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AQA GCSE Physics revision notes

Atomic structure

Section 4.4
12 specification points

Notes and three levels of exam-style practice for each registered specification point in this section.

Checked against AQA 8463 section 4.4

Checked against AQA 8463 section 4.4. Review basis: the qualification registry sourced from the AQA GCSE Physics (8463) specification; registry verification recorded 17 July 2026.

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4.4.1.1

The structure of an atom

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • An atom has a tiny, positively charged nucleus containing protons and neutrons, with negatively charged electrons arranged at different energy levels around it.
  • Compare scales using a ratio: an atom has radius about 1×1010m1\times10^{-10}\,\mathrm{m}, while its nucleus has less than 1/100001/10\,000 of the atom's radius.
  • Most atomic mass is concentrated in the nucleus; absorbing electromagnetic radiation can move an electron to a higher energy level, while emitting it can move the electron lower.
  • A common error is to draw the nucleus as most of the atom: it contains most of the mass but occupies only a very small central region.
A tiny central nucleus with electrons occupying energy levels around it.
Worked example

An atom has radius 1.0×1010m1.0\times10^{-10}\,\mathrm{m} and its nucleus has radius 8.0×1015m8.0\times10^{-15}\,\mathrm{m}. Calculate how many times larger the atom's radius is.

  1. 1.Calculate (1.0×1010)/(8.0×1015)=0.125×105=1.25×104(1.0\times10^{-10})/(8.0\times10^{-15})=0.125\times10^5=1.25\times10^4. The atom's radius is therefore 1250012\,500 times the nucleus's radius.

Answer: Use atom radius divided by nucleus radius. 1.25×1041.25\times10^4 times

Common mistakes

  • Don't draw the nucleus as most of the atom: it contains most of the mass but occupies only a very small central region.
  • Don't fall into the trap of drawing electrons inside the nucleus rather than in shells around it.

Exam tip

For atomic structure, give particle charge, relative mass and location precisely.

Tier 1 · Easy

ORIGINAL

Explain why an atom is described as mostly empty space even though nearly all its mass is concentrated at its centre.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Describe the positions and charges of the three subatomic particles in an atom, and state where nearly all the atom's mass is found.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

An atom absorbs electromagnetic radiation and later emits electromagnetic radiation. Explain what can happen to one of its electrons in the two changes.

[2 marks]

Total for this question: 2

Your progress and exam materials
4.4.1.2

Mass number, atomic number and isotopes

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Atomic number is the number of protons; mass number is the total number of protons and neutrons, so neutron number is mass number minus atomic number.
  • For a neutral atom, electron number equals proton number; for a positive ion, subtract the positive charge from the proton number to find its electrons.
  • Isotopes are atoms of the same element with the same proton number but different neutron numbers, so their atomic numbers match but their mass numbers differ.
  • A common error is to change the nucleus when an ion forms: losing outer electrons changes the charge, not the atomic number or mass number.
Worked example

A neutral atom contains 1717 protons and 2020 neutrons. State its atomic number, mass number and number of electrons.

  1. 1.The atomic number equals the proton number, so it is 1717. Add protons and neutrons for the mass number: 17+20=3717+20=37. A neutral atom has equal proton and electron numbers, so it has 1717 electrons.

Answer: Atomic number =17=17 Mass number =37=37 Number of electrons =17=17

Common mistakes

  • Don't change the nucleus when an ion forms: losing outer electrons changes the charge, not the atomic number or mass number.
  • Don't fall into the trap of calculating neutron number by adding atomic number and mass number.

Exam tip

Use neutron number = mass number − atomic number and keep isotope notation consistent.

Tier 1 · Easy

ORIGINAL

Two atoms have the same number of protons but different numbers of neutrons. State the relationship between the atoms and explain why they are the same element.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

For the ion 1327Al3+{}^{27}_{13}\mathrm{Al}^{3+}, determine the numbers of protons, neutrons and electrons.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Two isotopes of element QQ have mass numbers 6363 and 6565. An ion of the first isotope has charge 2+2+ and contains 2727 electrons. Determine the atomic number of QQ, the neutron number of each isotope, and explain why both are the same element.

