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AQA GCSE Chemistry revision notes

Using resources

Section 4.10
11 specification points

Notes and three levels of exam-style practice for each registered specification point in this section.

Checked against AQA 8462 section 4.10

Checked against AQA 8462 section 4.10. Review basis: the qualification registry sourced from the AQA GCSE Chemistry (8462) specification; registry verification recorded 17 July 2026.

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In the exam: No formula or equation sheet · calculator allowed in every paper

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4.10.1.1

Using the Earth's resources and sustainable development

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Natural resources provide warmth, shelter, food and transport; farmed timber and cotton can supplement wild supplies, while synthetic fibres and rubber can replace natural materials.
  • Classify a resource as finite if it is used much faster than it is replaced, and as renewable if natural processes replace it on a human timescale.
  • Sustainable development meets present needs without reducing the ability of future generations to meet theirs, so comparisons should include material use, energy, waste and environmental effects.
  • A common error is to call every natural resource renewable: crude oil and metal ores are natural but finite, whereas sustainably managed timber can be renewable.
  • Whether a supply is renewable also depends on the rate of use and management, not simply whether the material originated in nature.
Worked example

A mineral reserve contains 4.8×1084.8\times10^8 kg of usable ore. It is extracted at 6.0×1076.0\times10^7 kg per year. Calculate how many years the reserve would last if the rate stayed constant, and explain why the ore is finite.

  1. 1.Divide the reserve by the annual extraction: (4.8×108)/(6.0×107)=8.0(4.8\times10^8)/(6.0\times10^7)=8.0 years. Ore deposits take geological timescales to form, so this rate of use cannot be naturally replaced on a human timescale.

Answer: 8.08.0 years. The ore is used much faster than geological processes replace it.

Common mistakes

  • Don't fall into the trap of calling every natural resource renewable: crude oil and metal ores are natural but finite, whereas sustainably managed timber can be renewable.
  • Don't fall into the trap of defining sustainability only as recycling and omitting the needs of future generations.

Exam tip

For a sustainability comparison, consider raw materials, energy, waste and environmental effects over time.

Tier 1 · Easy

ORIGINAL

A factory uses crude oil to make polymer fibres and timber from a replanted forest to make boards. Classify each raw material as finite or renewable.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A company replaces crude-oil-based packaging with timber packaging from a replanted forest. Explain why this change does not automatically make the packaging sustainable.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

A building company compares insulation for a 4040-year project. Straw panels use a renewable crop, last 2020 years, require 1212 tonnes per installation and use 1.11.1 GJ of processing energy per tonne. Polymer panels use a finite raw material, last 4040 years, require 88 tonnes and use 4.64.6 GJ per tonne. Evaluate which choice is more sustainable. Use calculations.

[5 marks]

Total for this question: 5

Your progress and exam materials
4.10.1.2

Potable water

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Potable water is safe to drink because it has sufficiently low levels of dissolved salts and microbes; it is not chemically pure because dissolved substances remain.
  • In the UK, potable water is usually made by selecting a suitable fresh-water source, passing the water through filter beds and sterilising it with chlorine, ozone or ultraviolet light.
  • In water analysis, measure pH and dissolved solids and use distillation for purification; where fresh water is scarce, distillation or reverse osmosis can desalinate salty water but requires substantial energy.
  • A common error is to say filtration sterilises water: filter beds remove suspended solids, whereas sterilisation kills harmful microorganisms.
  • A potable-water process must be selected for the source: fresh water generally needs less energy to treat than seawater.
Worked example

Describe how fresh water containing mud particles and harmful bacteria is treated to make potable water. Give the purpose of each treatment step.

  1. 1.First select a suitable fresh-water source. Filtration removes insoluble particles such as mud. Sterilisation is a separate step and reduces harmful microorganisms to safe levels; an accepted agent is chlorine, ozone or ultraviolet light.

Answer: Pass it through filter beds to remove suspended solids, then sterilise it using chlorine, ozone or ultraviolet light to kill harmful microorganisms.

Common mistakes

  • Don't fall into the trap of saying filtration sterilises water: filter beds remove suspended solids, whereas sterilisation kills harmful microorganisms.
  • Don't fall into the trap of calling potable water chemically pure even though safe concentrations of dissolved substances remain.

Exam tip

Keep the treatment stages distinct: filtration removes solids, sterilisation reduces microbes, and desalination removes dissolved salts.

