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AQA GCSE Physics revision notes

Magnetism and electromagnetism

Section 4.7
10 specification points

Notes and three levels of exam-style practice for each registered specification point in this section.

Checked against AQA 8463 section 4.7

Checked against AQA 8463 section 4.7. Review basis: the qualification registry sourced from the AQA GCSE Physics (8463) specification; registry verification recorded 17 July 2026.

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In the exam: Equation sheet provided · calculator allowed in every paper

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(physics only) means this content belongs to AQA GCSE Physics (8463), the separate-science qualification, but not AQA Combined Science: Trilogy (8464). It is not an exam tier: (HT only) separately marks Higher-tier content.

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4.7.1.1

Poles of a magnet

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Magnetic forces are strongest at a magnet's north and south poles; like poles repel and unlike poles attract without touching.
  • A permanent magnet makes its own magnetic field, whereas an induced magnet becomes magnetic only while it is in another magnetic field.
  • For example, either pole of a permanent magnet attracts an unmagnetised iron nail because the nail becomes an induced magnet with the nearer end as the opposite pole.
  • A common error is to predict repulsion from an induced magnet: induced magnetism produces attraction, and most or all of it is lost quickly when the field is removed.
Worked example

A north pole is moved towards the north pole of a second permanent magnet. State the interaction and name the type of force involved.

  1. 1.Both approaching ends are north poles, so they are like poles and repel. The magnets exert this force across a gap, making it a non-contact force.

Answer: The poles repel. The interaction is a non-contact force.

Common mistakes

  • Don't predict repulsion from an induced magnet: induced magnetism produces attraction, and most or all of it is lost quickly when the field is removed.
  • Don't fall into the trap of saying a geographic north pole repels a magnet's north-seeking pole.

Exam tip

For magnetic poles, state both attraction or repulsion and the interacting pole names.

Tier 1 · Easy

ORIGINAL

State one difference between a permanent magnet and an induced magnet, including what happens when an external magnetic field is removed.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

An unmagnetised iron pin is attracted to the south pole of a bar magnet. Explain why the pin is attracted and what happens after the magnet is taken far away.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Objects P and Q are each either an unmagnetised iron sample or a permanent magnet. P attracts the north pole of a known permanent magnet, while Q repels it. Decide which object must be a permanent magnet and explain why the evidence for P is inconclusive.

[4 marks]

Total for this question: 4

Your progress and exam materials
4.7.1.2

Magnetic fields

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A magnetic field is the region where a magnet exerts a force on another magnet or on iron, steel, cobalt or nickel.
  • Plot a field by placing a compass at successive positions, marking the direction of its north-seeking end, and joining the marks with smooth directed lines.
  • Outside a bar magnet, field lines point from north to south and are closest at the poles; compass alignment with Earth's field is evidence that Earth's core must be magnetic.
  • A common error is to draw crossing field lines or arrows from south to north outside the magnet; each point has one field direction, defined by the force on a north pole.
Magnetic field lines leave the north pole and enter the south pole outside a bar magnet.
Worked example

State the direction of the magnetic field immediately outside a bar magnet near its north pole.

  1. 1.Use the field-line convention outside a magnet: arrows run from the north pole to the south pole.

Answer: The field points away from the north pole, towards the south pole.

Common mistakes

  • Don't draw crossing field lines or arrows from south to north outside the magnet; each point has one field direction, defined by the force on a north pole.
  • Don't fall into the trap of drawing magnetic field lines that cross or point south to north outside a magnet.

Exam tip

Draw field arrows from north to south outside the magnet and make close spacing show greater strength.

Tier 1 · Easy

ORIGINAL

State where the magnetic field around a bar magnet is strongest and describe how a field-line diagram shows this.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Describe how a student can map the direction of the magnetic field around a bar magnet using a small plotting compass.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Two field-pattern sketches are proposed for one bar magnet. Sketch A has widely spaced lines at the poles and crowded lines halfway between them; sketch B has crowded lines near the poles, no crossings, and arrows from north to south outside. Evaluate the sketches and relate a compass reading to your decision.

[4 marks]

Total for this question: 4

4.7.2.1

Electromagnetism

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A current in a straight conductor creates concentric field lines; increasing current strengthens the field, increasing distance weakens it, and a nearby compass deflection demonstrates the effect.
  • Use the right-hand grip rule for direction: point the thumb in the conventional-current direction and the curled fingers show the field direction.
  • A solenoid's turns reinforce to make a strong, nearly uniform internal field and a bar-magnet-shaped external field; adding an iron core strengthens it and makes an electromagnet.
  • When interpreting an electromagnetic-device diagram, trace current to magnetic field and then to force or motion; a common error is to name the electromagnet without explaining that causal chain.
Worked example

Give two changes that would increase the magnetic field strength at a fixed point inside a current-carrying solenoid.

