Write using indices.
Algebra
Notes and three levels of exam-style practice for each registered specification leaf in this section.
Open the printable packUse and interpret algebraic manipulation: ab for a × b, 3y for y + y + y and 3 × y, a² for a × a, a³ for a × a × a, a²b for a × a × b, a/b for a ÷ b, coefficients as fractions, brackets
- Algebraic notation shortens repeated operations: means , means , and means three lots of .
- Write number factors before letters, collect repeated factors as powers, and use a fraction bar for division; brackets show which whole expression an operation acts on.
- For example, is written , with as the coefficient of .
- Do not read as , or as ; powers describe repeated multiplication and coefficients describe multiplication.
Tier 1 · Easy
Tier 2 · Standard
Write in conventional algebraic notation, and state its coefficient.
Tier 3 · Hard
A rectangle has length and width . Write its area and its perimeter in conventional algebraic notation.
Substitute numerical values into formulae and expressions, including scientific formulae
- Substitution replaces every occurrence of a letter by its given numerical value while keeping the operations in the original order.
- Put negative or fractional values in brackets, evaluate powers before multiplication, and keep extra calculator figures until the final rounding step.
- For example, if , and , then .
- A common error is to substitute into as ; the square applies to the complete substituted value.
Tier 1 · Easy
Work out when .
Tier 2 · Standard
The kinetic energy of an object is given by . Work out when and .
Tier 3 · Hard
Use to calculate when and . Give your answer in standard form.
Understand and use the concepts and vocabulary of expressions, equations, formulae, identities, inequalities, terms and factors
- An expression has no equality sign; an equation is true only for particular values, while an identity is true for every permitted value and uses .
- A formula links quantities, an inequality compares their possible values, terms are separated by addition or subtraction, and factors are multiplied together.
- In , the left side has two terms and the right side shows the factors and .
- Do not call every statement containing an identity; test whether it is always true or only true when the variable has specific values.
Tier 1 · Easy
State whether is an expression, equation or inequality.
Tier 2 · Standard
For , state the number of terms on the left and name the two factors on the right.
Tier 3 · Hard
Classify each statement as an equation, an identity or an inequality: , , and .
Simplify and manipulate algebraic expressions (incl. surds and algebraic fractions): like terms, common factors, expanding two or more binomials, factorising quadratics incl. ax² + bx + c, indices
- Only like terms can be collected; index laws apply to matching bases, while surds are combined only after simplifying them to like surds.
- Expand by multiplying every term required, and factorise by first removing common factors before choosing factors that reproduce every quadratic term.
- For example, because the cross-terms are .
- Do not cancel terms across addition in an algebraic fraction; factorise the complete numerator and denominator, then cancel common factors and retain excluded values.
Tier 1 · Easy
Simplify .
Tier 2 · Standard
Factorise .
Tier 3 · Hard
Simplify , stating every value of excluded from the original expression.
Understand and use standard mathematical formulae; rearrange formulae to change the subject
- The subject of a formula is the variable isolated on one side of the equality; changing the subject keeps an equivalent relationship.
- Undo operations in reverse order and perform the same operation on both sides, clearing fractions or brackets before collecting terms containing the new subject.
- For example, from , subtracting and then dividing by gives .
- A common error is to move a term by changing its sign without applying an operation to the whole side, especially when the subject appears more than once.
Tier 1 · Easy
Make the subject of .
Tier 2 · Standard
Make the subject of .
Tier 3 · Hard
Make the subject of .
Know the difference between an equation and an identity; argue mathematically to show algebraic expressions are equivalent, and use algebra to support and construct arguments and proofs
- An equation is satisfied by particular values, whereas an identity states that two expressions are equivalent for every permitted value.
- For an algebraic proof, define an integer with a letter, translate the claim into algebra, and rearrange it into a form that guarantees the required property.
- For example, consecutive integers and have sum , which is odd because it is one more than a multiple of .
- Checking several numerical examples is evidence but not a proof; the algebra must cover every value allowed by the claim.
Tier 1 · Easy
Show that is equivalent to .
Tier 2 · Standard
Prove algebraically that the sum of two consecutive integers is odd.
Tier 3 · Hard
An odd number is written as . Demonstrate algebraically that squaring it leaves remainder after division by .
Interpret simple expressions as functions with inputs and outputs; interpret the reverse as the 'inverse function' and two successive functions as a 'composite function' (formal notation expected)
- A function maps each allowed input to one output; means substitute the complete input into the rule for .
- The inverse reverses a one-to-one function, while the composite applies first and then .
- For example, if , then because subtracting and dividing by reverses the rule.
- Do not interpret as or reverse the order of a composite; in , the right-hand function acts first.
Tier 1 · Easy
Given , work out .
