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Edexcel A-level Further Maths revision notes

Poisson and binomial distributions

Section FS1-2
Year 1
Year 1: this is the AS subject content the exam board publishes, which is what most schools teach in Year 12.
3 specification points

Notes and three levels of exam-style practice for each registered specification point in this section.

Checked against Edexcel 9FM0 section FS1-2

Checked against Edexcel 9FM0 section FS1-2. Review basis: the qualification registry sourced from the Pearson Edexcel Level 3 Advanced GCE in Further Mathematics (9FM0) specification; registry verification recorded 17 July 2026.

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In the exam: Formulae booklet provided · calculator allowed in every paper

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FS1-2.1

The Poisson distribution. The additive property of Poisson distributions.

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A Poisson distribution models a count of events occurring independently at a constant mean rate: P(X=x)=eλλxx!P(X=x)=e^{-\lambda}\dfrac{\lambda^x}{x!} for x=0,1,2,x=0,1,2,\ldots. Scale λ\lambda in proportion to the length or size of the observation interval.
  • If XPo(λ)X\sim\operatorname{Po}(\lambda) and YPo(μ)Y\sim\operatorname{Po}(\mu) are independent, then X+YPo(λ+μ)X+Y\sim\operatorname{Po}(\lambda+\mu).
  • This additive property also combines disjoint intervals of a Poisson process.
  • A real-world answer may require critical comment on constant rate and independence.
  • Examiners expect the parameter to match the requested interval and cumulative probabilities to use the correct complement and inclusive boundary.
A typical discrete, right-skewed Poisson probability mass function.
Worked example

Calls arrive at mean rate 1.41.4 per 1010 minutes. Find the probability of at least 55 calls in 3030 minutes.

  1. 1.For 3030 minutes, λ=3(1.4)=4.2\lambda=3(1.4)=4.2.
  2. 2.Let XPo(4.2)X\sim\operatorname{Po}(4.2).
  3. 3.P(X5)=1P(X4)=0.4102P(X\geq5)=1-P(X\leq4)=0.4102 to 44 significant figures.

Answer: The probability is 0.41020.4102.

Common mistakes

  • Don't use the rate for 1010 minutes as the parameter for a 3030-minute count.
  • Don't add parameters for counts that are not independent.
  • Don't calculate 1P(X5)1-P(X\leq5) for the event X5X\geq5.

Exam tip

Write the scaled distribution before using a calculator; this makes the interval conversion explicit.

Tier 1 · Easy

ORIGINAL

1.

A sensor records a Poisson-distributed number of amber flashes with mean 2.72.7 per minute. Find the probability of no amber flashes in one minute.

(2)

(Total for Question 1 is 2 marks)

Tier 2 · Standard

ORIGINAL

1.

Independent counts AA and BB have distributions Po(3.2)\operatorname{Po}(3.2) and Po(1.7)\operatorname{Po}(1.7). Find P(A+B7)P(A+B\geq7).

(3)

(Total for Question 1 is 3 marks)

Tier 3 · Hard

ORIGINAL

1.

Inspection pings are modelled by a Poisson process at a mean rate of 0.80.8 per 1010 minutes. Find the probability of exactly 22 pings in the first 1515 minutes and at most 22 pings in the next 3030 minutes. State two assumptions needed for the model and one feature of the real process that would make it unsuitable.

(8)

(Total for Question 1 is 8 marks)

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FS1-2.2

The mean and variance of the binomial distribution and the Poisson distribution.

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • For XBin(n,p)X\sim\operatorname{Bin}(n,p), E(X)=npE(X)=np and Var(X)=np(1p)\operatorname{Var}(X)=np(1-p). For YPo(λ)Y\sim\operatorname{Po}(\lambda), both mean and variance equal λ\lambda.
  • Under a linear transformation, E(aX+b)=aE(X)+bE(aX+b)=aE(X)+b but Var(aX+b)=a2Var(X)\operatorname{Var}(aX+b)=a^2\operatorname{Var}(X) because adding a constant changes location, not spread.
  • These relationships can recover unknown distribution parameters from given means or variances and help compare models with observed data.
  • The binomial parameter nn must be a positive integer and 0p10\leq p\leq1.
  • Examiners expect simultaneous parameter equations to be solved exactly where possible and a standard deviation to be the positive square root of variance.
Worked example

A binomial random variable has mean 2424 and variance 1818. Find nn and pp.

