Successive crests of a progressive wave are apart and pass a point every . Calculate the wave speed.
Waves
Notes and three levels of exam-style practice for each registered specification leaf in this section.
Open the printable packProgressive waves
- A progressive wave transfers energy without a net transfer of matter; particles of a material medium oscillate about fixed equilibrium positions.
- Use , with in , in and in .
- For points separated by along a wave, the phase difference is radians, or degrees, reduced by whole cycles when appropriate.
- Amplitude is the maximum displacement from equilibrium. Do not confuse it with wavelength, which is the shortest distance between points in phase.
Tier 1 · Easy
Tier 2 · Standard
Two sensors on a ripple tank are apart along the direction of a progressive wave of wavelength . Determine the magnitude of their phase difference in both degrees and radians.
Tier 3 · Hard
Water waves of frequency and wavelength travel from P towards Q. Q is beyond P along the direction of travel. Determine the wave speed, the phase change from P to Q, and the delay between a crest passing P and that crest passing Q.
Longitudinal and transverse waves
- In a transverse wave, the displacement of particles or fields is perpendicular to the direction of energy transfer; electromagnetic waves and waves on a stretched string are examples.
- In a longitudinal wave, particle displacement is parallel to the direction of energy transfer, producing compressions and rarefactions; sound in air is an example.
- Only transverse waves can be polarised. Polarisation is therefore evidence that electromagnetic waves are transverse.
- A receiving aerial gives the strongest signal when aligned with the transmitted electric-field oscillations. Malus's law is not required for this specification.
- All electromagnetic waves travel at in a vacuum; do not use the speed of sound for a radio signal.
Tier 1 · Easy
State whether a sound wave travelling through air is longitudinal or transverse, and state the direction in which the air molecules oscillate.
Tier 2 · Standard
A radio transmitter produces a vertically polarised wave. Explain why the signal received by a straight aerial decreases when the aerial is rotated from vertical towards horizontal.
Tier 3 · Hard
At a distance of , a detector receives a radio pulse and a sound pulse that were emitted simultaneously. Take the speed of sound as . Calculate the arrival-time difference and explain why passing the radio wave through a correctly oriented polariser supports its classification as transverse.
Principle of superposition of waves and formation of stationary waves
- Superposition means that the resultant displacement at a point is the vector sum of the displacements due to the individual waves.
- A stationary wave is formed by two progressive waves of the same frequency travelling in opposite directions; it has nodes of zero amplitude and antinodes of maximum amplitude.
- For a string fixed at both ends, adjacent nodes are apart. The th harmonic has loops, nodes and frequency .
- In the first harmonic, and . A common error is to set .
- A stationary wave has no net energy transfer along the pattern; particles within one loop oscillate in phase, while particles in adjacent loops are in antiphase.
Tier 1 · Easy
State the difference between a node and an antinode in a stationary wave.
Tier 2 · Standard
A string of length is fixed at both ends. Its tension is and its mass per unit length is . Determine the frequency of its first harmonic.
Tier 3 · Hard
A string fixed at both ends has mass per unit length . Its third-harmonic stationary wave has frequency . Determine the string tension and the numbers of nodes and antinodes in this pattern.
Interference
- Coherent sources have a constant phase difference and the same frequency. Coherence is required for a stable interference pattern.
- Constructive interference occurs for path difference ; destructive interference occurs for path difference when the sources are in phase.
- For Young's double slits at small angles, fringe spacing is , where is slit-to-screen distance and is slit separation.
- Measure across several fringe spacings and divide to reduce percentage uncertainty. Keep , , and in consistent units.
- A laser supplies monochromatic coherent light, but laser beams must never be viewed directly or through an optical instrument.
Tier 1 · Easy
State the two conditions that two sources must satisfy to be coherent.
Tier 2 · Standard
Light of wavelength illuminates two slits separated by . A screen is from the slits. Calculate the fringe spacing.
Tier 3 · Hard
In a Young double-slit experiment, the distance from the first to the ninth bright fringe is . The screen is from the slits and the wavelength is . Determine the slit separation. Explain the appearance near the centre when the laser is replaced by white light.
Diffraction
- Diffraction is the spreading of a wave after it passes through an aperture or around an obstacle; it is most pronounced when the aperture is comparable with the wavelength.
- For a single slit, decreasing slit width or increasing wavelength increases the angular width of the central maximum.
- For a plane transmission grating at normal incidence, maxima satisfy , where is grating spacing and is the order.
- Convert a line density into spacing with in SI units, and reject an order if the calculation requires .
- A monochromatic single-slit pattern has a broad bright central maximum and weaker side maxima; white light gives a white centre with coloured edges.
Tier 1 · Easy
State how the width of the central diffraction maximum changes when monochromatic light passes through a narrower single slit.
Tier 2 · Standard
A diffraction grating has lines per . Light of wavelength is incident normally. Calculate the angle of the first-order maximum.
Tier 3 · Hard
A plane transmission grating has lines per . It is illuminated normally with light of wavelength . Determine the highest observable order and the angle of this order. Explain why the next order cannot occur.
Refraction at a plane surface
- The refractive index is . At a boundary, Snell's law is , with angles measured from the normal.
- Total internal reflection occurs only when light travels from higher to lower refractive index and the incidence angle exceeds the critical angle, where .
- A step-index fibre has a higher-index core and lower-index cladding, allowing total internal reflection while protecting the boundary and reducing signal leakage between fibres.
- Modal dispersion arises because rays follow paths of different lengths; material dispersion arises because refractive index and speed depend on wavelength.
- Dispersion and absorption broaden or weaken pulses, limiting bandwidth and repeater spacing. A common error is to use angles to the surface rather than to the normal.
Tier 1 · Easy
Light travels through a transparent material at . Calculate its refractive index.
Tier 2 · Standard
A ray in glass of refractive index meets a glass-air boundary at an incidence angle of . Determine whether total internal reflection occurs.
Tier 3 · Hard
A step-index optical fibre has core refractive index and cladding refractive index . A ray in the core meets the boundary at to the normal. Show that the ray is guided. Explain how material dispersion and modal dispersion broaden a light pulse in this fibre.