Tier 2 · Standard
Given , find and work out .
Tier 3 · Hard
Let and . Solve , where .
Work with coordinates in all four quadrants
- A coordinate gives horizontal position first and vertical position second; the signs determine the quadrant.
- Use differences in coordinates for movements, and average corresponding coordinates to find the midpoint of a line segment.
- For example, the midpoint of and is .
- Do not swap the coordinate order or ignore negative signs when subtracting endpoints; write each coordinate calculation separately.
Tier 1 · Easy
State the quadrant containing the point .
Tier 2 · Standard
Find the midpoint of the line segment joining and .
Tier 3 · Hard
The point divides the line segment from to in the ratio . Find the coordinates of .
Plot graphs of straight-line equations; use y = mx + c to identify parallel and perpendicular lines; find the equation of a line through two given points, or one point with a given gradient
- A straight line has equation , where is its gradient and is its intercept on the -axis.
- Find a gradient using , then substitute one known point to determine ; two accurate points are enough to draw the line.
- For example, the line of gradient through satisfies , so and the equation is .
- Parallel lines have equal gradients and perpendicular non-vertical lines have gradients whose product is ; do not merely change the sign.
Tier 1 · Easy
Write the equation of the line with gradient and -intercept .
Tier 2 · Standard
Find the equation of the line through and .
Tier 3 · Hard
Find the equation of the line through that is perpendicular to . Give your answer in the form .
Identify and interpret gradients and intercepts of linear functions graphically and algebraically
- The gradient measures change in the vertical quantity per unit change in the horizontal quantity; its sign shows whether the line rises or falls.
- Read the -intercept where and the -intercept where , using the axis scales and units before interpreting either value.
- For example, in , the gradient is the cost added per unit of , while is the cost when .
- Do not describe a contextual gradient or intercept as a bare number; include what it represents and the correct compound or original unit.
Tier 1 · Easy
State the gradient and -intercept of .
Tier 2 · Standard
A straight line crosses the axes at and . Find its gradient and both intercepts.
Tier 3 · Hard
A straight-line graph of water volume litres against time minutes passes through and . Find and interpret its gradient and -intercept, then write in terms of .
Identify and interpret roots, intercepts, turning points of quadratic functions graphically; deduce roots algebraically and turning points by completing the square
- Roots are the -coordinates where a quadratic graph meets the -axis, while the -intercept is found by setting .
- Factorising can reveal the roots, and completing the square into reveals the turning point and axis of symmetry .
- For example, , so its turning point is and its roots are and .
- In completed-square form, the turning point's -coordinate has the opposite sign to the value inside the bracket; do not report for .
Tier 1 · Easy
Find the roots and the -intercept of .
Tier 2 · Standard
For , state the turning point and axis of symmetry, and find the roots.
Tier 3 · Hard
Complete the square for . Hence state the turning point and find the roots.
Recognise, sketch and interpret graphs of linear, quadratic and simple cubic functions, the reciprocal y = 1/x (x ≠ 0), exponential y = k^x (k > 0), and y = sin x, cos x, tan x for angles of any size
- Recognise each family by its invariant shape: constant-gradient linear, symmetric quadratic, S-shaped cubic, two-branch reciprocal, and constant-ratio exponential.
- Sketch by marking intercepts, roots, turning points, asymptotes and representative values; for trigonometric graphs also use their periods and standard exact values.
- For example, has asymptotes and , with branches in quadrants I and III because and have the same sign.
- Do not draw a reciprocal graph touching an axis or treat exponential growth as a straight line; asymptotes may be approached without being reached.
Tier 1 · Easy
A graph passes through and its -value doubles whenever increases by . Name the function as linear, quadratic, cubic, reciprocal or exponential.
Tier 2 · Standard
For the graph , state both asymptotes and the two quadrants containing its branches.
Tier 3 · Hard
For on , list the -intercepts and the coordinates of every maximum and minimum needed for an accurate sketch.
Sketch translations and reflections of a given function [Higher only]
- For , translate the graph vertically by vector ; for , translate it horizontally by vector .
- The graph of is the reflection of in the -axis, while is its reflection in the -axis.
- For example, a point on becomes on .
- Horizontal changes act inside the function with the opposite apparent sign; moves the graph units left, not right.
Tier 1 · Easy
Describe fully the transformation from to .
Tier 2 · Standard
The point lies on . Find the corresponding point on and name the transformation.
Tier 3 · Hard
The point lies on . Find the corresponding point on , and describe the reflection and translations that produce the new graph.
Plot and interpret graphs (including reciprocal and exponential graphs) and graphs of non-standard functions in real contexts, to find approximate solutions e.g. simple kinematic problems
- A graph represents all ordered pairs that satisfy a rule; intercepts, turning points and asymptotes help describe its behaviour.