[5 marks]

Total for this question: 5

4.4.1.3

The development of the model of the atom (common content with chemistry)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Atoms were first treated as indivisible spheres; discovery of the electron led to the plum pudding model, with electrons embedded in a ball of positive charge.
  • Use scattering evidence in order: most alpha particles passed through, so atoms are mostly empty space; a few were strongly deflected, so charge and most mass occupy a tiny nucleus.
  • Bohr proposed electrons at specific distances, later evidence identified protons in the nucleus, and Chadwick's work provided evidence for neutrons.
  • A common error is to say Rutherford expected every alpha particle to rebound: the key comparison is between the observed pattern and the plum pudding model's prediction of only small deflections.
Worked example

Put these developments in chronological order: the nuclear model, the plum pudding model, evidence for the neutron, and electrons at specific distances from the nucleus.

  1. 1.The electron discovery produced the plum pudding model. Alpha scattering then produced the nuclear model. Bohr next placed electrons at specific distances, and Chadwick's neutron evidence came later.

Answer: Plum pudding model, nuclear model, electrons at specific distances, evidence for the neutron

Common mistakes

  • Don't say Rutherford expected every alpha particle to rebound: the key comparison is between the observed pattern and the plum pudding model's prediction of only small deflections.
  • Don't fall into the trap of describing Rutherford scattering without linking the observations to the nuclear model.

Exam tip

For model-development questions, link each new observation to the change it forced in the model.

Tier 1 · Easy

ORIGINAL

In the alpha-scattering experiment, most alpha particles passed straight through the metal foil. What did this observation show about the structure of an atom?

[1 mark]

Total for this question: 1

Tier 2 · Standard

ORIGINAL

In an alpha-scattering investigation, nearly all particles cross a thin metal sheet without changing direction, while a very small fraction turn through large angles. Explain two conclusions that caused the plum pudding model to be replaced.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A student says, 'Once the nucleus was proposed, the atomic model was complete.' Use later changes to the model to evaluate this statement.

[6 marks]

Total for this question: 6

4.4.2.1

Radioactive decay and nuclear radiation

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • An unstable nucleus decays at random; activity is its decay rate in becquerels (Bq\mathrm{Bq}), while count rate is the number of decays recorded each second by a detector such as a Geiger-Muller tube.
  • Identify radiation by composition and properties: alpha is two protons plus two neutrons, beta is a fast electron from the nucleus, gamma is electromagnetic radiation, and a neutron may also be emitted.
  • Alpha has the shortest range and greatest ionising power, beta is intermediate, and gamma is the most penetrating and least ionising of the three.
  • A common error is to call beta an orbital electron or gamma a charged particle: beta forms when a neutron changes into a proton, while gamma has no charge or mass.
Relative penetration of alpha, beta and gamma radiation.
Worked example

Name the radiation described in each case: (i) two protons and two neutrons, (ii) electromagnetic radiation from a nucleus, (iii) a fast electron emitted when a neutron changes.

  1. 1.Match composition before using penetration: a helium nucleus is alpha, an electromagnetic wave from the nucleus is gamma, and the nuclear electron produced in a neutron-to-proton change is beta.

Answer: (i) alpha (ii) gamma (iii) beta

Common mistakes

  • Don't call beta an orbital electron or gamma a charged particle: beta forms when a neutron changes into a proton, while gamma has no charge or mass.
  • Don't fall into the trap of saying gamma radiation is a charged particle.

Exam tip

Compare alpha, beta and gamma by ionising power, penetration and range.

