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The quadratic formula

Algebra
(1MA1) · Higher
ORIGINAL

When it won't factorise, use the formula — carefully with the signs and the rounding.

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Question

1

Solve 3x2−5x−1=03x^2 - 5x - 1 = 0, giving your answers to 2 decimal places.

Every step worked, with the reasoning.

  1. 1
    a=3, b=−5, c=−1a = 3,\ b = -5,\ c = -1

    Read off the coefficients, keeping the signs.

  2. 2
    x=−(−5)±(−5)2−4(3)(−1)2(3)x = \dfrac{-(-5) \pm \sqrt{(-5)^2 - 4(3)(-1)}}{2(3)}

    Substitute into x=−b±b2−4ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}.

  3. 3
    x=5±25+126=5±376x = \dfrac{5 \pm \sqrt{25 + 12}}{6} = \dfrac{5 \pm \sqrt{37}}{6}

    Simplify: b2−4ac=25−(−12)=37b^2 - 4ac = 25 - (-12) = 37.

  4. 4
    x=5+6.0836x = \dfrac{5 + 6.083}{6} or x=5−6.0836x = \dfrac{5 - 6.083}{6}

    37≈6.083\sqrt{37} \approx 6.083.

  5. 5
    x=1.85x = 1.85 or x=−0.18x = -0.18 (2 d.p.)

    Evaluate each and round to 2 decimal places.

Answer: x=1.85x = 1.85 or x=−0.18x = -0.18

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