Edexcel A-level Further Maths coverage

Further algebra and functions

Section CP-4
6 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

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CP-4.1

Understand and use the relationship between roots and coefficients of polynomial equations up to quartic equations.

  • For a monic cubic with roots α,β,γ\alpha,\beta,\gamma, the coefficients give α+β+γ=a\alpha+\beta+\gamma=-a, αβ+βγ+γα=b\alpha\beta+\beta\gamma+\gamma\alpha=b and αβγ=c\alpha\beta\gamma=-c in x3+ax2+bx+c=0x^3+ax^2+bx+c=0.
  • For a monic quartic, the elementary symmetric sums have alternating signs: sum of roots, pair products, triple products and the product are a,b,c,d-a,b,-c,d.
  • Derived sums are built from these relations; for example, α2=(α)22αβ\sum\alpha^2=(\sum\alpha)^2-2\sum\alpha\beta.
  • A common error is to ignore the leading coefficient or lose the alternating signs when the polynomial is not monic.

Tier 1 · Easy

3 marks
ORIGINAL

The roots of x35x2+2x+8=0x^3-5x^2+2x+8=0 are α,β,γ\alpha,\beta,\gamma. Without solving the equation, find α+β+γ\alpha+\beta+\gamma, αβ+βγ+γα\alpha\beta+\beta\gamma+\gamma\alpha and αβγ\alpha\beta\gamma.

Tier 2 · Standard

4 marks
ORIGINAL

The non-zero roots of 2x43x35x2+7x4=02x^4-3x^3-5x^2+7x-4=0 are α,β,γ,δ\alpha,\beta,\gamma,\delta. Without solving the equation, find α+β+γ+δ\alpha+\beta+\gamma+\delta and 1α+1β+1γ+1δ\frac1\alpha+\frac1\beta+\frac1\gamma+\frac1\delta.

Tier 3 · Hard

5 marks
ORIGINAL

The roots of x34x2+px6=0x^3-4x^2+px-6=0 are α,β,γ\alpha,\beta,\gamma, and α2+β2+γ2=10\alpha^2+\beta^2+\gamma^2=10. Determine pp and then find α3+β3+γ3\alpha^3+\beta^3+\gamma^3 without solving the cubic.

CP-4.2

Form a polynomial equation whose roots are a linear transformation of the roots of a given polynomial equation (of at least cubic degree).

  • If a new root is y=aα+by=a\alpha+b, rearrange to α=(yb)/a\alpha=(y-b)/a and substitute this expression into the original polynomial.
  • After substitution, multiply by a suitable power of aa to clear denominators, then collect powers of the new variable.
  • For a shift y=α+by=\alpha+b, replace the old variable by yby-b; for a scale y=aαy=a\alpha, replace it by y/ay/a.
  • A common error is to substitute the forward transformation ay+ba y+b instead of expressing the old root in terms of the new one.

Tier 1 · Easy

3 marks
ORIGINAL

The roots of t33t+1=0t^3-3t+1=0 are α,β,γ\alpha,\beta,\gamma. Form a polynomial equation whose roots are α+2,β+2,γ+2\alpha+2,\beta+2,\gamma+2.

Tier 2 · Standard

4 marks
ORIGINAL

The roots of 2t3t2+4t3=02t^3-t^2+4t-3=0 are α,β,γ\alpha,\beta,\gamma. Form a polynomial equation whose roots are 3α13\alpha-1, 3β13\beta-1 and 3γ13\gamma-1.

Tier 3 · Hard

6 marks
ORIGINAL

The roots of t42t3+t2+3t1=0t^4-2t^3+t^2+3t-1=0 are α,β,γ,δ\alpha,\beta,\gamma,\delta. Form a polynomial equation whose roots are 23α2-3\alpha, 23β2-3\beta, 23γ2-3\gamma and 23δ2-3\delta.

CP-4.3

Understand and use formulae for the sums of integers, squares and cubes and use these to sum other series.

  • Use r=1nr=n(n+1)2\sum_{r=1}^n r=\frac{n(n+1)}2, r=1nr2=n(n+1)(2n+1)6\sum_{r=1}^n r^2=\frac{n(n+1)(2n+1)}6 and r=1nr3=[n(n+1)2]2\sum_{r=1}^n r^3=\left[\frac{n(n+1)}2\right]^2.
  • Expand a polynomial expression in rr, split the summation term by term, and then substitute the standard formulae.
  • For example, (3r22r+4)=3r22r+4n\sum(3r^2-2r+4)=3\sum r^2-2\sum r+4n before simplification.
  • A common error is to treat 1\sum 1 as 11 instead of nn, or to change the summation limits while expanding.