  1. 1.np=24np=24 and np(1p)=18np(1-p)=18.
  2. 2.Divide the variance equation by the mean equation: 1p=1824=341-p=\dfrac{18}{24}=\dfrac34.
  3. 3.Thus p=14p=\dfrac14 and n=24/(1/4)=96n=24/(1/4)=96.

Answer: n=96n=96 and p=14p=\dfrac14.

Common mistakes

  • Don't use npnp as both the mean and variance of a binomial distribution.
  • Don't add bb to the variance when transforming aX+baX+b.
  • Don't multiply variance by aa rather than a2a^2.

Exam tip

When both binomial mean and variance are given, divide the equations first to isolate 1p1-p.

Tier 1 · Easy

ORIGINAL

1.

Given XBin(80,0.15)X\sim\operatorname{Bin}(80,0.15), find E(X)E(X) and Var(X)\operatorname{Var}(X).

(2)

(Total for Question 1 is 2 marks)

Tier 2 · Standard

ORIGINAL

1.

The random variable YY is Poisson and Var(2Y+3)=28\operatorname{Var}(2Y+3)=28. Find the parameter of YY and E(2Y+3)E(2Y+3).

(4)

(Total for Question 1 is 4 marks)

Tier 3 · Hard

ORIGINAL

1.

A binomial random variable XX has mean 1818 and variance 13.513.5. Determine nn and pp. Hence find P(X=18)P(X=18), giving your answer to 44 significant figures.

(6)

(Total for Question 1 is 6 marks)

FS1-2.3

The use of the Poisson distribution as an approximation to the binomial distribution.

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • When nn is large and pp is small, XBin(n,p)X\sim\operatorname{Bin}(n,p) may be approximated by YPo(np)Y\sim\operatorname{Po}(np). State why the conditions are reasonable and set λ=np\lambda=np.
  • The event boundary remains discrete and unchanged: no continuity correction is used for a binomial-to-Poisson approximation.
  • Calculator cumulative functions or complements can then evaluate the probability.
  • The approximation becomes less reliable when pp is not small or when the binomial trials are not independent with constant success probability.
  • Examiners expect approximation notation or clear wording, the value of λ\lambda, and a probability answer labelled approximate rather than exact.
Worked example

Let XBin(800,0.006)X\sim\operatorname{Bin}(800,0.006). Use a Poisson approximation to estimate P(X7)P(X\geq7).

  1. 1.nn is large, pp is small and np=4.8np=4.8, so use YPo(4.8)Y\sim\operatorname{Po}(4.8).
  2. 2.P(X7)P(Y7)P(X\geq7)\approx P(Y\geq7).
  3. 3.P(Y7)=1P(Y6)=0.2092P(Y\geq7)=1-P(Y\leq6)=0.2092 to 44 significant figures.

Answer: P(X7)0.2092P(X\geq7)\approx0.2092.

Common mistakes

  • Don't use λ=p\lambda=p instead of λ=np\lambda=np.
  • Don't apply a continuity correction even though both distributions are discrete.
  • Don't quote the approximation without checking that nn is large and pp is small.

Exam tip

A full approximation line should state the conditions, YPo(np)Y\sim\operatorname{Po}(np) and the unchanged event.

Tier 1 · Easy

ORIGINAL

1.

Let XBin(900,0.004)X\sim\operatorname{Bin}(900,0.004). State a suitable Poisson approximation and use it to estimate P(X=0)P(X=0).

(3)

(Total for Question 1 is 3 marks)

Tier 2 · Standard

ORIGINAL

1.

The number of flawed seals in a batch has distribution XBin(400,0.01)X\sim\operatorname{Bin}(400,0.01). Use a Poisson approximation to estimate P(X6)P(X\geq6).

(4)

(Total for Question 1 is 4 marks)

Tier 3 · Hard

ORIGINAL

1.

For XBin(200,0.015)X\sim\operatorname{Bin}(200,0.015), calculate P(X2)P(X\leq2) exactly and by a Poisson approximation. Find the percentage error of the approximation relative to the exact value.

(6)

(Total for Question 1 is 6 marks)

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