Maths

Vectors, series & differential equations

Edexcel Core Pure CP1, CP4.3-4.6, CP6, CP9

A-level Further Maths (9FM0) · exam-style practice, examiner-report intelligence and the tools that drill it.

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  • Proof by induction has four visible stages: verify the base case, state the assumption for n=kn=k, prove the result for n=k+1n=k+1, then conclude for all permitted integers. The step must use the assumption rather than re-proving a special case (CP-1.1).
  • Use r=n(n+1)/2\sum r=n(n+1)/2, r2=n(n+1)(2n+1)/6\sum r^2=n(n+1)(2n+1)/6 and r3=[n(n+1)/2]2\sum r^3=[n(n+1)/2]^2 after expanding a polynomial in rr (CP-4.3).
  • For differences, rewrite uru_r as f(r+1)f(r)f(r+1)-f(r) so intermediate terms cancel. Worked example: 1r(r+1)=1r1r+1\dfrac1{r(r+1)}=\dfrac1r-\dfrac1{r+1}, hence r=1n1r(r+1)=nn+1\sum_{r=1}^n\dfrac1{r(r+1)}=\dfrac{n}{n+1} (CP-4.4).
  • A Maclaurin series is f(x)=r=0f(r)(0)r!xrf(x)=\sum_{r=0}^{\infty}\dfrac{f^{(r)}(0)}{r!}x^r. Derive it when asked; otherwise combine the standard series (CP-4.5).
  • The exe^x, sinx\sin x and cosx\cos x series are valid for every real xx; ln(1+x)\ln(1+x) is valid for 1<x1-1<x\le1; the non-terminating binomial series is valid for x<1|x|<1. If the binomial power is a non-negative integer, the series terminates and is an identity for all xx (CP-4.6).
  • A line in 3-D is r=a+λd\mathbf r=\mathbf a+\lambda\mathbf d; its Cartesian form comes from equating λ\lambda. A plane is rn=p\mathbf r\cdot\mathbf n=p, or a point plus two non-parallel direction vectors (CP-6.1 to CP-6.2).
  • The scalar product gives ab=abcosθ\mathbf a\cdot\mathbf b=|\mathbf a||\mathbf b|\cos\theta. It tests perpendicularity and supplies angles between lines, planes and a line and plane. For a line-plane angle α\alpha, use sinα=dn/(dn)\sin\alpha=|\mathbf d\cdot\mathbf n|/(|\mathbf d||\mathbf n|) (CP-6.3 to CP-6.4).
  • For a line-plane intersection, substitute the line into the plane to find the parameter. For the distance from point PP to line r=a+λd\mathbf r=\mathbf a+\lambda\mathbf d, solve [OP(a+λd)]d=0[\overrightarrow{OP}-(\mathbf a+\lambda\mathbf d)]\cdot\mathbf d=0 for the perpendicular foot, then take its distance from PP. Point-to-plane distance is OPnp/n|\overrightarrow{OP}\cdot\mathbf n-p|/|\mathbf n| (CP-6.5).
  • For lines a+λd\mathbf a+\lambda\mathbf d and b+μe\mathbf b+\mu\mathbf e, make their shortest connector c=a+λd(b+μe)\mathbf c=\mathbf a+\lambda\mathbf d-(\mathbf b+\mu\mathbf e) perpendicular to both lines: solve cd=0\mathbf c\cdot\mathbf d=0 and ce=0\mathbf c\cdot\mathbf e=0, then calculate c|\mathbf c| (CP-6.5).
  • For y+P(x)y=Q(x)y'+P(x)y=Q(x), the integrating factor is eP(x)dxe^{\int P(x)\,dx}. Multiplying makes the left side one derivative. Worked example: y+2y=exy'+2y=e^{-x} gives (e2xy)=ex(e^{2x}y)'=e^x, so y=ex+Ce2xy=e^{-x}+Ce^{-2x} (CP-9.1 to CP-9.2).
  • In modelling, define variables and units, translate each rate with the correct sign, solve, then interpret constants and long-term behaviour. For example, a falling particle with linear resistance proportional to speed can give dv/dt=gkvdv/dt=g-kv; its terminal speed g/kg/k follows by setting dv/dt=0dv/dt=0. A plausible equation can still be a poor model if that limit or its assumptions are unrealistic (CP-9.3).
  • For y+ay+by=0y''+ay'+by=0, solve the auxiliary equation m2+am+b=0m^2+am+b=0. Distinct real roots give two exponentials, a repeated root gives (A+Bx)emx(A+Bx)e^{mx}, and complex roots p±iqp\pm iq give epx(Acosqx+Bsinqx)e^{px}(A\cos qx+B\sin qx) (CP-9.4 and CP-9.6).
  • For a non-homogeneous equation, write y=CF+PIy=\text{CF}+\text{PI}. Choose the PI trial from the forcing term; if it duplicates part of the CF, multiply the trial by enough powers of xx (CP-9.5).
  • Simple harmonic motion satisfies x=ω2xx''=-\omega^2x and has solution x=Acosωt+Bsinωtx=A\cos\omega t+B\sin\omega t, with amplitude A2+B2\sqrt{A^2+B^2} and period 2π/ω2\pi/\omega; the acceleration always points towards the equilibrium position. Damping adds a velocity term and makes the auxiliary roots reveal under-, critical or over-damping (CP-9.7 to CP-9.8).
  • For coupled first-order equations, eliminate one variable to produce a second-order equation, solve it, then recover the eliminated variable from an original equation. Use every initial condition and substitute back into both equations as a check (CP-9.9).
  • Common errors: proving only the k+1k+1 case in induction, omitting a series validity range, confusing a plane normal with a line direction, using cosine instead of sine for a line-plane angle, dropping the integration constant, or choosing a PI already contained in the CF.
  • Exam technique: separate modelling, solving and interpretation. Define the equation first, keep exact constants until the final line, and use calculator graphs or numerical substitution only as checks on the analytic solution.

