Back to number questions

Pearson Edexcel GCSE (9–1) Mathematics

Number — topic question pack

1MA1

Original practice paper written in the style of Edexcel papers — not a Pearson publication. This pack is untiered and can include both Foundation and Higher content.

Name: __________________________________

Class: __________________________________

Answer every question. Show all stages of your working. The total number of marks is 56.

This topic pack mixes calculator and non-calculator practice. Each question states whether a calculator may be used.

Question paper

1

Here are five numbers: 0.7, 3/5, 0.68, 5/8, 71%.

Non-calculator

ORIGINAL

Write these five numbers in order of size. Start with the smallest number.

(2)

(Total for Question 1 is 2 marks)

2

In a box, 2/5 of the counters are red and the rest are blue. There are 18 red counters.

Non-calculator

ORIGINAL

Work out the number of blue counters in the box.

(2)

(Total for Question 2 is 2 marks)

3

Work out an estimate for (38.2 × 5.9) ÷ 0.21.

Non-calculator

ORIGINAL

(a)Show that a suitable estimate is 1200.

(2)

(b)Is your estimate larger or smaller than the exact answer? Give a reason.

(1)

(Total for Question 3 is 3 marks)

4

Work out, giving each answer as a mixed number in its simplest form.

Non-calculator

ORIGINAL

(a)2 1/3 + 1 3/4

(2)

(b)4 2/5 − 1 7/10

(2)

(Total for Question 4 is 4 marks)

5

Work out the following, taking care with negative numbers and order of operations.

Non-calculator

ORIGINAL

(a)−5 − (−8) + (−3)

(1)

(b)(−4)² − 3 × (−2)

(2)

(Total for Question 5 is 3 marks)

6

Work out the following.

Either calculator policy

ORIGINAL

(a)3/4 of 60

(1)

(b)35% of 220

(1)

(Total for Question 6 is 2 marks)

7

This question is about prime factors, HCF and LCM.

Non-calculator

ORIGINAL

(a)Write 84 as a product of its prime factors.

(2)

(b)Given that 120 = 2³ × 3 × 5, find the highest common factor (HCF) of 84 and 120.

(1)

(c)Find the lowest common multiple (LCM) of 84 and 120.

(1)

(Total for Question 7 is 4 marks)

8

This question is about surds. Give each answer in its simplest form.

Non-calculator

ORIGINAL

(a)Simplify √50.

(2)

(b)Rationalise the denominator of 6/√3.

(2)

(Total for Question 8 is 4 marks)

9

Write 0.45 as a fraction in its simplest form.

Non-calculator

ORIGINAL

Give your answer as a fraction in its simplest form.

(1)

(Total for Question 9 is 1 mark)

10

Work out the following, using a formal written method. You must show your working.

Non-calculator

ORIGINAL

(a)Work out 347 × 26

(2)

(b)Work out 546 ÷ 14

(2)

(Total for Question 10 is 4 marks)

11

This question is about rounding and accuracy.

Non-calculator

ORIGINAL

(a)Round 6.7482 to 2 decimal places.

(1)

(b)Round 3849 to 2 significant figures.

(1)

(c)A length L is 24 cm, measured to the nearest centimetre. Use inequalities to write down the error interval for L.

(2)

(Total for Question 11 is 4 marks)

12

Write down the value of each of the following.

Non-calculator

ORIGINAL

(a)

(1)

(b)√81

(1)

(c)the cube root of 27

(1)

(Total for Question 12 is 3 marks)

13

A café offers a set meal. There are 4 different starters, 6 different main courses and 3 different desserts. A meal is one starter, one main course and one dessert.

Non-calculator

ORIGINAL

(a)Work out the number of different meals that can be made.

(2)

(b)A password is made from 2 letters (each from A to Z, letters may repeat) followed by 1 digit (0 to 9). Work out the number of different possible passwords.

(2)

(Total for Question 13 is 4 marks)

14

This question is about money and time.

Calculator

ORIGINAL

(a)A worker is paid £11.50 per hour. She works 7.5 hours on each of 5 days. Work out her total pay for the 5 days.

(2)

(b)A train leaves a station at 09:48. The journey takes 2 hours 35 minutes. Work out the time the train arrives.

(2)

(Total for Question 14 is 4 marks)

15

This question is about standard form.

Either calculator policy

ORIGINAL

(a)Write 4 700 000 in standard form.

(1)

(b)Write 3.2 × 10⁻⁴ as an ordinary number.

(1)

(c)Work out (3 × 10⁵) × (2 × 10³). Give your answer in standard form.

(2)

(Total for Question 15 is 4 marks)

16

Two lighthouses can be seen from a harbour. One lighthouse flashes every 12 seconds. The other lighthouse flashes every 18 seconds. At 8 pm exactly, both lighthouses flash at the same time.

Non-calculator

ORIGINAL

(a)Work out the number of seconds after 8 pm when the two lighthouses next flash at the same time.

(2)

(b)A third lighthouse flashes every 8 seconds and also flashes at 8 pm exactly. Work out the number of seconds after 8 pm when all three lighthouses next flash at the same time.