Tier 1 · Easy

ORIGINAL

State the unit of activity and explain what an activity of 11 in this unit means.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Radiation PP is stopped by card, QQ crosses card but is stopped by a thin aluminium sheet, and RR crosses both but is reduced by thick lead. Identify PP, QQ and RR, then state which has the greatest ionising power.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A sealed source must send radiation through several centimetres of tissue to a target while limiting ionisation of healthy tissue along the path. Compare alpha, beta and gamma, and choose the most suitable radiation.

[5 marks]

Total for this question: 5

4.4.2.2

Nuclear equations

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Balance a nuclear equation by making the total mass number and total atomic number equal on both sides.
  • For alpha emission use 24α{}^{4}_{2}\alpha; for beta-minus emission use 10β{}^{0}_{-1}\beta, so the daughter's atomic number is one greater while its mass number is unchanged.
  • For example, after one alpha emission a parent labelled A,ZA,Z becomes A4,Z2A-4,Z-2; gamma emission changes neither number.
  • A common error is to decrease atomic number in beta-minus decay: the emitted beta has atomic number 1-1, so the daughter must increase by 11 to balance.
Worked example

Complete 84218X82214Y+?{}^{218}_{84}X\rightarrow{}^{214}_{82}Y+\,? by giving the emitted particle in full nuclear notation.

  1. 1.Subtract daughter numbers from parent numbers: 218214=4218-214=4 and 8482=284-82=2. The missing radiation is therefore an alpha particle, 24α{}^{4}_{2}\alpha.

Answer: Mass number of the particle =4=4 and atomic number =2=2. 24α{}^{4}_{2}\alpha

Common mistakes

  • Don't decrease atomic number in beta-minus decay: the emitted beta has atomic number 1-1, so the daughter must increase by 11 to balance.
  • Don't fall into the trap of changing both atomic and mass number for beta-minus decay.

Exam tip

Balance both mass number and atomic number on each side of a nuclear equation.

Tier 1 · Easy

ORIGINAL

A nucleus emits gamma radiation. State what happens to the nucleus's mass number and atomic number.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Complete the beta-minus equation 53131XZAY+10β{}^{131}_{53}X\rightarrow{}^{A}_{Z}Y+{}^{0}_{-1}\beta by determining AA and ZZ.

[2 marks]

Total for this question: 2

Tier 3 · Hard

ORIGINAL

A nucleus 96240M{}^{240}_{96}M emits one alpha particle and then two beta-minus particles. Determine the mass number and atomic number of the final nucleus, showing the change at each stage.

[4 marks]

Total for this question: 4

4.4.2.3

Half-lives and the random nature of radioactive decay

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Half-life is the time for the number of undecayed nuclei, activity or net count rate to fall to half its initial value; individual nuclear decays remain unpredictable.
  • Subtract background count rate before finding successive halvings, then divide the elapsed time by the number of half-lives.
  • A fall from 960960 to 120120 is three halvings because 960480240120960\rightarrow480\rightarrow240\rightarrow120; Higher tier can express the remaining-to-original ratio as 1:81:8.
  • A common error is to subtract the same amount in every half-life or to halve a gross detector reading without first removing background.
An exponential activity curve showing one half-life.
Worked example

The activity of a sample falls from 640Bq640\,\mathrm{Bq} to 160Bq160\,\mathrm{Bq} in 1010 hours. Determine its half-life.

  1. 1.The activity halves twice in the 1010-hour interval. Divide the total time by two: 10/2=510/2=5 hours.

Answer: 640320160640\rightarrow320\rightarrow160 is two half-lives. Half-life =5=5 hours

Common mistakes

  • Don't subtract the same amount in every half-life or to halve a gross detector reading without first removing background.
  • Don't fall into the trap of saying exactly half the nuclei decay in every small sample.

Exam tip

For half-life, show repeated halving or use two well-separated points on the decay curve.

