Magnesium burns in oxygen to form . Name the type of reaction and explain your choice in terms of oxygen.
Chemical changes
Notes and three levels of exam-style practice for each registered specification leaf in this section.
Open the printable packMetal oxides
- A metal reacting with oxygen forms a metal oxide; the metal is oxidised because it gains oxygen.
- Reduction is the loss of oxygen from a substance, while oxidation is the gain of oxygen.
- For example, heating copper in oxygen forms copper oxide: .
- Do not decide oxidation from the presence of oxygen alone: track whether oxygen is gained or lost by the named substance.
Tier 1 · Easy
Tier 2 · Standard
A student heats of copper in oxygen and obtains of copper oxide. Calculate the mass of oxygen gained and state what has happened to the copper.
Tier 3 · Hard
Hydrogen is passed over hot copper oxide: . Identify what is oxidised and what is reduced, explaining each answer using oxygen transfer.
The reactivity series
- A useful order is potassium, sodium, lithium, calcium, magnesium, carbon, zinc, iron, hydrogen and copper, from more reactive to less reactive.
- Metal reactivity is linked to how readily its atoms form positive ions; more reactive metals form positive ions more readily.
- A more reactive metal displaces a less reactive metal from its compound, so displacement evidence can establish an order.
- At room temperature, potassium, sodium and lithium react rapidly with cold water, calcium less vigorously and magnesium very slowly; zinc, iron and copper do not. Metals above hydrogen react with dilute acids, increasingly slowly down to iron, while copper does not; reactions with steam are outside this point.
Tier 1 · Easy
Place magnesium, copper and zinc in decreasing order of reactivity.
Tier 2 · Standard
Metal P displaces Q from a solution of Q ions. Metal Q displaces R from a solution of R ions. Metal R does not displace P from a solution of P ions. Deduce the reactivity order of P, Q and R and justify it.
Tier 3 · Hard
Four metals W, X, Y and Z are tested at room temperature. W reacts rapidly with cold water. X reacts slowly with dilute acid but not with cold water. Y does not react with cold water, reacts quickly with dilute acid and displaces X from an X salt solution. Z shows no reaction with dilute acid. Deduce their order from most to least reactive and explain the position of Z relative to hydrogen.
Extraction of metals and reduction
- Very unreactive metals can occur native, but most metals occur as compounds and must be extracted by chemical reactions.
- A metal below carbon in the reactivity series can be extracted from its oxide by reduction with carbon.
- In oxygen-transfer language, the metal oxide is reduced because it loses oxygen; carbon is oxidised because it gains oxygen.
- Use supplied evidence to evaluate an extraction route; detailed industrial processes beyond reduction of oxides with carbon are not required here.
Tier 1 · Easy
Copper is less reactive than carbon. Explain why carbon can be used to obtain copper from copper oxide.
Tier 2 · Standard
Aluminium is above carbon, zinc is below carbon and gold is very unreactive. For each metal, choose the most suitable description: found as the metal itself, extracted from its oxide using carbon, or requires a method other than carbon reduction. Explain each choice.
Tier 3 · Hard
Consider . Identify the substance oxidised and the substance reduced, explaining each identification using oxygen transfer. A proposed alternative uses less fuel but produces only half as much copper per batch. State two pieces of additional information needed to judge which route is preferable.
Oxidation and reduction in terms of electrons (HT only)
- Oxidation is loss of electrons and reduction is gain of electrons: OIL RIG.
- A half equation shows electrons explicitly and must balance both atoms and total charge.
- In a metal displacement, the more reactive metal loses electrons while the displaced metal ions gain electrons.
- Do not identify redox from charge signs alone: compare the same species before and after the reaction and track electron transfer.
Tier 1 · Easy
The half equation is . State whether zinc is oxidised or reduced and explain why.
Tier 2 · Standard
Complete and balance the half equation and identify the process.
Tier 3 · Hard
Magnesium is added to copper(II) ion solution. Write the oxidation half equation, the reduction half equation and the overall ionic equation. Identify the species oxidised and the species reduced.
Reactions of acids with metals
- Acids react with magnesium, zinc and iron to produce a salt and hydrogen gas.
- Hydrochloric acid forms chloride salts, while sulfuric acid forms sulfate salts.
- For example, ; the metal has replaced hydrogen from the acid.
- Do not add water as a product: acid plus metal gives salt plus hydrogen. At Higher Tier, metal atoms lose electrons and are oxidised, while hydrogen ions gain electrons and are reduced.
Tier 1 · Easy
Name the two products when magnesium reacts with dilute hydrochloric acid.