Tier 1 · Easy

ORIGINAL

Explain why potable water can be safe to drink without being pure water in the chemical sense.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A water company passes river water through filter beds and then declares it potable. Evaluate this treatment and state one suitable additional process.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

An island must desalinate 1.5×1061.5\times10^6 litres of sea water each day. Distillation would use 2.82.8 MJ per litre and reverse osmosis would use 0.0180.018 MJ per litre. Calculate the daily energy saved by reverse osmosis and evaluate its use if membranes need regular replacement.

[5 marks]

Total for this question: 5

4.10.1.3

Waste water treatment

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Sewage and agricultural waste water need organic matter and harmful microbes removed; industrial waste water may also contain harmful chemicals requiring extra treatment. Sewage treatment begins with screening and grit removal, followed by sedimentation that separates sewage sludge from liquid effluent.
  • The sludge is treated by anaerobic digestion, while the effluent receives aerobic biological treatment before it is released.
  • Fresh ground water is generally easiest to make potable; waste water needs biological treatment and salt water needs energy-intensive desalination.
  • Do not reverse the anaerobic sludge and aerobic effluent stages.
  • The amount and type of contamination determine why industrial waste water may need additional chemical treatment.
Sewage treatment separates liquid effluent from sludge before different biological treatments.
Worked example

Explain how the sludge and effluent from a sedimentation tank are treated biologically.

  1. 1.Treat the two streams separately. Anaerobic microorganisms break down organic matter in the sludge without oxygen. Air or oxygen is supplied to the effluent so aerobic microorganisms can break down its remaining organic material.

Answer: Sludge undergoes anaerobic digestion by microorganisms without oxygen; effluent undergoes aerobic biological treatment by microorganisms supplied with oxygen.

Common mistakes

  • Don't fall into the trap of reversing the biological stages by giving aerobic treatment for sludge and anaerobic digestion for effluent.
  • Don't fall into the trap of saying screening removes dissolved salts or microorganisms instead of large objects and grit.

Exam tip

Write sewage treatment in order from screening to sedimentation, then separate the sludge and effluent routes.

Tier 1 · Easy

ORIGINAL

State the two treatment stages used before sewage is allowed to settle and name the two products of sedimentation.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A student sends sewage sludge for aerobic treatment and liquid effluent for anaerobic digestion. Correct both parts of this plan.

[2 marks]

Total for this question: 2

Tier 3 · Hard

ORIGINAL

A treatment works processes 9.5×1039.5\times10^3 m3 of sewage in one day. Sedimentation separates 7.0%7.0\% of this volume as sludge. Calculate the sludge volume and explain why making potable water from treated waste water is generally harder than making it from fresh ground water.

[5 marks]

Total for this question: 5

4.10.1.4

Alternative methods of extracting metals (HT only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Higher tier: Phytomining uses plants to absorb metal compounds from low-grade ore; the plants are harvested and burned, leaving ash rich in metal compounds.
  • Bioleaching uses bacteria to produce a leachate solution containing metal compounds, avoiding the movement and disposal of large amounts of rock.
  • Copper can be recovered from these solutions by electrolysis or by displacement with a metal more reactive than copper, such as scrap iron.
  • A common error is to claim biological extraction gives pure metal directly: both methods first produce metal compounds that need further processing.
  • Higher tier: these methods can exploit low-grade ores with less rock movement, but extraction is slow and further processing still uses energy.
Worked example

Bioleaching produces a solution containing copper compounds. Explain how scrap iron can be used to obtain copper from this solution.

  1. 1.Place scrap iron in the copper-compound solution. Because iron is above copper in the reactivity series, iron atoms form ions while copper ions gain electrons and become copper metal. The deposited copper can then be separated from the mixture.

Answer: Iron is more reactive than copper, so iron displaces copper from the solution and solid copper is formed.

Common mistakes

  • Don't fall into the trap of claiming biological extraction gives pure metal directly: both methods first produce metal compounds that need further processing.
  • Don't fall into the trap of confusing phytomining with bioleaching by assigning bacteria to the plant-uptake process.

Exam tip

Higher tier: name the organism or plant stage, the metal-compound product and the final recovery method.

Tier 1 · Easy

ORIGINAL

Describe how phytomining produces material containing copper compounds.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

Compare phytomining with bioleaching by naming the organism used and the copper-containing product obtained from each. Explain why neither method produces pure copper directly.