Tier 1 · Easy

ORIGINAL

Explain why the exact time at which one particular unstable nucleus will decay cannot be predicted, even when the isotope's half-life is known.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A detector records 420420 counts per minute beside a source at time zero and 7070 counts per minute 1818 minutes later. Background count rate is 2020 counts per minute. Calculate the source's half-life.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A detector beside a source reads 830830 counts per minute initially and 130130 counts per minute after 1212 minutes. Background is 3030 counts per minute. Determine the half-life, then explain why repeated one-minute readings taken at the same time would not all be identical.

[6 marks]

Total for this question: 6

4.4.2.4

Radioactive contamination

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Contamination is the unwanted presence of material containing radioactive atoms; irradiation is exposure to nuclear radiation without transfer of radioactive material.
  • Compare hazards by asking whether the source can remain on or enter the body, which radiation it emits, and how exposure can be shortened, shielded or kept at a distance.
  • An alpha contaminant outside the body may be stopped by skin, but the same material inside the body can be especially hazardous because alpha is strongly ionising at short range.
  • A common error is to say an irradiated object must become radioactive; irradiation stops when exposure ends, whereas contaminating atoms continue to decay until removed or decayed.
Worked example

A wrapped instrument is placed near a sealed gamma source and then removed. No radioactive material touches it. State whether this is contamination or irradiation, and whether the instrument becomes radioactive.

  1. 1.The source only exposes the instrument to radiation; no radioactive atoms are transferred. This is irradiation, and the irradiated instrument does not itself become a radioactive source.

Answer: The instrument is irradiated. It does not become radioactive.

Common mistakes

  • Don't say an irradiated object must become radioactive; irradiation stops when exposure ends, whereas contaminating atoms continue to decay until removed or decayed.
  • Don't fall into the trap of confusing irradiation with contamination by radioactive material.

Exam tip

State whether the hazard is an external source or radioactive material on or inside the body.

Tier 1 · Easy

ORIGINAL

Radioactive liquid is spilled onto a worker's glove. Explain why removing the glove reduces the worker's exposure even after the original container has been moved away.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Compare the hazard from an alpha-emitting speck held outside the body with the hazard if the same speck is inhaled. Give a suitable precaution.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A small study reports that workers exposed near a sealed radiation source have a higher illness rate. Explain why publishing the method and results for peer review is important before concluding that irradiation caused the illnesses.

[5 marks]

Total for this question: 5

4.4.3.1

Background radiation (physics only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Background radiation is always present and includes natural sources such as radioactive rocks and cosmic rays, plus man-made fallout from weapons tests and nuclear accidents.
  • When comparing measurements, allow for location, altitude, surrounding rock and occupation, and subtract a local background count rate when isolating a source's count rate.
  • For dose, 1000mSv=1Sv1000\,\mathrm{mSv}=1\,\mathrm{Sv}; a worker's total dose can be estimated by adding the contributions from different exposures over the stated time.
  • A common error is to assume a detector should read zero after a test source is removed: background radiation continues to produce counts.
Worked example

Classify each source of background radiation as natural or man-made: cosmic rays, radioactive rock, and fallout from a nuclear weapons test.

  1. 1.Cosmic radiation arrives from space and radioactivity occurs naturally in rock. Fallout is produced by human nuclear weapons testing, so it is man-made.

Answer: Cosmic rays: natural Radioactive rock: natural Weapons-test fallout: man-made

Common mistakes

  • Don't assume a detector should read zero after a test source is removed: background radiation continues to produce counts.
  • Don't fall into the trap of assuming background count is zero when no source is present.

Exam tip

Subtract background count from the measured count before interpreting source activity.

Tier 1 · Easy

ORIGINAL

A detector still records counts after a test source has been removed. Give one source of these counts and explain why the reading is not necessarily a detector fault.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A detector averages 1818 counts per minute at sea level on sedimentary ground and 3131 counts per minute at a high-altitude site on granite. Suggest two reasons for the difference and explain why neither reading should be treated as zero-source error.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A cave guide receives 0.006mSv0.006\,\mathrm{mSv} per working week from surrounding rock and works 4848 weeks. An airline worker receives 0.009mSv0.009\,\mathrm{mSv} per working week from additional cosmic radiation for 4848 weeks. Calculate each annual occupational dose, compare them, and express the larger in sieverts.

