AQA GCSE Chemistry coverage

The rate and extent of chemical change

Section 4.6
11 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

Open the printable pack
4.6.1.1

Calculating rates of reactions

  • Mean rate is the quantity of reactant used or product formed divided by the time taken; suitable units include g s1\text{g s}^{-1} and cm3 s1\text{cm}^3\text{ s}^{-1}.
  • On a quantity-time graph, a steeper gradient means a faster reaction. A curve becoming horizontal shows that the measured quantity is no longer changing.
  • To find a mean rate, subtract the two quantity readings and divide by the time interval; Higher Tier also uses mol s1\text{mol s}^{-1} and calculates an instantaneous rate from a tangent gradient.
  • A common error is to divide the final reading by the clock time even when the graph or table starts from a non-zero quantity; always calculate the change first.

Tier 1 · Easy

2 marks
ORIGINAL

A reaction produces 72cm372\,\text{cm}^3 of gas in 40s40\,\text{s}. Calculate its mean rate.

Tier 2 · Standard

3 marks
ORIGINAL

The mass of a reaction flask falls from 83.40g83.40\,\text{g} to 82.56g82.56\,\text{g} during the first 35s35\,\text{s}. Calculate the mean rate of mass loss.

Tier 3 · Hard

5 marks
ORIGINAL

Reaction R forms 84cm384\,\text{cm}^3 of gas in 70s70\,\text{s}. Reaction S forms 99cm399\,\text{cm}^3 in 55s55\,\text{s}. Calculate both mean rates and determine the percentage by which S is faster than R.

4.6.1.2

Factors which affect the rates of chemical reactions

  • Reaction rate can be changed by concentration in solution, pressure for gases, surface area of a solid, temperature and the presence of a catalyst.
  • Increasing concentration, gas pressure, solid surface area or temperature usually increases rate; a suitable catalyst also increases rate.
  • In the required practical, concentration can be varied while gas volume is measured, or while a colour or turbidity change is timed; other variables must be controlled.
  • A common error is to change total volume as well as concentration without recognising the extra variable. Use measured volumes and keep temperature, quantities not under test and apparatus consistent.

Tier 1 · Easy

1 mark
ORIGINAL

A solid reactant is crushed into smaller pieces without changing its mass. State the effect on the reaction rate.

Tier 2 · Standard

4 marks
ORIGINAL

A student investigates how acid concentration affects the rate of gas production from marble chips. Describe how the student should collect suitable results while changing only the acid concentration.

Tier 3 · Hard

5 marks
ORIGINAL

In a turbidity experiment, relative acid concentrations of 20%20\%, 40%40\% and 60%60\% give disappearance times of 162162, 8181 and 54s54\,\text{s}. Describe the relationship shown and give two limitations of using the disappearance time as a rate measurement.

4.6.1.3

Collision theory and activation energy

  • A reaction occurs only when reactant particles collide and the collision has at least the activation energy.
  • Greater concentration or gas pressure puts more particles into a given volume, so collisions occur more frequently and rate increases.
  • Higher temperature makes particles move faster, causing more frequent collisions and a larger fraction of collisions with energy at least equal to the activation energy.
  • Smaller solid pieces have a larger surface area to volume ratio. A common error is to say that temperature only increases collision frequency and omit the greater collision energy.

Tier 1 · Easy

2 marks
ORIGINAL

State the two conditions needed for a collision between reactant particles to lead to a reaction.

Tier 2 · Standard

3 marks
ORIGINAL

Explain, using collision theory, why increasing the pressure of two reacting gases increases their reaction rate at constant temperature.

Tier 3 · Hard

6 marks
ORIGINAL

A fixed 64cm364\,\text{cm}^3 of solid is cut either into cubes of side 2.0cm2.0\,\text{cm} or cubes of side 1.0cm1.0\,\text{cm}. Calculate the total surface area for each set and explain which reacts faster with an acid.

4.6.1.4

Catalysts

  • A catalyst increases reaction rate without being used up overall; different reactions may require different catalysts, and enzymes are biological catalysts.
  • Catalysts provide a different reaction pathway with a lower activation energy, so a greater fraction of collisions can lead to reaction at the same temperature.
  • On a reaction profile, the catalysed curve has a lower peak but the reactant and product energy levels, and therefore the overall energy change, stay the same.
  • A common error is to say a catalyst gives particles more energy or increases product yield. It changes the pathway and rate, not the energy levels or final amount fixed by a limiting reactant.

Tier 1 · Easy

1 mark
ORIGINAL

Complete the statement: a catalyst increases reaction rate by providing a different pathway with a lower what?