[5 marks]

Total for this question: 5

Tier 3 · Hard

ORIGINAL

A conventional process yields 760760 kg of copper using 5.45.4 GJ and moves 320320 tonnes of rock in 22 days. A bioleaching process yields 690690 kg using 1.71.7 GJ, moves 3838 tonnes of residue and takes 6060 days. Calculate the energy used per kilogram of copper for each process and evaluate bioleaching.

[5 marks]

Total for this question: 5

4.10.2.1

Life cycle assessment

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • A life cycle assessment considers extracting and processing raw materials, manufacture and packaging, use during the product's lifetime, and end-of-life disposal, including transport at every stage.
  • Compare products using available data for energy, water, resources and waste, and keep the functional use the same before making numerical comparisons.
  • For comparisons such as paper and plastic shopping bags, use the same function: divide a reusable product's lifetime impacts by its uses and add per-use impacts such as washing.
  • A common error is to treat an LCA as fully objective: pollutant effects can require value judgements, and selective LCAs can omit stages to support a preferred conclusion.
  • Transport can contribute at every stage, and a fair comparison must use consistent system boundaries for both products.
Worked example

A reusable food container takes 1414 MJ to manufacture, is used 100100 times and takes 0.0300.030 MJ to wash after each use. A disposable container takes 0.240.24 MJ to manufacture and is used once. Calculate the lifetime energy per use for each container.

  1. 1.The reusable container uses 14+(100×0.030)=1714+(100\times0.030)=17 MJ in its lifetime. Dividing by 100100 gives 0.170.17 MJ per use. The disposable container is used once, so its value remains 0.240.24 MJ per use.

Answer: Reusable: 0.170.17 MJ per use; disposable: 0.240.24 MJ per use.

Common mistakes

  • Don't fall into the trap of treating an LCA as fully objective: pollutant effects can require value judgements, and selective LCAs can omit stages to support a preferred conclusion.
  • Don't fall into the trap of comparing products that deliver different numbers of uses without converting impacts to the same functional unit.

Exam tip

Structure an LCA answer by stage, then identify where missing data or value judgements limit the conclusion.

Tier 1 · Easy

ORIGINAL

State the four main stages considered in a life cycle assessment.

[4 marks]

Total for this question: 4

Tier 2 · Standard

ORIGINAL

An industry-funded life cycle assessment compares two bottles but omits transport and disposal and reports only total energy use. Give two reasons why its conclusion may be unreliable.

[2 marks]

Total for this question: 2

Tier 3 · Hard

ORIGINAL

Two protective packages perform the same job. Package A uses 1.81.8 MJ in manufacture, 0.400.40 MJ in transport and produces 6060 g of end-of-life waste; its pollutant-effect score is 22. Package B uses 0.900.90 MJ in manufacture, 1.11.1 MJ in transport and produces 2525 g of waste; its pollutant-effect score is 77. Evaluate the packages and explain one limitation of the comparison.

[5 marks]

Total for this question: 5

4.10.2.2

Ways of reducing the use of resources

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Reducing use, reusing products and recycling materials can lower demand for limited raw materials, energy use, waste and environmental damage.
  • Reuse keeps a product in service without remaking it; recycling processes the material into a new product and usually requires collection, separation and energy.
  • Metals can be melted and recast, glass can be crushed and remelted, and scrap steel can replace some newly extracted iron in steel production.
  • A common error is to assume recycling has no impact: it often saves raw materials and energy but still needs transport, sorting and processing.
  • The best option depends on the material and product because reduction usually avoids more processing than reuse or recycling.
Worked example

Producing a metal from ore uses 15.215.2 MJ kg-1, while producing it from sorted scrap uses 1.81.8 MJ kg-1. Calculate the energy saved when 840840 kg is produced from scrap.

  1. 1.The saving per kilogram is 15.21.8=13.415.2-1.8=13.4 MJ. For 840840 kg, the saving is 13.4×840=1125613.4\times840=11256 MJ, which is 1.13×1041.13\times10^4 MJ to three significant figures.

Answer: 1.13×1041.13\times10^4 MJ saved.

Common mistakes

  • Don't fall into the trap of assuming recycling has no impact: it often saves raw materials and energy but still needs transport, sorting and processing.
  • Don't fall into the trap of calling reuse and recycling the same process even though recycling requires material reprocessing.