[4 marks]

Total for this question: 4

4.4.3.2

Different half-lives of radioactive isotopes (physics only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Radioactive isotopes span a very wide range of half-lives, so the duration and rate of a hazard depend on the isotope present.
  • Compare hazards using both activity and persistence: a short half-life means rapid decay and a quickly falling hazard, while a long half-life can leave material radioactive for much longer.
  • For equal numbers of unstable nuclei, a shorter-half-life isotope undergoes decays more rapidly at first; a longer-half-life isotope generally creates the longer waste-management problem.
  • A common error is to call either short or long half-life always safer: risk also depends on quantity, radiation type, route into the body and exposure time.
Worked example

Two contaminants have half-lives of 66 hours and 2424 years. Which contaminant can remain a disposal hazard for longer? Explain your choice.

  1. 1.A longer half-life means fewer successive halvings occur in a fixed time. The 2424-year isotope therefore remains radioactive over a much longer storage period.

Answer: The isotope with the 2424-year half-life Its activity falls much more slowly, so radioactive material persists for longer.

Common mistakes

  • Don't call either short or long half-life always safer: risk also depends on quantity, radiation type, route into the body and exposure time.
  • Don't fall into the trap of saying a long half-life always means a high activity.

Exam tip

A half-life comparison must distinguish activity from how quickly activity decreases.

Tier 1 · Easy

ORIGINAL

Samples PP and QQ contain equal numbers of unstable nuclei and emit the same type of radiation. PP has the shorter half-life. Which sample has the greater initial activity? Explain.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Samples AA and BB initially have the same activity and emit the same type of radiation. AA has half-life 33 hours; BB has half-life 4040 years. Compare how their hazards change after the samples are securely stored.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Equal numbers of nuclei of isotopes CC and DD are spilled. CC has half-life 2.0×102s2.0\times10^2\,\mathrm{s} and DD has half-life 6.0×107s6.0\times10^7\,\mathrm{s}. Compare the likely initial and long-term hazards, stating why half-life alone cannot determine the total risk.

[5 marks]

Total for this question: 5

4.4.3.3

Uses of nuclear radiation (physics only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A medical tracer for exploring an organ should be detectable outside the body, so a penetrating radiation such as gamma is useful, and its half-life should limit the time the patient remains radioactive.
  • For controlling or destroying unwanted tissue, direct radiation at the target or place a suitable source close to it while limiting dose to healthy cells.
  • Evaluate a use by comparing diagnostic or treatment benefit with absorbed dose, radiation type, half-life, exposure time and the consequences of not carrying out the procedure.
  • A common error is to discuss only usefulness: every evaluation needs a linked risk, such as ionisation damaging healthy cells, and a way the exposure is controlled.
Worked example

Give two reasons why a gamma-emitting isotope can be suitable as a tracer for exploring an internal organ.

  1. 1.A tracer must be detected without surgery, which requires radiation able to leave the body. Gamma is penetrating and relatively weakly ionising, giving the two linked advantages.

Answer: Gamma can penetrate out of the body to an external detector. Gamma is less ionising than alpha or beta, so it causes less cell damage for a comparable exposure.

Common mistakes

  • Don't discuss only usefulness: every evaluation needs a linked risk, such as ionisation damaging healthy cells, and a way the exposure is controlled.
  • Don't fall into the trap of choosing a radiation source without considering penetration and half-life.

Exam tip

Justify a medical or industrial source using penetration, ionisation and half-life together.

Tier 1 · Easy

ORIGINAL

Explain why a medical tracer's half-life should be long enough for an investigation but not unnecessarily long.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A doctor proposes directing nuclear radiation at a tumour to destroy unwanted tissue. A smaller dose will also reach nearby healthy tissue, and without treatment the tumour is likely to grow. Evaluate this use of radiation.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A hospital needs an internal tracer that will be measured by a detector outside the body during a four-hour investigation. Candidate JJ emits alpha and has half-life 1212 years; KK emits gamma and has half-life 66 hours; LL emits gamma and has half-life 3030 years. Choose the best candidate and justify why the other two are less suitable.