  1. 1.A larger current produces a stronger field from every turn. Easily magnetised iron concentrates and strengthens the solenoid's field.

Answer: Increase the current. Add an iron core.

Common mistakes

  • Don't make this mistake: When interpreting an electromagnetic-device diagram, trace current to magnetic field and then to force or motion; a common error is to name the electromagnet without explaining that causal chain.
  • Don't fall into the trap of reversing current direction without reversing the magnetic field direction.

Exam tip

Use a plotting compass to map field direction and identify where fields reinforce or oppose.

Tier 1 · Easy

ORIGINAL

Describe the shape of the magnetic field around a straight current-carrying wire and how its strength changes with distance from the wire.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A vertical wire carries conventional current upwards. Describe the field-line shape and how a student determines its direction when viewed from above.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Coil X has 80 closely spaced turns and no core. Coil Y has 80 identical turns carrying the same current but contains an iron core. Compare their fields, then explain why reversing the current through Y reverses its poles without removing its field-strength advantage.

[5 marks]

Total for this question: 5

4.7.2.2

Fleming's left-hand rule (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • The motor effect is the force produced when a current-carrying conductor lies in a magnetic field; the conductor and field-producing magnet exert forces on each other.
  • For Fleming's left-hand rule, hold the thumb, first finger and second finger mutually perpendicular: thumb is force, first finger is field from north to south, and second finger is conventional current.
  • For a conductor perpendicular to the field, calculate force with F=BIlF=BIl; for example, B=0.30TB=0.30\,\text{T}, I=2.0AI=2.0\,\text{A} and l=0.40ml=0.40\,\text{m} give F=0.24NF=0.24\,\text{N}.
  • A common error is to use electron flow for the current finger or to apply F=BIlF=BIl unchanged when the conductor is not at right angles to the field.
Worked example

In Fleming's left-hand rule, state what the first finger and thumb represent.

  1. 1.Recall the ordered labels: first finger is field, second finger is conventional current, and thumb is force.

Answer: First finger: magnetic field direction. Thumb: force or motion direction.

Common mistakes

  • Don't use electron flow for the current finger or to apply F=BIlF=BIl unchanged when the conductor is not at right angles to the field.
  • Don't fall into the trap of using Fleming's right hand instead of the left hand for the motor effect.

Exam tip

Apply Fleming's left-hand rule with field, current and force mutually perpendicular.

Tier 1 · Easy

ORIGINAL

A current-carrying wire in a magnetic field experiences an upward force. The magnetic field is unchanged, but the current is reversed. State the new force direction and explain.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A 0.18m0.18\,\text{m} wire section is perpendicular to a 0.45T0.45\,\text{T} magnetic field and carries 3.2A3.2\,\text{A}. Calculate the force on the section.

[2 marks]

Total for this question: 2

Tier 3 · Hard

ORIGINAL

A wire of active length 0.35m0.35\,\text{m} experiences a 0.63N0.63\,\text{N} downward force while carrying 4.0A4.0\,\text{A} perpendicular to a uniform field. Determine the magnetic flux density. Then state the new force direction if only the current is reversed.

[4 marks]

Total for this question: 4

4.7.2.3

Electric motors (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • In a motor, opposite sides of a current-carrying coil experience forces in opposite directions because their currents run oppositely through the magnetic field.
  • These forces form a turning effect; use Fleming's left-hand rule separately on each active side to predict the rotation direction.
  • A split-ring commutator reverses the current every half-turn, so the forces swap sides and the turning effect continues in the same rotational direction.
  • A common error is to say the coil turns because unlike poles attract; the required explanation is the motor-effect force on current-carrying conductors in a magnetic field.
Worked example

State the energy transfer performed by an electric motor and name the effect that produces its turning force.

  1. 1.A motor uses current to produce motion, so its useful transfer is electrical to kinetic. The force on the current-carrying coil is the motor effect.

Answer: Electrical energy is transferred to kinetic energy. The motor effect produces the force.

Common mistakes

  • Don't say the coil turns because unlike poles attract; the required explanation is the motor-effect force on current-carrying conductors in a magnetic field.
  • Don't fall into the trap of saying the forces on a motor coil act in the same direction.

Exam tip

Explain motor rotation using opposite forces on the two current-carrying sides of the coil.

Tier 1 · Easy

ORIGINAL

In a simple electric motor the current in the coil is reversed every half-turn. Explain why this reversal is necessary.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Explain why a rectangular current-carrying coil between magnetic poles begins to rotate rather than simply moving sideways.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A simple motor is turning slowly. Explain how increasing the current and adding a stronger magnet affect its motion, and explain why its split-ring commutator must reverse the current after each half-turn.