Exam tip

For an ‘evaluate’ question, give a saved resource or impact and also a collection, sorting, transport or processing cost.

Tier 1 · Easy

ORIGINAL

Give one example each of reducing, reusing and recycling a material resource.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

A glass bottle can either be washed and refilled or crushed, melted and made into a new bottle. Identify which option is reuse and which is recycling, and explain why reuse will usually require less processing.

[3 marks]

Total for this question: 3

Tier 3 · Hard

ORIGINAL

For 60006000 deliveries, a company can use 0.120.12 kg single-use trays or reusable crates. Each 9.09.0 kg crate lasts 120120 deliveries. Single-use trays require 3.03.0 MJ kg-1 to make. Crates require 5.55.5 MJ kg-1 to make and 0.100.10 MJ of washing energy per delivery. Evaluate the switch to crates using raw-material mass and energy.

[5 marks]

Total for this question: 5

4.10.3.1

Corrosion and its prevention (chemistry only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Corrosion is the destruction of a material by chemical reactions with substances in its environment; rusting is the corrosion of iron and needs both oxygen and water.
  • To test rusting conditions, change the presence of air or water while keeping identical iron samples, temperature and time the same.
  • Barrier methods such as grease, paint and electroplating keep air and water away; aluminium protects itself with an adherent oxide layer.
  • A common error is to say any metal coating protects a scratch: sacrificial protection works only when the coating metal is more reactive than iron, as zinc is in galvanising.
  • An experiment establishing rusting conditions needs comparison samples that isolate oxygen and water while all other variables remain controlled.
Worked example

Plan an experiment using three identical iron nails to show that both air and water are needed for rusting.

  1. 1.Put one nail in contact with both air and water. Keep a second in dry air using a drying agent so water is absent. Put a third in boiled water and add an oil layer so oxygen cannot re-enter. Use identical nails at the same temperature for the same time. Only the nail with both air and water should rust.

Answer: Compare a nail in air and water with a nail in dry air and a nail in boiled water covered by oil; keep other conditions the same and record rusting.

Common mistakes

  • Don't fall into the trap of saying any metal coating protects a scratch: sacrificial protection works only when the coating metal is more reactive than iron, as zinc is in galvanising.
  • Don't fall into the trap of saying galvanising is only a barrier and omitting that zinc can protect exposed iron sacrificially.

Exam tip

For sacrificial protection, compare metal reactivity and state that the more reactive coating oxidises instead of iron.

Tier 1 · Easy

ORIGINAL

State the two substances that must both be present for iron to rust.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A scratch through paint exposes steel and rust begins, but a scratch through a zinc coating can remain protected. Explain both observations.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

Iron harbour bolts can be coated with metal X or copper. The reactivity order is magnesium, X, iron, copper. Evaluate the protection given by each coating if it is scratched through to the iron.

[5 marks]

Total for this question: 5

4.10.3.2

Alloys as useful materials (chemistry only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Bronze is copper and tin and is used for statues; brass is copper and zinc and is used for fittings. Jewellery gold is alloyed with silver, copper or zinc: 2424 carat is pure gold and 1818 carat is 75%75\% gold.
  • High-carbon steel is strong but brittle and suits cutting tools; low-carbon steel is softer and shapeable for car bodies; chromium-nickel stainless steel resists corrosion and suits sinks or cutlery.
  • Choose an alloy by linking composition to measured properties and the intended use; low-density aluminium alloys are useful for aircraft parts.
  • A common error is to describe an alloy as a compound: its proportions can vary, and different compositions can give different properties.
  • Different steels are not interchangeable: carbon content and alloying elements change strength, brittleness, shapeability and corrosion resistance.
Worked example

A gold ring has mass 12.0g12.0\,\text{g} and is 1818 carat. Calculate the mass of gold in the ring.

  1. 1.Use the specification relationship: 1818 carat gold is 75%75\% gold.
  2. 2.Convert to a decimal and multiply: 0.75×12.0g0.75\times12.0\,\text{g}.
  3. 3.Evaluate the gold mass: 9.0g9.0\,\text{g}.

Answer: 9.0g9.0\,\text{g} of gold

Common mistakes

  • Don't fall into the trap of describing an alloy as a compound: its proportions can vary, and different compositions can give different properties.
  • Don't fall into the trap of linking an alloy to a use without stating the property that makes the composition suitable.

