
- A common error is to inspect whether is positive or negative instead of checking the sign of the derivative.
Tier 1 · Easy
A function has derivative . State the values of for which the function is increasing.
Tier 2 · Standard
Work out where is decreasing and where it is increasing.
Tier 3 · Hard
Work out the intervals on which is increasing and the interval on which it is decreasing.
Understand and use the notation d2y/dx2; know that it measures the rate of change of the gradient function
- is the derivative of , so it measures how the gradient changes as changes.
- Differentiate the original function twice, simplifying negative or fractional powers before or after differentiating as convenient.
- At a point, means the gradient is increasing and means the gradient is decreasing.
- A common error is to square ; the superscript records a second differentiation, not a square.
Tier 1 · Easy
For , work out .
Tier 2 · Standard
A curve has . Work out the value of at which the gradient is changing at a rate of , given .
Tier 3 · Hard
For the curve , work out the ranges of for which the gradient is increasing. Give exact values.
Use of differentiation to find maxima and minima points on a curve
- At a stationary point, ; solve this equation and substitute each -value into the original curve to obtain coordinates.
- If at a stationary point it is a local maximum; if it is a local minimum.
- A change of gradient from positive to negative also proves a maximum, while negative to positive proves a minimum.
- Always give the full coordinates when a question asks for points, and state their nature rather than stopping at the stationary -values.
Tier 1 · Easy
The curve has a stationary point where . Use to determine its nature.
Tier 2 · Standard
The curve has stationary points where and . Work out their coordinates and determine their nature.
Tier 3 · Hard
Work out the coordinates and nature of every stationary point of .
Using calculus to find maxima and minima in simple problems
- Define the quantity to be optimised as a function of one variable, using any length, perimeter or other constraint to remove extra variables.
- Differentiate the resulting function and solve , or the corresponding derivative for the quantity in the question.
- Check that the stationary value is the required maximum or minimum, using , a sign change or the shape of a quadratic.
- Return to the requested quantity: a stationary input value is not the final answer when the question asks for a maximum area or volume.
- Reject values that are impossible in the context, such as negative lengths or values outside the stated domain.
Tier 1 · Easy
A quantity is modelled by for . Find the greatest possible value of by differentiating.
Tier 2 · Standard
A rectangle has side lengths cm and cm, where . Use calculus to work out its maximum area.
Tier 3 · Hard
The upper corners of a rectangle lie on at and , where . The lower corners lie on the -axis. Use calculus to work out the maximum area of the rectangle.
Sketch/interpret a curve with known maximum and minimum points
- A local maximum is a turning point where the curve changes from increasing to decreasing; a local minimum changes from decreasing to increasing.
- On a sketch, plot and label the known turning points and intercepts before joining them with a smooth curve.
- Use the sign of the gradient to decide which sections rise or fall as increases.
- A sketch shows the required shape and key features; it does not need an exact scale, but it must not introduce extra turning points or intercepts.
Tier 1 · Easy
A smooth curve has a local maximum at and a local minimum at , with no other stationary points. State where the curve is decreasing.
Tier 2 · Standard
Sketch the cubic , which has local maximum and local minimum . Label , and the -intercept .
Tier 3 · Hard
A continuous smooth curve has roots , and . It has a local maximum at and a local minimum at , with no other turning points. Sketch a possible curve, labelling all five given points.