AQA GCSE Chemistry coverage

Chemical changes

Section 4.4
15 spec leafs

Notes and three levels of exam-style practice for each registered specification leaf in this section.

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4.4.1.1

Metal oxides

  • A metal reacting with oxygen forms a metal oxide; the metal is oxidised because it gains oxygen.
  • Reduction is the loss of oxygen from a substance, while oxidation is the gain of oxygen.
  • For example, heating copper in oxygen forms copper oxide: 2Cu+O22CuO2\mathrm{Cu}+\mathrm{O_2}\rightarrow2\mathrm{CuO}.
  • Do not decide oxidation from the presence of oxygen alone: track whether oxygen is gained or lost by the named substance.

Tier 1 · Easy

2 marks
ORIGINAL

Magnesium burns in oxygen to form MgO\mathrm{MgO}. Name the type of reaction and explain your choice in terms of oxygen.

Tier 2 · Standard

3 marks
ORIGINAL

A student heats 6.4g6.4\,\mathrm{g} of copper in oxygen and obtains 8.0g8.0\,\mathrm{g} of copper oxide. Calculate the mass of oxygen gained and state what has happened to the copper.

Tier 3 · Hard

4 marks
ORIGINAL

Hydrogen is passed over hot copper oxide: CuO+H2Cu+H2O\mathrm{CuO}+\mathrm{H_2}\rightarrow\mathrm{Cu}+\mathrm{H_2O}. Identify what is oxidised and what is reduced, explaining each answer using oxygen transfer.

4.4.1.2

The reactivity series

  • A useful order is potassium, sodium, lithium, calcium, magnesium, carbon, zinc, iron, hydrogen and copper, from more reactive to less reactive.
  • Metal reactivity is linked to how readily its atoms form positive ions; more reactive metals form positive ions more readily.
  • A more reactive metal displaces a less reactive metal from its compound, so displacement evidence can establish an order.
  • At room temperature, potassium, sodium and lithium react rapidly with cold water, calcium less vigorously and magnesium very slowly; zinc, iron and copper do not. Metals above hydrogen react with dilute acids, increasingly slowly down to iron, while copper does not; reactions with steam are outside this point.

Tier 1 · Easy

1 mark
ORIGINAL

Place magnesium, copper and zinc in decreasing order of reactivity.

Tier 2 · Standard

3 marks
ORIGINAL

Metal P displaces Q from a solution of Q ions. Metal Q displaces R from a solution of R ions. Metal R does not displace P from a solution of P ions. Deduce the reactivity order of P, Q and R and justify it.

Tier 3 · Hard

5 marks
ORIGINAL

Four metals W, X, Y and Z are tested at room temperature. W reacts rapidly with cold water. X reacts slowly with dilute acid but not with cold water. Y does not react with cold water, reacts quickly with dilute acid and displaces X from an X salt solution. Z shows no reaction with dilute acid. Deduce their order from most to least reactive and explain the position of Z relative to hydrogen.

4.4.1.3

Extraction of metals and reduction

  • Very unreactive metals can occur native, but most metals occur as compounds and must be extracted by chemical reactions.
  • A metal below carbon in the reactivity series can be extracted from its oxide by reduction with carbon.
  • In oxygen-transfer language, the metal oxide is reduced because it loses oxygen; carbon is oxidised because it gains oxygen.
  • Use supplied evidence to evaluate an extraction route; detailed industrial processes beyond reduction of oxides with carbon are not required here.

Tier 1 · Easy

2 marks
ORIGINAL

Copper is less reactive than carbon. Explain why carbon can be used to obtain copper from copper oxide.

Tier 2 · Standard

4 marks
ORIGINAL

Aluminium is above carbon, zinc is below carbon and gold is very unreactive. For each metal, choose the most suitable description: found as the metal itself, extracted from its oxide using carbon, or requires a method other than carbon reduction. Explain each choice.

Tier 3 · Hard

6 marks
ORIGINAL

Consider 2CuO+C2Cu+CO22\mathrm{CuO}+\mathrm{C}\rightarrow2\mathrm{Cu}+\mathrm{CO_2}. Identify the substance oxidised and the substance reduced, explaining each identification using oxygen transfer. A proposed alternative uses less fuel but produces only half as much copper per batch. State two pieces of additional information needed to judge which route is preferable.

4.4.1.4

Oxidation and reduction in terms of electrons (HT only)

  • Oxidation is loss of electrons and reduction is gain of electrons: OIL RIG.
  • A half equation shows electrons explicitly and must balance both atoms and total charge.
  • In a metal displacement, the more reactive metal loses electrons while the displaced metal ions gain electrons.
  • Do not identify redox from charge signs alone: compare the same species before and after the reaction and track electron transfer.

