AQA GCSE Physics coverage

Particle model of matter

Section 4.3
8 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

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4.3.1.1

Density of materials

  • Density is mass per unit volume: ρ=m/V\rho=m/V, with SI unit kg/m3\text{kg/m}^3.
  • Measure a regular solid's dimensions to calculate its volume, find an irregular solid's volume by displacement, and find a liquid's mass by subtracting the empty container's mass.
  • In the particle model, solids and liquids are usually denser than gases because their particles are much closer together; density also depends on particle mass and arrangement.
  • A common error is to mix units such as grams and cubic metres; convert both mass and volume into a compatible unit system before dividing.

Tier 1 · Easy

2 marks
ORIGINAL

A sample has mass 0.54kg0.54\,\text{kg} and volume 2.0×104m32.0\times10^{-4}\,\text{m}^3. Calculate its density.

Tier 2 · Standard

4 marks
ORIGINAL

An irregular mineral has mass 0.390kg0.390\,\text{kg}. When fully submerged, it displaces 1.50×102cm31.50\times10^2\,\text{cm}^3 of water. Calculate its density in kg/m3\text{kg/m}^3.

Tier 3 · Hard

6 marks
ORIGINAL

Describe how to determine the densities of a rectangular metal block, a small irregular stone and a liquid. Name suitable apparatus and state the calculation used in each case.

4.3.1.2

Changes of state

  • The state changes are melting, freezing, boiling, evaporation, condensation and sublimation.
  • Use particle arrangements and motion to describe the change, while keeping the number and type of particles unchanged.
  • Mass is conserved during a change of state in a closed system because no particles are created or destroyed.
  • A common error is to describe a state change as a chemical reaction; it is physical because reversing it restores the material's original properties.

Tier 1 · Easy

2 marks
ORIGINAL

Name the changes of state from gas to liquid and from solid directly to gas.

Tier 2 · Standard

3 marks
ORIGINAL

A sealed container holds 75.0g75.0\,\text{g} of ice. The ice melts completely. State the mass of water formed and explain why it is unchanged.

Tier 3 · Hard

4 marks
ORIGINAL

A solid air freshener gradually forms a gas and later deposits as solid crystals on a cold surface. Explain why these are physical changes and describe the particle arrangement before and after each change.

4.3.2.1

Internal energy

  • Internal energy is the total kinetic energy and potential energy of all the particles in a system.
  • When a system is heated, track whether the supplied energy raises particle kinetic energy and temperature or changes particle potential energy during a state change.
  • Within one state, a higher temperature means a greater average particle kinetic energy and therefore usually a greater internal energy for the same sample.
  • A common error is to say that temperature always rises when internal energy increases; during a change of state, internal energy changes while temperature stays constant.

Tier 1 · Easy

2 marks
ORIGINAL

Define the internal energy of a system.

Tier 2 · Standard

3 marks
ORIGINAL

A solid is heated but does not melt. Explain how its particles and internal energy change.

Tier 3 · Hard

5 marks
ORIGINAL

A pure solid is heated at a steady rate. Its temperature rises, remains constant while it melts, then rises again. Explain the changes in kinetic energy, potential energy and internal energy during all three stages.

4.3.2.2

Temperature changes in a system and specific heat capacity

  • For a temperature change without a change of state, ΔE=mcΔθ\Delta E=mc\Delta\theta links energy change, mass, specific heat capacity and temperature change.
  • Calculate Δθ=θfinalθinitial\Delta\theta=\theta_{\text{final}}-\theta_{\text{initial}}, convert mass to kilograms and rearrange the equation algebraically before inserting values.
  • For the same energy input, a larger mass or larger specific heat capacity gives a smaller temperature rise.
  • A common error is to confuse specific heat capacity in J/(kgC)\text{J/(kg}\,{}^\circ\text{C)} with specific latent heat in J/kg\text{J/kg}; the former applies when temperature changes.

Tier 1 · Easy

2 marks
ORIGINAL

State the meaning of specific heat capacity and give its unit.

Tier 2 · Standard

2 marks
ORIGINAL

A 2.0kg2.0\,\text{kg} metal block warms by 35C35\,{}^\circ\text{C}. Its specific heat capacity is 450J/(kgC)450\,\text{J/(kg}\,{}^\circ\text{C)}. Calculate the increase in its thermal energy store.

Tier 3 · Hard

5 marks
ORIGINAL

Two insulated blocks each receive 54kJ54\,\text{kJ}. Block A has mass 1.5kg1.5\,\text{kg} and specific heat capacity 900J/(kgC)900\,\text{J/(kg}\,{}^\circ\text{C)}. Block B has mass 0.75kg0.75\,\text{kg} and specific heat capacity 450J/(kgC)450\,\text{J/(kg}\,{}^\circ\text{C)}. Calculate both temperature rises and explain the difference.