Tier 2 · Standard

3 marks
ORIGINAL

An uncatalysed reaction has an activation energy of 79kJ mol179\,\text{kJ mol}^{-1} and an overall energy change of 24kJ mol1-24\,\text{kJ mol}^{-1}. A catalyst lowers the activation energy to 43kJ mol143\,\text{kJ mol}^{-1}. State the reduction in activation energy and the catalysed reaction's overall energy change.

Tier 3 · Hard

5 marks
ORIGINAL

In the first 30s30\,\text{s}, a reaction forms 48cm348\,\text{cm}^3 of gas with solid X and 21cm321\,\text{cm}^3 without X. Both tests eventually form 72cm372\,\text{cm}^3, and the dry mass of X is unchanged. Use the data to explain why X is a catalyst.

4.6.2.1

Reversible reactions

  • In a reversible reaction, products can react to form the original reactants; the equation uses the reversible arrow \rightleftharpoons.
  • Changing conditions can favour one direction, so the same chemical system may be driven towards products or back towards reactants.
  • For a general reaction A+BC+D\mathrm{A+B\rightleftharpoons C+D}, the forward process forms C and D while the reverse process consumes C and D to reform A and B.
  • A common error is to treat the double arrow as meaning the reaction must have reached equilibrium. Reversibility is possible even before the two rates become equal.

Tier 1 · Easy

1 mark
ORIGINAL

State what is meant by a reversible reaction.

Tier 2 · Standard

2 marks
ORIGINAL

The reaction J+KL+M\mathrm{J+K\rightleftharpoons L+M} is reversible. State which substances react in the reverse reaction and which substances they form.

Tier 3 · Hard

4 marks
ORIGINAL

Blue hydrated copper sulfate is heated and forms white anhydrous copper sulfate and water. Adding water to the white solid reforms the blue substance. Explain how these observations show a reversible reaction and identify the change of condition used in each direction.

4.6.2.2

Energy changes and reversible reactions

  • If the forward direction of a reversible reaction is exothermic, the reverse direction is endothermic.
  • The two directions transfer the same amount of energy with opposite signs because one direction exactly reverses the energy change of the other.
  • A forward energy change of q-q corresponds to a reverse energy change of +q+q; reactant and product energy levels exchange roles.
  • A common error is to change only the sign but not recognise the change in energy flow: the exothermic direction releases energy and the endothermic direction takes it in.

Tier 1 · Easy

1 mark
ORIGINAL

The forward direction of a reversible reaction is exothermic. State the energy-change type of the reverse direction.

Tier 2 · Standard

2 marks
ORIGINAL

The forward direction of a reversible reaction transfers 67kJ mol167\,\text{kJ mol}^{-1} to the surroundings. State the energy change for the reverse direction, including its sign.

Tier 3 · Hard

4 marks
ORIGINAL

A reversible reaction has a forward activation energy of 145kJ mol1145\,\text{kJ mol}^{-1} and a forward overall energy change of 38kJ mol1-38\,\text{kJ mol}^{-1}. Calculate the reverse activation energy and state the reverse overall energy change.

4.6.2.3

Equilibrium

  • A reversible reaction can reach dynamic equilibrium only in a closed system that prevents reactants and products from escaping.
  • At equilibrium, the forward and reverse reactions continue at exactly the same rate; neither reaction has stopped.
  • Because the two rates are equal, the macroscopic amounts or concentrations remain constant even though particles continue to react in both directions.
  • A common error is to say equilibrium means equal amounts of reactants and products. The amounts are constant, but they do not have to be equal.

Tier 1 · Easy

1 mark
ORIGINAL

State the relationship between the forward and reverse reaction rates at equilibrium.

Tier 2 · Standard

3 marks
ORIGINAL

A student says, 'The concentrations stay constant at equilibrium because both reactions have stopped.' Explain why this statement is incorrect.

Tier 3 · Hard

4 marks
ORIGINAL

In a sealed vessel, the measured forward and reverse rates in arbitrary units are: at 0s0\,\text{s}, 5.25.2 and 0.00.0; at 20s20\,\text{s}, 3.63.6 and 1.71.7; at 40s40\,\text{s}, 2.82.8 and 2.82.8; at 60s60\,\text{s}, 2.82.8 and 2.82.8. Determine when equilibrium is first reached and explain what the later readings show.

4.6.2.4

The effect of changing conditions on equilibrium (HT only)

  • The relative amounts of reactants and products at equilibrium depend on the reaction conditions.
  • If an equilibrium condition changes, the system responds in the direction that counteracts that change; this is Le Chatelier's principle.
  • Predict a shift by identifying the imposed change first, then choosing the direction that consumes an addition or replaces a removal, or that opposes a temperature or pressure change.
  • A common error is to assume every change moves equilibrium towards products. Some changes favour reactants, and simultaneous changes can have opposing effects.