Tier 1 · Easy

2 marks
ORIGINAL

The half equation is ZnZn2++2e\mathrm{Zn}\rightarrow\mathrm{Zn^{2+}}+2\mathrm{e^-}. State whether zinc is oxidised or reduced and explain why.

Tier 2 · Standard

3 marks
ORIGINAL

Complete and balance the half equation Cl2+eCl\mathrm{Cl_2}+\square\,\mathrm{e^-}\rightarrow\square\,\mathrm{Cl^-} and identify the process.

Tier 3 · Hard

5 marks
ORIGINAL

Magnesium is added to copper(II) ion solution. Write the oxidation half equation, the reduction half equation and the overall ionic equation. Identify the species oxidised and the species reduced.

4.4.2.1

Reactions of acids with metals

  • Acids react with magnesium, zinc and iron to produce a salt and hydrogen gas.
  • Hydrochloric acid forms chloride salts, while sulfuric acid forms sulfate salts.
  • For example, Zn+2HClZnCl2+H2\mathrm{Zn}+2\mathrm{HCl}\rightarrow\mathrm{ZnCl_2}+\mathrm{H_2}; the metal has replaced hydrogen from the acid.
  • Do not add water as a product: acid plus metal gives salt plus hydrogen. At Higher Tier, metal atoms lose electrons and are oxidised, while hydrogen ions gain electrons and are reduced.

Tier 1 · Easy

2 marks
ORIGINAL

Name the two products when magnesium reacts with dilute hydrochloric acid.

Tier 2 · Standard

3 marks
ORIGINAL

Write a balanced symbol equation for iron reacting with dilute sulfuric acid to form iron(II) sulfate and hydrogen.

Tier 3 · Hard

4 marks
ORIGINAL

Higher Tier: magnesium reacts with hydrochloric acid according to Mg+2H+Mg2++H2\mathrm{Mg}+2\mathrm{H^+}\rightarrow\mathrm{Mg^{2+}}+\mathrm{H_2}. Write the oxidation and reduction half equations, then identify the species oxidised and the species reduced.

4.4.2.2

Neutralisation of acids and salt production

  • An acid and an alkali or base form a salt and water; an acid and a metal carbonate form a salt, water and carbon dioxide.
  • Hydrochloric acid makes chlorides, nitric acid makes nitrates and sulfuric acid makes sulfates.
  • The positive ion in the alkali, base or carbonate supplies the metal part of the salt.
  • A common error is to choose the salt only from the acid: both the acid's negative ion and the other reactant's positive ion are needed.

Tier 1 · Easy

2 marks
ORIGINAL

Potassium hydroxide is neutralised by nitric acid. Name the salt formed and the other product.

Tier 2 · Standard

3 marks
ORIGINAL

Complete the word equation and explain the salt name: copper oxide + sulfuric acid \rightarrow ______ + ______.

Tier 3 · Hard

5 marks
ORIGINAL

Aluminium hydroxide reacts with sulfuric acid. Deduce the formula of aluminium sulfate and balance the symbol equation.

4.4.2.3

Soluble salts

  • Warm dilute acid gently, then add an insoluble metal oxide or carbonate in small portions until some solid remains unreacted.
  • Filter to remove the excess insoluble solid; the filtrate is the salt solution.
  • Use a water bath or electric heater to evaporate some water, allow the concentrated solution to cool and crystallise, then separate and dry the crystals.
  • Do not evaporate all the water with strong heating, because this can spit, lose product or leave an impure powder rather than good crystals.

Tier 1 · Easy

2 marks
ORIGINAL

Why is an insoluble solid added to an acid until some remains unreacted when making a soluble salt?

Tier 2 · Standard

4 marks
ORIGINAL

Put these stages for making copper sulfate crystals from copper oxide and dilute sulfuric acid into a safe, logical order: crystallise, filter, warm the acid, add excess copper oxide, evaporate some water, dry the crystals.

Tier 3 · Hard

6 marks
ORIGINAL

Describe how to prepare a pure, dry sample of zinc chloride crystals using zinc carbonate and dilute hydrochloric acid. Include the purpose of each separation or heating stage.