(2)

(Total for Question 16 is 4 marks)

17

Work out the following, using the correct priority of operations.

Non-calculator

ORIGINAL

(a)5 + 3 × 4

(1)

(b)(8 − 2)² ÷ 4

(2)

(c)20 − 6 ÷ 2

(1)

(Total for Question 17 is 4 marks)

Pearson Edexcel GCSE (9–1) Mathematics

Mark scheme — Number

1

Answer: 3/5, 5/8, 0.68, 0.7, 71%

M1 for converting all five numbers to a common form (e.g. decimals: 0.7, 0.6, 0.68, 0.625, 0.71). A1 for the fully correct order 3/5, 5/8, 0.68, 0.7, 71% (accept the decimal/percentage equivalents in the same order).

2 marks

2

Answer: 27

M1 for a complete method, e.g. 18 ÷ 2 × 5 = 45 (total) then 45 − 18, or 3/5 of the total using 18 = 2/5. A1 for 27.

2 marks

3

(a)

Answer: 40 × 6 ÷ 0.2 = 240 ÷ 0.2 = 1200

M1 for rounding each number to 1 significant figure (40, 6 and 0.2). A1 for a correct evaluation leading to 1200.

(b)

Answer: Larger (an overestimate), because 38.2 and 5.9 were rounded up while 0.21 was rounded down, and dividing by a smaller number makes the result larger.

B1 for larger / overestimate with a valid reason (numerator rounded up and/or dividing by a smaller number).

3 marks

4

(a)

Answer: 4 1/12

M1 for a correct common denominator, e.g. 28/12 + 21/12 (or 7/3 + 7/4). A1 for 49/12 or 4 1/12.

(b)

Answer: 2 7/10

M1 for a correct common denominator, e.g. 44/10 − 17/10. A1 for 27/10 or 2 7/10.

4 marks

5

(a)

Answer: 0

B1 for 0.

(b)

Answer: 22

M1 for correctly evaluating 16 and −6 (i.e. squaring and multiplying before subtracting). A1 for 22.

3 marks

6

(a)

Answer: 45

B1 for 45.

(b)

Answer: 77

B1 for 77.

2 marks

7

(a)

Answer: 2² × 3 × 7

M1 for a correct method (factor tree or repeated division) reaching primes. A1 for 2² × 3 × 7 (accept 2 × 2 × 3 × 7).

(b)

Answer: 12

B1 for 12 (product of the common primes 2² × 3; ft their factorisation of 84).

(c)

Answer: 840

B1 for 840 (2³ × 3 × 5 × 7; ft their factorisation).

4 marks

8

(a)

Answer: 5√2

M1 for √25 × √2 (or √(25 × 2)). A1 for 5√2.

(b)

Answer: 2√3

M1 for multiplying numerator and denominator by √3, giving 6√3/3. A1 for 2√3.

4 marks

9

Answer: 9/20

B1 for 9/20 (from 45/100 simplified).

1 mark

10

(a)

Answer: 9022

M1 for a complete correct method (e.g. long multiplication or a grid with all partial products) with not more than one arithmetic error. A1 for 9022.

(b)

Answer: 39

M1 for a complete correct division method (e.g. short/long division or building up multiples of 14). A1 for 39.

4 marks

11

(a)

Answer: 6.75

B1 for 6.75.

(b)

Answer: 3800

B1 for 3800.

(c)

Answer: 23.5 ≤ L < 24.5

B1 for 23.5 as the lower bound and 24.5 as the upper bound. B1 for the fully correct interval 23.5 ≤ L < 24.5 (accept ≤ … < convention).

4 marks

12

(a)

Answer: 125

B1 for 125.

(b)

Answer: 9

B1 for 9.

(c)

Answer: 3

B1 for 3.

3 marks

13

(a)

Answer: 72

M1 for 4 × 6 × 3. A1 for 72.

(b)

Answer: 6760

M1 for 26 × 26 × 10. A1 for 6760.

4 marks

14

(a)

Answer: £431.25

M1 for 11.50 × 7.5 × 5 (or 11.50 × 37.5). A1 for 431.25.

(b)

Answer: 12:23

M1 for a correct time method (e.g. 09:48 + 2 h = 11:48, then + 35 min). A1 for 12:23.

4 marks

15

(a)

Answer: 4.7 × 10⁶

B1 for 4.7 × 10⁶.

(b)

Answer: 0.00032

B1 for 0.00032.

(c)

Answer: 6 × 10⁸

M1 for 3 × 2 = 6 and 10⁵ × 10³ = 10⁸ (or 600 000 000). A1 for 6 × 10⁸.

4 marks

16

(a)

Answer: 36 seconds

M1 for a correct method to find the LCM of 12 and 18 (e.g. listing multiples, or 2² × 3²). A1 for 36.

(b)

Answer: 72 seconds

M1 for a correct method to find the LCM of 12, 18 and 8 (e.g. 2³ × 3²). A1 for 72.

4 marks

17

(a)

Answer: 17

B1 for 17 (multiplication before addition).

(b)

Answer: 9

M1 for 6² = 36 (brackets then power). A1 for 9.

(c)

Answer: 17

B1 for 17 (division before subtraction).

4 marks