[6 marks]

Total for this question: 6

4.7.2.4

Loudspeakers (physics only) (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A moving-coil loudspeaker uses the motor effect to convert variations in electrical current into pressure variations in a sound wave.
  • The alternating current in the voice coil repeatedly reverses, so the motor-effect force reverses and the coil moves backwards and forwards in the permanent magnet's field.
  • The coil is attached to a cone: larger current variations produce larger cone displacements and a louder sound, while faster variations produce a higher-frequency sound.
  • A common error is to describe electromagnetic induction in a loudspeaker; induction is used by a microphone, whereas a loudspeaker requires force on a supplied current.
Worked example

Name the effect used by a moving-coil loudspeaker and state what the cone transfers energy to.

  1. 1.Current in a magnetic field gives a force by the motor effect. The moving cone makes pressure variations in the air, transferring energy as sound.

Answer: The motor effect. The cone transfers energy to the surrounding air as sound waves.

Common mistakes

  • Don't describe electromagnetic induction in a loudspeaker; induction is used by a microphone, whereas a loudspeaker requires force on a supplied current.
  • Don't fall into the trap of saying the cone moves without the current changing direction.

Exam tip

Link alternating current to a reversing force and therefore vibration of the loudspeaker cone.

Tier 1 · Easy

ORIGINAL

For the same moving-coil loudspeaker, state how increasing the amplitude and increasing the frequency of the alternating current affect the sound.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Explain how an alternating electrical signal makes the cone of a moving-coil loudspeaker vibrate.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Signal A has twice the frequency of signal B but a smaller current amplitude. Compare the sounds produced when each signal drives the same ideal loudspeaker, and justify both comparisons using the coil's motion.

[4 marks]

Total for this question: 4

4.7.3.1

Induced potential (physics only) (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • The generator effect induces a potential difference when a conductor moves relative to a magnetic field or when the magnetic field around it changes; a complete circuit then carries an induced current.
  • Increase the induced potential difference by increasing relative speed, field strength or coil turns; reversing either the relative motion or the magnetic-field direction reverses the induced potential difference and current.
  • The induced current creates its own magnetic field opposing the change that produced it, so pushing a magnet into a coil produces a magnetic effect that resists the push.
  • A common error is to say a stationary magnet permanently induces current in a stationary coil: induction requires relative motion or a changing magnetic field.
Worked example

A bar magnet is held motionless inside a coil connected to a sensitive voltmeter. State the reading after the magnet has stopped moving and explain it.

  1. 1.The generator effect needs a changing magnetic field around the conductor. Once the magnet is stationary, that change stops, so no potential difference is induced.

Answer: The reading is zero. There is no relative motion or change in magnetic field through the coil.

Common mistakes

  • Don't say a stationary magnet permanently induces current in a stationary coil: induction requires relative motion or a changing magnetic field.
  • Don't fall into the trap of claiming a stationary magnet inside a coil induces a potential difference.

Exam tip

For induction, state the change in magnetic field through the conductor and how to increase it.

Tier 1 · Easy

ORIGINAL

State two changes that increase the induced potential difference when a bar magnet is moved into a coil.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A magnet is pushed into a 200-turn coil and then withdrawn at the same speed. Describe the two voltmeter pulses and state two changes that would increase their magnitudes.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A student feels a resisting force while pushing the north pole of a magnet into a short-circuited coil. Explain the resistance, predict what happens to the induced current direction when the magnet is pulled out, and state why pulling it out faster requires more work per second.

[6 marks]

Total for this question: 6

4.7.3.2

Uses of the generator effect (physics only) (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • An alternator rotates a coil in a magnetic field and generates alternating potential difference, so its output reverses every half-turn.
  • A dynamo uses a split-ring commutator to exchange coil connections every half-turn, producing a direct potential difference of one polarity.
  • For steady rotation, the alternator graph crosses zero when the coil sides move parallel to the field and reaches maximum magnitude when they cut field lines at the greatest rate.
  • A common error is to draw a constant dc line for a dynamo: its output keeps one polarity but normally varies in magnitude as the coil rotates.
Worked example

State which device generates ac, an alternator or a dynamo, and identify the output produced by the other device.

  1. 1.Match the devices to their outputs: continuous slip rings retain the alternator's reversal, while a split-ring commutator makes the dynamo output unidirectional.

Answer: An alternator generates ac. A dynamo generates dc.

Common mistakes

  • Don't draw a constant dc line for a dynamo: its output keeps one polarity but normally varies in magnitude as the coil rotates.
  • Don't fall into the trap of confusing an alternator's slip rings with a motor's split-ring commutator.