4.4.2.4

The pH scale and neutralisation

  • The pH scale runs from 00 to 1414: acids have pH below 77, neutral solutions have pH 77, and alkalis have pH above 77.
  • Universal or wide-range indicator gives an approximate pH from colour; a calibrated pH probe gives a numerical reading.
  • Acids in water produce H+\mathrm{H^+} ions, while aqueous alkalis contain OH\mathrm{OH^-} ions.
  • Neutralisation is H++OHH2O\mathrm{H^+}+\mathrm{OH^-}\rightarrow\mathrm{H_2O}; equal volumes are not necessarily neutral if the reacting amounts differ.

Tier 1 · Easy

3 marks
ORIGINAL

Classify solutions with pH 33, pH 77 and pH 1111 as acidic, neutral or alkaline.

Tier 2 · Standard

3 marks
ORIGINAL

A colourless solution may have pH 55, 77 or 99. Describe how to determine its approximate pH and state one method that would give a more precise numerical value.

Tier 3 · Hard

5 marks
ORIGINAL

An alkali is added in small portions to an acidic solution until its pH changes from 22 to 77. Explain the pH change in terms of ions, write the ionic equation for neutralisation, and explain why adding equal volumes of acid and alkali would not always give pH 77.

4.4.2.5

Titrations (chemistry only)

  • Use a volumetric pipette to transfer a fixed volume to a conical flask and a burette to deliver the other solution accurately.
  • Add a suitable indicator, approach the end point dropwise while swirling, and record the burette difference as the titre.
  • Repeat until concordant titres are obtained, then calculate a mean from concordant results rather than including a rough value.
  • At Higher Tier, use the balanced equation and volumes in dm3\mathrm{dm^3} to calculate concentrations in moldm3\mathrm{mol\,dm^{-3}} and gdm3\mathrm{g\,dm^{-3}}.

Tier 1 · Easy

2 marks
ORIGINAL

Name the apparatus used to transfer exactly 25.0cm325.0\,\mathrm{cm^3} of alkali and the apparatus used to add a measured, variable volume of acid.

Tier 2 · Standard

5 marks
ORIGINAL

Describe how to obtain an accurate mean titre when titrating a strong alkali with a strong acid.

Tier 3 · Hard

5 marks
ORIGINAL

Higher Tier: 25.0cm325.0\,\mathrm{cm^3} of sodium hydroxide is neutralised by 18.60cm318.60\,\mathrm{cm^3} of 0.150moldm30.150\,\mathrm{mol\,dm^{-3}} hydrochloric acid. The equation has a 1:11:1 ratio. Calculate the sodium hydroxide concentration in moldm3\mathrm{mol\,dm^{-3}} and gdm3\mathrm{g\,dm^{-3}}. Use Mr(NaOH)=40.0M_r(\mathrm{NaOH})=40.0.

4.4.2.6

Strong and weak acids (HT only)

  • A strong acid ionises completely in water, whereas a weak acid ionises only partially.
  • Hydrochloric, nitric and sulfuric acids are strong; ethanoic, citric and carbonic acids are weak.
  • Strength describes degree of ionisation, while concentration describes the amount of solute per volume; either a strong or weak acid may be dilute.
  • For whole-number pH values, a decrease of one pH unit means a tenfold increase in hydrogen ion concentration, not an increase of one unit.

Tier 1 · Easy

2 marks
ORIGINAL

State the difference between a strong acid and a weak acid in aqueous solution.

Tier 2 · Standard

4 marks
ORIGINAL

Equal-concentration solutions of hydrochloric acid and ethanoic acid are compared. Predict which has the lower pH and explain why. State whether the comparison tells you that either solution is more concentrated.

Tier 3 · Hard

4 marks
ORIGINAL

Solution A has pH 22 and solution B has pH 55. Calculate how many times greater the hydrogen ion concentration is in A than in B. Explain why saying 'A is 33 times more acidic' is incorrect.

4.4.3.1

The process of electrolysis

  • An electrolyte is a molten ionic compound or ionic solution whose mobile ions allow it to conduct electricity.
  • Positive ions move to the negative cathode, while negative ions move to the positive anode.
  • When ions are discharged at the electrodes, they form elements; the electric current drives this decomposition process.
  • In the electrolyte, charge is carried by moving ions rather than free electrons; a solid ionic compound does not conduct because its ions are fixed.

Tier 1 · Easy

2 marks
ORIGINAL

State which electrode attracts positive ions during electrolysis and give the charge on that electrode.

Tier 2 · Standard

3 marks
ORIGINAL

Solid sodium chloride does not conduct electricity, but molten sodium chloride does. Explain this difference in terms of ions.