Where students actually lose marks

An induction proof needs a sentence that closes the logical chain from the base case and the implication to all integers in the stated domain.

Original 9FM0-style exam guidance

In 3-D geometry, write the direction vector and normal vector explicitly before selecting the angle formula; this prevents complementary-angle errors.

Original 9FM0-style exam guidance

For differential-equation models, marks are spread across forming the equation, solving it, applying conditions and interpreting the result. Do not compress these into one calculator line.

Original 9FM0-style exam guidance

Try it — exam-style

Hard
10 marks
ORIGINAL

The line ll is r=(102)+λ(211)\mathbf r=\begin{pmatrix}1\\0\\2\end{pmatrix}+\lambda\begin{pmatrix}2\\1\\-1\end{pmatrix} and the plane Π\Pi is x+2y+2z=7x+2y+2z=7. (a) Find lΠl\cap\Pi. (b) Find the acute angle between ll and Π\Pi. (c) Find the distance from the origin to Π\Pi.

Medium
7 marks
ORIGINAL

Prove by induction that r=1nr3=[n(n+1)2]2\displaystyle\sum_{r=1}^{n}r^3=\left[\dfrac{n(n+1)}2\right]^2 for every positive integer nn.

Medium
7 marks
ORIGINAL

Find the Maclaurin expansion of excosxe^x\cos x up to and including the term in x4x^4. Hence estimate e0.2cos(0.2)e^{0.2}\cos(0.2).

Medium
8 marks
ORIGINAL

A model for temperature TT degrees Celsius at time tt minutes is dTdt+0.2T=4\dfrac{dT}{dt}+0.2T=4, where T(0)=10T(0)=10. Solve the equation, find when T=15T=15, and state the limiting temperature predicted by the model.

Hard
10 marks
ORIGINAL

Solve y+4y+13y=10exy''+4y'+13y=10e^{-x} subject to y(0)=1y(0)=1 and y(0)=0y'(0)=0. Comment on the long-term behaviour.

Hard
8 marks
ORIGINAL

Solve u=u+vu'=u+v, v=4u+vv'=4u+v subject to u(0)=1u(0)=1 and v(0)=0v(0)=0.

Questions are written in the style of past Edexcel papers (source shown on each) — never copied from them.

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