Exam tip

Compare generators by naming the rotating part and whether the output is alternating or direct.

Tier 1 · Easy

ORIGINAL

Explain why the potential difference produced by a rotating-coil alternator reverses every half-turn.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

An alternator coil completes five rotations each second. Determine the frequency and period of its output potential difference, then state how the graph changes if the rotation rate doubles.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Two otherwise identical rotating-coil generators use the same field and speed. Generator P uses slip rings; generator Q uses a split-ring commutator. Compare their potential-difference-against-time graphs and explain the role of Q's commutator.

[5 marks]

Total for this question: 5

4.7.3.3

Microphones (physics only) (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A moving-coil microphone uses the generator effect to convert pressure variations in sound into variations in current in an electrical circuit.
  • Sound pressure makes a diaphragm vibrate; its attached coil moves relative to a permanent magnet's field, inducing a varying potential difference.
  • The induced signal follows the diaphragm: greater sound amplitude gives greater coil speed and signal amplitude, while sound frequency sets the signal frequency.
  • A common error is to supply a driving current to the microphone coil; the sound-driven motion induces the signal, whereas supplied current drives a loudspeaker.
Worked example

State the input and output of a moving-coil microphone.

  1. 1.A microphone is a transducer from sound to electrical signal, so identify air-pressure variation as the input and a varying electrical signal as the output.

Answer: Input: pressure variations in a sound wave. Output: variations in electrical potential difference or current.

Common mistakes

  • Don't supply a driving current to the microphone coil; the sound-driven motion induces the signal, whereas supplied current drives a loudspeaker.
  • Don't fall into the trap of describing a microphone as converting electrical energy into sound.

Exam tip

A microphone explanation should follow sound vibration to coil motion to induced electrical signal.

Tier 1 · Easy

ORIGINAL

A louder sound of the same pitch enters a moving-coil microphone. Compare the new electrical signal with the original signal.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Explain the sequence by which a singer's sound produces an electrical signal in a moving-coil microphone.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Tones P and Q have the same pitch, but P is louder. Tones R and S have the same loudness, but R has the higher pitch. All four are recorded by one ideal moving-coil microphone. Compare the relevant electrical signals and explain the generator-effect link.

[5 marks]

Total for this question: 5

4.7.3.4

Transformers (physics only) (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A transformer has primary and secondary coils wound on an easily magnetised iron core; alternating current in the primary produces a changing core field that induces a potential difference in the secondary.
  • Use VpVs=npns\dfrac{V_{\mathrm{p}}}{V_{\mathrm{s}}}=\dfrac{n_{\mathrm{p}}}{n_{\mathrm{s}}}: more secondary turns than primary turns gives a step-up transformer, and fewer gives a step-down transformer.
  • For an ideal transformer, input and output powers are equal, so VpIp=VsIsV_{\mathrm{p}}I_{\mathrm{p}}=V_{\mathrm{s}}I_{\mathrm{s}}; raising transmission potential difference reduces current for the same power and therefore reduces heating losses.
  • A common error is to connect a transformer to steady dc: without a changing primary current there is no continuously changing core field and therefore no continuous secondary potential difference.
Worked example

A transformer has 300 turns on its primary coil and 900 turns on its secondary coil. State whether it is step-up or step-down and give the potential-difference factor.

  1. 1.The turn ratio is ns/np=900/300=3n_{\mathrm{s}}/n_{\mathrm{p}}=900/300=3. The secondary has more turns, so Vs=3VpV_{\mathrm{s}}=3V_{\mathrm{p}} and the transformer is step-up.

Answer: It is step-up. The secondary potential difference is three times the primary potential difference.

Common mistakes

  • Don't connect a transformer to steady dc: without a changing primary current there is no continuously changing core field and therefore no continuous secondary potential difference.
  • Don't fall into the trap of using the turns ratio upside down when calculating secondary potential difference.

Exam tip

Write Vp/Vs=Np/NsV_p/V_s=N_p/N_s and use conservation of power for an ideal transformer.

Tier 1 · Easy

ORIGINAL

Explain why connecting a transformer primary to a steady direct current does not produce a continuous potential difference across the secondary.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

An ideal transformer has 12001200 primary turns and 8080 secondary turns. Its primary potential difference is 230V230\,\text{V}. Calculate the secondary potential difference.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

An ideal step-up transformer supplies 18.0kW18.0\,\text{kW} at 12.0kV12.0\,\text{kV} from a 240V240\,\text{V} primary. Calculate the secondary current, the primary current and the secondary-to-primary turn ratio. Explain one transmission advantage of the high output potential difference.

[6 marks]

Total for this question: 6

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