Tier 3 · Hard

5 marks
ORIGINAL

A molten ionic compound contains only M2+\mathrm{M^{2+}} and X\mathrm{X^-} ions. Describe the movement of both ions when a direct current is applied, name the type of substance formed at each electrode, and state what carries charge through the melt.

4.4.3.2

Electrolysis of molten ionic compounds

  • A molten binary ionic compound contains only its metal ions and non-metal ions, so its products are predictable from those ions.
  • The metal forms at the negative cathode and the non-metal forms at the positive anode when inert electrodes are used.
  • For molten lead bromide, lead forms at the cathode and bromine forms at the anode.
  • Do not apply the aqueous-solution rules to a molten compound: there is no water supplying competing hydrogen or hydroxide ions.

Tier 1 · Easy

2 marks
ORIGINAL

Predict the products at the cathode and anode when molten zinc chloride is electrolysed using inert electrodes.

Tier 2 · Standard

4 marks
ORIGINAL

Molten lead bromide is electrolysed with inert electrodes. Name each product, identify its electrode, and explain why lead bromide must be molten.

Tier 3 · Hard

5 marks
ORIGINAL

A binary compound has formula CaCl2\mathrm{CaCl_2}. Predict both electrolysis products in the molten state and explain how the formula supports the relative numbers of calcium ions and chloride ions discharged.

4.4.3.3

Using electrolysis to extract metals

  • Electrolysis extracts metals that are too reactive for carbon reduction or that react with carbon.
  • Extraction uses much energy because the ionic compound must be molten and an electric current must be maintained.
  • Aluminium is extracted from a molten mixture of aluminium oxide and cryolite; the mixture has a lower melting point than pure aluminium oxide.
  • Oxygen produced at the carbon anode reacts with carbon to form carbon dioxide, so the positive electrodes wear away and must be replaced.

Tier 1 · Easy

2 marks
ORIGINAL

Explain why aluminium is extracted using electrolysis rather than by reducing aluminium oxide with carbon.

Tier 2 · Standard

3 marks
ORIGINAL

Cryolite is mixed with aluminium oxide before electrolysis. Explain how this reduces the energy cost of extraction.

Tier 3 · Hard

5 marks
ORIGINAL

An aluminium plant considers two electrolytes. Mixture A melts at 950C950\,^{\circ}\mathrm{C}; mixture B melts at 1210C1210\,^{\circ}\mathrm{C}. Both contain the same amount of aluminium oxide and give the same aluminium output. The cells use carbon anodes. Choose the likely lower-energy mixture and explain both your choice and why the anodes need regular replacement.

4.4.3.4

Electrolysis of aqueous solutions

  • An aqueous electrolyte contains ions from the dissolved compound as well as H+\mathrm{H^+} and OH\mathrm{OH^-} originating from water.
  • At the cathode, hydrogen forms if the metal is more reactive than hydrogen; otherwise the metal forms.
  • At the anode, a halide ion forms its halogen; if no halide is present, oxygen forms.
  • Apply both electrode rules separately and assume inert electrodes unless told otherwise; do not simply name the elements in the solute.

Tier 1 · Easy

2 marks
ORIGINAL

Predict the products at inert electrodes during electrolysis of aqueous sodium chloride.

Tier 2 · Standard

4 marks
ORIGINAL

Aqueous copper(II) sulfate is electrolysed using inert electrodes. Predict both products and justify each using the discharge rules.

Tier 3 · Hard

6 marks
ORIGINAL

Predict and compare the electrode products for aqueous magnesium chloride and aqueous silver nitrate, both with inert electrodes. Explain every product using relative reactivity or the halide rule.

4.4.3.5

Representation of reactions at electrodes as half equations (HT only)

  • At the cathode, positive ions gain electrons, so cathode reactions are reductions.
  • At the anode, negative ions lose electrons, so anode reactions are oxidations.
  • Balance a half equation by conserving atoms and total charge; electrons go on the side needed to balance charge.
  • Check electron direction: electrons are reactants in a reduction half equation and products in an oxidation half equation.

Tier 1 · Easy

2 marks
ORIGINAL

Complete the cathode half equation Al3++eAl\mathrm{Al^{3+}}+\square\,\mathrm{e^-}\rightarrow\mathrm{Al} and name the process.

Tier 2 · Standard

3 marks
ORIGINAL

Write the balanced half equation for bromide ions forming bromine at the anode and explain why it is oxidation.

Tier 3 · Hard

6 marks
ORIGINAL

During electrolysis of aqueous sodium sulfate with inert electrodes, hydrogen forms at the cathode and oxygen forms at the anode. Write a balanced half equation for each electrode and label oxidation and reduction.