Tier 1 · Easy

3 marks
ORIGINAL

Evaluate r=120r(r+1)\sum_{r=1}^{20}r(r+1).

Tier 2 · Standard

4 marks
ORIGINAL

Show that r=1n(3r22r+4)=n(2n2+n+7)2\sum_{r=1}^{n}(3r^2-2r+4)=\frac{n(2n^2+n+7)}2.

Tier 3 · Hard

6 marks
ORIGINAL

Prove that r=1nr(r+1)(2r+1)=n(n+1)2(n+2)2\sum_{r=1}^{n}r(r+1)(2r+1)=\frac{n(n+1)^2(n+2)}2. Hence evaluate the sum when n=15n=15.

CP-4.4

Understand and use the method of differences for summation of series including use of partial fractions.

  • The method of differences rewrites a term as f(r)f(r+1)f(r)-f(r+1), so intermediate terms cancel when the series is written out.
  • Partial fractions often reveal the required difference, such as 1r(r+1)=1r1r+1\frac1{r(r+1)}=\frac1r-\frac1{r+1}.
  • Write the first few and last few terms before cancelling; the surviving boundary terms determine the finite sum.
  • A common error is to cancel the final terms as well as the intermediate ones or to omit a constant factor from the partial fractions.

Tier 1 · Easy

3 marks
ORIGINAL

Use the method of differences to find r=1n1(r+2)(r+3)\sum_{r=1}^{n}\frac1{(r+2)(r+3)}.

Tier 2 · Standard

5 marks
ORIGINAL

Find a closed form for r=1n1r(r+2)\sum_{r=1}^{n}\frac1{r(r+2)}. Hence evaluate the sum for n=10n=10.

Tier 3 · Hard

6 marks
ORIGINAL

Use partial fractions and the method of differences to prove that r=1n1r(r+1)(r+2)=n(n+3)4(n+1)(n+2)\sum_{r=1}^{n}\frac1{r(r+1)(r+2)}=\frac{n(n+3)}{4(n+1)(n+2)}. Hence find the corresponding infinite sum.

CP-4.5

Find the Maclaurin series of a function including the general term.

  • The Maclaurin series is f(x)=r=0f(r)(0)r!xrf(x)=\sum_{r=0}^{\infty}\frac{f^{(r)}(0)}{r!}x^r wherever the expansion is valid.
  • Differentiate repeatedly, identify f(r)(0)f^{(r)}(0), and include factorials and powers of xx explicitly in the general term.
  • Products or composites can sometimes be handled more efficiently by combining known series or by using a complex exponential and taking a real part.
  • A common error is to give only the first few terms when the question asks for a general term, or to omit r!r! from the denominator.

Tier 1 · Easy

3 marks
ORIGINAL

Find the Maclaurin series of f(x)=11xf(x)=\frac1{1-x} and give its general term.

Tier 2 · Standard

4 marks
ORIGINAL

Find the Maclaurin series of e2xe^{2x} through degree 44, and state the general term.

Tier 3 · Hard

6 marks
ORIGINAL

Find the Maclaurin series of excosxe^x\cos x through degree 55, and give a general term for the series.

CP-4.6

Recognise and use the Maclaurin series for e^x, ln(1+x), sin x, cos x and (1+x)^n, and be aware of the range of values of x for which they are valid (proof not required).

  • ex=r=0xrr!e^x=\sum_{r=0}^{\infty}\frac{x^r}{r!}, while sinx=xx33!+\sin x=x-\frac{x^3}{3!}+\cdots and cosx=1x22!+\cos x=1-\frac{x^2}{2!}+\cdots; all three are valid for every real xx.
  • ln(1+x)=xx22+x33\ln(1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\cdots for 1<x1-1<x\leq1.
  • The binomial series (1+x)n=1+nx+n(n1)2!x2+(1+x)^n=1+nx+\frac{n(n-1)}{2!}x^2+\cdots is valid for x<1|x|<1 when it does not terminate; a non-negative integer power gives an identity for all xx.
  • A common error is to substitute axax into a standard series without also changing its range of validity.

Tier 1 · Easy

3 marks
ORIGINAL

Write down the Maclaurin series for cosx\cos x through degree 66, and state its range of validity.

Tier 2 · Standard

4 marks
ORIGINAL

Write the first four terms of the expansion of (12x)1/2(1-2x)^{-1/2}, and state the range of values of xx for which it is valid.

Tier 3 · Hard

6 marks
ORIGINAL

Use standard Maclaurin series to show that ln(1+x1x)=2(x+x33+x55+)\ln\left(\frac{1+x}{1-x}\right)=2\left(x+\frac{x^3}{3}+\frac{x^5}{5}+\cdots\right). State the range of validity and use terms up to x5x^5 to approximate ln(3/2)\ln(3/2).