Exam tip

Use a composition → property → use chain, and convert carat values to percentages when a numerical comparison is required.

Tier 1 · Easy

ORIGINAL

Name the two metals in bronze and the two metals in brass.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

Identify the most suitable steel — high-carbon, low-carbon or stainless — for each use: a cutting blade, a pressed car-body panel and a kitchen sink. Justify each choice.

[6 marks]

Total for this question: 6

Tier 3 · Hard

ORIGINAL

A 2.402.40 kg brass fitting contains 68.0%68.0\% copper by mass and the rest is zinc. Calculate the mass of zinc. Explain why a manufacturer might use this brass rather than pure copper when data show brass is harder but slightly less electrically conductive.

[4 marks]

Total for this question: 4

4.10.3.3

Ceramics, polymers and composites (chemistry only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • Soda-lime glass is made by heating sand, sodium carbonate and limestone; borosilicate glass contains sand and boron trioxide and melts at a higher temperature. Clay ceramics are shaped while wet and heated in a furnace; different reaction conditions allow the same ethene monomer to form both LDPE and HDPE.
  • Thermosoftening polymers melt on heating because chains can move past one another, whereas cross-links between chains prevent thermosetting polymers from melting.
  • A composite has a matrix or binder surrounding a reinforcement; examples include glass-fibre polymer, carbon-fibre polymer and concrete.
  • Link the components' combined properties to the use.
  • Material comparisons may require quantitative data, so values and units should support rather than replace the structure-property explanation.
Worked example

Explain, in terms of structure, why a thermosoftening polymer melts when heated but a thermosetting polymer does not.

  1. 1.Compare movement between chains. Heating weakens the attractions between separate thermosoftening chains enough for them to slide, so the solid softens and melts. Covalent cross-links join thermosetting chains into a network and prevent that sliding, so heating does not melt the polymer.

Answer: Thermosoftening polymer chains can move past one another when heated; thermosetting polymers have strong cross-links between chains that stop this movement, so they do not melt.

Common mistakes

  • Don't fall into the trap of saying thermosetting polymers melt because their chains slide past one another despite the cross-links.
  • Don't fall into the trap of calling the reinforcement the matrix in a composite and reversing the roles of the two components.

Exam tip

When selecting a material, identify its structure or components, link these to a property, then link the property to the use.

Tier 1 · Easy

ORIGINAL

Glass fibres are surrounded and held together by a polymer resin in a composite. Identify the reinforcement and the matrix.

[2 marks]

Total for this question: 2

Tier 2 · Standard

ORIGINAL

A carbon-fibre polymer contains carbon fibres held in a polymer resin. Identify the reinforcement and the matrix, then explain why the composite is useful where high strength and low mass are required.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A transparent oven window must work at 720720 °C. Soda-lime glass softens at 650650 °C. Borosilicate glass softens at 900900 °C, is transparent and has density 2.252.25 g cm-3. An opaque clay ceramic works to 11001100 °C. Identify the most suitable material and calculate the mass of an 8080 cm3 window.

[5 marks]

Total for this question: 5

4.10.4.1

The Haber process (chemistry only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • The Haber process makes ammonia from nitrogen obtained from air and hydrogen commonly obtained from natural gas: N2+3H22NH3\mathrm{N_2+3H_2\rightleftharpoons2NH_3}.
  • Purified gases pass over an iron catalyst at about 450450 °C and 200200 atmospheres; cooling liquefies ammonia, and unreacted nitrogen and hydrogen are recycled.
  • Higher tier: the equation gives a 1:3:21:3:2 mole ratio and the same gas-volume ratio at equal temperature and pressure, so one amount of nitrogen reacts with three of hydrogen to form two of ammonia.
  • Higher tier: lower temperature and higher pressure favour ammonia equilibrium yield, but industry compromises for a fast enough rate and acceptable energy and equipment costs; a catalyst changes rate, not equilibrium position.
  • Removing liquid ammonia and recycling unreacted gases allow continuous production despite incomplete conversion in one pass.
Worked example

Higher tier: determine the volumes of hydrogen and ammonia associated with 40dm340\,\text{dm}^3 of nitrogen at the same temperature and pressure.