Tier 2 · Standard
Write a balanced symbol equation for iron reacting with dilute sulfuric acid to form iron(II) sulfate and hydrogen.
Tier 3 · Hard
Higher Tier: magnesium reacts with hydrochloric acid according to . Write the oxidation and reduction half equations, then identify the species oxidised and the species reduced.
Neutralisation of acids and salt production
- An acid and an alkali or base form a salt and water; an acid and a metal carbonate form a salt, water and carbon dioxide.
- Hydrochloric acid makes chlorides, nitric acid makes nitrates and sulfuric acid makes sulfates.
- The positive ion in the alkali, base or carbonate supplies the metal part of the salt.
- A common error is to choose the salt only from the acid: both the acid's negative ion and the other reactant's positive ion are needed.
Tier 1 · Easy
Potassium hydroxide is neutralised by nitric acid. Name the salt formed and the other product.
Tier 2 · Standard
Complete the word equation and explain the salt name: copper oxide + sulfuric acid ______ + ______.
Tier 3 · Hard
Aluminium hydroxide reacts with sulfuric acid. Deduce the formula of aluminium sulfate and balance the symbol equation.
Soluble salts
- Warm dilute acid gently, then add an insoluble metal oxide or carbonate in small portions until some solid remains unreacted.
- Filter to remove the excess insoluble solid; the filtrate is the salt solution.
- Use a water bath or electric heater to evaporate some water, allow the concentrated solution to cool and crystallise, then separate and dry the crystals.
- Do not evaporate all the water with strong heating, because this can spit, lose product or leave an impure powder rather than good crystals.
Tier 1 · Easy
Why is an insoluble solid added to an acid until some remains unreacted when making a soluble salt?
Tier 2 · Standard
Put these stages for making copper sulfate crystals from copper oxide and dilute sulfuric acid into a safe, logical order: crystallise, filter, warm the acid, add excess copper oxide, evaporate some water, dry the crystals.
Tier 3 · Hard
Describe how to prepare a pure, dry sample of zinc chloride crystals using zinc carbonate and dilute hydrochloric acid. Include the purpose of each separation or heating stage.
The pH scale and neutralisation
- The pH scale runs from to : acids have pH below , neutral solutions have pH , and alkalis have pH above .
- Universal or wide-range indicator gives an approximate pH from colour; a calibrated pH probe gives a numerical reading.
- Acids in water produce ions, while aqueous alkalis contain ions.
- Neutralisation is ; equal volumes are not necessarily neutral if the reacting amounts differ.
Tier 1 · Easy
Classify solutions with pH , pH and pH as acidic, neutral or alkaline.
Tier 2 · Standard
A colourless solution may have pH , or . Describe how to determine its approximate pH and state one method that would give a more precise numerical value.
Tier 3 · Hard
An alkali is added in small portions to an acidic solution until its pH changes from to . Explain the pH change in terms of ions, write the ionic equation for neutralisation, and explain why adding equal volumes of acid and alkali would not always give pH .
Titrations (chemistry only)
- Use a volumetric pipette to transfer a fixed volume to a conical flask and a burette to deliver the other solution accurately.
- Add a suitable indicator, approach the end point dropwise while swirling, and record the burette difference as the titre.
- Repeat until concordant titres are obtained, then calculate a mean from concordant results rather than including a rough value.
- At Higher Tier, use the balanced equation and volumes in to calculate concentrations in and .
Tier 1 · Easy
Name the apparatus used to transfer exactly of alkali and the apparatus used to add a measured, variable volume of acid.
Tier 2 · Standard
Describe how to obtain an accurate mean titre when titrating a strong alkali with a strong acid.
Tier 3 · Hard
Higher Tier: of sodium hydroxide is neutralised by of hydrochloric acid. The equation has a ratio. Calculate the sodium hydroxide concentration in and . Use .
Strong and weak acids (HT only)
- A strong acid ionises completely in water, whereas a weak acid ionises only partially.
- Hydrochloric, nitric and sulfuric acids are strong; ethanoic, citric and carbonic acids are weak.
- Strength describes degree of ionisation, while concentration describes the amount of solute per volume; either a strong or weak acid may be dilute.
- For whole-number pH values, a decrease of one pH unit means a tenfold increase in hydrogen ion concentration, not an increase of one unit.
Tier 1 · Easy
State the difference between a strong acid and a weak acid in aqueous solution.
Tier 2 · Standard
Equal-concentration solutions of hydrochloric acid and ethanoic acid are compared. Predict which has the lower pH and explain why. State whether the comparison tells you that either solution is more concentrated.
