Skip to content
Maths

Exponentials & logarithms

Edexcel Pure 6

A-level Maths (9MA0) · exam-style practice, examiner-report intelligence and the tools that drill it.

Board and spec code confirmed against Edexcel 9MA0 · registry checked 2026-07-11How this checking works

The topic on one screen

  • The three log laws do all the work: loga+logb=log(ab)\log a + \log b = \log(ab), logalogb=log(a/b)\log a - \log b = \log(a/b), kloga=log(ak)k\log a = \log(a^k).
  • loga(x)=y\log_a(x) = y means ay=xa^y = x. When stuck, convert to index form.
  • Solving ax=ba^x = b: take logs of both sides, x=logblogax = \dfrac{\log b}{\log a} — exact form first, decimal only if asked.
  • ee and ln\ln are inverses: elnx=xe^{\ln x} = x and ln(ex)=x\ln(e^x) = x. ln\ln appears the moment calculus is involved.
  • Log-linear modelling: V=abtV = ab^t becomes logV=loga+tlogb\log V = \log a + t\log b — a straight line in logV\log V against tt. Intercept gives aa, gradient gives bb.
  • A quadratic in disguise: 32x3^{2x} is (3x)2(3^x)^2 — substitute y=3xy = 3^x and factorise.

Where students actually lose marks

Log-manipulation marks require simplest form — an answer left as a sum of logs when a single log is demanded, or with un-processed coefficients, loses the final accuracy mark.

June 2023 Paper 1 mark scheme (Q06)

In the exponential-model question the marks come from linking the printed graph to the algebra: intercept =loga= \log a and gradient =logb= \log b. Students who quote aa and bb without that link lose the reasoning marks.

June 2023 Paper 1 mark scheme (Q11)

Where an exact answer is asked for, working with surds/logs must stay exact throughout — rounding mid-working forfeits the accuracy marks (general guidance printed in every scheme).

June 2023 Paper 1 mark scheme (general guidance)

Try it — exam-style

Medium
ORIGINAL · after June 2023 Paper 1 Q06

1.

Given a=log2xa = \log_2 x and b=log2(x+8)b = \log_2(x + 8), express in terms of aa and/or bb: (i) log2(x3)\log_2(x^3), (ii) log2(x2+8x)\log_2(x^2 + 8x).

(3)

(Total for Question 1 is 3 marks)

Hard
ORIGINAL · after June 2023 Paper 1 Q11

2.

The value VV of a car, tt years after purchase, is modelled by V=abtV = ab^t. The graph of log10V\log_{10} V against tt is a straight line through (0,4)(0, 4) and (20,3.5)(20, 3.5). Find aa and bb.

(4)

(Total for Question 2 is 4 marks)

Hard
ORIGINAL

3.

Solve 32x5(3x)+4=03^{2x} - 5(3^x) + 4 = 0, giving exact answers.

(4)

(Total for Question 3 is 4 marks)

Easy
ORIGINAL

4.

Solve ln(2x+3)=2\ln(2x + 3) = 2, giving your answer exactly.

(2)

(Total for Question 4 is 2 marks)

Questions are written in the style of past Edexcel papers (source shown on each) — never copied from them.

Get the printable question packbrowser print view

Drill it properly

Stuck on exponentials & logarithms?

Log-linear modelling comes up nearly every year and students freeze — I teach the two-line method that unlocks it. Free intro call, then a free first lesson.