  1. 1.Read the balanced equation N2+3H22NH3\mathrm{N_2+3H_2\rightleftharpoons2NH_3}.
  2. 2.Use the gas-volume ratio 1:3:21:3:2.
  3. 3.Calculate hydrogen: 3×40=120dm33\times40=120\,\text{dm}^3; ammonia: 2×40=80dm32\times40=80\,\text{dm}^3.

Answer: 120dm3120\,\text{dm}^3 of hydrogen reacts and 80dm380\,\text{dm}^3 of ammonia forms.

Common mistakes

  • Don't fall into the trap of claiming the iron catalyst increases the equilibrium yield of ammonia rather than increasing the rates of both directions.
  • Don't fall into the trap of saying the highest possible pressure and lowest possible temperature are used without considering rate, energy and equipment costs.

Exam tip

Higher tier: explain each compromise separately—temperature affects rate and equilibrium, pressure affects equilibrium and cost, while the catalyst affects rate.

Tier 1 · Easy

ORIGINAL

State the source of nitrogen, the usual source of hydrogen and the catalyst used in the Haber process.

[3 marks]

Total for this question: 3

Tier 2 · Standard

ORIGINAL

Explain how ammonia is separated from the gases leaving a Haber reactor and why the remaining gases are returned to the reactor.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A plant sends 800800 kg of a nitrogen-hydrogen mixture through a Haber reactor. After one pass, 184184 kg of ammonia is separated. Calculate the percentage of the feed converted to ammonia in this pass and explain what happens to the remaining gases.

[4 marks]

Total for this question: 4

4.10.4.2

Production and uses of NPK fertilisers (chemistry only)

Notes
Evidence from your answers: none yet
Your confidence:

A self-report of how sure you feel. It does not measure mastery. Evidence from your answers reaches secure after the latest Tier 2/3 attempt is correct, with three correct distinct drills across at least two dates and two practice sources.

Explanation

  • NPK fertilisers are formulations containing salts that supply nitrogen, phosphorus and potassium in suitable percentages to improve agricultural productivity.
  • Ammonia is used to make ammonium salts and nitric acid; potassium chloride, potassium sulfate and phosphate rock are obtained by mining.
  • Phosphate rock is insoluble and is treated with acids to make useful salts: nitric acid gives calcium nitrate, sulfuric acid can give calcium sulfate or single superphosphate, and phosphoric acid gives calcium phosphate or triple superphosphate.
  • A common error is to describe industrial fertiliser production as a scaled-up school crystallisation only: industry uses integrated, often continuous processes with different raw materials and controls.
  • The required NPK percentages make the fertiliser a formulation rather than a single pure compound.
Worked example

Name one useful salt formed when phosphate rock is treated with each acid: nitric acid, sulfuric acid and phosphoric acid.

  1. 1.Match the acid anion to the named calcium salt from phosphate-rock treatment. Nitrate comes from nitric acid, sulfate from sulfuric acid and phosphate from phosphoric acid; the superphosphate names are accepted industrial product names.

Answer: Nitric acid: calcium nitrate; sulfuric acid: calcium sulfate or single superphosphate; phosphoric acid: calcium phosphate or triple superphosphate.

Common mistakes

  • Don't fall into the trap of describing industrial fertiliser production as a scaled-up school crystallisation only: industry uses integrated, often continuous processes with different raw materials and controls.
  • Don't fall into the trap of stating that phosphate rock is applied directly as the phosphorus component even though it is insoluble.

Exam tip

Match each acid treatment to the named fertiliser salt and distinguish integrated industrial production from a batch laboratory preparation.

Tier 1 · Easy

ORIGINAL

State what the letters N, P and K represent on an NPK fertiliser label and explain why phosphate rock is not used directly as a fertiliser.

[4 marks]

Total for this question: 4

Tier 2 · Standard

ORIGINAL

An NPK fertiliser contains ammonium nitrate, a treated phosphate salt and potassium chloride in controlled proportions. State which ingredient supplies N, P and K, and explain why the product is a formulation.

[4 marks]

Total for this question: 4

Tier 3 · Hard

ORIGINAL

A laboratory batch makes 3535 g of ammonium salt every 4545 minutes. An integrated industrial process operates continuously at 2.42.4 kg per minute. Calculate the mass each route makes in 3.03.0 hours and compare the routes for large-scale fertiliser production.

[5 marks]

Total for this question: 5

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