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Radioactive decay and half-life

Nuclear physics
AQA 7408
In the data booklet
ORIGINAL

N = N0 e−lambda t and T1/2 = ln(2) / lambda

Keep time and decay constant in matching units; hours with per hour is just as valid as seconds with per second.

Verified against AQA 7408 (2026 spec)

Know the equation

SymbolQuantityUnit
Nnumber of undecayed nuclei after time tno unit
N0initial number of undecayed nucleino unit
lambdadecay constants−1 (or matching time−1)
ttimes (or matching time unit)
T1/2half-lifes (or matching time unit)

Rearrangements

  • lambda = -ln(N / N0) / t
  • t = -ln(N / N0) / lambda
  • N0 = N elambda t
  • lambda = ln(2) / T1/2

Apply it — mark your own working

Work each one out on paper first, then reveal the mark scheme and tick the marks you actually earned. That is exactly how you should mark past papers.

Q1
4 marks

A radioactive sample initially contains 8.0 x 1012 undecayed nuclei and has a half-life of 6.0 h. Calculate the number of undecayed nuclei after 15 h.

Do the calculation on paper first — then mark it.

Q2
4 marks

The activity of a source falls from 12 MBq to 3.6 MBq in 8.0 h. Calculate its half-life.

Do the calculation on paper first — then mark it.

Where the marks get lost

  • Mixing hours with a decay constant in s−1 without converting one of them.
  • Using log base 10 instead of ln when undoing e.
  • Assuming a non-integer number of half-lives must be rounded; use the exponential for the exact fraction remaining.

Exam tip: Activity A obeys the same exponential ratio as N because A = lambda N. In ratio calculations, MBq can stay as MBq because the common factor cancels.

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