4.3.2.3

Changes of state and specific latent heat

  • Specific latent heat is the energy needed to change the state of 1kg1\,\text{kg} of a substance with no temperature change, using E=mLE=mL.
  • Use specific latent heat of fusion for solid-liquid changes and specific latent heat of vaporisation for liquid-vapour changes.
  • A flat section on a heating or cooling graph marks a state change: energy changes particle potential energy while average kinetic energy and temperature remain constant.
  • A common error is to apply E=mcΔθE=mc\Delta\theta across a state-change plateau; use E=mLE=mL for that stage and calculate any temperature-changing stages separately.

Tier 1 · Easy

2 marks
ORIGINAL

Define specific latent heat.

Tier 2 · Standard

2 marks
ORIGINAL

A 0.28kg0.28\,\text{kg} frozen material is already at its melting point. Calculate the transfer required to melt it completely, given Lf=3.10×105J/kgL_f=3.10\times10^5\,\text{J/kg}.

Tier 3 · Hard

5 marks
ORIGINAL

A 0.15kg0.15\,\text{kg} sample of water is heated from 20C20\,{}^\circ\text{C} to 100C100\,{}^\circ\text{C} and then completely vaporised at 100C100\,{}^\circ\text{C}. Calculate the total energy supplied. Use c=4200J/(kgC)c=4200\,\text{J/(kg}\,{}^\circ\text{C)} and Lv=2.26×106J/kgL_v=2.26\times10^6\,\text{J/kg}.

4.3.3.1

Particle motion in gases

  • Gas molecules are in constant random motion, and gas temperature is related to their average kinetic energy.
  • Explain gas pressure through molecules colliding with container walls and changing momentum, which exerts a force on the walls.
  • At constant volume, heating increases average molecular speed, making collisions more frequent and harder, so pressure increases.
  • A common error is to say that heating creates more particles or makes each particle larger; the same molecules move faster unless gas enters or leaves.

Tier 1 · Easy

1 mark
ORIGINAL

State how the average kinetic energy of gas molecules changes when the gas temperature increases.

Tier 2 · Standard

4 marks
ORIGINAL

A sealed rigid flask of gas is heated. Explain why the gas pressure increases.

Tier 3 · Hard

5 marks
ORIGINAL

Two identical sealed rigid containers hold the same number of molecules of the same gas. Gas A is at a higher temperature than gas B. Compare the molecular motion and pressures, and explain why the comparison would be less certain if the containers had different volumes.

4.3.3.2

Pressure in gases (physics only)

  • Gas pressure produces a net force at right angles to a container wall or any other surface.
  • For a fixed mass of gas at constant temperature, use pV=constantpV=\text{constant}, so p1V1=p2V2p_1V_1=p_2V_2.
  • Increasing volume at constant temperature makes wall collisions less frequent per unit area, so pressure decreases.
  • A common error is to use p1/V1=p2/V2p_1/V_1=p_2/V_2; pressure and volume are inversely proportional, so their product stays constant.

Tier 1 · Easy

2 marks
ORIGINAL

A fixed mass of gas is kept at constant temperature while its volume doubles. State what happens to its pressure.

Tier 2 · Standard

3 marks
ORIGINAL

A gas occupies 4.0×103m34.0\times10^{-3}\,\text{m}^3 at a pressure of 1.2×105Pa1.2\times10^5\,\text{Pa}. It is compressed at constant temperature to 1.5×103m31.5\times10^{-3}\,\text{m}^3. Calculate the new pressure.

Tier 3 · Hard

5 marks
ORIGINAL

A syringe contains 3.20×102cm33.20\times10^2\,\text{cm}^3 of gas at 2.40×102kPa2.40\times10^2\,\text{kPa}. The outlet is sealed and the gas remains at constant temperature while the pressure rises to 3.60×102kPa3.60\times10^2\,\text{kPa}. Calculate the final volume and the decrease in volume. Explain the pressure rise using particles.

4.3.3.3

Increasing the pressure of a gas (physics only) (HT only)

  • Work is an energy transfer by a force; doing work on an enclosed gas transfers energy to its internal energy store.
  • Identify the force and displacement during compression, calculate work with W=FsW=Fs when appropriate, and account for any energy transferred to the surroundings.
  • Rapid compression can raise gas temperature because increased internal energy gives the molecules greater average kinetic energy.
  • A common error is to attribute warming only to friction in the pump; compression itself involves work being done on the gas.

Tier 1 · Easy

2 marks
ORIGINAL

Explain why the air in a sealed bicycle pump can become warmer when the handle is pushed in quickly.

Tier 2 · Standard

3 marks
ORIGINAL

180J180\,\text{J} of work is done on an enclosed gas, with negligible energy transfer to the surroundings. State the change in internal energy and explain the likely temperature change.

Tier 3 · Hard

4 marks
ORIGINAL

A piston exerts a constant force of 250N250\,\text{N} while moving 0.18m0.18\,\text{m} into a sealed cylinder. During compression, 12J12\,\text{J} is transferred from the gas to the surroundings. Calculate the increase in the gas's internal energy and explain the effect on its temperature.