- Reciprocal graphs such as have two branches and approach the axes without meeting them, while exponential graphs change by a constant multiplier for equal changes in .
- To solve two equations graphically, plot both relations on the same axes and read the coordinates of their intersection points.
- In a real context, state what an intersection or graph feature means and use sensible units; a common error is to report a coordinate with no interpretation.
Tier 1 · Easy
The time hours for a fixed journey is modelled by , where is the average speed in km/h. Work out the point on this graph when and interpret it.
Tier 2 · Standard
Higher only: Plot and for . Use the intersection to estimate the solution of to one decimal place.
Tier 3 · Hard
For , two moving objects have distances from a marker modelled by and , with in metres and in seconds. Draw both graphs and estimate the later time when the objects are equally far from the marker.
Calculate or estimate gradients of graphs and areas under graphs (incl. quadratic and other non-linear); interpret e.g. distance-time, velocity-time and financial graphs (not calculus) [Higher only]
- The gradient between two points is change in the vertical coordinate divided by change in the horizontal coordinate; its units come from those axes.
- For a curve, draw a tangent at the required point and calculate the gradient using two well-separated points on that tangent.
- Estimate an area under a curve by splitting it into strips and using trapezia; on a velocity-time graph this area represents displacement.
- Read the scale before calculating and interpret the sign and units; a common error is to use two points on the curve instead of two points on the tangent.
Tier 1 · Easy
A distance-time graph is a straight line from to , where time is in seconds and distance is in metres. Calculate and interpret its gradient.
Tier 2 · Standard
A velocity-time graph joins the points , , and with straight lines. Work out the distance travelled in the first seconds.
Tier 3 · Hard
A curved velocity-time graph passes through the values m/s at seconds. Use three trapezia to estimate the distance travelled. A tangent at passes through and ; estimate the acceleration then.
Recognise and use the equation of a circle with centre at the origin; find the equation of a tangent to a circle at a given point [Higher only]
- A circle with centre and radius has equation .
- A point lies on the circle when its coordinates make the left-hand side equal to .
- The tangent at a point is perpendicular to the radius through that point, so their gradients multiply to when both gradients are defined.
- Substitute the given point into the final tangent equation to check it; a common error is to use the radius gradient without taking its negative reciprocal.
Tier 1 · Easy
Write down the equation of the circle with centre and radius .
Tier 2 · Standard
The point lies on the circle . Determine the tangent's equation there.
Tier 3 · Hard
The tangent to at meets the positive coordinate axes. Find the exact area of the triangle enclosed by the tangent and the axes.
Solve linear equations in one unknown algebraically (including those with the unknown on both sides of the equation); find approximate solutions using a graph
- Keep an equation balanced by carrying out the same operation on both sides until the unknown is isolated.
- Expand brackets and collect unknown terms on one side before collecting constants on the other.
- A graphical solution is the -coordinate where the graphs representing the two sides of the equation intersect.
- Clear fractions using a common multiple and check by substitution; a common error is to change a sign when moving a term without applying a valid operation.
Tier 1 · Easy
Solve .
Tier 2 · Standard
Draw and on the same axes. Use the intersection to solve , giving an estimate to one decimal place.
Tier 3 · Hard
Solve .
Solve quadratic equations (including those requiring rearrangement) algebraically by factorising, by completing the square and by using the quadratic formula; find approximate solutions using a graph
- Rearrange a quadratic equation into before choosing a solution method.
- Factorising uses the zero-product rule, while completing the square rewrites the quadratic so that a squared expression can be isolated.
- For , the quadratic formula is ; a graph gives roots as -intercepts or intersections.
- Keep both roots unless the context excludes one; a common error is to lose the negative value when taking a square root.
Tier 1 · Easy
Solve by factorising.
Tier 2 · Standard
Higher only: Solve by completing the square. Give exact answers.
Tier 3 · Hard
Higher only: The curves and intersect twice. Use the quadratic formula to find the exact -coordinates, then give the values a graph should show to two decimal places.
Solve two simultaneous equations in two variables (linear/linear or linear/quadratic) algebraically; find approximate solutions using a graph
- A simultaneous solution is an ordered pair that satisfies both equations and appears graphically as an intersection point.
- For two linear equations, eliminate one variable by adding or subtracting suitable multiples of the equations.
- When one equation is quadratic, substitute the linear expression into it, solve the resulting quadratic and find the paired value for every root.
- Check every ordered pair in both original equations; a common error is to give two -values without their corresponding -values.
Tier 1 · Easy
Solve simultaneously and .
Tier 2 · Standard
On the same axes draw and . Use the graph to estimate their point of intersection to one decimal place.