Tier 1 · Easy

1 mark
ORIGINAL

State Le Chatelier's principle for a system at equilibrium when a condition is changed.

Tier 2 · Standard

3 marks
ORIGINAL

For R2P\mathrm{R\rightleftharpoons2P} at equilibrium, some P is removed. Predict the direction of shift and explain it using Le Chatelier's principle.

Tier 3 · Hard

4 marks
ORIGINAL

The forward reaction A+2BC\mathrm{A+2B\rightleftharpoons C} is exothermic. At equilibrium, the concentration of B and the temperature are both increased. Explain why the information given is insufficient to predict the final change in the amount of C.

4.6.2.5

The effect of changing concentration (HT only)

  • Increasing a reactant concentration shifts equilibrium towards products until a new equilibrium is established.
  • Decreasing a product concentration also shifts equilibrium towards products because the forward reaction replaces some of the removed product.
  • For any concentration change, identify which side contains the changed substance and choose the direction that consumes an addition or replaces a removal.
  • A common error is to say the imposed concentration is completely restored. The system only counteracts the change, and all concentrations settle at new constant values.

Tier 1 · Easy

1 mark
ORIGINAL

A reactant is added to a mixture at equilibrium. State the direction in which the equilibrium shifts.

Tier 2 · Standard

3 marks
ORIGINAL

For D+EF\mathrm{D+E\rightleftharpoons F}, some F is continuously removed from an equilibrium mixture. Explain the effect on the relative amount of F that is formed.

Tier 3 · Hard

4 marks
ORIGINAL

For N2+3H22NH3\mathrm{N_2+3H_2\rightleftharpoons2NH_3} at equilibrium, extra hydrogen is added while the temperature is kept constant. Predict the effect of this concentration change on the amounts of all three substances as a new equilibrium is reached.

4.6.2.6

The effect of temperature changes on equilibrium (HT only)

  • Increasing temperature favours the endothermic direction because that direction takes in energy and counteracts the heating.
  • Decreasing temperature favours the exothermic direction because that direction releases energy and counteracts the cooling.
  • First label the forward reaction as exothermic or endothermic, then apply the temperature change to predict whether the relative amount of products rises or falls.
  • A common error is to use the rule that higher temperature increases rate and conclude that product yield must rise. Both directions speed up; equilibrium position depends on energy transfer.

Tier 1 · Easy

1 mark
ORIGINAL

The forward reaction is endothermic. State the effect of increasing temperature on the relative amount of products at equilibrium.

Tier 2 · Standard

3 marks
ORIGINAL

The forward direction of XY\mathrm{X\rightleftharpoons Y} is exothermic. Explain the effect of decreasing temperature on the equilibrium yield of Y.

Tier 3 · Hard

5 marks
ORIGINAL

For the same equilibrium, product yields are 68%68\% at 300K300\,\text{K}, 49%49\% at 400K400\,\text{K} and 32%32\% at 500K500\,\text{K}. Reaction time falls as temperature rises. Deduce the energy-change type of the forward reaction and explain why an industrial process might use an intermediate temperature.

4.6.2.7

The effect of pressure changes on equilibrium (HT only)

  • For gaseous equilibria, increasing pressure shifts the position towards the side with fewer gas molecules in the balanced symbol equation.
  • Decreasing pressure shifts the position towards the side with more gas molecules; only gaseous species are counted for this rule.
  • Count the stoichiometric coefficients of gases on both sides before predicting a shift. If the totals are equal, pressure does not change the equilibrium position.
  • A common error is to count different chemical formulae rather than molecules, or to include solids and liquids when applying the pressure rule.

Tier 1 · Easy

1 mark
ORIGINAL

A gaseous equilibrium has three gas molecules on the left of its equation and one on the right. State the direction of shift when pressure is increased.

Tier 2 · Standard

3 marks
ORIGINAL

For N2(g)+3H2(g)2NH3(g)\mathrm{N_2(g)+3H_2(g)\rightleftharpoons2NH_3(g)}, predict and explain the effect of increasing pressure on the equilibrium yield of ammonia.

Tier 3 · Hard

5 marks
ORIGINAL

Pressure is decreased for each equilibrium: (1) 2SO2(g)+O2(g)2SO3(g)\mathrm{2SO_2(g)+O_2(g)\rightleftharpoons2SO_3(g)}; (2) H2(g)+I2(g)2HI(g)\mathrm{H_2(g)+I_2(g)\rightleftharpoons2HI(g)}. Predict the effect on the product amount in each case and justify both predictions.