Tier 3 · Hard
Solution A has pH and solution B has pH . Calculate how many times greater the hydrogen ion concentration is in A than in B. Explain why saying 'A is times more acidic' is incorrect.
The process of electrolysis
- An electrolyte is a molten ionic compound or ionic solution whose mobile ions allow it to conduct electricity.
- Positive ions move to the negative cathode, while negative ions move to the positive anode.
- When ions are discharged at the electrodes, they form elements; the electric current drives this decomposition process.
- In the electrolyte, charge is carried by moving ions rather than free electrons; a solid ionic compound does not conduct because its ions are fixed.
Tier 1 · Easy
State which electrode attracts positive ions during electrolysis and give the charge on that electrode.
Tier 2 · Standard
Solid sodium chloride does not conduct electricity, but molten sodium chloride does. Explain this difference in terms of ions.
Tier 3 · Hard
A molten ionic compound contains only and ions. Describe the movement of both ions when a direct current is applied, name the type of substance formed at each electrode, and state what carries charge through the melt.
Electrolysis of molten ionic compounds
- A molten binary ionic compound contains only its metal ions and non-metal ions, so its products are predictable from those ions.
- The metal forms at the negative cathode and the non-metal forms at the positive anode when inert electrodes are used.
- For molten lead bromide, lead forms at the cathode and bromine forms at the anode.
- Do not apply the aqueous-solution rules to a molten compound: there is no water supplying competing hydrogen or hydroxide ions.
Tier 1 · Easy
Predict the products at the cathode and anode when molten zinc chloride is electrolysed using inert electrodes.
Tier 2 · Standard
Molten lead bromide is electrolysed with inert electrodes. Name each product, identify its electrode, and explain why lead bromide must be molten.
Tier 3 · Hard
A binary compound has formula . Predict both electrolysis products in the molten state and explain how the formula supports the relative numbers of calcium ions and chloride ions discharged.
Using electrolysis to extract metals
- Electrolysis extracts metals that are too reactive for carbon reduction or that react with carbon.
- Extraction uses much energy because the ionic compound must be molten and an electric current must be maintained.
- Aluminium is extracted from a molten mixture of aluminium oxide and cryolite; the mixture has a lower melting point than pure aluminium oxide.
- Oxygen produced at the carbon anode reacts with carbon to form carbon dioxide, so the positive electrodes wear away and must be replaced.
Tier 1 · Easy
Explain why aluminium is extracted using electrolysis rather than by reducing aluminium oxide with carbon.
Tier 2 · Standard
Cryolite is mixed with aluminium oxide before electrolysis. Explain how this reduces the energy cost of extraction.
Tier 3 · Hard
An aluminium plant considers two electrolytes. Mixture A melts at ; mixture B melts at . Both contain the same amount of aluminium oxide and give the same aluminium output. The cells use carbon anodes. Choose the likely lower-energy mixture and explain both your choice and why the anodes need regular replacement.
Electrolysis of aqueous solutions
- An aqueous electrolyte contains ions from the dissolved compound as well as and originating from water.
- At the cathode, hydrogen forms if the metal is more reactive than hydrogen; otherwise the metal forms.
- At the anode, a halide ion forms its halogen; if no halide is present, oxygen forms.
- Apply both electrode rules separately and assume inert electrodes unless told otherwise; do not simply name the elements in the solute.
Tier 1 · Easy
Predict the products at inert electrodes during electrolysis of aqueous sodium chloride.
Tier 2 · Standard
Aqueous copper(II) sulfate is electrolysed using inert electrodes. Predict both products and justify each using the discharge rules.
Tier 3 · Hard
Predict and compare the electrode products for aqueous magnesium chloride and aqueous silver nitrate, both with inert electrodes. Explain every product using relative reactivity or the halide rule.
Representation of reactions at electrodes as half equations (HT only)
- At the cathode, positive ions gain electrons, so cathode reactions are reductions.
- At the anode, negative ions lose electrons, so anode reactions are oxidations.
- Balance a half equation by conserving atoms and total charge; electrons go on the side needed to balance charge.
- Check electron direction: electrons are reactants in a reduction half equation and products in an oxidation half equation.
Tier 1 · Easy
Complete the cathode half equation and name the process.
Tier 2 · Standard
Write the balanced half equation for bromide ions forming bromine at the anode and explain why it is oxidation.
Tier 3 · Hard
During electrolysis of aqueous sodium sulfate with inert electrodes, hydrogen forms at the cathode and oxygen forms at the anode. Write a balanced half equation for each electrode and label oxidation and reduction.