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Reaction enthalpy from mean bond enthalpies

Energetics
AQA 7405
ORIGINAL

dH = sum(bonds broken) - sum(bonds formed)

Count bonds in the balanced gaseous equation, then subtract energy released making bonds from energy absorbed breaking them.

Board and spec code confirmed against AQA 7405 · registry checked 2026-07-11How this checking works

Work it, then mark it

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Q1

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g). Mean bond enthalpies: C-H 413, O=O 498, C=O in CO2 805, O-H 464 kJ/mol. Calculate dH.

[3 marks]

Total for this question: 3

Do the calculation on paper first — then mark it.

Where the marks get lost

  • Counting two O-H bonds instead of four in two water molecules.
  • Using liquid-water formation data with gaseous mean bond enthalpies.

Exam tip: Mean bond enthalpies apply to gaseous molecules and therefore give an approximate reaction enthalpy.

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