[6 marks]

Total for this question: 6

4.4.4.1

Nuclear fission (physics only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Fission is the splitting of a large, unstable nucleus; it usually begins when the nucleus absorbs a neutron.
  • A fission event produces two smaller nuclei of roughly equal size, two or three neutrons and gamma rays, with released energy appearing as kinetic energy of the products.
  • Emitted neutrons can trigger further fissions: limiting how many continue gives a controlled reactor chain reaction, while continued multiplication gives an uncontrolled release.
  • A common error is to describe fission as two small nuclei joining; that is fusion, whereas fission starts with one large nucleus splitting.
A neutron-induced fission event releasing two smaller nuclei and three neutrons.
Worked example

State what usually starts a fission event and name two products other than the two smaller nuclei.

  1. 1.Begin with neutron absorption by the large unstable nucleus. After splitting, list products beyond the two daughter nuclei: emitted neutrons, gamma radiation and released kinetic energy.

Answer: A large unstable nucleus absorbs a neutron. Two or three neutrons are emitted. Gamma rays are emitted; energy or kinetic energy is also an acceptable second product.

Common mistakes

  • Don't describe fission as two small nuclei joining; that is fusion, whereas fission starts with one large nucleus splitting.
  • Don't fall into the trap of saying a neutron is created from nothing in a fission chain reaction.

Exam tip

In fission, identify neutron absorption, nucleus splitting, released energy and emitted neutrons.

Tier 1 · Easy

ORIGINAL

Explain how neutrons released by one fission event can produce a chain reaction.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

In a simplified chain reaction, every fission releases three neutrons and every released neutron causes one new fission. Starting with one fission in generation 1, calculate the numbers of fissions in generations 2, 3 and 4.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

Sketch and label a chain-reaction diagram beginning with a neutron absorbed by one large unstable nucleus. Show that fission releasing two neutrons can cause the next generation, then explain how a controlled reactor prevents the number of fissions increasing each generation.

[5 marks]

Total for this question: 5

4.4.4.2

Nuclear fusion (physics only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Fusion is the joining of two light nuclei to form a heavier nucleus.
  • Identify fusion from the pattern of two small nuclear reactants becoming one larger nuclear product, rather than from the presence of radiation alone.
  • The combined mass of the nuclear product can be slightly less than that of the starting nuclei; the mass difference is converted into energy carried by radiation.
  • A common error is to call any energy-releasing nuclear process fusion: fission splits one large nucleus, while fusion joins two light nuclei.
Worked example

Complete the definition: nuclear fusion is the joining of two ______ nuclei to make a ______ nucleus.

  1. 1.Fusion begins with two light nuclei and combines them into a nucleus heavier than either starting nucleus.

Answer: light heavier

Common mistakes

  • Don't call any energy-releasing nuclear process fusion: fission splits one large nucleus, while fusion joins two light nuclei.
  • Don't fall into the trap of confusing fusion of light nuclei with fission of a heavy nucleus.

Exam tip

For fusion, name the light nuclei, the heavier product and the need for very high temperature.

Tier 1 · Easy

ORIGINAL

In nuclear fusion the product nucleus has slightly less mass than the two original nuclei. State what happens to this missing mass, and name the condition needed for fusion to occur.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Compare nuclear fusion with nuclear fission in terms of the nuclei before and after each process, and state one energy feature shared by them.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

An experiment shows two light nuclei combining into one heavier nucleus while radiation leaves the reaction. The measured mass of the heavier nucleus is slightly smaller than the total mass of the two starting nuclei. Explain why the observations support fusion and account for the mass difference.

[5 marks]

Total for this question: 5

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