Tier 3 · Hard
Higher only: Solve simultaneously and .
Find approximate solutions to equations numerically using iteration [Higher only]
- Iteration rewrites an equation as and repeatedly applies from a stated starting value.
- Keep extra calculator digits during the repeated substitutions and round only the reported value.
- A stable decimal answer is supported when successive iterates agree to the requested accuracy, provided the iteration converges.
- Substitute the approximation into the original equation as a check; a common error is to reuse instead of the latest iterate.
Tier 1 · Easy
The iteration starts with . Work out and , giving each to three decimal places.
Tier 2 · Standard
Use with to find . Give the result to four decimal places.
Tier 3 · Hard
Let . Show that has a root between and . Starting with , use to find this root to four decimal places.
Translate simple situations or procedures into algebraic expressions or formulae; derive an equation (or two simultaneous equations), solve the equation(s) and interpret the solution
- Choose a variable and state what it represents before translating each quantity into an algebraic expression.
- Use the relationship in the situation to form an equation or a pair of simultaneous equations, including consistent units.
- Solve the equation, then translate the mathematical result back into the quantities asked for.
- Reject values that are impossible in context, such as negative lengths or ages; a common error is to stop at an unlabelled value of the variable.
Tier 1 · Easy
A rectangle has width cm and length cm. Its perimeter is cm. Form and solve an equation to find both dimensions.
Tier 2 · Standard
A club sells tickets. Adult tickets cost £7 and junior tickets cost £4. The total received is £203. Form two equations and find how many tickets of each type were sold.
Tier 3 · Hard
Mira is years older than Theo. In years, the product of their ages will be . Form an equation and find their current ages.
Solve linear inequalities in one or two variable(s), and quadratic inequalities in one variable; represent the solution set on a number line, using set notation and on a graph
- Solve a linear inequality like an equation, but reverse the inequality sign when multiplying or dividing by a negative number.
- On a number line use a filled endpoint for or and an open endpoint for or .
- For two-variable inequalities, draw each boundary and test a point to identify the required region; strict inequalities use dashed boundaries.
- For a quadratic inequality, find the roots and test the intervals they create; a common error is to assume the answer always lies between the roots.
Tier 1 · Easy
Higher only: Solve . Give the answer in set notation and describe its number-line representation.
Tier 2 · Standard
Higher only: On coordinate axes, show the region satisfying both and . State the intersection of the boundary lines and identify which boundaries are included.
Tier 3 · Hard
Higher only: Solve . Give the solution in set notation and describe it on a number line.
Generate terms of a sequence from either a term-to-term or a position-to-term rule
- A term-to-term rule produces each new term from the preceding term or terms, so begin with every stated starting value.
- A position-to-term rule gives the term directly from its position ; substitute in order.
- Write down intermediate terms when a repeated procedure is used so that alternating or multi-step rules remain in the correct order.
- Check whether the first term corresponds to ; a common error is to substitute unless the sequence explicitly starts there.
Tier 1 · Easy
A sequence has position-to-term rule . Write down its first four terms.
Tier 2 · Standard
A sequence starts . Each later term is one more than the sum of the previous two terms. Write down the next three terms.
Tier 3 · Hard
The th term of a sequence is . Generate the first six terms.
Recognise and use triangular, square and cube numbers, arithmetic progressions, Fibonacci type sequences, quadratic sequences, simple geometric progressions (r^n, r rational > 0 or a surd) and others
- Square and cube numbers have forms and , while triangular numbers have form .
- Arithmetic progressions have a constant first difference; quadratic sequences have constant second differences.
- In a Fibonacci-type sequence, later terms are formed from preceding terms, while a geometric progression has a constant multiplier between consecutive terms.
- Check more than one step before naming a pattern; a common error is to assume a sequence is arithmetic from a single pair of terms.
Tier 1 · Easy
The sequence is made from a named type of number. Name the type and write down the next two terms.
Tier 2 · Standard
A Fibonacci-type sequence begins , with each term after the second equal to the sum of the previous two. Find the eighth term.
Tier 3 · Hard
Higher only: A geometric progression begins . State the common ratio and find the eighth term in exact form.
Deduce expressions to calculate the nth term of linear and quadratic sequences
- For a linear sequence with common difference , begin with and adjust the constant so that the expression gives the first term.
- For a quadratic sequence , the constant second difference is .
- After finding , subtract the values of from the sequence; the remaining linear sequence determines and .
- Verify the expression against several given terms; a common error is to use the first term itself as the constant in the th-term expression.
Tier 1 · Easy
Find an expression for the th term of .
Tier 2 · Standard
Higher only: Find an expression for the th term of .
Tier 3 · Hard
Higher only: A quadratic sequence starts . Deduce its th term and determine the position of the term equal to .